which of the following is the symbol for parallel lines AB and XY?

Answer:

7000

Step-by-step explanation:

70/100 * marked price = original price - 100

marked price = 140/100* og price

70/100 * 140/100 * og price = original price - 100

49/50 * og price = orignal price - 100

1/50 of original price = 100

orignal price = 5000

marked price = 140/100 * 5000 = 7000

Answer:

100

Step-by-step explanation:

0.2*500=100

Answer:

27

Step-by-step explanation:

Hi there!

We are given this set of data:

22, 15, 31, 40, 27

And we want to find the average (or the mean) of the set

To find the mean, we add up all of the values of the data set and then divide it by how many pieces of data we have

So first, add 22, 15, 31, 40 and 27 together

22+15+31+40+27=135

We have 5 pieces of data, so divide 135 by 5

135/5=27

The mean is 27

Hope this helps!

[tex]\boxed{\large{\mathbf{\blue{ANSWER~:) }}}}[/tex]

we know that,

[tex]\boxed{\sf{mean=\dfrac{sum ~of~ data}{no~ of~ data } }}[/tex]

According to the question,

Therefore,

the average (mean) of the given set of data.(22,15,31,40,27) is 27.

Answer:

7 - 2c < - 30

*To do this equation you would have to start with -30, because of "less than"

Hope this helps.

Common difference = 2nd term - first term = -22.5-(-18)= -22.5+18 = -4.5

Answer:

3 C

4 B

5 B

6C

Step-by-step explanation:

3. the negative of the functiin reflects the original function on the x axis

4. multiplying by a number greater than 1 increases the slop of the original function

5. subtracting from x translates the function to the right

6. subtracting from f(x) translates the function down

:) :) :) :) :) :) :) :) :) :) :) :) :)

Incomplete question

Let the area be = 100 square meter

Cost of plaster = Rs 315 per square meter

No of walls = 4

Total area = 400 square meter

Then cost = 400 × 315

= Rs 1,26,000

Answered by Gauthmath must click thanks and mark brainliest

There are infinitely many rational no.s between two no.s

one rational number between 1 and 2 is

11/10

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

Step-by-step explanation:

9x²+bx+ 100

(3x)²+ bx + 10²

(3x)² + 10² + bx

(3x)² + 10² + bx

Answer:

[tex]{ \tt{ - 2 {x}^{2} + 5x - 3 = 0 }} \\ { \tt{2 {x}^{2} - 5x + 3 = 0}} \\ { \tt{(2x - 3)(x - 1) = 0}} \\ { \tt{x = \frac{3}{2} \: and \: 1}}[/tex]

Answer:

2 i think

Step-by-step explanation:

sorry if im wrong

Answer:welcome

Step-by-step explanation: sorry I jsit really needed the points

Answer:

Remember that a triangle rectangle of length L and width W has an area:

A = W*L

In our rectangle, we have two sides along the x and y axes.

So one of the vertices of our triangle rectangle is the point (0, 0)

And the other vertex, is along the line:

y = -4x + 20

So, if the opposite vertex is at the point:

(x₁, y₁)

We can define the length as the difference between the x-values of each vertex.

L = (x₁ - 0) = x₁

And the width, similarly, as:

W = (y₁ - 0) = y₁

Such that the point (x₁, y₁) is a solution for the equation y = -4x + 20, then we have:

y₁ = -4x₁ + 20

Then we can rewrite the width as:

W = -4x₁ + 20

Now, we can write the area of our rectangle as:

A = (x₁)*(-4x₁ + 20)

A = -4*x₁^2 + 20*x₁

Now we want to maximize the area, notice that the area is given by a quadratic equation with a negative leading coefficient.

Thus, the maximum will be at the vertex of that quadratic equation.

Remember that for a general quadratic equation:

y = a*x^2 + b*x + c

The x-value of the vertex is:

x = -b/(2*a)

so, in our case, the x-value of the vertex will be:

x₁ = -20/(-4*2) = 20/8 = 5/2

Now we can evaluate this in our area equation:

A = -4*(5/2)^2 + 20*(5/2)  = 49.36

This is the maximum area of the rectangle.

Answer:

OA⊥OC

∴∠AOB+BOC= 90°

5x+8+6n-6=90

11x+2=90

x=90-2/11

x=88/11

x=8

∠BOC=6x-6

=6(8)-6

=48-6

∠BOC=42°

------------------------------

Hope it helps...

Have a great day!!

Answer:

[tex]<BOC = 42[/tex]

Step-by-step explanation:

In this problem, it is given that lines (AO) and (OC) are perpendicular. This means that when the lines intersect, the four angles formed each have a measure of (90) degrees. As per the given diagram, angles (<AOR) and (<ROC) add up to make (<AOC). Thus, one can form the following equation and solve for (x).

[tex](<AOR) + (<ROC) = (<AOC)[/tex]

Substitute,

[tex](6x-6)+(5x+8)=90[/tex]

Simplify,

[tex]11x+2=90[/tex]

Inverse operations,

[tex]11x+2=90[/tex]

[tex]11x=88\\\\x=8[/tex]

Substitute this into the equation for the measure of angle (<BOC) to find the numerical angle measure:

[tex]<BOC = 6x-6\\x = 8\\\\= 6(8)-6\\\\=48-6\\\\=42[/tex]

Answers:

t is the number of seconds after the rocket is released

V(r) is the volume of the ball with radius r.

====================================================

Explanation:

There isn't much to say in terms of explanation. These variables are simply definitions.

Answer:

1 kg

Step-by-step explanation:

Number of chickadees = 100

Quantity of seed eaten = 100 kg

Number of days = 100

Quantity of seeds each chickadee eats per day =Number of chickadees ÷ Quantity of seed eaten ÷ Number of days

= 100 ÷ 100 ÷ 100

= 1 ÷ 100

= 0.01 kg of seed

How many kg of seeds can 10 chickadees eat in 10 days?

= Quantity of seeds each chickadee eats per day × number of chickadee × number of days

= 0.01 kg × 10 × 10

= 1 kg

10 chickadees eat 1 kg of seeds in 10 days

Answer:

Step-by-step explanation:

The central angle is twice as big as any angle sharing the endpoints  with the central angle of a chord where the angle is not below the smaller sector.

2*62 = x

x = 124

Answer:

s4 = 270

18+36+72+144 = 270

-- convergent sums to a single value

Step-by-step explanation:

9514 1404 393

Answer:

  (a) All three pyramids have the same volume

Step-by-step explanation:

The triangular base has an area of ...

  B = 1/2bh . . . . where b is the base of the triangle and h is its height.

The volume of the pyramid is ...

  V = 1/3BH . . . . where B is the area of the base, and H is the height of the pyramid.

Combining these equations gives ...

   V = 1/3(1/2bh)H = 1/6bhH

__

Pyramid 1 volume

  V1 = 1/6(12 m)(2 m)(10 m) = 40 m³

Pyramid 2 volume

  V2 = 1/6(6 m)(4 m)(10 m) = 40 m³

Pyramid 3 volume

  V3 = 1/6(12 m)(4 m)(5 m) = 40 m³

All three pyramids have the same volume.

Answer: [tex]x\in [53,\infty)[/tex]

Step-by-step explanation:

Given

Ade doubles her number and subtract 5 from it. The result cannot be less than 100

Suppose the number is [tex]x[/tex]

According to the question

[tex]\Rightarrow 2x-5\geq100\\\text{Solve the inequality}\\\Rightarrow 2x\geq105\\\Rightarrow x\geq52.5\\\text{for integer number, the range is given by }\\\Rightarrow x\in [53,\infty)[/tex]

[tex] \cos(45) = \frac{5 \sqrt{2} }{x} \\ \frac{1}{ \sqrt{2} } = \frac{5 \sqrt{2} }{x} \\ x = 10 \\ \\ \tan(45) = \frac{y}{5 \sqrt{2} } \\ 1 = \frac{y}{5 \sqrt{2} } \\ y = 5 \sqrt{2} [/tex]

I hope I helped you ^_^

Answer:

x≠-7

Step-by-step explanation:

The function will be undefined when the denominator is zero

x+7≠ 0

x≠-7

Answer:

A. 7

Step-by-step explanation:

3m + 21 = 6m

Move variables to one side to get:

3m + 21 = 6m

-3m         -3m

21 = 3m

Then isolate variable by dividing by 3

21/3 = 3m/3

m = 7

Choice A is the correct answer

Answer:

875.018

Step-by-step explanation:

To solve this, we must plug in 6 for our t value. So, we have the equation:

-4.982 - 20(6) + 1000

Following the rules of PEMDAS, we have:

-4.982 - 120 + 1000 = 875.018

Answer:

x = -6

Step-by-step explanation:

cube each side :

3x + 7 = 2x + 1

solve for x:

x = -6

Answer:

Step-by-step explanation:

1). WXYZ is a rectangle,

  Properties of a rectangle,

  i). Opposite sides are equal and parallel.

  ii). All interior angles measure 90°.

  iii). Diagonals are equal in measure.

a). WY = ZX = 30

 Therefore, ZT = [tex]\frac{1}{2}(ZX)[/tex]

                    [tex]ZT=15[/tex]

b). WY = ZX = 45

c). Since, WY = ZX,

    (4b - 16) = (3b + 5)

    4b - 3b = 16 + 5

     b = 21

2). GOAT is a rhombus and m∠OGA = 35°,

    a). m∠TGA = m∠OGA = 35°

    b). m∠GXO = 90°

    c). m∠GXT = 90°

    d). Since adjacent angles of a rhombus are supplementary,

         m∠OGT + m∠GTA = 180°

         70° + m∠GTA = 180°

         m∠GTA = 110°

         m∠GTO = [tex]\frac{1}{2}(m\angle GTA)[/tex]

                        = [tex]\frac{1}{2}(110^{\circ})[/tex]

                        = 55°

     e). Since, opposite angles of a rhombus are equal,

          m∠OGT = m∠OAT = 70°

     f). m∠GOA = m∠GTA = 110°

Answer:

no

Step-by-step explanation:

the square root of 2 is not rational