Which inequality matches the graph?

X, Y graph. X range is negative 10 to 10, and y range is negative 10 to 10. Dotted line on graph has positive slope and runs through negative 3, negative 8 and 1, negative 2 and 9, 10. Above line is shaded.

−2x + 3y > 7
2x + 3y < 7
−3x + 2y > 7
3x − 2y < 7

Answer:

answer is 6

Step-by-step explanation:

f(x) = x2 - 4x

f(-3)= -3*2-4*-3

      =-6-(-12)

      =6

Answer:

good evening good evening good evening good evening

Step-by-step explanation:

w

Answer:

∠b = 54°

they add up to 180

7x + 14 + 5x - 26 = 180

12x = 192

x=16

thus ∠b = 54°

Step-by-step explanation:

Explanation:

The gradient is the same as the slope

m = slope

m = rise/run

m = (change in y)/(change in x)

m = (y2-y1)/(x2-x1)

m = (6-1)/(6 - (-4))

m = (6-1)/(6+4)

m = 5/10

m = 1/2

In decimal form, this becomes 0.5

A slope of 1/2 means we move up 1 and to the right 2 units each time to generate points along the diagonal line.

A positive slope goes uphill as we move to the right (due to the positive rise value).

Answer:

One way to find the gradient is using the expression :

[tex]m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{y_{B} - y_{A}}{x_{B} - x_{A}}[/tex]

So [tex]m = \frac{6 - 1}{6- (-4)} =\frac{5}{10} =\frac{1}{2}[/tex]

The ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is 1: 5. Hence option C is true.

Given that;

The students in Shawn's class got to choose whether to visit the zoo or the aquarium.

Here, 3 students went to the zoo and 15 students went to the aquarium.

Hence, the ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is,

Ratio = 3 : 15

Ratio = 3/15

Ratio = 1/5

Ratio = 1 : 5

Thus, option C is true.

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( − 2 ) ( 3+ 2 2 − − 2 )

Hope this helps, have a great day!

Answer:

25

Step-by-step explanation:

5 cents = 0.05

1.25 / 0.05 = 25

let me know if i'm wrong

Answer:

25

Step-by-step explanation:

$1.25=125cents

125/5 = 25

Answer:

Step-by-step explanation:

[tex]a^{m}* a^{n}=a^{m+n}\\\\\\(\frac{-1}{2})^{-19}*(\frac{-1}{2})^{8}=(\frac{-1}{2})^{-2x +1}\\\\(\frac{-1}{2})^{-19+8}=(\frac{-1}{2})^{-2x+1}\\\\\\(\frac{-1}{2})^{-11}=(\frac{-1}{2})^{-2x+1}[/tex]

As bases are equal in boht sides, we can compare the exponents.

-2x + 1 = -11

Subtract 1 form both sides

-2x = -11 - 1

-2x = -12

Divide both sides by -2

x = -12/-2

x = 6

Answer:

2x^2 + x - 1

If I did anything you didn't understand let me know so I can explain.  

Step-by-step explanation:

All of them are quadratics so let's use that.

The first one is 2x^2 + x - 1.  To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them.  Something to  notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry.  So I am going to ignore the constant, because then finding the zeroes is much much simpler.  I am going to do this with all opions.

So 2x^2 + x - 1 I am just going to use 2x^2 + x.  If you factor out an x you get x(2x + 1)  So now we have it in factored form and we know the zeroes are 0 and -1/2.  The number directly in between these is -1/4, so the axis of symmetry is x = -1/4.  I don't know if there is only one with that axis of symmetry so i am going to check the rest.

2x^2 - x + 1 means we are only going to look at 2x^2 - x.  factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.

x^2 + 2x - 1 we only use x^2 + 2x.  Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1

x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.

So yep, it was just the first one.

9514 1404 393

Answer:

  (a)  f(x) = 2x^2 +x -1

Step-by-step explanation:

For ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the offered answer choices, the axes of symmetry are ...

  a) x = -1/(2·2) = -1/4 . . . . . . the function we're looking for

  b) x = -(-1)/(2·2) = 1/4

  c) x = -2/(2·1) = -1

  d) x = -(-2)/(2·1) = 1

The function with axis of symmetry x = -1/4 is f(x) = 2x^2 +x -1.

Answer:

(-4, 2) y(2, -8)

{-4 y(2, -8), 2 y(2, -8)}

-4 y(2, -8) + 2 y(2, -8) = -2 y(2, -8)

-y(2, -8)

2 sqrt(5) abs(y(2, -8))

Step-by-step explanation:

D

Answer:

C

Step-by-step explanation:

The center will be the midpoint of the line connecting A and B.

x=(-4+2)/2=-2/2=-1

y=(2-8)/2=-6/2=-3

Answer:

(2/3)n + 7

Step-by-step explanation:

Represent the number by n.

Then "two thirds of (that) number" is (2/3)n.

Finally, we add 7:

"Two-thirds of a number increased by seven" is (2/3)n + 7

Answer

root 354

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

(√19 -√7)(√19 +√7)

( a +b)( a -b) = a²-b²

(√19)² -(√7)² = 19 -7 = 12

=========================================================

Explanation:

We don't have a direct variation because the initial cost isn't $0

The equation for this situation is y = 25x+375, where x is the number of yearbooks purchased and y is the total cost.

Notice how this line doesn't go through the origin. All direct variation graphs are straight lines through the origin.

So that's why we have partial variation instead.

The initial cost is simply the set up cost, aka the cost when x = 0. That initial cost is $375. The initial cost is located at the y intercept.

From that initial cost, we then add on multiples of $25 depending on how many yearbooks are purchased.

-----------------

In short, because the initial cost is $375, which is some nonzero value, this means we don't have direct variation. Instead, we have partial variation.

Answer:

1. Angles 2, 3 and angles 1,3 are complementary angles(Given)

2. To prove :

Since Angles 2, 3 and angles 1,3 are complementary.

When angles are complementary, then the sum of the measures of angles is 90 degrees.

So,  and  (Definition of Complementary angles)

3.  (Substitution)

4.  (Subtraction property of equality)

Step-by-step explanation:

Here, we are to find the length and the , breadth of the rectangle

The length of the rectangle = 7 units and Breadth of the rectangle = 3 units

Let

length = l units

Breadth = b units

Perimeter of the rectangle = 20 units

length is the distance measured along the longest dimension of an object

width is the wideness of an object

perimeter refers to the total measurements of an objects

The breadth of a rectangle is 4 units less than its length

If,

Length = l

Then,

b = l - 4

Perimeter of a rectangle = 2(length + breadth)

20 = 2{l + (l - 4)

20 = 2(l + l - 4)

20 = 2(2l - 4)

20 = 4l - 8

20 + 8 = 4l

28 = 4l

l = 28/4

l = 7

b = l - 4

b = 7 - 4

b = 3 units

Read more:

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Answer:

8×4=32 and 8 groups of 4 equals 32.

Answer:

[tex]9\ days[/tex]

Step-by-step explanation:

[tex]We\ are\ given:\\No.\ of\ days\ A\ takes\ to\ complete\ some\ amount\ of\ work=15\ days\\No.\ of\ days\ B\ takes\ to\ complete\ the\ same\ amount\ of\ work=12\ days\\No.\ of\ days\ C\ takes\ to\ complete\ the\ same\ amount\ of\ work\ as\ A\ and\ B\ =20\ days\\[/tex]

[tex]Now,\\We\ can\ say\ that\ an\ object\ has\ to\ complete\ \frac{1}{n}th\ of\ the\\ work\ daily,\ to\ complete\ the\ work\ in\ n\ number\ of\ days.\ This\ is\ however\\ only\ true\ if\ the\ object\ covers\ equal\ amounts\ of\ work\ each\ day.[/tex]

[tex]Here,\\In\ 1\ day,\\A\ would\ cover\ \frac{1}{15}th\ of\ the\ work.\\B\ would\ cover\ \frac{1}{12}th\ of\ the\ work.\\C\ would\ cover\ \frac{1}{20}th\ of\ the\ work.[/tex]

[tex]Now,\\We\ are\ also\ given\ that:\\They\ work\ together\ for\ 2\ days\ on\ the\ same\ work.\\Hence,\\Total\ work\ done\ in\ 1\ day\ by\ A,B\ and\ C=\frac{1}{15}+\frac{1}{12}+\frac{1}{20}=\frac{4+5+3}{60}=\frac{12}{60}=\frac{1}{5}\\Hence, Total\ work\ done\ in\ 2\ days\ by\ A,B\ and\ C=2*\frac{1}{5}=\frac{2}{5}[/tex]

[tex]Hence,\\The\ portion\ of\ the\ total\ work\ left=1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}\\So,\\Since\ A\ has\ to\ complete\ \frac{3}{5}th\ of\ the\ work,\ lets\ compute\ the\ no.\ of\ days\ it\ takes\ to\ do\ so.\\Hence,\\No.\ of\ days\ A\ takes\ to\ complete\ the\ entire\ work=15\ days\\Hence,\\No.\ of\ days\ A\ takes\ to\ complete\ \frac{3}{5}th\ of\ the\ entire\ work=15*\frac{3}{5}=9\ days[/tex]

Answer:

9 days

Step-by-step explanation:

A does in 15days, so A in 1day does 1/15part

B does in 12days, so B in 1day does 1/12part

C does in 20days, so C in 1day does 1/20part

So. A+B+C in 1 day-- 1/15+1/12+1/20=(4+5+3)/60= 12/60=1/5 and in 2days 2/5 part..hence remaining work=1/1–2/5=(5–2) =3/5part.

Now A in 1/15 part takes 1day

So, in 3/5 part 15×3/5 = 9 days.

Answer:

30.7

Step-by-step explanation:

Assuming the angled are degrees and not radian.

side BC= (11÷sin67)•sin28= 5.6

angle ABC= 180-67-28=85°

A= 11•5.6•sin85÷2≈30.68

Answer:

x=400 m is the correct answer

Answer:

7

Step-by-step explanation:

10 minus 3 will give you the number

Answer:

7

Step-by-step explanation:

let the number added to 3 be 'x'

we know;

X+3=10

X=10-3

X=7

Answer:

58%

Step-by-step explanation:

10*5=50

7*3=21

21/50 chance to choose inside small rectangle

21/50*2 = 42/100 chance to choose inside small rectangle

100-42=58%

Answer:

3. (1-7/9)÷2 = 2/9÷2 = 1/9

reciprocal of 1/9 is 9

4. x+2/x=3

if you solve it, you get x = 1 and x = 2, so last option, 1 and 2, is the answer

Answered by GAUTHMATH

Answer:

44.4

Step-by-step explanation:

Since we have a right triangle, we can use trig functions

sin theta = opp / hyp

sin x = 7/10

Taking the inverse sin of each side

sin^-1 (sin x) = sin^-1(7/10)

x = 44.427

Rounding to the nearest tenth

x = 44.4

Answer:

y=1

Step-by-step explanation:

5=2-3y+6

3y=2-5+6

3y= -3+6

3y= 3

3y÷3=3÷3

y=1

Answer:

16

Step-by-step explanation:

Substitute y = 5 into the expression

y² - 3y + 6

= 5² - 3(5) + 6

= 25 - 15 + 6

= 16

Answer:

Step-by-step explanation:

Table I

Given function is,

f(x) = [tex]b^x[/tex]

From the table attached,

For x = 0.827, value of function f(0.827) = 5,

f(0.827) = [tex]b^{0.827}[/tex]

Therefore, [tex]b^{0.827}=5[/tex]

[tex]\text{log}(b^{0.827})=\text{log}(5)[/tex]

0.827[log(b)] = log(5)

log(b) = 0.8452

b = [tex]10^{0.8452}[/tex]

b = 7

Therefore, function 'f' will be,

f(x) = [tex]7^x[/tex]

For f(x) = 9,

9 = [tex]7^x[/tex]

log(9) = log([tex]7^x[/tex])

log(9) = x[log(7)]

x = 1.129

Table II

Given function is g(x) = [tex]\text{log}_b(x)[/tex]

From the given table,

For x = 7, g(x) = 1

1 = [tex]\text{log}_b(7)[/tex]

[tex]b^1=7[/tex]

b = 7

Therefore, the function 'g' will be,

g(x) = [tex]\text{log}_7(x)[/tex]

For g(x) = 1.318

1.318 = [tex]\text{log}_7(x)[/tex]

[tex]x=7^{1.318}[/tex]

[tex]x=12.9968[/tex]

[tex]x=13.997[/tex]

Answer:

D

Step-by-step explanation:

Note that I will be using a, b, and y instead of their Greek counterparts.

First, we know that sin(c+d) = sin(c)cos(d) + cos(d)sin(a) and sin(c-d) = sin(c)cos(d) - cos(d)sin(a). We can apply these here to get

sin(b+y) = sin(b)cos(y) + cos(b)sin(y)

sin(b-y) = sin(b)cos(y) - cos(b)sin(y)

sin(a+y) = sin(a)cos(y) + cos(a)sin(y)

sin(a-y) = sin(a)cos(y) - cos(a)sin(y)

Plugging these into our equation, we get

(sin(b)cos(y) + cos(b)sin(y) - (sin(b)cos(y) - cos(b)sin(y)))

/

(sin(a)cos(y) + cos(a)sin(y)-(sin(a)cos(y) - cos(a)sin(y)))

=

2cos(b)sin(y) / 2cos(a)sin(y)

= cos(b)sin(y)/cos(a)sin(y)

= cos(b)/cos(a)

Next, we can see that a+b = π, so we can subtract b from both sides to get a = π -b. Plugging that in for a in our equation, we get

cos(b) / cos(π-b)

After that, we know that cos(c-d) = cos(c)cos(d) - sin(c)sin(d). Plugging that in here, we get

cos(π-b) = cos(π)cos(b) - sin(π)sin(b)

= -cos(b) + 0

= -cos(b)

Plugging that back into our equation, we get

cos(b) / -cos(b) = -1

Answer:

(19-29x) over (x-4)

Step-by-step explanation:

Answer:

Just use m a t h w a y for the answer

Step-by-step explanation:

Thank me later,or dont thank me at all

Answer:

Step-by-step explanation:

This equation turns out to be a quartic. I'm not sure what should be done with. I can't believe you were asked to find its roots which are unbelievably complex. Here is a graph with the only 2 points that are easily found. If I am not solving what you need, please leave a note.