The information about the path is incomplete, so I'll just use a domain of a ≤ t ≤ b, where a > 0 and b < ∞.
Differentiating r(t) gives
[tex]\vec r(t) = 2t\,\vec\imath + 2t\,\vec\jmath + t\,\vec k \implies \dfrac{\mathrm d\vec r(t)}{\mathrm dt} = 2\,\vec\imath + 2\,\vec\jmath + \vec k[/tex]
with magnitude √(2² + 2² + 1²) = √5.
Then we have
[tex]\displaystyle \int_C f(x,y,z)\,\mathrm ds = \int_a^b f(2t,2t,t) \left\|\frac{\mathrm d\vec r(t)}{\mathrm dt}\right\| \,\mathrm dt \\\\= \sqrt5 \int_a^b \frac{2t+2t+t}{(2t)^2+(2t)^2+t^2}\,\mathrm dt \\\\ = \sqrt5 \int_a^b \frac{5t}{5t^2} \,\mathrm dt \\\\ = \sqrt5 \int_a^b \frac{\mathrm dt}t \\\\ = \sqrt5 (\ln(b)-\ln(a)) = \boxed{\sqrt5 \ln\left(\frac ba\right)}[/tex]
Add or Subtract: show all written work 30 POINTS!!
Answer:
I hope it helped U
stay safe stay happy
1+1×5−6+8×(4+4)−62
Find the ans here
Answer:
2
Step-by-step explanation:
1+1×5−6+8×(4+4)−62 =
1+1x5-6+8x(8)-62 =
1+5-6+64-62 =
2
Hope this helps! :)
Solve 2/5 x + 1/2 = 5/6
Answer:
5/6
Step-by-step explanation:
I'm assuming the x in your equation is used as a variable.
5/6-1/2= 2/6=1/3
2/5x=1/3
x=5/6
Barry is checking his bank account for a few transactions that he completed. He had $230
in his account to start and then contributed a check for $360. He paid his water, electric and
cable bill, which were $100, $46 and $107. How much money is in his bank account?
A. $253
B. $383
C. $590
D. $337
Answer:
D.
Step-by-step explanation:
$230 + $360 = $590
$590 - $253* = $337
$337
*( total sum of all the bills )
HELP PLEASE HELPPP PLEAE NO LINKS OR I WILL REPORT YOU PLEASE GIVE EXPLANATION
Answer:
(I got your back pal) Your answer is -41/21
Can you give me a brainlest it would help me a lot
I need answers for problem solving
Answer:
243
Step-by-step explanation:
the answer is 243 for number 6
Answer:
all you gotta do is do 2430 divided by ten
please answer this question
Step-by-step explanation:
all steps are in picture
the density of oxygen is 0.0001429 grams per cubic centimeter.how is this number written in scientific notation?
Which of the following fractions is in lowest form
fraction is in lowest term is no(b)
How many cubes of side 2cm can be fitted into a box 12 cm long, 8cm wide and 4cm high?
Answer:
there are 48cubes fetted into a box
Help please thanksss!!
Answer:
4. 3,52 - Tenths
0.352 - Hundredths
5. 65.09 - Ones
7.005 - Thousandths
6. 753.4 - Tens
0.051 - Hundredths
Let A = {a, b, c, d}, B = {a, c, d, e}. Let f : A → R and g : B → R such that f = {(a, 1),(b, 2),(c, 2),(d, 4)} and g = {(a, 0),(c, 4),(d, 8),(e, 0)}. State the domain and find: f/g
Answers:
Domain = {c, d}f/g = { (c, 1/2), (d, 1/2) }============================================================
Explanation:
The domain of f: {a,b,c,d} which is drawn from set A.
The domain of g: {a,c,d,e} which is drawn from set B
So far, we can see the possible inputs are: a,b,c,d,e
Let's go through each lowercase letter of the given sets
If 'a' is plugged into f/g, then we'll have 0 in the denominator due to the ordered pair (a,0) in function g. This causes a division by zero error so the input 'a' is not allowed in the domain of f/g.If we tried b, then it would work for function f, but it doesn't work for function g. If we tried to compute g(b), then the result is undefined. This is because the lowercase b input is not found in set uppercase B which is where function g selects its inputs from. So b is eliminated.The input c does work however. f(c) = 2 because of the ordered pair (c,2) in the function f. Similarly, g(c) = 4. This means f/g = 2/4 = 1/2 when the input is c. This shows that c is a valid input in the domain of f/g.The input d is pretty much the same story as input c. Moreover, the input d leads to the same output as c does. This time we have f/g = 4/8 = 1/2 when the input is d. Therefore, d is another valid input in the domain of f/g.The input e is not valid because (e,0) will lead to a division by zero error, as it's part of the g(x) function. So we must eliminate 'e' as a valid option in the domain. Even if we didn't have a division by zero error, we still have the fact that 'e' is not in the domain of the first function f. This is another reason why f/g is not defined when the input is 'e'.To summarize, only inputs c and d are valid in the domain.
The domain is the set {c, d}
Both inputs in the domain lead to the output 1/2. This means the range of f/g is {1/2}. Despite having just one element inside, we must use curly braces to indicate we have a set.
The function f/g is { (c, 1/2), (d, 1/2) }
We simply list all of the (x,y) ordered pairs to describe the function. In this case, there are only two such pairs.
PLS HELP!! Will give brainliest!
Angle AOC measures 84 degrees. Angle AOB = 3x and BOC is x
First, write the equation you would use to find the answer then find the value of x
Answer:
∠AOB + ∠BOC = ∠AOC we will be using this equation
x = 21 this is the value of x
Step-by-step explanation:
Angle AOC = 84
Angle AOB = 3x
Angle BOC = x
it is given that Angle AOC = 84so we just need to add Angle AOB and Angle BOC
now lets make the equation we that we will be using
∠AOB + ∠BOC = ∠AOC
3x + x = 84
4x = 84
x = 84 ÷ 4
x = 21
Step-by-step explanation:
Here, we have,
AOC=84°
AOB=3x
BOC=x
Now, the required equation will be;AOC=AOB+BOC[whole part axiom]
or, 84°=3x+x
or, 84°=4x
or, 84°÷4=x
or, x=21°
Thus, the equation to find the answer is AOC=AOB+BOC and the value of x is 21°.
5x²+4x+3=0 solve for x
Answer:
[tex]{ \underline{ \sf{x \: is \: \: \{ \frac{ - 5 + i \sqrt{35} }{10} \} } \: \: and \: \: \{ \frac{ - 5 - i \sqrt{35} }{10} \}} }[/tex]
Step-by-step explanation:
[tex]5 {x}^{2} + 4x + 3 = 0 [/tex]
from quadratic formular:
[tex]{ \sf{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }} [/tex]
general equation:
[tex] {ax}^{2} + bx + c = 0[/tex]
a is 5, b is 4 and c is 3:
substitute in formular:
[tex]{ \sf{x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 5 \times 3) } }{(2 \times 5)} }} \\ \\ { \sf{x = \frac{ - 5± \sqrt{ - 35} }{10} }}[/tex]
but from complexes, i² = -1
[tex]{ \sf{x = \frac{ - 5± \sqrt{35 {i}^{2} } }{10} }} \\ \\ = { \sf{x = \frac{ - 5±i \sqrt{35} }{10} }}[/tex]
Determine whether the following statement is true or false.
A proper use of units can help us to determine the meaning of the slope of a linear function.
Here we want to see if the statement:
"A proper use of units can help us to determine the meaning of the slope of a linear function" is true or false.
We will see that it is true.
First, a general linear equation can be written as:
y = a*x + b
Where a is the slope, x is the independent variable, y is the dependent variable, and b is the y-intercept.
The proper use of units is:
y and b must have the same units.
x can have any type of units
The slope must have the quotient between the units of y and the units of x.
Where the proper use of units means that we have the same units on both sides of the expression.
Now, assume that we know the units of y and x.
For example:
y is miles (then b is also in miles)
x is in hours
Then, with the proper use of units, we can see that the units of the slope are:
miles/hour, or miles per hour.
With this (only knowing the units of x and y) we can see that the slope will be a speed.
So yes, the proper use of units is really important, as this has a lot of information (particularly, the meaning of the slope in a linear equation)
Thus, the statement is true.
If you want to learn more, you can read:
https://brainly.com/question/20286983
I need help ASAP whit this question
Answer:
B. 7
Step-by-step explanation:
The original box must be 1 by 1 by 1.
So then the new box would be 2 by 2 by 2.
2×2×2=8
8-1=7
I hope this helps!
pls ❤ and mark brainliest pls!
iwidncuhbcffbhbhvfrhur3huivr4hiuvriuvfruvfiuvfjivfrjiovrjiovfriojvrfjiovfiovrfmvr mkormkvmkvkmorbemoivbe
Answer:
3.14159265358979
Step-by-step explanation:
PLEASEEE HELP!!!!!!!
Temperatures in Verkhoyansk, Russia have been recorded as low as -90°F and
as high as 98°F. What is the difference between the highest and lowest recorded
temperatures in Verkhoyansk?
Do the mathematics please. I will give a reward.
9514 1404 393
Answer:
p = -3/4b -3/4
Step-by-step explanation:
Vectors are perpendicular when their dot product is zero.
A·B = p(4) +b(3) -3(-1) = 4p +3b +3
We want this to be zero, so ...
4p +3b +3 = 0
4p = -3b -3
p = -3/4b -3/4 . . . . the value of p that makes A⊥B
A number is multiplied by 16, and that product is added to 4. The sum is equal to the product of 4 and 9. Find the number.
Answer:
The number is 2
Step-by-step explanation:
x * 16 + 4 = 9*4
x * 16 + 4 = 36
x * 16 + 4 - 4 = 36 - 4
x * 16 = 32
x * 16 / 16 = 32 / 16
x = 2
Answer:
The number is 2
Step-by-step explanation:
let the number be "a"
16a+4=4×9
16a+4=36
16a=36-4
16a=32
a=2
If , then the ordered pair of f -1(10) = (10, 31) (10, 3) (3, 10)
help asap
Answer:
B
Step-by-step explanation:
f^(-1) (x) = (x-1)/3
f^(-1) (10) = (10-1)/3 = 3.
PLEASE HELP NOW
write and solve an equation to find the value of X. please explain in details and show your work!
Answer:
Solution=96°+x+35°
=x+96°+35°
=x=96°-35°
=x=61°
I want to know how to solve this.
Answer:
B
I just did it and got it right
<7 and <8 are complimentary angles. <5 = <8 and m<6 = 29. Find the measure of angle 7 and angle 5
Here <5=<8 then
<7=<6=29[tex]\\ \sf\longmapsto <7+<8=90[/tex]
[tex]\\ \sf\longmapsto 29+<8=90[/tex]
[tex]\\ \sf\longmapsto <8=90-29[/tex]
[tex]\\ \sf\longmapsto <8=61[/tex]
<5=61°least multiple of 2983548
Answer:
it must be 2983548×2............
Calculate simple interest and compound interest assuming that principal amount is $ 10,000; interest rate is 9% for three years. What is the amount different between compound and simple interest?
Step-by-step explanation:
Please mark me as brainlyest
Use the Distributive Property to multiply. 2(b – 7)
Answer:
2b - 14
Step-by-step explanation:
2(b – 7)
2b - 14
Answer:
[tex]2b-14[/tex]
Step-by-step explanation:
Using the distributive property, [tex]2(b-7)[/tex] can be written as [tex](2\cdot b)-(2\cdot7)[/tex] which solved/simplified is [tex]2b-14[/tex]
Man, it's late! Well, hope this helped you out and answered your question!
Determine all values of the constant k for which the given set of vectors is linearly independent in R4.{(1,1,0,−1), (1,k,1,1),(5,1,k,1), (−1,1,1,k)}
If these vectors are to be linearly independent, then there exists some not-all-zero choice for scalars [tex]c_1,c_2,c_3,c_4[/tex] such that
[tex]c_1(1,1,0,-1) + c_2(1,k,1,1) + c_3(5,1,k,1) + c_4(-1,1,1,k) = (0,0,0,0)[/tex]
We can recast this as a system of linear equations,
[tex]\begin{bmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\\c_4\end{bmatrix} = \begin{bmatrix}0\\0\\0\\0\end{bmatrix}[/tex]
This system has a solution if the coefficient matrix on the left side is not singular. So we attempt to find k such that it *is* singular, i.e. the determinant is zero:
• A cofactor expansion along the first column gives
[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = \begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} - \begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} + \begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix}[/tex]
• Cofactor expansions along the first columns of the remaining 3x3 matrices give
[tex]\begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} = k \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}1&1\\1&k\end{vmatrix} + \begin{vmatrix}1&1\\k&1\end{vmatrix} = k^3-3k+2[/tex]
[tex]\begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} = \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}5&-1\\1&k\end{vmatrix} + \begin{vmatrix}5&-1\\k&1\end{vmatrix} = k^2-4k+3[/tex]
[tex]\begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix} = \begin{vmatrix}1&1\\k&1\end{vmatrix} - \begin{vmatrix}5&-1\\k&1\end{vmatrix} + \begin{vmatrix}5&-1\\1&1\end{vmatrix} = -k^2 - 6k + 7[/tex]
It follows that
[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = (k^3-3k+2) - (k^2-4k+3) + (-k^2 - 6k + 7) \\\\ \begin{vmatrix}\cdots\end{vmatrix} = k^3 - 2k^2 - 5k + 6 = (k-3)(k-1)(k+2)[/tex]
which makes the coefficient matrix singular if k = 3, k = 1, or k = -2.
Then the four vectors are linearly independent for
[tex]\left\{ k\in\mathbb R \mid k\not\in\{-2,1,3\}\right\}[/tex]
Find the area of each shaded region. Show your reasoning.
maybe we could answer if there waas a pic=]
616÷2=308. I got 38 instead of 308 when solved with long division
Answer:
U forgot to add zero while dividing
