Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12

Answers

Answer 1

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer 2

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.


Related Questions

Help please! !!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

the answer is -16(t-2)(t+1)

Step-by-step explanation:

21. A square park has an area of 120 m2

a) What are the dimensions of the park? Give your answer to the nearest metre.
b) If fencing costs $18.50/m, how much would it cost to install a fence around the park?
Show your work

plsss help me quick :((

Answers

Answer:

120m2

$6.25

$4.50

85

57

12

12

32

54

69

87

89

12

34

58

(2x+y)2-y2 if x=-3 y=4 and z=-5

Answers

Answer:
-12
Hope this helps!
So your equation it (2x+y)2-y2 so then you will substitute meaning your equation will now be 2(-3)+4*2-(4)2 and I assume it’s squared and there is a lot of things missing but I get -6+8-16 all together it would be 14 that’s what I get at least

solve pls brainliest

Answers

Answer:

[tex]18 {m}^{2} [/tex]

Step-by-step explanation:

[tex]area \: = 6m \times 4m \\ = 24 {m}^{2} \\ \\ grass \: area = 3m \times 2m \\ = 6 {m}^{2} \\ \\ cement \: area \: = 24 {m}^{2} - 6 {m}^{2} \\ = 18 {m}^{2} [/tex]

Answer:

18 m^2

Step by step explanation:

In these types of math problems, we have two ways to solve.

1) Directly find the area of the shaded area.

2)Find the unshaded area and then minus that from the total area.

In this case, I will use the second way.

The grass area (unshaded) is 3 x 2 = 6 m^2 ( 6 square meters )

The total area (grass + cement) is 4 x 6 = 24 m^2 ( 24 square meters )

Now, we want the area of the cement part but the grass's area is also in the total.

So, we minus 6m^2 from 24m^2.

Then we get 18m^2.

And that is the answer.

I hope it helps.

(Note : because this problem is easy, you can use both ways but most use the second way. There may also be problems where we can use only the first or second way.)

HELP ME OUT PLEASE!!!
WILL GIVE BRAINLIEST!!!

Answers

Answer:

-4 9/10, -4 3/4, -4.2

Step-by-step explanation:

A. -4.9

B. -4.75

C. -4.2

ANSWER:

-4 9

10

-4 3

10

-4.2

Step-by-step explanation:

HOPE IT HELPSSSS

the sum of three whole numbers in a row is 57. what are the three numbers?

Answers

Answer:

18, 19, 20

Step-by-step explanation:

(n) + (n + 1) + (n + 2) = 57

3n + 3 = 57

3n = 57 - 3 = 54

n = 54/3 = 18

three numbers are 18, 18+1, 18+2

18, 19, 20

Answer:

18,19,20

Step-by-step explanation:

x + (x+1) + (x+2) = 57

x + x + 1 + x + 2 = 57

Combine like terms

3x + 3 = 57

subtract 3 from both sides

3x = 54

divide both sides by 3

x = 18

The answer is 18, 19, 20

Since we know the value of x, we can look at it like this:

x + (x+1) + (x+2) --- > 18 + (18+ 1) + (18+2) --> 18 + 19 + 20

(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme​

Answers

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]

For which function is the ordered pair (5, 10) not a solution?

y = 15 - x
y = x - 5
y = x + 5
y = 2 x

Answers

Answer:

y = x - 5

Step-by-step explanation:

y = x - 5

10 = 5 - 5

10 is not equal 0

Answer:

y = x - 5

Step-by-step explanation:

y = x - 5

10 = 5 - 5

10 is not equal 0

pasagot po please
answer it please​

Answers

Answer:

24 I hope help you yieeeeeee

Answer:

ummmmmmmmmmm itsssssssss

Step-by-step explanation:

Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²​

Answers

Solution:

[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]

Answer:

[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]

Hope it helps.

Do comment if you have any query.

When there’s a power to the second outside of the parentheses, you multiply the entire equation by its self, so (4a - 5b)(4a-5b)=16a^2-40ab+25b^2

what is the awnser and solve for C
2c=6–3c

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

[tex]\fbox \colorbox{black}{ \colorbox{white}{C} \:  \:  \:   \:  \:  \:  \: \: \colorbox{white}{  = }  \:  \:  \:  \:  \:   + \colorbox{white}{6/5}}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

Let's find the value of c ~

[tex]2c = 6 - 3c[/tex]

[tex]2c + 3c = 6[/tex]

[tex]5c = 6[/tex]

[tex]c = \dfrac{6}{5} \: \: or \: \: 1.2[/tex]

Answer:

c= -6

Step-by-step explanation:

2c -6 = 3c

we move all to the left

2c -6 (3c)= 0

add everything and the variables

-1c - 6 = 0

move all terms containing c to the left everything else to the right

-1c = 6

c=6/-1

c=-6

Express the tan G as a fraction in simplest terms.

Answers

Answer:

[tex]\frac{\sqrt{70} }{5}[/tex]

3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1

Answers

Answer:

Option D)  [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]

Step-by-step explanation:

Given the equation, T = 15 + c × n, where:

T = represents the total monthly gym cost

c =  represents the additional charge for a group class, and

n = represents the number of group classes attended

Solution:

In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n  algebraically.

The first step is to subtract 15 from both sides:

T = 15 + c × n

T - 15 = 15 - 15 + c × n

T - 15 = c × n

Next, divide both sides by c to isolate n :

[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]

[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]

Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].

Which of the following is true?

|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5

Answers

Answer:

|-4| < |-5|

Step-by-step explanation:

because if modules is given sub sign will be deducate

Can someone help me with this please​

Answers

Answer:

y=1/2x

Step-by-step explanation:

Answer:

10

9

8

7

6

5

4

3

2

1

0 1 2 3 4 5 6 7 8 9 10

Step-by-step explanation:

So the arrow is pointing at 10 and  5

Answer 10 5

Not 5

its 10 5

So the answer is 10 5

pls help me with this:((((((​

Answers

Answer: Multiple answers

Step-by-step explanation:

Answer: Multiple answers

Step-by-step explanation:

P.E.M.D.A.S (order of operations)

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction (From left to right)

M=Multiplication

D=Division

Multiplication is done before division.

So, multiply 1.21*2 for the first problem, and 1.20*2 for the other 2 problems.

1.

24/(1.21)2 becomes 24/2.42

24/2.42= 9.9173553719 (or 9.92 rounded, or 9.9)

2.

29/(1.20)2 becomes 29/2.4

29/2.4= 12.0833333333 (or 12.08 rounded, or 12.1)

3.

40/(1.20)2 becomes 40/2.4

40/2.4= 16.6666666667 (or 16.7 rounded)

I am not sure if you have to round your answers up, so I provided those answers as well in case.

Hope this helps!

fill in the blank with the letter of the description that best matches the term for the verb porter, match the subject pronoun with the correct form of the verb. i'll mark Brainliest if the answers are correct.

A. portons
B. porte
C. portez
D. portes
E. portent
FILL IN THE BLANK

je ____
tu ____
nous ____
vous ____
ils ____

Answers

Step-by-step explanation:

je........porte

tu.......portes

nous.......portons

vous........portez

ils......portent

the common multiple of 4 and 20 is? a.3 b.4 c.8 d.20

Answers

Answer:

i belive its A

Step-by-step explanation: hope this helps :)

Answer:

B. 4

Step-by-step explanation:

4 times 5 is 20 and 20 divided by 5 is 4

-x+3y=0
x+3y=12

System of linear equation by elimination

Answers

Answer:

x=6

y=2

Step-by-step explanation:

-x+3y=0 (1)

x+3y=12 (2)

(1)+(2)<=> 6y=12

A 250-foot length of fence is placed around a three-sided animal pen.
Two of the sides of the pen are 100 feet long each. Does the fence
form a right triangle? Prove that your answer is correct.

Answers

Step-by-step explanation:

no it does not form a right triangle. 

 

a+b+c = 250

 

1002 + 502 does not equal 1002

nor 1002 + 1002  does not equal 502

 

so therefore the sides are 100, 100, and 50 but these do not make a right triangle

tony purchases a pair of jeans for 45.49 before tax the jeans were originally priced at 69.99 what was the percent discount a 35% B 20% C 65% and D 80% pls help
the book is think up

Answers

Answer:

your so funny for a annoying kid

Step-by-step explanation:

A convenience store purchased a magazine and marked it up 100% from the original cost of $2.30. A week later, the store placed the magazine on sale for 50% off. What was the discount price?

Can someone help plz

Answers

Here’s ur help The answer is 571

Andrew shovels snow for 4 %2 hours and makes
$27. How much did he make per hour?
And how much does he earn in 8 hours?

Answers

He got paid $54! :)

6p - 5 =13
3
-3
12
15

Answers

Answer:

6p=13+5

6p=18

p=18/6

p=3

BRAINLIEST, 5 STARS, AND A THANKS FOR WHOEVER HELPS!

Which statement about the answer to this problem is most accurate?
​5\6−3\8=19\24​


The answer 19\24 is reasonable because both fractions are closer to 1\2 than they are to 1, making the difference close to 0.

The answer 19\24 is reasonable because ​5\6​ and 3\8​ are both closer to 1 than to 1\2, making the difference close to 0.

The answer 19\24 is not reasonable because ​5\6​ is closer to 1 than to ​1\2​, and ​3\8​ is close to ​1\2​, making the difference close to 1\2. ​

The answer​ 19\24 ​is not reasonable because ​5\6​ is closer to ​1\2​ than to 1, and ​3\8​ is closer to 0 than to ​1\2, making the difference close to​ ​1\2​.

Answers

Answer:

The answer 19\24 is not reasonable because ​5\6​ is closer to 1 than to ​1\2​, and ​3\8​ is close to ​1\2​, making the difference close to 1\2. ​

Step-by-step explanation:

Answer:

1/2 1 0

Step-by-step explanation:


Consider this function.
h(x) = (x - 2)^2+3

Which of the following domain restrictions would enable h(x) to have an inverse function?
a. x < 1
b. x >5
c. x < 3
d. x > 4

(Ps: all four answer and larger equal then or smaller equal then

Answers

Answer:

No inverse function:  (a), (b), (c)

Inverse function exists:  (d)

Step-by-step explanation:

The graph of h(x) = (x - 2)^2 + 3 is a parabola that opens upward and has vertex at (2, 3).  If the entire graph is drawn, and the horizontal line test then applied, h(x) would not have an inverse, because the horizontal line would intersect the  parabolic graph twice.

Note that if we restricted the domain to x ≥ 2, the resulting graph would pass the horizontal line test.  This would also be true for x ≥ 3, x ≥ 4, and so on.  Not so for (a) x < 1.  False for x > -5.  True for x < 3.  True for x > 4.

No inverse function:  (a), (b), (c)

Inverse function exists:  (d)

The greatest possible number whose digits are all even numbers from 1 to 9

Answers

Answer:

8642

Step-by-step explanation:

Our even numbers from 1-9 are:

2,4,6,8

The largest possible number using the even numbers once is 8642.

Hoped this helped

In a class of 33 students, the ratio of girls to boys is 6:5. How many are there

3. $ 70 is to be divided among Joseph, Ann and Mary in the ratio 3:5:6. How much would

each receive?​

Answers

Answer:

18 girls and 15 boys.

Step-by-step explanation:

not sure on question 2. $21.33, $23.33, $25.33???

which rotation about its center will carry a regular hexagon onto itself

Answers

There are 6 angles between neighbour vertices, they all are equal (because a hexagon is regular) and their sum is 360°. Thus each angle has a measure of 360°/6=60°. Each subsequent rotation by 60° also maps a hexagon onto itself.

Help me this question is so hard i fried up my brain yesterday working on it for so long!!!!

Answers

Hello there! (:

The answer is 9.

3^4=3*3*3*3 (81)

3^2=9

81:9=9

So the answer is 9.

Hope it helps! If you have any question or query, feel free to ask! (:

~An excited gal

[tex]SparklingFlower[/tex]

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