Which expression has a negative value?
7-31-4/2)
(15-7)-(9:3)
0-517+(-14) ]- 30

Answer:

yes tht right pls mark me branilest

Step-by-step explanation:

1) -4

2) -8, -6, -4, -3, 0, 3, 5

3) (a) -8 + 5 - 3 - 2

-13 + 5

-8

(b) -7 - 9 + 4 + 3

-7 - 9 + 7

-9

Answer:

-9x+20

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

Given

[tex]2^{3x+1}[/tex] = [tex]2^{10}[/tex]

Since bases on both sides are equal, both 2, then equate the exponents

3x + 1 = 10 ( subtract 1 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Its 1

Doubled:-

[tex]\\ \rm\longmapsto 1\times 1=1=1^3[/tex]

[tex]\\ \rm\longmapsto 1\times 1\times 1=1=1^2[/tex]

Answer:

15/22

Step-by-step explanation:

3/11 ÷ 2/5

3/11 x 5/2

3/11 x 5/2 = 15/22

3/11 divided by 2/5 is equal to 15/22.

Here, we have,

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction.

The reciprocal of a fraction is obtained by flipping the numerator and denominator.

Let's calculate 3/11 divided by 2/5:

(3/11) ÷ (2/5)

To divide, we multiply by the reciprocal:

(3/11) * (5/2)

Now, multiply the numerators together and the denominators together:

(3 * 5) / (11 * 2) = 15/22

Therefore, 3/11 divided by 2/5 is equal to 15/22.

To learn more on division click:

brainly.com/question/21416852

#SPJ6

Answer:

X=2

Step-by-step explanation:

8-x=6

there the answer is 2

Answer:

t = d/r; t = 5

Step-by-step explanation:

Hi there!

1) Isolate t

d = rt

Divide both sides by r

d/r = rt/r

d/r = t

t = d/r

2) Solve for t when distance is 40 and the rate is 8

t = d/r

Replace d with 40 and rate with 8

t = 40/8

t = 5

I hope this helps!

Answer:

yes a right triangle

Step-by-step explanation:

Using the converse of Pythagoras' theorem.

If the square on the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.

longest side = 61 and 61² = 3721 , then

60² + 11² = 3600 + 121 = 3721

Since 61² = 60² + 11² then the triangle is right.

Answer:

3

Step-by-step explanation:

This is a classic puzzle!  If you pick out three socks, and they have only 2 colors, you'll get at least one match because they can't be 3 different colors.

Answer:

1/2

please mark me brainliest

Answer:

Perimeter = 38.8m

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

39cm

Step-by-step explanation:

When you find the upper and lower bounds of values with decimals, you will decrease or increase the value by increments of 0.05. Since we are just trying to find the upper bound we will add 0.05 to the values we are given.

15.6 + 0.05 = 15.65cm

3.8 + 0.05 = 3.85cm

Now that we have those values, we can find the perimeter using the formula [ 2(L + W) ]

= 2(15.65 + 3.85)

= 2(19.5)

= 39cm

Best of Luck!

Answer:

1/3÷5

=1/3×1/5

=1/15

each child receive 1/15 of cake

Answer:

Option(c) 34m

Step-by-step explanation:

Perimeter of a rectangle = 2(length + breadth)

length = 12m

breadth/width = 5m

Perimeter = 2(12 + 5)

                = 2(17)

                = 34m

Answer:

34

you just add, 12+5+12+5 to get 34

Answer:

g^-1(x)=x/2+3/2

Step-by-step explanation:

Answer:

.75

Step-by-step explanation:

8 red marbles, 3 blue marbles, and 1 green marble = 12 marbles

P( not blue) = marbles that are not blue / total

                     =(8red+1 green) / 12

                     =9/12

                      = 3/4

                       .75

Answer:

Step-by-step explanation:

First off, your polynomial should be a third degree, not a second degree. That's probably why you didn't get someone to answer this for you already.

If x + 2k is a factor of that polynomial, then by the Zero Product Property

x + 2k = 0 and x = -2k. That means that, by the factor theorem, f(-2k) = 0 (which means that if you plug -2k in for all the x's you get a zero). Therefore,

[tex]3(-2k)^3+6k(-2k)^2-14(-2k)-3=0\\-24k+24k+28k-3=0\\28k-3=0\\28k=3\\k=\frac{3}{28}[/tex]

Answer:

the answer is in picture

Answer:

There is no Image

So Instead

There should be the lowest extreme aka 0, and hights extreme (Whatever number is last) Then you've got average (The Middle) and n the middle of it is the median.

Answer: give me brainliest

Step-by-step explanation:

ax+by=a-b

ax=a-b-by

x=a-b-by/a←

bx-ay=a+b

substituting

b(a-b-by/a)-ay=a+b

ab-b²-b²y/a-ay=a+b

ab-b²-b²y-a²y/a=a+b

ab-b²-(b²+a²)y=a²+ab

-(b²+a²)y=a²+ab-ab+b²

(b²+a²)y=-(a²+b²)

y=-(a²+b²)/a²+b²

y=-1←

substituting value of y

x=a-b-b(-1)/a

x=a-b+b/a

x=a/a

x=1

Answer:

is 5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

So first when dividing fractions you need to invert and multiply. Thus the fraction becomes:

1/4 * 20/1.

When simplified it becomes 20/4 which is 5.

HOPE THIS HELPED

Answer:

place value of 2 is 100

Step-by-step explanation:

please brainleist my answer

Answer:

The place value of 2 in 6.253 is 200

Step-by-step explanation:

Place value of 2 is occurring in hundreds

Answer:

Step-by-step explanation:

( C ). 112°

Answer: Approximately 18.33%

Work Shown:

11/60 = 0.1833 approximately

This decimal converts to 18.33% when moving the decimal point over to the right two spots. Round this value however you need to.

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

Answer:

Step-by-step explanation:

40905

40509

50095

40059

Is greatest to least. You want it to go the other way around.

40059

40095

40509

40905

The smallest number is determined by the number on the right. Then your keep going left to get to the largest. The answer is the second one down.

Answer:

47.06 United States Dollar

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

Answer:

A

Step-by-step explanation:

in step 1, when expanding the bracket, ken needed to do 2×5y AS WELL as 2×-1 which they didn't do. the correct answer after the first step should be 10y-2=18

Answer:

The last one

Step-by-step explanation:

It doesn't make sense for that to be true