if ABCD is a cyclic quadrilateral and A,B,C,D are its interior angles , then prove that
tanA/2+tanB/2=cotC/2+cotD/2

answer the question plz
dont spam or else i will report that ​

Answers

Answer 1

9514 1404 393

Explanation:

In a cyclic quadrilateral, opposite angles are supplementary. This means ...

  A + C = 180°   ⇒   A/2 +C/2 = 90°   ⇒   C/2 = 90° -A/2

  B + D = 180°   ⇒   B/2 +D/2 = 90°   ⇒   D/2 = 90° -B/2

It is a trig identity that ...

  tan(α) = cot(90° -α)

so we have ...

  tan(A/2) = cot(90° -A/2) = cot(C/2)

and

  tan(B/2) = cot(90° -B/2) = cot(D/2)

Adding these two equations together gives the desired result:

  tan(A/2) +tan(B/2) = cot(C/2) +cot(D/2)


Related Questions

Simplify the expression

Answers

Answer:

6

Step-by-step explanation:

3 sqrt(20) / sqrt(5)

We know that sqrt(a) /sqrt(b) = sqrt(a/b)

3 sqrt(20/5)

3 sqrt(4)

3 *2

6

what the person above me said

What is the solution to the inequality x(x – 3) > 0?

Answers

Answer:

The solution to the inequality is [tex](-\infty, 0) \cup (3, \infty)[/tex]

Step-by-step explanation:

We have a product, which is positive if both terms is positive or if both is negative.

Both positive:

[tex]x > 0[/tex]

[tex]x - 3 > 0 \rightarrow x > 3[/tex]

Then the intersection of these two is: [tex]x > 3[/tex]

Both negative:

[tex]x < 0[/tex]

[tex]x - 3 < 0 \rightarrow x < 3[/tex]

Then the intersection of those two is: [tex]x < 0[/tex]

Then:

Union of two solutions:

[tex]x < 0[/tex] or [tex]x > 3[/tex]

Then

[tex](-\infty, 0) \cup (3, \infty)[/tex]


Given that yx is a diameter of V, find mZVX if mYVZ=(15r -1)", mWVX =(8x- 2).mUVW =(7x +15).
and mYVU = 3x + 5).
A 32
B 45°
C 70
D. 134

Answers

C

Answer: the answer is (C)

Find the value of y and show work

Answers

Answer:

75

Step-by-step explanation:

∠K and ∠ R are congruent (equal)

Triangle Sum Theory - angles of all triangles add to 180

180 - 79 - 26 = 75

Simplify -4 + (-3) + 6.

Answers

Answer:3/6 in simplest fraction form is 1/2.

Step-by-step explanation:EASY and my chanel is FireFlameZero if u can check dat out

Rewrite the equation by completing the square.
x^2 + 7x + 12 = 0

Answers

Answer:

x^2 + 7x + 12 = 0

x^2 + 7x  = -12

(+3)(+4)=0

=−3

=−4

I also love r        o      blox

Hope This Helps!!!

Answer:

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

Step-by-step explanation:

Given

x² + 7x + 12 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + 7x

x² + 2([tex]\frac{7}{2}[/tex] )x + [tex]\frac{49}{4}[/tex] - [tex]\frac{49}{4}[/tex] + 12 = 0

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{49}{4}[/tex] + [tex]\frac{48}{4}[/tex] = 0 , that is

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

A review of combination

Answers

Answer:

What is a Combination? A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order. Combinations can be confused with permutations.

#happylearning

Express the following repeating decimal as a fraction in simplest form.

Answers

Answer:

[tex]0.\overline{369} = \frac{41}{111}[/tex]

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

[tex]x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}[/tex]

Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].

Answers

Answer:

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

Step-by-step explanation:

Midpoint of a segment:

The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.

Midpoint of s1:

Using the endpoints given in the exercise.

[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]

[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]

Thus:

[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]

Midpoint of s2:

[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]

[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]

Thus:

[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]

Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.

Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So

[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]

[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

21(2-y)+12y=44 find y​

Answers

Answer: y= -2/9
Explanation:
21(2-y)+12y=44
42-21y+12y=44
42-9y=44
-9y=2
y=-2/9

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]21\left(2-y\right)+12y=44[/tex]

[tex]42-21y+12y=44[/tex]

[tex]~add ~similar\:elements[/tex]

[tex]42-9y=44[/tex]

[tex]Subtract~42~from~both~sides[/tex]

[tex]42-9y-42=44-42[/tex]

[tex]-9y=2[/tex]

[tex]Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]

[tex]y=-\frac{2}{9}[/tex]

----------------------

hope it helps...

have a great day!

What is the median of the following set of numbers?
1 5
12 1 121
1
121
13
O A. 27
ОВ.
COIN
OC. .
12
OD.

Answers

1 5

12 1 121

1

121

13

O A. 27

ОВ.

COIN

OC. .

12

OD. ????????????????

Median of the given data is 8.5.

What is median?

In statistics, the median is the middle value of the given list of data in order. Data or observations can be sorted in ascending or descending order.

Given data,

1 , 5, 12, 1, 121, 1, 121, 13

Arranging in ascending order

1, 1, 1, 5, 12, 13, 121, 121

Number of elements N = 8

When number of elements is odd

Median = (N/2 th term + (N/2)+1 th term)/2

Median = (8/2 th term + (8/2)+1 th term)/2

Median = (4th term + 5th term)/2

Median = (5+12)/2

Median = 17/2

Median = 8.5

Hence, 8.5 is the median of the given data.

Learn more about median here:

https://brainly.com/question/28060453

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When we expand (2x + 1/2)^6, what is the coefficient on the x^4 term?

Answers

Answer: The coefficient before x^4 is 60

Step-by-step explanation:

Hey! So I am not an expert at this, but you have to use the binomial theorem

I have attached of the Pascals Triangle (one shows the row numbering as well)

Basically in a pascal triangle, you add the two numbers above it to get the next number below

As you can see, the rows start from 0 instead of 1

The 6th row contains the numbers 1, 6, 15, 20, 15, 6, 1 which would be the coefficient terms

NOTE: the exponents always add to 6, the first term starts at 6 and decrease it's exponent by 1 each time (6, 5, 4, 3, 2, 1, 0) and the second term increases it's exponent by 1 each time (0, 1, 2, 3, 4, 5, 6)

Using this information the third term from the sixth row (15) would be where it is x^4 (I have circled it on the second image)

It would be 15 × 2^4 × (1/2)^2 = 60

The reason why it is 2^4 and (1/2)^2 is because the third term has the exponents 4 and 2 (bolded on the NOTE) which means that the first term must be put to the power of 4 and the second term must be put to the 2nd power

Sorry for the lousy explanation. I really hope this makes sense! Let me know if this helped :)

Which is correct?????????????

Answers

Answer:

It discusses the role of the God in influencing our decisions

Answer:

I believe it is choice D

Step-by-step explanation:

in the excerpt it talks about how sight gives us the ability to observe and experience. it also states "we prefer sight to almost everything else." hope I'm right! ☺️

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