which pair of terms are not like terms?
A. 4a and 7a
B. 3p^2q and -p^2q
C. 2mn and mn^2
D. -x and 3x

Answers

Answer 1

Answer:

C.

Step-by-step explanation:

Like terms must have exactly the same variables and exactly the same exponents.

In C., you have mn and mn^2. That makes the variable parts not the same, so they are not like terms.

Answer: C.


Related Questions

A necklace is made from 2 purple pyramids and 12 yellow spheres. What is the ratio of pyramids to spheres in its simplest form?​

Answers

Answer:

1:6

Step-by-step explanation:

2:12

\/

1:6

Have a nice day!

     If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

1:6

Step-by-step explanation:

2/12 = 1/6

HELP PLSSS!!!
What is the equation of the line?
A: y=2x+2
B: y= 1/2x -4
C: y=1/2x + 2
D: y=2x-4
GIVING BRAINLY TO CORRECT ANSWER

Answers

Answer:

The answer is C

Step-by-step explanation:

Hope that helps ;)

The answer is D. 99.999%

write a peacewise function for the graph
please help me

Answers

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Prove that ~

[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]


by using first principle of differentiation ~​

Answers

Answer:

METHOD I:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

Substituting these in eqn. (i)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

sec x can be written as 1/ cos(x)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

Taking LCM

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

By Cosines sum to product formula, i.e.,

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

2/ h can also be written as 1/(h/ 2)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

We have limₓ→₀ (sin x) / x = 1.

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

h→0 means h/ 2→0

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

METHOD II:

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

sec x can also  be written as (cos x)⁻¹

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

Any base with negative exponent is equal to its reciprocal with same positive exponent

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

The inner function that remains is cos x whose derivative is -sin x.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

cos²x can also be written as (cos x).(cos x)

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

sin x/ cos x is tan x, while 1/ cos x is sec x

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Hence, Proved!

help - does anyone know how to calculate the gradient of this?

Answers

Answer:

To calculate the gradient of a straight line we choose two points on the line itself. From these two points we calculate: The difference in height (y co-ordinates) ÷ The difference in width (x co-ordinates). If the answer is a positive value then the line is uphill in direction.

To calculate the gradient of a straight line we choose two points on the line. The difference in height y co-ordinates ➗ the difference with width x co-ordinates.
If the answer is positive value then the line is uphill in direction
If the answer is negative value then the line is downhill in direction

Write two Pythagorean triplets each having one of the numbers as 5.

Answers

Answer:

3, 4, 5 and 5, 12, 13

Step-by-step explanation:

The square of the largest side is equal to the sum of the squares of the other 2 sides.

5² = 3² + 4²

13² = 5² + 12²

The 2 triplets are (3, 4, 5 ) and (5, 12, 13)

solve pls brainliest

Answers

Answer:

64%

Step-by-step explanation:

Step 1: Divide 16 by 25

-> [tex]\frac{16}{25}[/tex] -> [tex]0.64[/tex]

Step 2: Multiply quotient by 100.

[tex]0.64 * 100[/tex] [tex]6.4 * 10[/tex] [tex]64[/tex] 64%

Therefore, 16/25 as a percentage is 64%.

Answer:

Well you can make a proportion

Percentage means ”Out of a hundred”

So you can make a proportion with any fraction Equal to x/100 since

X is the unknown perctange.

in this case it’s 16/25

16/25 = x/100

So cross multiply To solve for X

1600= 25x

x= 64

So 64 Percent

In this case you can use benchmarks. If you do it more or long enough, you’d memorize them.

In this case 25 is a bench mark of 1/4 or 25. 25 goes into 100 4 times so you can multiply 16 by 4 to get your percentage since if you do multiply 4, you have to do it to both the numerator and the Denominator.

so 16/25

16*4= 64

25*4=100

64/100 or 64 percent.

Common benchmarks for percentages

5, 10, 20, 25, 50

5 is always multiply by 20

10 is always multiply by 10

20 is always multiplied by 5

25 is always multiplied by 4

50 is always multiplied by 2

solve pls brainliest

Answers

Answer:

first put 2 in the numerator for the first blank and 2/9 in the second blank

Step-by-step explanation:

1/3 equals 3/9 and 3/9-1/9=2/9

Answer:

[tex]\frac{3}{9}[/tex]

Step-by-step explanation:

w + 12 = 20 *


ANSWER ASAP PLS​

Answers

Answer:

the nwser is 8 please mark brainliest

Step-by-step explanation:

A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST

Answers

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J

Helppp pleasee ........

Answers

y=3
to solve this you just substitute 4 in for x into the equation and solve for y. since negative 3 plus 7 is 4, y=4

Answer:

y=3

Step-by-step explanation:

y = - x +7

x=4

so y = -4 +7

y = 3

If we convert 0.14 x10^3 to scientific notation, which direction should the

decimal move and how spaces should it move?

Answers

Answer:

Move it to the right by 3 spaces.

Step-by-step explanation:

10^3 is 1000

On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140

help!! !,
is it right or not ​

Answers

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

Yep!!! Your correct

What is the 4th equivalent fraction to 1/12?

Answers

Answer:

Where's the Answer? There's No

Hello there!

Remember that equivalent fractions have the same value.

[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]

Therefore, the 4th equivalent fraction to 1/12 is [tex]\frac{4}{48}[/tex]

Hope this helps you!

~Just a felicitous girlie

#HaveASplendidDay

[tex]SilentNature :)[/tex]

Solve for x x^2 + 6x + 1 = 0

Answers

Answer:

x = -.1715 ≈ - .172    or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square   Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9  = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

[tex]\sqrt{(x + 3)^{2}[/tex]  = [tex]\sqrt{8}[/tex]

 x + 3 = ±  [tex]\sqrt{8}[/tex]

  x = -3 ± [tex]\sqrt{8}[/tex]

   x = -3 + [tex]\sqrt{8}[/tex]   or x = -3 - [tex]\sqrt{8}[/tex]

   x = -.1715 ≈ - .172    or x = -5.83

Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12

Answers

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?
Pick one:
5cm
20cm
200cm
720cm

Answers

Answer:

20cm

Step-by-step explanation:

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?

Pick one:

5cm

20cm

200cm

720cm

--------------------

scale = 1:6000

so

1200 : 6000 =  0.2m

0.2m = 20 cm

Answer:

20cm

Step-by-step explanation:

«A scale of 1:6000» means the model is smaller than the bridge by a factor of 6000. We can also make up a proportion [tex]\dfrac{1}{6000}=\dfrac{x}{1200}[/tex], where the left side is the scale, x is the model length, 1200 is the bridge length (in meters). So, finding x or just dividing 1200 by 6000, we get 0.2 meters. Provided 1 m = 100 cm, 0.2 m is 0.2 × 100 = 20 cm.

Ms. Henderson's plant is 613 inches tall. It is 156 inches taller than Megan's plant.

How tall is Megan's plant?

Answers

Answer:

Megan's plant is 457 Inches tall

Step-by-step explanation:

Which of the following tables does not represent a function?


x y
-1 1
-2 1
-3 1

x y
-5 1
-5 -2
-5 -5

x y
-4 0
2 0
5 7

x y
-5 1
-3 -2
-1 -5

Answers

Step-by-step explanation:

the second one (with the -5 as x values) is not a function, because the valid x value -5 has more than one associated different solution value y.

for a function a valid x value can lead only to exactly one result y value.

9. 2 less than 3 times a number is the same as 2114. What is the number?

Enter your answer as a decimal or simplified mixed number in the box. The number is.

Answers

Answer:

705.3 repeated I don't know if that's what you want but

3 times of 705.33 and 2 subtracted is equal to 2114.

What is Simplification?

Simplification in mathematical terms is a process to convert a long mathematical expression in simple and easy form.

Given that,

2 less than 3 times a number equal to 2114.

Let the required number is x.

According to given condition,

3x - 2 = 2114

3x = 2114 + 2

3x = 2116

x = 2116 / 3

x = 705.33

The required number is 705.33.

To know more about Simplification on :

https://brainly.com/question/2804192

#SPJ5

find the value of x. only type the “number”

Answers

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

the perimeter of this triangle is 46cm find x​

Answers

Answer:

the value of x is 12

......

Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =​

Answers

Step-by-step explanation:

f(x) = -3x - 8

f(-3) = -3(-3) - 8

f(-3) = 9 - 8

f(-3) = 1

if y varies inversely as n and m = 8 when n = 3 find m whenn =12

Answers

Answer:

24

Step-by-step explanation:

m=8x4 n=3x4 so that is the answer

1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84​

Answers

Answer:

4x - 12 = 84

Step-by-step explanation:

The last answer choice is correct because when you cross-multiply:

[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]

you get 4x - 12 = 84.

Therefore, the last option is correct.

Answer:

D would be the answer (4x-12=84)

Step-by-step explanation:

4/7=12/x-3

=>1/7=3/x-3

=>x-3=21

Multiplying both sides by 4

4(x-3)=4x21

=>4x-12=84

Hope this helped :)

a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance remains after 8 seconds?

Answers

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

The size of the substance after 8 seconds will be 1.25 g

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams.

Start with 20g at 0 seconds and divide by half after 2 seconds and you have 10g.

4 seconds you have 5g.

6 seconds you have 2.5g.

8 seconds you have 1.25g.

To know more about an expression follow

https://brainly.com/question/1581557

#SPJ5

2x2-5x-2 solve by quadratic formula 9leave answers in simplest radical form)

Answers

Answer:

-5x+2

Step-by-step explanation:

1. Multiply number 2 and 2=4 so it is

4-5x-2

2. Combine like terms

-5x+4-2

3. Subtract the numbers

-5x+2

Select the correct answer.
What is ?

A.

B.

C.

D.

Answers

Answer:

B. 7 1/2

Step-by-step explanation:

1. To solve this problem, we have to multiply 2 1/2 by the reciprocal of 1/3.

In other words, multiply 2 1/2 by the inverse of 1/3, which is 3.

2. (Solving)

[tex]2\frac{1}{2} *3[/tex] [tex]\frac{5}{2} *3[/tex] [tex]\frac{15}{2}[/tex] [tex]7\frac{1}{2}[/tex]

Therefore, the answer is B. 7 1/2.

Answer:

its B mark branli.est pls

Step-by-step explanation:

Which best describes the error in finding the area of the parallelogram?


15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.

8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.

The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.

The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.

Question 2
Correct the error.

A=

=
m2

Answers

Answer:

104

Step-by-step explanation:

What is x squared = 100

Answers

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[tex] {x}^{2} = 100[/tex]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

Answer:

your equation is this... x2 - 100

since you have no x term to the first power you can write 0x... like this

x2 + 0x - 100

Now, what numbers will add to 0 and multiply to -100

The numbers 10 and -10 will

10 + -10 = 0

10 * -10 = -100

therefore

(x - 10)(x + 10) is the way you factor it

Step-by-step explanation:

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