How could semantics be defined?
A.
as a set of rules that studies how words are broken down into morphemes
B.
as a set of rules that is concerned with understanding the meaning of words
C.
as a set of rules that dictates how vowels and consonants are pronounced
D.
as a set of rules that determines how words can be arranged into sentences
Answer:
its b >.<
Explanation:
just trust me laddies
Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words
What are semantics ?Semantics can be defined as the message conveyed by words in a sentence and context where the sentence is placed. It is a set of rules that is concerned with the understanding of words in sentences used in a context.
Hence we can conclude that Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words.
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How many times more gravitational potential energy would the same lander have on top of a 350-m hill on Earth? It would have times more gravitational potential energy
Answer:
6
Explanation:
Just did it.
The gravitational potential energy would the same lander have on top of a 350-m hill on Earth is 6.
What is gravitational potential energy?If an object is lifted, work is done against gravitational force. The object gains energy.
The equation for calculating gravitational potential energy is
GPE =mgh
where, GPE is the gravitational potential energy, m is the mass, h is the change in height and g is the acceleration due to gravity.
The heavier the particle and the higher it is over the ground, the more gravitational potential energy it holds. Gravitational potential energy increments as weight and level increments.
Given is the height of hill h = 350m.
Thus, the same lander will have the the potential energy 6 times more.
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what force is the total force felt by an object?
Answer:
net force
Explanation:
Net force felt by an object.
What two things must you know to describe the motion of an object? __________________________________________________________________________
Distance is _________________________________________________________________
What is the displacement of a cyclist, who travels 1 mile north, then 1 mile east, and finally 1 mile south? ___________________________
Define speed ________________________________________________________________
How do speed and velocity differ? ______________________________________________
__________________________________________________________________________
How do velocities combine? In opposite directions? ________________________________ In the same direction? ________________________________________________________
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves upstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank? ___________________________________
The rate at which velocity changes is called ________________________
True or false? Acceleration is the result of increases or decreases in speed.
A horse on a carousel that is moving at a constant speed is accelerating because _________________________________________________________________________
True or false? When the final velocity is less than the initial velocity of an object, the acceleration is negative.
The total distance traveled divided by the total time is _______________________
What are some common units for speed (give at least two) _____________ ___________
Define velocity ____________________________________________________________
Define acceleration _________________________________________________________
A quantity that has both magnitude and direction is called a _________________.
WILL MARK BRAINLIEST PLEASE HELP DUE IN 2 MINS
On a distance-time graph speed is a ____________ line and thus a ____________ graph.
On a distance-time graph acceleration is a ___________ line and thus a _______________ graph.
Answer:
velocity is vector Quantity
1. A ball rolls off of a table with a speed of 3.2 m/s. The table is 1.6 m high.
a) When does the ball hit the ground? (time)
b) How far away from the base of the table does the ball travel?
c) With what vertical speed does the ball hit the floor?
Answer:
Explanation:
for vertical displacement h = 1.6 , let time taken be t , initial vertical velocity = 0
h = ut + 1/2 g t²
= 1/2 g t²
1.6 = .5 x 9.8 x t²
t² = .3265
t = .57 s
b )
velocity in horizontal direction = 3.2 m /s
horizontal displacement
= 3.2 x .57 = 1.82 m
c )
for vertical movement
v = u + gt
= 0 + 9.8 x .57
= 5.58 m /s
John has gradually added time to his running routine to reach his goal of running a 5k. John has reached his goal of running a 5k without stopping. This achievement is an example of
Answer:
pursuing a goal
Explanation:
Since there are no answer choices provided I would say that this is an example of pursuing a goal. This is basically all of the tasks and struggles that an individual must go through in order to finally achieve a certain goal. It also involves gradually breaking barriers and pushing forward by increasing the complexity of the tasks until you are able to break through all of them to reach the end-goal that you have been striving for. Which is exactly what John has been doing in this scenario by gradually increasing his running time.
HELP PLS HURRY !!!!!!!!!
What do all elements in a column in the periodic table have in common? (2 points)
Answer:
Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.
Explanation:
1. Using the data table below, model (draw) the orbital motion of the two planets (D and
N).
A. Determine the distance based on the mass and amount of force.
a. In the chart, write 'more' or 'less', then be sure to represent the distance in
your model drawing.
B. Be sure to represent the objects' masses appropriately.
C. Include gravitational force arrows in your model.
D. On your drawing mark where the planet will be increasing and decreasing in velocity
for each planet
Mass
Distance
Gravitational Force
Sun
10
X
X
2
8
Planet D
Planet N
6
3
3
Make sure to attach your drawn model in the space below.
Answer: 110 N
Explanation: trust me
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied
Answer:
6N
Explanation:
Given parameters:
Pressure applied by the woman = 300N/m²
Area = 0.02m²
Unknown:
Force applied = ?
Solution:
Pressure is the force per unit area on a body
Pressure = [tex]\frac{force}{area}[/tex]
Force = Pressure x area
Force = 300 x 0.02 = 6N
If you are in a car at a stop sign and then the driver
presses on the gas pedal really hard, which way is the car
accelerating?
Answer:
it wont be because the hand brake would be on
Location A on the surface of Earth bas a much higher temperature than Location Which statement is most likely true A.Both locations are at the poles B.Both are at the equator C.Location A is at the equator and Location B is the poles D.Location at the poles and location B is the equator
Answer:
The anwser is b
Explanation:
Answer:
the answer is B
I know because i just did it
A flashlight that is powered by 3 Volts and uses a bulb with a
resistance of 68. will have a current of Amps
A parallel circuit contains a battery with a voltage of 9 V. The total resistance in the circuit is 18 ohms. Which claim about the current in the circuit can be supported mathematically from the relationships between voltage, current, and resistance? A.
the current flowing through the circuit is 0.5 amps because current is related to voltage and resistance by the formula I = V/R
B.
the current flowing through the circuit is 162 amps because current is related to voltage and resistance by the formula I = VR
C.
the current flowing through the circuit is 27 amps because current is related to voltage and resistance by the formula I = R + V
D.
: the current flowing through the circuit is 2 amps because current is related to voltage and resistance by the formula I = R/V
Answer:
Its C I fell confident
Explanation:
I took 2 hrs I tried on this for u dont get mad have a wonderful day :D
So the incorrect option is C the current flowing through the circuit is 27 amps because the current is related to voltage and resistance by the formula I = R + V
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).
Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.
Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit.
To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists.
E = I x R
So the incorrect option is C the current flowing through the circuit is 27 amps because the current is related to voltage and resistance by the formula I = R + V
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A ball is thrown horizontally with an initial
velocity of 20 m/s from the top of a tower
60 m high. What is the initial vertical
velocity of the ball?
a. O m/s
b. 20 m/s
c. 3.5 m/s
d. 9.81 m/s
The initial vertical velocity of a ball thrown horizontally with an initial velocity of 20 m/s from the top of a 60 m high tower is 0 m/s (option a).
The ball is thrown horizontally, so its velocity will have only components in the x-direction (horizontal). The components of the initial velocity in the y-direction (vertical) will be zero.
For a ball's velocity to have components in the vertical and horizontal direction, the ball must be thrown at a certain angle to the ground, describing a parabolic movement.
In a parabolic movement, the vertical and horizontal components of the velocity would be:
[tex] v_{x} = v_{i}cos(\theta) [/tex]
[tex] v_{y} = v_{i}sin(\theta) [/tex]
Where:
[tex] v_{i} [/tex]: is the initial velocity
θ: is the angle
Therefore, the initial vertical velocity of the ball is zero (option a).
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A projectile was fired from ground with 50 m/s initial velocity at 45 degree angle. How long will stay in the air? What is range? What is the maximum height the projectile?
Answer:
1. Time of flight = 7.22 s
2. Range = 255.10 m
3. Maximum height = 63.77 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 50 m/s
Angle of projection (θ) = 45°
Time of flight (T) =?
Range (R) =?
Maximum height (H) =?
1. Determination of the time of flight
Initial velocity (u) = 50 m/s
Angle of projection (θ) = 45°
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
T = 2uSine θ /g
T = 2 × 50 Sine 45 / 9.8
T = 100 × 0.7071 /9.8
T = 7.22 s
2. Determination of the range.
Initial velocity (u) = 50 m/s
Angle of projection (θ) = 45°
Acceleration due to gravity (g) = 9.8 m/s²
Range (R) =?
R = u²Sine 2θ /g
R = 50² × Sine (2×45) /9.8
R = 2500 × Sine 90 /9.8
R = 2500 × 1 / 9.8
R = 255.10 m
3. Determination of the maximum height.
Initial velocity (u) = 50 m/s
Angle of projection (θ) = 45°
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (H) =
H = u²Sine²θ /2g
H = 50² × (Sine 45)² / 2 × 9.8
H = 2500 × (0.7071)² / 19.6
H = 63.77 m
Answer:
Time spent in the air is 7.22 sThe range of the projectile is 255.1 mThe maximum height of the projectile is 63.77 mExplanation:
Given;
initial velocity of projection, u = 50 m/s
angle of projection, θ = 45°
Time spent in the air is the time of flight, given as;
[tex]T = \frac{2usin \theta}{g}\\\\T = \frac{2(50)sin (45)}{9.8}\\\\T = 7.22 \ s[/tex]
The range of the projectile is given by;
[tex]R = \frac{u^2sin(2\theta)}{g}\\\\R = \frac{u^2sin(2*45)}{g}\\\\ R = \frac{u^2sin(90)}{g}\\\\ R = \frac{u^2(1)}{g}\\\\R=R_{max} = \frac{u^2}{g} =\frac{50^2}{9.8} = 255.1 \ m[/tex]
The maximum height of the projectile is given by;
[tex]H = \frac{u^2sin^2\theta}{2g}\\\\H = \frac{(50)^2sin^2(45)}{2*9.8}\\\\H = 63.77 \ m[/tex]
Which describes the role of oxygen in photosynthesis? *
It is a reactant, so it is released by the plant.
It is a product, so it is released by the plant.
It is a reactant, so it enters the plant.
It is a product, so it enters the plant.
Answer:
It is a product, so it is released by the plant.
Explanation:
[tex]6CO2 + 6H2O[/tex] → [tex]C6H12O6 + 6O2[/tex]
The plant uses water and carbon dioxide to create glucose and oxygen. Glucose is plant food, and Oxygen is given off as a byproduct.
Answer:
It is a product, so it is released by the plant.
Explanation:
A car increases velocity from 30 m/s to 60 m/s in 4 seconds. Calculate the average acceleration of the car over this time.
0.3 m/s2
7.5 m/s2
0.6 m/s2
4.8 m/s2
Answer:
B.7.5m/s2
Explanation:
average acceleration=change invelocity/time taken
a=(60-30)/4
=7.5m/s2
The average acceleration of the car 7.5 m/s²
The parameters given in the question are;
initial velocity= 30 m/s
final velocity= 60 m/s
time= 4 seconds
The formula that can be used to calculate the average acceleration is
= final velocity-initial velocity/time
= 60-30/2
= 30/2
= 7.5
Hence the average acceleration is 7.5 m/s²
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Is it okay to keep an albino gecko
Answer:
Yes
Explanation:
Johanna took her younger brother to the playground because he likes to swing. Look at the diagram below that shows Johanna pushing her brother on a swing.
12. After Johanna pushes for a while, she begins to feel tired. What type of energy is transformed into the kinetic energy she uses? A. chemical B. electrical C. nuclear D. thermal - Help fast I have my test soon!
Answer:
A. chemical
Explanation:
the type of energy our body contain is chemical energy and that chemical energy is the one used while pushing the swing.. so I guess it's chemical energy.. based on my knowledge hope this helps.
This man proposed that all matter was composed of atoms
Answer:
John Dalton
Explanation:
How do atoms of different non metals stabilize themselves?
Pls help
Answer:
by taking other atoms that have one shell and putting it i the spot that they need t in
Explanation:
Katie is making a strawberry milkshake in her blender. A 0.05kg strawberry is rapidly spun around the inside of the container with a speed of 11.0 m/s, held by a centripetal force of 12.0 N. What is the radius of the blender at the strawberry’s location? Round answers to two decimal places.
Answer:
The radius of the blender is approximately 0.5041[tex]\bar 6[/tex] meters
Explanation:
The given parameters are;
The mass of the strawberry, m = 0.05 kg
The speed with which the strawberry is spun, v = 11.0 m/s
The centripetal force holding the strawberry = 12.0 N
The formula for the centripetal force, [tex]F_c[/tex], is given as follows;
[tex]F_c = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the centripetal rotation, which is the radius of the blender
[tex]\therefore r = \dfrac{m \cdot v^2}{F_c}[/tex]
Substituting the values gives;
[tex]\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6[/tex]
The radius of the blender, r ≈ 0.5041[tex]\bar 6[/tex] meters.
Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?
Answer:
80 km is distance and 30km north is displacement
Explanation:
distance= 50+30=80km
displacement= 50-20=30
his displacement is 30km north
When Tyler drives 50 km north and then drives back 30 km south, we have:
1. The distance that he covers is 80 km.
2. Tylor's displacement is 20 km.
1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:
[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]
Hence, the distance traveled by Tyler was 80 km.
2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:
[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]
Therefore, Tyler's displacement is 20 km.
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Which of the following correctly puts the objects in order by increasing inertia?
A. bird, butterfly, airplane
B. butterfly, bird, airplane
C. airplane, bird, butterfly
D. buttferfly, bird, airplane
Ceres is a large asteroid that orbits the Sun between Mars and Jupiter. Ceres has a mass of 9.4 x 1020 kg and a radius of about 4.7 x 10° m.
If a spacecraft attempts to land on the asteroid, what acceleration due to gravity will it experience near the surface?
Answer:
The acceleration due to gravity near the surface of Ceres is approximately 0.284 m/s²
Explanation:
The given parameters are;
The mass of Ceres = 9.4 × 10²⁰ kg
The radius of Ceres, r = 4.7 × 10⁶ m
By Newton's law of gravitation, we have;
[tex]Gravitational \ force\ on \ the \ spacecraft \ near \ Ceres, \ F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]
Therefore;
[tex]Acceleration \ due \ to \ gravity \ g =G\dfrac{m_{1}}{r^{2}}[/tex]
Where;
m₁ = The mass of Ceres = 9.4 × 10²⁰ kg
m₂ = The mass of the spacecraft
G = 6.6743 × 10⁻¹¹ N·m²/kg²
Substituting the values, we get;
[tex]g \ near \ the \ surface \ of \ Ceres = \dfrac{ 6.6743 \times 10^{-11} \times 9.4 \times 10 ^{20}}{(4.7 \times 10^5)^{2}} \approx 0.284 \ m/s^2[/tex]
The acceleration due to gravity near the surface of Ceres ≈ 0.284 m/s²
Is static electricity more harmful than it is helpful or vice versa
Answer:
You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.
Explanation:
You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.
hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N l need process
Answer:
735N
Explanation:
Weight is a measurement of force.
F = Force
m = mass
a = acceleration
F = m*a
F = 75kg*9.8m/s²
F = 735N
In lab you submerge 100 g of iron nails at 40 0C in 100 g of water at 20 0 C. Specific heat of iron is 0.12 cal/g∙0C. Equate the heat gained by water to the heat lost by nails and show that the final temperature of water becomes 22.1 0C.
Let T be the final temperature of water and nails (iron).
Given that the initial temperature of 100 g nails, [tex]T_{1F}=40^{\circ}C[/tex].
Specific heat of the iron, [tex]C_F=0.12 cal/g^{\circ}C[/tex].
So, the heat lost by nails [tex]= mC_F(T_{1F}-T}[/tex]
[tex]=100\times 0.12 \times (40-T)\cdots(i)[/tex]
The initial temperature of 100 g water, [tex]T_{1w}=20^{\circ}C.[/tex]
Specific heat of water, [tex]C_w=1 cal/g^{\circ}C[/tex]
So, the heat gained by water [tex]= mC_w(T-T_{1w}}[/tex]
[tex]=100\times 1 \times (T-20)\cdots(ii)[/tex]
As the exergy is conserved, so
the heat lost by the nails = the heat gained by the water
From equation (i) and (ii), we have
[tex]100\times 0.12 \times (40-T)=100(T-20)[/tex]
[tex]\Rightarrow 0.12(40-T)=T-20[/tex]
[tex]\Rightarrow 0.12\times 40 -120T=T-20[/tex]
[tex]\Rightarrow 0.12T+T=4.8+20[/tex]
[tex]\Rightarrow 1.12T=24.8[/tex]
[tex]\Rightarrow T=24.8/1.12= 22.1^{\circ}C[/tex]
Hence, the final temperature of both, iron nails as well as water, become [tex]22.1^{\circ}C[/tex].
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is decreasing at a rate of 3.1m/s2.
What is the student's mass?
What is the net force on the student?
What value does the scale read?
Answer:
1) The mass of the student is approximately 73.39 kg
2) The net force on the student is approximately 947.523 N
3) The value the scale will read is approximately 96.59 kg
Explanation:
The given parameters are;
The weight of the student = 720 N
The speed at which the elevator is decreasing = 3.1 m/s²
1) The weight of the student = The mass of the student × The acceleration due to gravity
The acceleration due to gravity is a constant = 9.81 m/s²
Substituting the known values gives;
720 N = The mass of the student × 9.81 m/s²
∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg
2) The forces acting on the student are;
i) The force of gravity which is the weight of the student acting downwards
ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student
The net force, [tex]F_{net}[/tex] = The weight of the student + The inertia force of the slowing elevator
∴ The net force, [tex]F_{net}[/tex] = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N
3) The scale will read the mass of the student as follows;
Mass reading of student on the scale = Force on scale/9.81
∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg
The value the scale will read = 96.59 kg.
The mass of student is, 73.46 kg.
The net force acting on the student is 942.72 N.
The reading of the scale is 96.70 kg
Given data:
The weight of student is, W = 720 N.
The magnitude of acceleration is, [tex]a = 3.1 \;\rm m/s^{2}[/tex].
The standard expression for the weight is,
[tex]W =mg[/tex]
Here, g is the gravitational acceleration. And m is the mass of student.
Solving as,
[tex]W =mg\\\\720 = m \times 9.8\\\\m = 73.46 \;\rm kg[/tex]
Thus, the mass of student is, 73.46 kg.
Since, the force of gravity which is the weight of the student acting downwards . The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student. Then the net force is,
[tex]F_{net} = W+(ma)[/tex]
Solving as,
[tex]F_{net} = 720+(73.46 \times 3.1)\\\\F_{net}=947.72 \;\rm N[/tex]
Thus, we can conclude that the net force acting on the student is 942.72 N.
The reading of the scale is given as,
[tex]reading=\dfrac{F_{net}}{g}[/tex]
Solving as,
[tex]reading = \dfrac{947.72}{9.8}\\\\reading=96.70 \;\rm kg[/tex]
Thus, we can conclude the reading of the scale is 96.70 kg.
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