Which action would decrease the strength of attraction between a magnet and an iron object
A. Moving the magnet farther away from the iron object
B. Moving the iron object closer to the magnet
C. Decreasing the number of electrons on the magnet
D. Increasing the number of electrons on the magnet

Answer:

the moment

Explanation:

the shorter the distance from the force, the lesser the torque acting on it

Uhhh.. creep. Can you like..not?

Answer: Lol what the heck I never heard this type of question. but I mean you see it when you go to the beach so yeah that's all I'm telling you U-U

Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

Solution:

The coefficient of volume expansion

p = ΔV/V1Δt

3a = V2-V1/V1Δt

Given

a = = 11 x 10-6 / °C

V2 is the final volume

V1 is the initial volume = 100cm³

Δt = 100-0 = 100°C

Substitute

3(11 x 10-6) = V2-100/100(100)

33*10^-6 * 10000 = V2-100

33*10^-2 = V2-100

V2 = 100 + 0.33

V2 = 100.33

Hence the new volume is 100.33cm³

Answer:

1.8 J

Explanation:

I had this exact question today and found someone who had solved it before, this was their response to the work done by gravity. They used the name "physicsmom"

Vertical distance = 1.8 sin 30 = .9 m

W = 2 N * .9 m = 1.8J

Good luck! I hope this helps!

The work done on the box by the gravity is 0.072 J.

The given parameters;

The work done on the box by gravity is calculated as follows;

W = FΔr

where;

F is the net horizontal force on the block

The net horizontal force on the box  is calculated as follows;

[tex]\Sigma F_x = F_g sin(\theta ) - F_k\\\\ \Sigma F_x = F_g sin(\theta ) - \mu_k F_n \\\\ \Sigma F_x = 2 \times sin(30 ) - (tan \theta) \times F_n\\\\ \Sigma F_x = 1 - (tan\ 30) \times 1.73\\\\ \Sigma F_x = 0.04 \ N[/tex]

The work done on the box by gravity is calculated as;

W = 0.04 x 1.8

W = 0.072 J.

Thus, the work done on the box by the gravity is 0.072 J.

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The measurement of length and time is calculated the average speed with the expression

         [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]

Average velocity is defined as the change in displacement between the interval time

      [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]

where [tex]v_{avg}[/tex] is the average velocity, Δx is the displacement in the interval, and Δt the time.

To carry out this measurement, it must be taken into account that the velocity is a vector, for which we define a reference system, it can be a vertical axis with the upward direction as positive, therefore the downward displacement is negative.

A tape measure is placed and the interval during which the scalar distance measurement is performed is defined, the most as is to use time as an independent variable (controlled by the researcher) that is measured with a stopwatch.

The displacement is measured for each given time interval and these two quantities are divided. The sign of the velocity is negative because it goes down

Using the measurements of length and time, the average velocity is calculated with the expression

         [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]t

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Answer:

i think the answer is solar,

Explanation:

because it is a natural resource im sorry if im wrong

Answer:

C. backhand stroke

Explanation:

Your hand will be rotated counterclockwise about a fourth of the racquet handle during this stroke. The correct response is to backhand stroke. Option C is correct.

When playing tennis, a backhand is a stroke in which the player's torso is crossed and the ball is struck with the palm towards the opponent's chest and the back of the hand traveling toward them.

A backhand in tennis can be made with one or both hands.

With this stroke, your hand will be turned about a quarter circle counter-clockwise on the handle of your racquet. Backhand stroke is the right answer.

Hence. option C is correct.

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Answer:

what are the answers to select? or do you just say them

Explanation:

???

Answer:

c and d

Explanation:

Answer: the answer is d

Explanation:

Answer:

not change, decrease

Explanation:

Torque refers to the measure of the force that enables an object to rotate about an axis.

An old-fashioned tire swing exerts a force on the branch and a torque about the point where the branch meets the trunk. If you hang the swing closer to the trunk, this will not change the force and decrease the torque.

A tire swing when old can have aa small force. An old-fashioned tire swing exerts a force on the branch and a torque about the point where the branch meets the trunk. If you hang the swing closer to the trunk, this will not change, the force and decrease the torque.

IT also state that when the net force is zero,  but the net torque is not  zero, the object is will not be in static equilibrium

For one too be able to change angular momentum, a torque must act on it over some timeframe.

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Answer:

.....

Explanation:

Answer:

An antimony can form 3 bonds

Let me know if this helps

Thanks!

:)

Explanation:

Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.

Answer:

C) radio → infrared → ultraviolet → gamma

Explanation:

It Increases left to right therefore it decreases right to left

Answer:

a) [tex] v_{0y} = 9.72 m/s [/tex]

b) [tex] v_{0x} = 20.85 m/s [/tex]

c) [tex] t = 2.01 s [/tex]

d) [tex] h_{max} = 4.82 m [/tex]

Explanation:

a) The initial vertical velocity is given by:

[tex] v_{0y} = v*sin(\theta) [/tex]

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

[tex] v_{0y} = 23 m/s*sin(25) = 9.72 m/s [/tex]

b) The initial horizontal velocity can be calculated as follows:

[tex] v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s [/tex]

c) The flight time can be calculated using the following equation:

[tex] v_{0x} = \frac{x}{t} [/tex]

Where:

x: is the total distance = 42 m

[tex] t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s [/tex]

d) The maximum height is given by:

[tex] v_{fy}^{2} = v_{0y}^{2} - 2gh_{max} [/tex]

Where:

[tex] v_{fy}[/tex]: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

[tex]h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m[/tex]

I hope it helps you!                                  

Answer:

A mixture is when two or more substances combine physically together.

However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.

Explanation:

Answer:

Im going to take an educated guess and say its B.

Explanation:

A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.

When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.

Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

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Answer:

A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun

Answer:

Electromagnetic Induction by a Moving Magnet

Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.

Explanation:

Answer:

35, I got you bro, i got you

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]   (1)  

Where:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]

[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]

[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

Answer:

Vertical velocity = 8.28 m/s

Horizontal velocity = 28.3 m/s

__________________________________________________________

We are Given:

Initial velocity of the ball = 40 m/s

Angle of elevation of the ball = 45°

Time interval = 2 seconds

__________________________________________________________

Vertical and Horizontal Components:

Vertical Component:

The vertical component of the ball can also be written as:

40*Sin(45°)

40*(1/√2)                                                          [since Sin(45°) = 1/√2]

40/√2 m/s

Horizontal Component:

The horizontal component of the ball can also be written as:

40*Cos(45°)

40*(1/√2)                                               [Since Cos(45°) = 1/√2]

40/√2 m/s

__________________________________________________________

Speed of the Ball after 2 seconds:

Horizontal Velocity:

Since the horizontal velocity is not affected by any force during the flight, the horizontal velocity after 2 seconds will also be 40/√2 m/s

Since √2 = 1.41:

Horizontal velocity = 28.3 m/s

Vertical Velocity:

v = u + at                            [First equation of motion]

v = 40/√2 + (-10)(2)          

[g is negative because it is acting against the direction of motion]

v = 40/√2 - 20

v = [tex]\frac{40-20\sqrt{2} }{\sqrt{2} }[/tex]                          [taking the LCM]

v = 8.28 m/s                    [√2 = 1.41]

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]

Answer:

m = 0.5

Explanation:

Given that,

The length of the blade of scissors = 5 cm

The length of the handle = 2.5 cm

Here, effort arm is 2.5 cm and load arm is 5 cm. The mechanical advantage is the ratio of effort arm to the load arm as follows :

[tex]m=\dfrac{2.5}{5}\\\\m=0.5[/tex]

So, the ideal mechanical advantage of a pair of scissors is 0.5.

Answer:

The answer is the 4th one

Explanation:

Good luck man

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation;

[tex]a = \frac{6 - 0}{6}[/tex]

[tex]a = \frac{6}{6}[/tex]

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(6) + \frac {1}{2}*1*(6)^{2}[/tex]

[tex] S = 0 + \frac {1}{2}*1*36[/tex]

[tex] S = 0.5 *36[/tex]

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex]Distance, S = speed * time[/tex]

Substituting into the above equation;

[tex]Distance, S = 6 * 5[/tex]

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.