When solving equations, if I subtract 5 on the right side of the equation do I have to subtract 5 on the left side of the equation?

Answer:

common difference = 4

Step-by-step explanation:

common difference is the difference between the successive term and its preceding term.

let's take the successive term of -20 that is - 16

common difference (d) = successive term - preceeding term

= -16 -(-20)

= -16 + 20

= 4

if we take the successive term of -16 that is -12

we'll get the same common difference.

d = -12 -(-16)

d = -12 + 16

d = 4

this means that the common difference for an AP remains constant.

Answer:

[tex]\frac{4}{9}[/tex]

Step-by-step explanation:

The equation would be

[tex]\frac{1}{3} +\frac{1}{9} =total[/tex]

First, change the denominator to a common multiple.

The LCM (least common multiple) of 3 and 9 is 9.

[tex]\frac{3}{9} +\frac{1}{9} =total[/tex]

Add to solve.

[tex]\frac{4}{9}[/tex]

I hope this helps!

Answer:

4/9

Step-by-step explanation:

We need to add the amounts together

1/3 + 1/9

Getting a common denominator

1/3 *3/3   + 1/9

3/9 + 1/9

4/9

Answer:

8/10

Step-by-step explanation:

 The distance of B from the boat is 8.99 miles

To calculate  the distance of the the boat from B we use cosine rule.

Cosine rule is a formula use to find one side of a triangle if two sides and an angle is given.

Cosine rule formula can be stated as

From the question,

⇒ Given:

⇒ Substitute these values into equation 1 and solve for R

Hence, the distance of B from the boat is 8.99 miles.

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Answer:

speed is 2t - 5

velocity is 2t - 5

a = 2 m/s²

Step-by-step explanation:

Given the position of a particle expressed as:

s(t) = t^2 - 5t + 1

speed v = ds/dt

ds/dt = 2t - 5

Hence the speed is 2t - 5

velocity can also  be expressed as the speed, hence, velocity is 2t - 5

Acceleration is the change in velocity with respect to time. Hence;

a = dv/dt

a = 2 m/s²

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

[tex]h(x) = -\frac{1}{3}x^2 + 4[/tex] --- [tex]x \ne 2[/tex]

[tex]h(x) = -4[/tex] --- [tex]x= 2[/tex]

Required

[tex]h(-5)\ \&\ h(2)[/tex]

Calculating h(-5)

This implies that: x = -5

[tex]-5 \ne 2[/tex]

So, we make use of:

[tex]h(x) = -\frac{1}{3}x^2 + 4[/tex]

Substitute -5 for x

[tex]h(-5) = -\frac{1}{3} * (-5)^2 + 4[/tex]

[tex]h(-5) = -\frac{1}{3} * 25 + 4[/tex]

[tex]h(-5) = -\frac{25}{3} + 4[/tex]

Take LCM

[tex]h(-5) = \frac{-25+12}{3}[/tex]

[tex]h(-5) = -\frac{13}{3}[/tex]

Calculating h(2)

This implies that: x = 2

[tex]2 = 2[/tex]

So, we make use of:

[tex]h(x) = -4[/tex]

Substitute 2 for x

[tex]h(2) = -4[/tex]

Use the above explanation to answer your question

Answer:

4th option and 3rd option

Step-by-step explanation:

Using the recursive rule and a₁ = 7 , then

a₂ = 3a₁ - 6 = (3 × 7) - 6 = 21 - 6 = 15

a₃ = 3a₂ - 6 = (3 × 15) - 6 = 45 - 6 = 39

a₄ = 3a₃ - 6 = (3 × 39) - 6 = 117 - 6 = 111

a₅ = 3a₄ - 6 = (3 × 111) - 6 = 333 - 6 = 327

The first 5 terms are 7, 15, 39, 111, 327

---------------------------------------------------------------------

Similarly using the recursive rule and a₁ = 9

a₂ = 3a₁ + 3 = (3 × 9) + 3 = 27 + 3 = 30

a₃ = 3a₂ + 3 = (3 × 30) + 3 = 90 + 3 = 93

a₄ = 3a₃ + 3 = (3 × 93) + 3 = 279 + 3 = 282

a₅ = 3a₄ + 3 = (3 × 282) + 3 = 846 + 3 = 849

The first 5 terms are 9, 30, 93, 282, 849

Answer:

f(g(x)) = 9x^2 +12x -1

Step-by-step explanation:

f(g(x)) means you replace the x in f(x) with g(x), which is 3x + 1:

(3x+1)^2 + 2(3x+1) - 4

then expand and simplify:

(3x+1)(3x+1) + 6x+2 - 4

9x^2+6x+1 + 6x+2 - 4

and then collect all like terms:

9x^2

6x + 6x = 12x

1 + 2 - 4 = -1

Answer:

Step-by-step explanation:

Let the smaller number = x

Let the larger number = x + 1

5*(x + 1) = 59

You can do this. The problem says that when the larger number is multiplied by 5, you get 59. You are also told that the numbers are whole numbers. 59 divided by 5 leaves a remainder which is not a whole number.

Answer:

The height is 0.014

Step-by-step explanation:

Use the formula, V=πr2h

h=V

πr2=13

π·172≈0.014

Answer:

write your question properly

Step-by-step explanation:

Answer:

D. Closed circle on 8, shading to the right.

Answer:

x = - 3, y = 2

Step-by-step explanation:

Given the 2 equations

y = x + 5 → (1)

y = - 2x - 4 → (2)

Substitute y = x + 5 into (2)

x + 5 = - 2x - 4 ( add 2x to both sides )

3x + 5 = - 4 ( subtract 5 from both sides )

3x = - 9 ( divide both sides by 3 )

x = - 3

Substitute x = - 3 into either of the 2 equations and evaluate for y

Substituting into (1)

y = - 3 + 5 = 2

Answer: -3x+y=-4

Step-by-step explanation:

Standard form is Ax+By=C. In y=Mx+b form, it would be y=3x-4. To put it into standard form you subtract 3x from both sides. So then you have -3x+y=-4.

Answer: B. 4 × 10⁻⁵

Step-by-step explanation:

0.00003762 = 3.762 × 10⁻⁵ ≈ 4 × 10⁻⁵

Answer:

b

Step-by-step explanation:

[tex]4 \times {10}^{ - 5} = 4 \times \frac{1}{100000} [/tex]

Answer:

6 + 12/13, or 90/13 people will be served

Step-by-step explanation:

Ratios stay the same, no matter the quantity.

Given this, we can say that (13 grapes / 3 people) = (30 grapes / x amount of people)

13/3 = 30 / x

multiply both sides by 3 to remove a denominator

13 = 30 * 3 /x

multiply both sides by x to remove the other denonimator

13 * x = 30 * 3

13 * x = 90

divide both sides by 13 to isolate the x

x = 90/13 = 6 + 12/13 ≈6.92 people

Answer:

4

Step-by-step explanation:

6(6+x) = 5(5+x+3)

36+6x = 25+5x+15

6x-5x=40-36

x=4

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

See this attachment

Answer:

⊥

Step-by-step explanation:

d and b meet at a 90 degree angle ( as shown by the box)

The lines are perpendicular (⊥)

Answer:

180m cubed

Step-by-step explanation:

Multiply the length, width, and height together: 6×6×5=180

Answer:

Formula of a rectangular prism:

L x W x H

Now we place in the numbers and solve:

5 x 6 x 6 = 180 m3

Answer:

The speed is 20.8  m/s

Step-by-step explanation:

If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory

Let the maximum height is h and initial velocity is u.

From first equation of motion

v = u + at

0 = u - g x 3

u = 3 g.....(1)

Use third equation of motion

[tex]v^2 = u^2 - 2 gh \\\\0 = 9 g^2 - 2 gh \\\\h = 4.5 g[/tex]

Let the speed at half the height is v'.

[tex]v^2 = u^2 + 2 gh \\\\v'^2 = 0 + 2 g\times 2.25 g\\\\v'^2 = 4.5\times 9.8\times9.8\\\\v' = 20.8 m/s[/tex]

Answer:

Option B

<F = 26°

<D = 64.01°

FD = 89

Answered by GAUTHMATH

For right triangle EFD,  m ∠F ≈ 26°, m ∠D ≈ 64.01° and FD = 89

The correct answer is an option (B)

It is the longest side of the right triangle.

For a right triangle,

[tex]a^{2}+ b^{2} = c^{2}[/tex], where c is hypotenuse and a, b area other two sides of the right triangle

For given example,

We have been given a right triangle EFD with hypotenuse FD.

Also, EF = 80, ED = 39

Using the Pythagoras theorem,

[tex]\Rightarrow FD^{2}= EF^{2} + ED^{2}\\\\ \Rightarrow FD^{2}= 80^{2} + 39^{2}\\\\ \Rightarrow FD^2 = 6400 + 1521\\\\ \Rightarrow FD^2 = 7921\\\\\Rightarrow FD = 89[/tex]

Consider, sin(F)

[tex]\Rightarrow sin(F)=\frac{ED}{FD} \\\\\Rightarrow sin(F)=\frac{39}{89}\\\\ \Rightarrow sin(F)=0.4382\\\\\Rightarrow \angle F=sin^{-1}(0.4382)\\\\\Rightarrow \angle F=25.98^{\circ}\\\\\Rightarrow \angle F\approx 26^{\circ}[/tex]

Now, consider sin(D)

[tex]\Rightarrow sin(D)=\frac{FE}{FD}\\\\ \Rightarrow sin(D)=\frac{80}{89}\\\\ \Rightarrow \angle D = sin^{-1}(0.8988)\\\\\Rightarrow \angle D = 64.009^{\circ}\\\\\Rightarrow \angle D \approx 64.01^{\circ}[/tex]

Therefore, for right triangle EFD,  m ∠F ≈ 26°, m ∠D ≈ 64.01° and FD = 89

The correct answer is an option (B)

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Answer:

Step-by-step explanation:

Answer:

X=20

a< = 125

Step-by-step explanation:

Answer:

C -2,-1

Step-by-step explanation:

I pulled up a graph of a circle. -2, -1 is outside the circle

Answer:

g(f(2)) = 41

b)41

Step-by-step explanation:

g(f(2)) = 41

f(2)= 2(2²) + 5 = 13

So g(f(2)) → g(n = 13)

g(n = 13)→ 3(13) + 2 = 41

Answer:

(r - c)(4), is the profit made in George's new store after 4 months which is $4,500

Step-by-step explanation:

The given parameters for George's store are;

The amount of revenue George makes each month, r(x) = x² + 6·x + 10

The expenses each month, c(x) = x² - 4·x + 5

Where;

x = The number of months the store has opened the doors

r(x) and c(x) are measured in hundreds of dollars

The amount of profit from the store, P = Revenue - Expenses

Therefore, the profit made on a given month, x, is P(x), which is found as follows;

P(x) = r(x) - c(x) = (r - c)(x)

Therefore, (r - c)(4) = P(4), is the profit realized from George's new store, after 4 months

(r - c)(4) = 4² + 6·4 + 10 - (4² - 4·4 + 5) = 45

Answer:

The new store will have a profit of $4500 after its fourth month in business.

Step-by-step explanation:

I took the quiz

Answer:

hope this helps you

have a great day