When iron(III) oxide (Fe2O3) is exposed to carbon monoxide (CO) under high pressure, metallic iron (Fe) and carbon dioxide (CO2) are produced. Write and balance the reaction equation

When Iron(III) Oxide (Fe2O3) Is Exposed To Carbon Monoxide (CO) Under High Pressure, Metallic Iron (Fe)

Answers

Answer 1

Answer:

The equation is Fe₂O₃ + CO ⇒ Fe + CO₂.

The balanced reaction equation is Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂.

Explanation:

First, we have to write our equation. It's actually pretty straightforward - first we look for our reactants (looks like it's Fe₂O₃ and CO), then we look for our products (Fe and CO₂). Then, we have to balance it so that both sides have the same number of both element.

Currently, we have the equation Fe₂O₃ + CO ⇒ Fe + CO₂. There are 2 Fe atoms, 4 O atoms, and 1 C atom on the left side. There is 1 Fe atom, 2 O atoms, and 1 C atom on the right side.

First thing we can do is give our Fe on the right side a coefficient of 2. This will make it equivalent to the 2 Fe atoms on the left side:

Fe₂O₃ + CO ⇒ 2Fe + CO₂

Next, we need to make sure that we have the same number of C and O atoms on each side. This takes a little bit of thinking, but what we have to do is give CO a coefficient of 3 and CO₂ a coefficient of 3. This gives us 6 O atoms on the left side (when we include the O₃) and 6 O atoms on the right side (since there are 3 O₂ atoms and 3 times 2 is 6). Here's what that looks like:

Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂

And that's how I balanced the equation. It can be confusing, but with enough practice, it will get easier and easier. :)


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In order to complete a reaction, a chemist needs to react 4 moles of aluminum atoms with 3 moles of oxygen molecules. How many grams of aluminum would be required to make this happen?

Answers

Answer:

4 Al + 3 O2 → 2 Al2O3

To react with 4 moles of Al, (3×32) g oxygen is required.

So, to react with 2.4 moles of Al, {(3×32)/4} × 2.4 = 57.6 g oxygen is required.

Hope this helps.

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Answers

Since 1 calories is 4.1858 Joules, 86.5kJ is 86.5 x (1/4.1858) = 20.66510583 kCal = 20.7 kCal (3 s.f)

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The formation of aluminum chloride can be described by the balanced chemical equation. 2Al+3Cl2⟶2AlCl3 How many moles of Cl2 molecules are required to react with 3.90 mol Al atoms? moles of Cl2 required

Answers

moles(AL)/moles(CL2) = 2/3

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Sắp xếp 4 axit sau theo thứ tự tính axit tăng dần:
CH3-CH2-CH2-COOH (1), CH3-CH2-CHCl-COOH (2)
CH3-CHCl-CH2-COOH (3), CH2Cl-CH2-CH2-COOH (4

Answers

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An initial solution of orange juice has a solute concentration of 0.50 M and a volume of 155.0 mL. What is the final solute concentration of the juice after its been diluted with 52.5mL of water?

Answers

Answer:

0.37 M

Explanation:

An initial solution of orange juice has a solute concentration of 0.50 M and a volume of 155.0 mL. What is the final solute concentration of the juice after its been diluted with 52.5mL of water?

the old molarity was 0.50 M, and a volume of 1555.0 ml

the new volume is a total of 155.0 ml + 52.5 ml =207.5 ml

so the new molarity is (155.0/207.5) X 0.50 M = 0.37 M

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Answers

Answer:

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Explanation:

How many peaks will you observe in the 13C spectrum of cyclohexane ?
1 1 - incorrect
3
6

Answers

3 peaks

Explanation:

You can do this perfectly well without referring to chemical shift tables at all. In the spectrum there are a total of three peaks - that means that there are only three different environments for the carbons, despite there being four carbon atoms.

A \pu{1.60 g}1.60 g1, point, 60, space, g calcium supplement contains 37.8\%37.8%37, point, 8, percent \ce{Ca}CaC, a by mass. The calcium is present in the supplement as \ce{CaCO3}(s)CaCOX 3 ​ (s) (molar mass \pu{100.09 g/mol}100.09 g/mol100, point, 09, space, g, slash, m, o, l). How many grams of \ce{CaCO3}(s)CaCOX 3 ​ (s) are in the calcium supplement?

Answers

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

We want to calculate the mass of CaCO₃ in a 1.60 g supplement. We need to consider the following relationships.

The mass percent of Ca is 37.8%, that is, there are 37.8 g of Ca every 100 g of supplement.The molar mass of Ca is 40.08 g/mol.The molar ratio of Ca to CaCO₃ is 1:1.The molar mass of CaCO₃ is 100.09 g/mol.

[tex]1.60gSup \times \frac{37.8gCa}{100gSup} \times \frac{1molCa}{40.08gCa} \times \frac{1molCaCO_3}{1molCa} \times \frac{100.09gCaCO_3}{1molCaCO_3} = 1.51gCaCO_3[/tex]

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

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A 1.60 g calcium supplement contains 37.8% Ca by mass. The calcium is present in the supplement as CaCO₃(s) (molar mass 100.09 g/mol). How many grams of CaCO₃(s) are in the calcium supplement?

Given: 800 mL of 2.5 M NaCl. Find grams of NaCl needed

Answers

Answer:

Answer: molar mass of NaCl is 58.5 gm/mol. This refers to the fact that 1 mole of NaCl weighs 58.5 gram.

Explanation:

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).
2Mg + 0 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

Answers

Answer:

x=403/24,3 = 16.58 gm MgO

EXPLANATION

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO)

2Mg + 0 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

Oxygen exist in nature as O2, diatomic.

so

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).

2Mg + 02 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

2 moles of Mg produce 2 moles of MgO

1 mole of Mg weighs 24.3 and produces 1 mole of MgO

Mg HAS AN ATOMIC MASS OF 24.3

Mg HAS A MOLAR MASS OF 24.3 +16 = 40.3gm/mole

so 24.3 gm of Mg produce 40.3 gm MgO

set up the ratio

10 gm Mg/x of MgO  = 24.3/40.3

or

10/x = 24.3/40.3

cross multiply and isolate x (use Algebra I)

24.3x =403

x=403/24,3 = 16.58 gm MgO

Identify the reactant that gets oxidized in the following reaction.

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A) Ag in AgNO₃
B) I in CaI₂
C) N in AgNO₃
D) Ca in CaI₂
E) This is not an oxidation/reduction type of reaction

Answers

Answer:

E) This is not an Oxidation/ Reduction type of reaction

Explanation:

Oxidation involves the loss of electrons while reduction involves the addition of electrons. None of the elements change their oxidation number in the reaction, so this is not an oxidation/reduction type of reaction.

The addition of oxygen and the removal is electrons is called oxidation. In a reaction that has both the process is called the redox reactions.

The correct answer to the question is option E

In this reaction, not any elements have the loose and gain the electrons in order to tell the oxidation and reduction.

This reaction is a neutralization reaction.

Hence, the correct answer is E that is not an oxidation/reduction type of reaction.

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jkhjkhjkh

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Answer:

seriously ....,........

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Answers

Answer:

The atomic mass of radon is 222.

Explanation:

. That means that one mole of radon weighs 222 grams (222 grams/moles). We can therefore make the following equation:

Grams × (1/222) = Moles of Radon

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Answers

Nuclear Fission

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Nuclear fission is a process where the nucleus of an atom is split into two or more smaller nuclei, known as fission products. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

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Explanation:

Select all the correct answers.

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B. Planets with a greater diameter have longer days.
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Discussion;

The lattice energy of an ionic compound is a measure of the strength of the bond in the compound.

The lattice energy is Inversely proportional to the distance of the atoms apart.

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D. The total volume of the objects

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Answer:

A and C

Explanation:

I took the test

The distance between the objects' centers and The amount of matter in the objects are two characteristics determine the strength of the gravitational force between two objects.

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All objects with mass or energy are attracted to one another by gravity, which is a fundamental interaction.

The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions.

As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.

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Answers

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Answers

1 g/cm3 to kg/m3 = 1000 kg/m3

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giving brainly for correct answer! :)

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Answer:

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