Answer:
it is a letter b
Step-by-step explanation:
that does not contain an outlet
Which relationship is always true for the angles x,y and z of triangle ABC
Answer:
B. y + z = x
Step-by-step explanation:
x is an exterior angle of the triangle.
y and z are the opposite angles opposite the exterior angle.
The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.
Thus:
y + z = x
Helppppo plsssssssssss I need helppp with thissss
Answer:
82 is what r equals
Step-by-step explanation:
So, lets go over what we know:
D equals rt, or r * t:
D=r*t
The table shows:
t=2 - d=164
t=3 - d=246
These are the only 2 values we need to look at.
We know that D= r*t, and we can just plug in the values found in the table for t and d to solve for r. So:
164= r * 2
Divide both sides by 2 to iscolate r:
82=r
So it seems like r is equal to 82, however this might be exponential or inaccurate, so lets double check witht the nexty values on the table:
246=r*3
Divide by 3 to iscolate the r:
82=r
So we know that r must equal 82.
Hope this helps!
CAN SOMEONE PLEASE HELP ME GOOD, I need this to graduate ): 5. Given that AABC - ADEC, find the
value of x.
Answer:
ans: 4
Step-by-step explanation:
corresponding sides are proportional since given triangle are similar triangle, I.e
(4/5.5) = { (2x+8)/(6x-2)}
8/11 = ( x+ 4 ) / ( 3x - 1 )
8( 3x - 1 )= 11( x + 4 )
24x - 8 = 11x + 44
13x = 52
x = 4
Select the correct answer.
At a high school there are 53 players on the football team, 15 players on the baseball team, and 12 players on
the basketball team. How many ways can a committee be formed with 1 representative from each team?
Math
Answer:
53*15*12=9540
Step-by-step explanation:
its just 53 times 15 times 12 for all the possibilities.
Say the first football player was picked, same with the first baseball player, and the first basketball player were all picked, then another possiblity would be the first football player, the second baseball player, and the first basketball player, here is a numerical example.
Football Baseball Basketball
1 1 1
1 2 1
1 2 2
1 2 3
1 2 4
and so on including all the patterns it would be 9540 possibilities
The total number of ways of forming a committee by selecting one representative from each team is 9540.
What is combination?
A combination is a mathematical technique that determines the number of possible arrangements or the number of ways in a collection of items where the order of the selection does not matter.
Combination Formula[tex]nC_{r}= \frac{n!}{r!(n-r)!}[/tex]
Where,
[tex]nC_{r}[/tex] is a number of combination.
n is total number of objects in the set.
r is the number of choosing objects from the set.
Multiplication rule in combination?According to the multiplication rule in combination if there are a ways of doing something and b ways of doing another thing, then there are a · b ways of performing both actions.
According to the given question
Total number of football players = 53
Total number of baseball players = 15
Total number of basket ball players = 12
Therefore,
Number of ways of selecting one representative from football team is given by
[tex]53C_{1} =\frac{53!}{1!52!} = 53[/tex]
Number of ways of selecting one representative from baseball team is given by
[tex]15C_{1} =\frac{15!}{1!14!}=15[/tex]
Number of ways of selecting one representative from basketball team is given by
[tex]12C_{1} =\frac{12!}{1!11!} =12[/tex]
So, the total number of ways of forming a committee by selecting one representative from each team = 53 × 15 × 12 =9540.
Hence, total number of ways of forming a committee by selecting one representative from each team 9540.
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Find the value of y and show work
Answer:
75
Step-by-step explanation:
∠K and ∠ R are congruent (equal)
Triangle Sum Theory - angles of all triangles add to 180
180 - 79 - 26 = 75
answer only one question No 1 only
-10369
too lazy but that's the exact value
Answer:
Step-by-step explanation:
(-2)³ *(-4)² * 3⁴ = (-8) * 16 * 81
= -10368
can anyone pls answer this! it's really urgent!
Answer:
The answer is C
Step-by-step explanation:
You need to find a common denominator and in this case its 20. SO you change 3/4ths to 15/20 and 4/5ths to 16/20ths and 19/20 stays the same. Then you cancel out the 20 because its all the same number (I think) and you have your answer.
At Western University the historical mean of scholarship examination scores for freshman applications is 900. Ahistorical population standard deviation \sigmaσ= 180 is assumed known.
Each year, the assistant dean uses a sample of applications to determine whether the mean examination score for the new freshman applications has changed.
a. State the hypotheses.
b. What is the 95% confidence interval estimate of the population mean examination
score if a sample of 200 applications provided a sample mean \overline x
x
= 935?
c. Use the confidence interval to conduct a hypothesis test. Using \alphaα= .05, what is your
conclusion?
d. What is the p-value?
Answer:
(910.053 ; 959.947)
Pvalue = 0.00596
Step-by-step explanation:
Given :
Population mean, μ = 900
Sample size, n = 200
Population standard deviation, σ = 180
The hypothesis :
H0 : μ = 900
H0 : μ ≠ 900
The 95% confidence interval:
Xbar ± Margin of error
Margin of Error = Zcritical * σ/√n
Since the σ is known, we use the z- distribution
Zcritical at 95% confidence = 1.96
Hence,
Margin of Error = 1.96 * 180/√200
Margin of Error = 24.947
95% confidence interval is :
935 ± 24.947
Lower boundary = 935 - 24.947 = 910.053
Upper boundary = 935 + 24.947 = 959.947
(910.053 ; 959.947)
Hypothesis test :
Test statistic
(935- 900) ÷ (180/√(200))
Test statistic = 2.750
Pvalue from Test statistic ;
Pvalue = 0.00596
Pvalue < α ; Reject H0 and conclude that score has changed
Hence, we can conclude that the score has changed
Instructions: Find the value of x
I’ll mark brainliest please help
The little lines theu each section are telling you all those sections are identical, which mean they are the same length.
You are told one section is 10, which means x is also 10
X = 10
At Dubai English School, 549 students use buses to go to school. If this number is 75% of the total school enrollment, then how many students are enrolled in total?
A square-based tent covers an area of 64 square feet. What is the length of one side of the tent?
Answer:
8 feet
Step-by-step explanation:
A square's area can be expressed as l², with l representing one side of the tent. Therefore, as our area is 64, we can say that 64 = l². Taking the square root of both sides, we get that √64 = l, and l = 8 feet
what percentage of the appies are yellow?
Answer:
20%
Step-by-step explanation:
6 out of 30. = 1/5 = multiply 5*20= 100 and 1*20= 100 so it is 20% of 100.
Need help on this question been stuck on it
Answer:
Exponential Function
Step-by-step explanation:
y values increase by x4
Answer:
exponential function
the ans is b
Which expression are greater than 1/2? Choose all the apply
Answer:
25/30
5/8
Step-by-step explanation:
Which fraction is it out of all of these 6/14,5/8,25/30,or 3/6?
to determine which fractions are greater than 1/2, convert the fractions to decimals
to convert to decimals, divide the numerator by the denominator
1/2 = 0.5 less than half
6/14 = 0.43 less than half
5/8 = 0.625 greater than half
25 / 30 = 0.83 greater than half
3 / 6 = 0.5 equal to half
How do you solve x[tex]x^{2} +4x+3=0[/tex]?
Answer:
[tex]{ \tt{ {x}^{2} + 4x + 3 = 0}} \\ { \tt{(x + 1)(x + 3) = 0}} \\ \\ { \tt{x = - 1 \: \: and \: \: - 3}}[/tex]
Question 11 of 45
Which similarity postulate or theorem can be used to verify that the two
triangles shown below are similar?
12
6 R
X 2 z
O A. Similarity cannot be determined,
B. SSS theorem
O C. AA postulate
D. SAS theorem
Answer:
You are only given a Side, an Angle, and then a side. So that is what I would choose. It can't be AA because you weren't given two angles. It can't be SSS because you weren't given 3 sides.
Step-by-step explanation:
ΔPQR and ΔXYZ are similar due to the SSS theorem.
Option B is the correct answer.
What is triangle congruency?There are ways to prove that two triangles are congruent.
- Side-Side-Side (SSS) Congruence.
The three sides of one triangle are equal to the corresponding three sides of another triangle.
- Side-Angle-Side (SAS) Congruence.
The two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle.
- Angle-Side-Angle (ASA) Congruence.
The two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle.
- Angle-Angle-Side (AAS) Congruence.
We have,
Similar triangles are triangles that have the same shape but may have different sizes.
Two triangles are similar if their corresponding angles are equal, and their corresponding sides are proportional.
When two triangles are similar, they have the same shape, but one may be larger or smaller than the other.
Now,
ΔPQR and ΔXYZ
PQ/XY = 12/4 = 3
PR/XZ = 6/2 = 3
Since the two sides are proportional,
QR/YZ will be proportional.
Now,
PQ/XY = PR/XZ = QR/YZ
ΔPQR and ΔXYZ are similar due to the SSS theorem.
Thus,
ΔPQR and ΔXYZ are similar due to the SSS theorem.
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Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].
Answer:
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
Step-by-step explanation:
Midpoint of a segment:
The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.
Midpoint of s1:
Using the endpoints given in the exercise.
[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]
[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]
Thus:
[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]
Midpoint of s2:
[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]
[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]
Thus:
[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]
Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.
Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So
[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]
[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
Your manager is trying to determine what forecasting method to use. Based upon the following historical data, calculate the following forecast and specify what procedure you would utilize.MONTH DEMANDJanuary 59February 65March 65April 67May 71June 70July 77August 77September 77October 75November 83December 81Calculate the simple three-month moving average forecast for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 78.33b) 74.67c) 76.33d) 77.00Calculate the weighted three-month moving average using weights of 0.50 (t-1), 0.30 (t-2), and 0.20 (t-3) for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 79.40b) 77.00c) 76.00d) 73.70Calculate the single exponential smoothing forecast for February through December using an initial forecast (F1=F-January) of 63. (Use alpha of 0.2) What is the forecast for December? (Round your answer to 2 decimal places) a) 66.30b) 74.37c) 72.22d) 71.52Calculate the mean absolute deviation (MAD) for the forecasts made by each technique in April through December. Which forecasting method do you prefer? (Round your answer to 2 decimal places)a) 3-month moving average (4.15)b) 3-month weighted moving average (3.99)c) Exponential smoothing method (alpha=0.30) (3.58)d) 3-month weighted moving average (3.58)
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the attached file.
For question 1:
Forecast for December:
[tex]\to \frac{(77+75+83)}{3} \\\\ \to 78.33[/tex]
For question 2:
Forecast for December:
[tex]\to (77 \times .5+75 \times 3+83 \times .2) \\\\\to 79.40[/tex]
For question 3:
Forecast for December:
[tex]\to 72.22+(83-72.22)\times 0.2 \\\\\to 74.37[/tex]
For question 4:
So, the 3-month weighted moving average (3.58)
When comparing two box-plots that show the same type of information, what determines agreement within the data?
A.the range of the quartiles in each data set
B.the median of each data set
C.the mean of each data set
D.the number of values in each data set
Answer:
c.the mean of each data set
Answer:
A
Step-by-step explanation:
What is the value of 6 / x + 2x squared when x = 3
Answer:
8
Step-by-step explanation:
The equation will become 6/3+2(3)
-->6/3=2
-->Because of Order of Operation we will multiply the 2 and 3 before adding so 2(3) = 6
--> 6+2=8
Answer:
x=6
Step-by-step explanation:
when its squared you multiply by 2
anyone help me, let's prove
Answer:
In my opinion the limit is equal to 1 not 0, sorry.
Step-by-step explanation: 6 25 13 43
lim n ⇒∞ ((2n - 1)/2n)
lim n ⇒∞ (2n/2n) - 1)/2n) 2n/2n = 1 1/∞ = 0
= 1 - 0
= 1
when I graphed the function I also got 1
Find Length of x line OR
Both figures r similar (given )
so :-[tex] \frac{5}{2.5} = \frac{3}{1.5} = \frac{2}{1} = \frac{4}{x} \\ \frac{2}{1} = \frac{4}{x} \\ \frac{ \cancel{2}}{1} = \frac{ \cancel{4}^ { \tiny{2}}}{x} \\ x = 2 \: \: ans[/tex]
A box with a square base and open top must have a volume of 256000 c m 3 . We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only x , the length of one side of the square base.
Answer:
Follows are the response to the given question:
Step-by-step explanation:
The volume of the box:
[tex]V = x\times x \times h = 256000 \ cm^3\\\\\to x^2 \times h = 256000\\\\\to h = \frac{256000}{x^2}[/tex]
The surface area of the open box is:
[tex]A(x) = x \times x + 2 \times (x \times h +x \times h)\\\\A(x) = x^2 + 4 \times x \times h\\\\A(x) = x^2 + \frac{1024000}{x}\\\\\frac{d(x^n)}{dx} = n \times x^{(n - 1)}\\\\[/tex]
Use above formula
[tex]A'(x) = 2 \times x - \frac{1024000}{x^2}\\\\[/tex]
[tex]A'(x) = 0\\\\2\times x - \frac{1024000}{x^2} = 0\\\\2x = \frac{1024000}{x^2}\\\\x^3 = 512000\\\\x = (512000)^{(\frac{1}{3})} = 80\ cm\\\\[/tex]
Now
[tex]A''(x) = 2\times 1 + 2\times \frac{1024000}{x^3}\\\\A''(x) = 2 + \frac{2048000}{x^3}\\\\x = 80 \ cm\\\\A''(80) = 2 + \frac{2048000}{80^3} = 6\\\\[/tex]
therefore [tex]A"(x) > 0,[/tex] x amount of material used in minimum.
[tex]h = \frac{256000}{80^2} = 40\ cm[/tex]
In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2 +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.
Answer:
(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]
(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant
Step-by-step explanation:
Given
[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation
[tex]n = 30[/tex]
[tex]p = 4[/tex] --- independent variables i.e. x1 to x4
[tex]SSR = 1760[/tex]
[tex]SST = 1805[/tex]
[tex]\alpha = 0.05[/tex]
Solving (a): Test of significance
We have:
[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
First, we calculate the t-score using:
[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]
[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]
[tex]t = 440 \div \frac{45}{25}[/tex]
[tex]t = 440 \div 1.8[/tex]
[tex]t = 244.44[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
Solving (c): [tex]SSE(x_2 ,x_3)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
Solving (d): F test of significance
The null and alternate hypothesis are:
We have:
[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant
[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant
For this model:
[tex]y =11.1 -3.6x_2+8.1x_3[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
[tex]SST = 1805[/tex]
[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
[tex]p_{(x_2,x_3)} = 2[/tex]
[tex]\alpha = 0.05[/tex]
Calculate the t-score
[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]
[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]
[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]
[tex]t = 27.5 \div 1.8[/tex]
[tex]t = 15.28[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Hence, we reject the null hypothesis
Are these triangles congruent?
Answer:
yes...
Step-by-step explanation:
its a congrate triangle
Use the substitution method to solve the system of equations. Choose the correct ordered pair. 4(x + 4) = 8(y + 2); 18y - 22 = 3x + 2
x = 30
y = 2
Get the explanation from the image I have shared.
Hope it helps you
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights of oranges are also normally distributed with a mean of 131 grams and a standard deviation of 20 grams. Amy has an apple that weighs 90 grams and an orange that weighs 155 grams.
Required:
a. Find the probability a randomly chosen apple exceeds 100 g in weight.
b. What weight do 80% of the apples exceed?
Answer:
a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.
b) The weight that 80% of the apples exceed is of 78.28g.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.
This means that [tex]\mu = 85, \sigma = 8[/tex]
a. Find the probability a randomly chosen apple exceeds 100 g in weight.
This is 1 subtracted by the p-value of Z when X = 100. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 85}{8}[/tex]
[tex]Z = 1.875[/tex]
[tex]Z = 1.875[/tex] has a p-value of 0.9697
1 - 0.9696 = 0.0304
0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.
b. What weight do 80% of the apples exceed?
This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.84 = \frac{X- 85}{8}[/tex]
[tex]X - 85 = -0.84*8[/tex]
[tex]X = 78.28[/tex]
The weight that 80% of the apples exceed is of 78.28g.
A payday loan company charges a $90 fee for a $500 payday loan that will be repaid in 16 days.
Treating the fee as interest paid, what is the equivalent annual interest rate?
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
Interest amount paid on loan = $90
Principal value, amount borrowed = $500
Period, t = 16 days
The equivalent annual interest :
Using the simple interest formula :
simple interest = principal * rate * time
Using, days of year = 365
Plugging in the values into the formula :
90 = 500 * rate * (16/365)
90 = 500 * rate * 0.0438356
90 = 21.917808 * rate
Rate = 90 / 21.917808
Rate = 4.10 = 4.10 * 100% = 410%
If days of year = 360 is used :
90 = 500 * rate * (16/360)
Rate = 90 / 22.222
Rate = 4.05 = 4.105 * 100% = 405%:
HELP PLEASE IM STUCK!
1. Which of these describes the relation for this set of coordinate pairs?
{(-1, 5), (12, 18), (0, 6), (-3, 3), (4, ?), (?, 11)}
a. x - y = 6 b. f(x) = x +6 c. f(x) = 6 d. y = 6x e. None of these
Answer:
b) f(x) = x + 6
Step-by-step explanation:
The coordinate (0, 6) makes the y-intercept = 6. Only one of these functions has that intercept: f(x) = x + 6. If you plug in each coordinate the outputted y-value matches up, making this the right answer.
PLEASE HELP ME WILL GIVE BRAINLIEST
Answer:
Reason 5
Step-by-step explanation:
Reason 1 and 2 are Given
Reason 3 is Reflexive
Reason 4 is Side-Side-Side congruency
Answer:
Reason 5
Step-by-step explanation:
It helps to know what CPCTC means and how it's used.
CPCTC means "corresponding parts of congruent triangles are congruent."
To use it, you must first either prove two triangles to be congruent or be given that two triangles are congruent.
Once you have the congruent triangles, then you state that two corresponding parts of those triangles are congruent, and you use CPCTC as the reason.
In step 4, the triangles are proven congruent by SSS.
Then CPCTC can be used as reason 5 for stating that the corresponding angles A and C are congruent.