Which graph shows the solution to the system of linear inequalities?
y>2/3x+3
y ≤ -1/3x+2

Answer:

[tex] \large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{✽ \: m \: \angle \: RQP = m \: \angle \: RQH + m \: \angle \: HQP}}[/tex]

[tex] \large{ \tt{⇾ \: 152 \degree = \: m \: \angle \: \: RQH + 95 \degree}}[/tex]

[tex] \large{ \tt{⇾ \: 152 \degree - 95 \degree = m \: \angle \: RQH}}[/tex]

[tex] \boxed{ \large{ \tt{⇾ \: 57 \degree = m \: \angle \: RQH}}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Step-by-step explanation:

this is the correct answer for the question

Answer:

w = 5

y = 4

Step-by-step explanation:

w+y=9

3w-y=11

4w = 20

w = 5

y = 4

Answer:

b

Step-by-step explanation:

the function has exactly one x-intercept

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating [tex]t[/tex] in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

[tex]\cos^{2} t + \sin^{2} t = 1[/tex] (1)

Where:

[tex]\cos t = \frac{y-3}{2}[/tex] (2)

[tex]\sin t = x - 1[/tex] (3)

By (2) and (3) in (1):

[tex]\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1[/tex]

[tex]\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1[/tex] (4)

The motion of the particle describes an ellipse.

Answer:

5 sandwiches he made in bread

Answer:

I think 6.............,..........

Answer:

[tex]Pr = \frac{1}{2002}[/tex]

Step-by-step explanation:

See comment for complete question;

Given

[tex]n = 14[/tex]

[tex]r = 5[/tex] -- committee members

[tex]k = 4[/tex] ---- officers (i.e. president, CEO, COO and CFO)

Required

Probability of selecting 5 youngest qualified members

First, we calculate the number of ways the committee can be appointed;

Any 5 members can be part of the committee; This means that we won't consider the order.

So, the number of ways is:

[tex]^{14}C_5[/tex]

This gives:

[tex]^{14}C_5 = \frac{14!}{9!5!}[/tex]

So, we have:

[tex]^{14}C_5 = \frac{14*13*12*11*10*9!}{9!*5*4*3*2*1}[/tex]

[tex]^{14}C_5 = \frac{14*13*12*11*10}{5*4*3*2*1}[/tex]

[tex]^{14}C_5 = \frac{240240}{120}[/tex]

[tex]^{14}C_5 = 2002[/tex]

There can only be a set of 5 young people. So, the probability is:

[tex]Pr = \frac{1}{2002}[/tex]

Hello,

answer C (11,-23)

[tex]\left\{\begin{array}{ccc}3a+b&=&10\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}6a+2b&=&20\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}3a+b&=&10\\2a&=&22\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&10-3*11\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&-21\end{array}\right.\\[/tex]

Answer: C. (11,-23)

Step-by-step explanation:

Step-by-step explanation:

we know that 1m=100cm

so 1m:5m(final)

1:5

Answer:

1/5

Step-by-step explanation:

Since 100cm = 1m

then

100cm:5m becomes 1m:5m

which in fraction is 1/5

Answer:

0.2

Step-by-step explanation:

The total number of points in PS is a sum of the number of points in :

PQ + QR + RS ;

PQ = 7 ; QR = 13 ; RS = 5

PS = (7 + 13 + 5) = 25

Probability that point selected at random is in RS ;

Required outcome = point in RS

Total possible outcomes = points in PS

Probability = RS / PS = 5 / 25 = 0.2

Answer:

Im sorry but why is this a question? Like what school gives this out

Answer:

A number is right 12 centimetres

Answer:

The solution (- infinity , 1].

Step-by-step explanation:

[tex]\frac{3 - z}{z + 1}\geq 1\\\\3 - z \geq z +1\\\\3-1 \geq2 z\\\\2 \geq 2 z\\\\z\leq 1[/tex]

So, the solution (- infinity , 1]

the graph would steeper, meaning more savings over time

Answer:

B)7

Step-by-step explanation:

2-(-8)=10

10+(-3)=7

Answer: The answer would be D

Step-by-step explanation:

Answer:The zeros are 7 and 5, because y=(x-7)(x-5)

Step-by-step explanation:

So a Quadratic function,A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero

9514 1404 393

Answer:

  48 +j64 ohms

Step-by-step explanation:

The impedance of a series circuit is the sum ...

  R + jXl -jXc

  = 48 +j100 -j36

  = 48 +j64 . . . . ohms

_____

Additional comment

"j" is the electrical engineer's name for √-1, because "i" is used to represent current.

Step 1: Find the LCD (Least Common Denominator)

The LCD between 4 and 8 is 8. Therefore, if I change all of the fractions to have a denominator of 8, the problem is as such:

3/8 - 2/8 = ?

Step 2: Subtract

3/8 - 2/8 = 1/8

Hope this helps!

Answer:

[tex]\frac{1}{8}[/tex] (1/8)

Step-by-step explanation:

8·1=8

4·2=8

LCD=8

If the denominator is multiplied, the numerator also has to be multipled by the same value.

Hope this helped! Please mark brainliest :)

Step-by-step explanation:

x²+12x=40

(x+6)²-6²-40=0

(x+6)²-76 = 0

Answer:

check the attachment

Step-by-step explanation:

2x - y = - 4

- y = - 4 - 2x

y = 2x + 4

slope of the line = 2 with y - intercept 4

Answer:

2

Step-by-step explanation:

Since x=0, and it's not <0, the "else statement" is executed making y=0+2

There is a category called "computer and technology", maybe you can get better answers if you select that instead of "mathematics"

Answer:

There are 2 x intercepts

9514 1404 393

Answer:

  x = 30°

Step-by-step explanation:

The lines will be parallel if and only if the sum of the marked angles is 180°:

  4x +2x = 180°

  6x = 180° . . . . . collect terms

  x = 30° . . . . . . . divide by 6

Answer:

[tex]\frac{11}{24}[/tex]

Step-by-step explanation:

3/8 + 1/4 + 1/2 - 2/3

- > 1/4 =  2/8

3/8 + 2/8 + 1/2 - 2/3

5/8 + 1/2 - 2/3

- > 1/2 = 4/8

5/8 + 4/8 - 2/3

9/8 - 2/3

- > LCM of 8,3: 24

- > 9/8 = 27/24

- > 2/3 = 16/24

27/24 - 16/24

11/24

Hope this helps you.

Answer:

option d is correct one in which value of T lies

Hi there!

[tex]\large\boxed{p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4}[/tex]

Recall a Taylor series centered at x = 0:

[tex]p(x) = f(0) + f'(0)(x) + \frac{f''(0)}{2}x^{2} + \frac{f'''(0)}{3!}x^{3} + ...+ \frac{f^n}{n!}x^n[/tex]

Begin by finding the derivatives and evaluate at x = 0:

f(0) = 7(0)e⁰ = 0

f'(x) = 7eˣ + 7xeˣ   f'(0) = 7e⁰ + 7(0)e⁰ = 7

f''(x) = 7eˣ + 7eˣ + 7xeˣ  f''(0) = 7(1) + 7(1) + 0 = 14

f'''(x) = 7eˣ + 7eˣ + 7eˣ + 7xeˣ    f'''(0) = 21

f⁴(x) = 7eˣ + 7eˣ + 7eˣ + 7eˣ + 7xeˣ   f⁴(0) = 28

Now that we calculated 4 non-zero terms, we can write the Taylor series:

[tex]p(x) = 0 + 7x + \frac{14}{2}x^2 + \frac{21}{3!}x^3 + \frac{28}{4!}x^4[/tex]

Simplify:

[tex]p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4[/tex]

Answer:

x = 3

y = 8

Step-by-step explanation:

In the given triangle FGH,

m∠F + m∠G + m∠H = 180° [Triangle sum theorem]

60° + 90° + m∠H = 180°

m∠H = 30°

If the given triangles FGH and TUV are congruent, their corresponding sides will be equal in measure.

m∠F = m∠T

7y + 4 = 60°

7y = 56

y = 8

GH ≅ UV

8x - 12 = 12

8x = 24

x = 3

Using the AAS congruence theorem, the values of x and y that show that both triangles are congruent are: x = 3 and y = 8.

According to the angle-angle-side congruence theorem (AAS), two triangles are congruent if they have two corresponding congruent angles and one pair of corresponding non-included sides that are congruent.

Thus, by the AAS theorem, we have:

8x - 12 = 12

8x = 12 + 12

8x = 24

x = 3

Also,

7y + 4 = 60

7y = 60 - 4

7y = 56

y = 8

Therefore, using the AAS congruence theorem, the values of x and y that show that both triangles are congruent are: x = 3 and y = 8.

Learn more about AAS congruence theorem on:

https://brainly.com/question/3168048