Which expression is equivalent to the difference shown?

Answer:

0.663 ( c )

Step-by-step explanation:

U1 = 0.1 , U2 = 0.8

using the "cosine" version of Box-Muller to generate a single Nor(-1,4) random variable

first step : generate single obsⁿ from N ( -1,4 )

attached below is the detailed solution

Answer:

(5 7 11 12 13 14)

Step-by-step explanation:

Q inter R = 7 and 11

So the union between p and 7 and 11 is the answer above

Answer:

djjdjdjdjdjdjdjdjdidi

$28.62 not including tax.

Answer:

0.0726 = 7.26% probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Suppose 49% of American singers are Grammy award winners.

This means that [tex]p = 0.49[/tex]

Sample of size 502

This means that [tex]n = 502[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.49[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.49*0.51}{502}} = 0.0223[/tex]

What is the probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%?

Proportion below 49% - 4% = 45% or above 49% + 4% = 53%. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability the proportion is below 45%

p-value of Z when X = 0.45. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.45 - 0.49}{0.0223}[/tex]

[tex]Z = -1.79[/tex]

[tex]Z = -1.79[/tex] has a p-value of 0.0363.

2*0.0363 = 0.0726

0.0726 = 7.26% probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%

Given:

The limit problem is:

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

To find:

The value of the given limit problem.

Solution:

We have,

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]

Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].

Answer:

(0, -9)

Step-by-step explanation:

The y intercept is the y value when x =0

(0, -9)

Answer:

Step-by-step explanation:

This appears to be an SSA application of solving the triangle

We have 2 sides, so we will use the law of cosines

The law of cosines defines for a triangle ABC with side a/b/c with corresponding angles A/B/C

a^2 = b^2+c^2 - 2*b*c * (cos A)

this applies to the other 2 sides

first using the pythagorean theorem we find that BC = sqrt(55)

then we substitute all 3 sides into our equation to find angle A

55 = 64 + 9 - 2*8*3* (cos A)

18 = 2*8*3(cos A)

3/8 = (cos A)

and angle A is approximately 68 degrees

Please check if I'm correct

Answer:

67.98°

Step-by-step explanation:

Given 2 sides, you can find the missing angle of a right triangle using basic trig functions.

Since Cos∅=adjacent/ hypotenuse, we can use the adjacent side to the angle, 3 and they hypotenuse, 8 in the ratio by doing 3/8. This is 0.375. Then we use the inverse cosine function to find the angle. This gives 67.98°

Or

Cos∅=0.375

Cos^-1= 67.98

Step-by-step explanation:

2nd number = x

1st number = x - 7

5 (x - 7) = 6x + 9

5x - 35 = 6x + 9

- x = 44

x = - 44

1st number = -51

2nd number = -44

Proof: 5 (-51) = 6(-44) + 9

-255 = -264 + 9

-255 = -255

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

Iam going to do question 21

Step-by-step explanation:

1/7*x=2

1/7x=2

x=2:1/7

x=2*7/1

x=14

Answer:

6x -15

Step-by-step explanation:

plug in gx for x in fx. So you have 2(3x-9) + 3

Answer:

l don't know

Step-by-step explanation:

Answer:

E and C

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

(f×g)×x = f(x)×g(x)

Given:

The equation is:

[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]

To find:

The solution for the given equation.

Solution:

We have,

[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]

It can be written as:

[tex]\ln x+\ln x^2=2\ln 8[/tex]              [tex][\because \ln e^x=x][/tex]

[tex]\ln (x\cdot x^2)=2\ln 8[/tex]              [tex][\because \ln a+\ln b=\ln (ab)][/tex]

[tex]\ln (x^3)=\ln 8^2[/tex]         [tex][\because \ln x^n=n\ln x ][/tex]

On comparing both sides, we get

[tex]x^3=8^2[/tex]

[tex]x^3=64[/tex]

Taking cube root, we get

[tex]x=\sqrt[3]{64}[/tex]

[tex]x=4[/tex]

Therefore, the required solution is [tex]x=4[/tex].

Answer:

x=4

Step-by-step explanation:

What is the true solution to the equation below?

ln e Superscript ln x Baseline + ln e Superscript ln x squared Baseline = 2 ln 8

x = 2

x = 4

x = 8

Answer:

[tex] {f}^{ - 1} (x) = \frac{x}{3} + \frac{7}{3} [/tex]

hence option d is the correct option.

Answer:

Option C is answer.

Step-by-step explanation:

Hey there!

Given;

f(x) = (3-x) /7

Let f(x) be "y".

y = (3-x) /7

Interchanging "x" and "y".

x = (3-y)/7

7x = 3-y

y = 3-7x

Therefore, f'(x) = 3-7x.

Hope it helps!

===============================================

Explanation:

It might help to draw out the picture as shown below. The pool itself (just the water only) is the inner rectangle. The outer rectangle is the pool plus the border of those 1 by 1 tiles.

The pool is a rectangle 90 feet by 80 feet. If we add on the tiles, then we get a larger rectangle that is 90+2 = 92 feet by 80+2 = 82 feet.

We add on 2 since we're adding two copies of "1" on either side of each dimension.

The larger rectangle's area is 92*82 = 7544 square feet

The smaller rectangle's area is 90*80 = 7200 square feet

The difference in areas is 7544-7200 = 344 square feet.

Each 1 by 1 tile is of area 1*1 = 1 sq foot, meaning that 344 tiles will get us the 344 square foot border around the pool.

Answer:

x^2+y^2=r^2 is quation of circle whose centre is (0,0)

Answer:

A. 32

Step-by-step explanation:

If the center is (0, 0) and a point is (0, 4) then the distance from the center to that point is 4 units. That distance is the radius. If you are dilating by a factor of 4, multiply the radius by 4 and you get 16. The new radius is 16 and the diameter= radius*2.

16*2=32

Answer:

mean = 7

median = 7

range = 9

mid range = 7.5

Step-by-step explanation:

3, 5, 6, 7, 7, 9, 12

Range is the difference between the highest and lowest values of a set of observations

Range = highest value - lowest value

12 - 3 = 9  

Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order

3, 5, 6, 7, 7, 9, 12

median = 7

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of the numbers / total number

(6 + 12 + 5 + 7+  7 + 3 + 9) / 7 = 7

Mid range = (highest value + lowest value) / 2

(12 + 3) / 2 = 7.5

Answer/Step-by-step explanation:

2. a. 5y - 3 = -18

Add 3 to both sides

5y - 3 + 3 = -18 + 3

5y = -15

Divide both sides by 5

5y/5 = -15/5

y = -3

b. -3x - 9 = 0

Add 9 to both sides

-3x - 9 + 9 = 0 + 9

-3x = 9

Divide both sides by -3

-3x/-3 = 9/-3

x = -3

c. 4 + 3(z - 8) = -23

Apply the distributive property to open the bracket

4 + 3z - 24 = -23

Add like terms

3z - 20 = -23

Add 20 to both sides

3z - 20 + 20 = - 23 + 20

3z = -3

Divide both sides by 3

3z/3 = -3/3

z = -1

d. 1 - 2(y - 4) = 5

1 - 2y + 8 = 5

-2y + 9 = 5

-2y + 9 - 9 = 5 - 9

-2y = -4

-2y/-2 = -4/-2

y = 2

3. First, find the sum of 3pq + 5p²q² + p³ and p³ - pq

(3pq + 5p²q² + p³) + (p³ - pq)

3pq + 5p²q² + p³ + p³ - pq

Add like terms

= 3pq - pq + 5p²q² + p³ + p³

= 2pq + 5p²q² + 2p³

Next, subtract 2pq + 5p²q² + 2p³ from 3p³ - 2p²q² + 4pq

(3p³ - 2p²q² + 4pq) - (2pq + 5p²q² + 2p³)

Apply distributive property to open the bracket

3p³ - 2p²q² + 4pq - 2pq - 5p²q² - 2p³

Add like terms

3p³ - 2p³ - 2p²q² - 5p²q² + 4pq - 2pq

= p³ - 7p²q² + 2pq

4. Perimeter of the rectangle = sum of all its sides

Perimeter = 2(L + B)

L = (5x - y)

B = 2(x + y)

Perimeter = 2[(5x - y) + 2(x + y)]

Perimeter = 2[5x - y + 2x + 2y]

Add like terms

Perimeter = 2(7x + y)

Substitute x = 1 and y = 2 into the equation

Perimeter = 2(7(1) + 2)

Perimeter = 2(7 + 2)

Perimeter = 2(9)

Perimeter = 18 units

5. First let's find the quotient to justify if the value we get is greater than or less than 2.25

7⅙ ÷ 3⅛

Convert to improper fraction

43/6 ÷ 25/8

Change the operation sign to multiplication and turn the fraction by the left upside down.

43/6 × 8/25

= (43 × 8)/(6 × 25)

= (43 × 4)/(3 × 25)

= 172/75

≈ 2.29

Therefore, the quotient of 7⅙ ÷ 3⅛ is greater than 2.25

Answer:

y = 14

Step-by-step explanation:

[tex] \frac{15}{21} = \frac{5}{7} [/tex]

[tex] \frac{10}{x} = \frac{5}{7} [/tex]

[tex]x = 14[/tex]

Now,

10/15 = y/21

15y = 10*21

y = 210/15

y = 14

This is a Right answer...

I hope you understand..

Mark me as brainliest...

Answer:

The price of 1 exercise book is $122.45.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the price of one exercise book.

y is the price of one textbook.

Total cost of 10 exercise books and 2 textbooks is $1400.00.

This means that:

[tex]10x + 2y = 1400[/tex]

Since we want x:

[tex]2y = 1400 - 10x[/tex]

[tex]y = 700 - 5x[/tex]

One also finds the total cost of 3 textbooks and 30 exercise books is $3000.

This means that:

[tex]3x + 30y = 3000[/tex]

Since [tex]y = 700 - 5x[/tex]

[tex]3x + 30(700 - 5x) = 3000[/tex]

[tex]3x + 21000 - 150x = 3000[/tex]

[tex]147x = 18000[/tex]

[tex]x = \frac{18000}{147}[/tex]

[tex]x = 122.45[/tex]

The price of 1 exercise book is $122.45.

Answer:The 95% Rule states that approximately 95% of observations fall within two ... about 95% will be within two standard deviations of the mean, and about 99.7% will be ... Suppose the pulse rates of 200 college men are bell-shaped with a mean of 72 ... 1.2 - Samples & Populations ... 3.5 - Relations between Multiple Variables.

Step-by-step explanation:

Answer:

[tex]\log_{10}(147) = 2.1673[/tex]

Step-by-step explanation:

Given

[tex]\log_{10} 3 = 0.4771[/tex]

[tex]\log_{10} 5 = 0.6990[/tex]

[tex]\log_{10} 7= 0.8451[/tex]

[tex]\log_{10} 11 = 1.0414[/tex]

Required

Evaluate [tex]\log_{10}(147)[/tex]

Expand

[tex]\log_{10}(147) = \log_{10}(49 * 3)[/tex]

Further expand

[tex]\log_{10}(147) = \log_{10}(7 * 7 * 3)[/tex]

Apply product rule of logarithm

[tex]\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)[/tex]

Substitute values for log(7) and log(3)

[tex]\log_{10}(147) = 0.8451 + 0.8451 + 0.4771[/tex]

[tex]\log_{10}(147) = 2.1673[/tex]

Answer:

Growth: y = 1700(1.25)^t, y = 4000(1.0825)^t, y = 1.5(10)^t

Decay: y =240(1/2)^t, y = 12,000(0.72)^t,  y = 8000(0.97)^t

Step-by-step explanation:

In an exponential equation, growth and decay are determined by the factor you are multiplying by exponentially. If it's under 1 you're basically exponentially dividing the initial value. Over 1 and you are increasing the value.

Answer:

2 Answers. #1. +11. [3+(3/7)] times 7 is 24. DarkBlaze347 May 1, 2015. +5. Good job, DB! civonamzuk May 1, 2015.

35 Online Users.

Step-by-step explanation:

brainliest please and follow:D

Answer:

Length of the rectangle:

[tex]x = \frac{4800}{106} = \frac{2400}{53} [/tex]

Breadth of the rectangle:

[tex]60\%(x) = \frac{60}{100} \times \frac{4800}{106} \: \: \: \: \: \: \: \: \: \: \: \\ =60 \times \frac{48}{106} \\ = \frac{2880}{106} [/tex]

Step-by-step explanation:

Longer side of the rectangle(length) = x

Shorter side of the rectangle(breadth) = (60%)x

Perimeter of the rectangle = 2(l+b) = 96 inches

Hence,

[tex]96 = 2(x + 60\%(x))[/tex]

[tex]96 = 2(x + \frac{6}{100 } x)[/tex]

[tex]96 = 2( \frac{100}{1 00} x + \frac{6}{100} x)[/tex]

[tex]96 = 2( \frac{106}{100} x)[/tex]

[tex]96 = \frac{106}{50} x[/tex]

[tex]96 \div \frac{106}{50} = x[/tex]

[tex]96 \times \frac{50}{106} = x[/tex]

[tex] \frac{4800}{106} = x[/tex]

Answer:

18 feet

Step-by-step explanation:

The question is  illustrated using the attached image.

From the image, we have:

[tex]\theta = 31.43^o[/tex] --- angle of depression

[tex]h = 11ft[/tex] --- Emir's height

Required

The distance from the base of the tree (x)

From the attached triangle, we have:

[tex]\tan(90 - \theta) = \frac{Opposite}{Adjacent}[/tex]

This gives:

[tex]\tan(90 - 31.43) = \frac{x}{11}[/tex]

[tex]\tan(58.57) = \frac{x}{11}[/tex]

Make x the subject

[tex]x = 11 * \tan(58.57)[/tex]

[tex]x = 18.00[/tex]

Answer:

18

Step-by-step explanation:

took the test

Answer:

7. [tex]x^{11}[/tex]   8. [tex]y^{2}\\[/tex]  9. [tex]p^{12}[/tex]  10.[tex]a^{3} b^{2}[/tex]  11.[tex]g^{16}[/tex]  12.[tex]r^{9} h^{3}[/tex]  13.[tex]m^{15} p^{6}[/tex]  14.[tex]k^{6} y[/tex]  15.[tex]x^6 z^4[/tex]

Step-by-step explanation:

7. [tex]x^3[/tex] × [tex]x^8[/tex] = [tex]x^{11}[/tex] when multiplying with exponents you add

8. [tex]\frac{y^{6} }{y^{4} }[/tex] = [tex]y^{2}[/tex] when dividing with exponents you subtract

9. [tex](p^{3})^4[/tex] = [tex]p^{12}\\[/tex] when it's power to power, you multiply

10. [tex]\frac{a^{9} b^{4}}{a^{6} b^{2}}[/tex] = [tex]a^{3} b^{2}[/tex]  (subtract exponents)

11. [tex](g^{8})^2[/tex] = [tex]g^{16}[/tex]  (multiply exponents)

12. [tex]r^{4} h^{2} r^{5} h[/tex] = [tex]r^{9} h^{3}[/tex]  (add exponents [tex]r^4 + r^5\\[/tex] and [tex]h^2 +h^1\\[/tex] )

13. [tex](m^{5} p^{2})^3[/tex] = [tex]m^{15} p^{6}[/tex] (multiply exponents)

14. [tex]\frac{k^{7} y^{4}}{y^{3}k}[/tex] =  [tex]k^{6} y[/tex] (subtract exponents [tex]k^7-k^1[/tex] and [tex]y^4-y^3\\[/tex] )

15. [tex]x^3 z^2 x^3 z^2[/tex] = [tex]x^6 z^4[/tex] (add exponents same as #12)