Answer:
Option A : 135°Step-by-step explanation:
If the table and ground are to be parallel then,
45° + x = 180° [Co-interior angles]
=> x = 180 - 45
=> x = 135° (Ans) (Option A)
Isosceles trapezoid EFGH has area 80 cm ^2, height 20 cm and legs 22 cm. One of the bases is 5 cm. How long is the remaining base ?
Answer:
3
Step-by-step explanation:
A = [tex]\frac{base1 + base2}{2}[/tex] x h Formula
[tex]\frac{base1 + 5}{2}[/tex] x 20 = 80 Substitution
[tex]\frac{base1 + 5}{2}[/tex] = 4 Work (divide by 20, multiply by 2, subtract 5)
base1 + 5 = 8
base1 = 3 Solution
I don’t know how to do this can someone help?
Answer:
Why your question is not visible
Your photo is black screen
Step-by-step explanation:
Please Mark me brainliest
Which correlation is most likely a causation?
the positive correlation between the sales of apples and sales of oranges at a farmer’s market
the positive correlation between the number of crimes in a city and the number of cars in the city
the positive correlation between the height of a person and the number of times a person bumps their head on a low ceiling
the positive correlation between the number of socks and number of shoes in a home
Answer:
The positive correlation between the number of socks and the number of shoes in home
Step-by-step explanation:
Nah i just get an example so that i can get clue,if my answer is wrong sorry in advanced
Helpppp please
Find the volume of this object.
Use 3 for pi
Answer:
The sphere
[tex]v=\frac{4}{3} \pi r^{3}=\frac{4}{3}*3.14 *2^{3}=\frac{4*3.14*8}{3}=\frac{100.48}{3}=33.493[/tex]
The cylinder
[tex]v=\pi r^{2} h=3.14*(\frac{4}{2} )^{2}*3=3.14*2^{2}*3=9.42*4=37.68[/tex]
Add those two volumes together:
[tex]33.493 + 37.68 = 71.173 in^{3}[/tex]
solve for y
[tex]2y - 3 = \sqrt{ {3y}^{2} - 10y + 12} [/tex]
absurd answers will be reported!!
Answer:
y = 3
Step-by-step explanation:
2y - 3 = [tex]\sqrt{3y^2-10y+12}[/tex]
square both sides to remove sqrt bracket
(2y - 3)^2 = ( [tex]\sqrt{3y^2-10y+12}[/tex] )^2
simplify both sides
(2y - 3)(2y - 3) = [tex]3y^2[/tex] - 10y + 12
[tex]4y^2[/tex] - 12y + 9 = [tex]3y^2[/tex] - 10y + 12
bring all value to left side
[tex]y^2[/tex] - 2y - 3 = 0
factor
(y - 3)(y + 1)
solve for y
y = 3, y = -1
When plugged back into the equation, only y = 3 is true
Answer:
y = 3
Step-by-step explanation :
[tex]2y - 3 = \sqrt{ 3y² - 10y + 12} [/tex]
Swap the sides both of the equation.
[tex]\sqrt{ 3y² - 10y + 12} = 2y - 3 [/tex]
To remove the brackets of equations square both side and simplify .
3y² - 10y + 12 = 4y² - 12y + 9
Move the expression to left-hand side and change its sign.
3y² - 10y + 12 - 4y² + 12y - 9 = 0
collect like terms
3y² - 4y² - 10y + 12y + 12 - 9 = 0
-y² + 2y + 3 = 0
Change the sign of expression. because it helps to solve.
y² - 2y - 3 = 0
Splits the term -2y
y² + y -3y - 3 = 0
Factor out y from the first pair and -3 from second pair of expression.
y ( y + 1 ) - 3 ( y + 1) = 0
Factor out y + 1 from the expression.
( y + 1 ) ( y - 3 ). = 0
When product and factors equals 0. at least one factor is 0.
y + 1 =0
y - 3 = 0
Solve for y
y = -1 and y = 3
If we plug the 3 as y in the expression we find that y = 3 is the true solution of this expression.
This equation has one solution which is y = 3.
Given f(x) = 1 - 2x with the range {-3, -5, -7 }, find the domain.
Answer:
{2,3,4}
Step-by-step explanation:
The range are simply the f(x) values
The range are the x values
To get the x values, we simply get x from each f(x)
So we have;
1-2x = -3
1+ 3 = 2x
2x = 4
x = 4/2
x = 2
Secondly;
1-2x = -5
1 + 5 = 2x
2x = 6
x = 6/2
x = 3
lastly;
1-2x = -7
1 + 7 = 2x
2x = 8
x = 8/2
x = 4
So the domain values are;
{2,3,4}
If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expression in the parabola's equation?
Answer:
[tex]y=a(x-h)^{2} +k[/tex]
[tex](x,y)=(-3,14)[/tex]
[tex](h,k)=(-4,6)[/tex]
[tex]14=a(-3-(-4))^{2})+6[/tex]
[tex]14=a(-3+4)^{2} +6[/tex]
[tex]14=a(1)^{2} +6,-6[/tex]
[tex]8=a[/tex]
[tex]ANSWER:8[/tex]
--------------------------
HOPE IT HELPS
HAVE A GREAT DAY!!
Solve for x. Round to the nearest tenth, if necessary.
The measurement of the angle K is 3x - 42, and it is obtuse. Find the restriction(s) on the values of x.
Answer:
x = 44° and 74°: x cannot be less than 44°, x cannot be greater than 74°.
Step-by-step explanation:
Obtuse angles are greater than 90° but less than 180°.
We can first solve for the lower bound of x.
[tex]3x-42=90[/tex][tex]3x=132\\[/tex][tex]x=44[/tex]°Thus the lower bound restriction of x is 44°
We can now solve for the upper bound of x.
[tex]3x-42=180[/tex][tex]3x=222[/tex][tex]x=74[/tex]°Thus the upper bound restriction of x is 74°
find the area of the triangle
What is the length of a diagonal of a square with a side length of 6?
A. 3
B. V
C. 3.12
D. 6
I need help ASAP please help! I have to choose between 4 graphs
Answer:
Step-by-step explanation:
This is a sideways cubic translated down 2 units. The graph shown is the sideways cubic translated up 2. So locate the graph that looks like this but has its "squiggly part" at -2 instead of 2.
Using the digits 0, 1, 2, ...8, 9, determine how many 4-digit numbers can be constructed according to the following criteria.
The number must be odd and greater than 6,000; digits may be repeated.
The number of 4-digit numbers that can be constructed is
Answer:
2000
Step-by-step explanation:
Since the number must be odd, it can have either 1, 3, 5, 7 or 9 in its one's place.
With a 4-digit number starting with 6, any of these digits can be in the one's place and it will still be greater than 6,000.
For the one's place, since we can choose from 5 digits, we have ⁵P₁. In the thousands place, we have one digit which is 6. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively.
So, the total number of 4 digit odd numbers greater than 6000 starting with 6 are 1 × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 1 × 10 × 10 × 5 = 500 numbers.
For the thousands place, we are left with the digits 7, 8 and 9. So, to arrange these 3 digits in the thousands place, we have ³P₁. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively. For the one's place, since we can choose from 5 digits, we have ⁵P₁.
So, the total number of 4 digit odd numbers greater than 6000 starting with 7, 8 or 9 are ³P₁ × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 3 × 10 × 10 × 5 = 1500 numbers.
So, the total number of 4-digit numbers greater than 6000 that can be constructed is 500 + 1500 = 2000 numbers.
Carina spent a total of $5.27 buying a pineapple for $3.40 and some tomatoes that were on sale for $0.85 per pound
what's the whole question??
calculate the exact value of 1 1/3- 3 5/6+ 5 1/9
[tex]\displaystyle\bf 1\frac{1}{3} -3\frac{5}{6} +5\frac{1}{9} =5+1-3+\frac{1^{/6}}{3} +\frac{1^{/2}}{9} -\frac{5^{/3}}{6}\\\\\\\ =3+\frac{6+2-15}{18} =3-\frac{7}{18}=\boxed{2\frac{11}{18} }[/tex]
. Out of 140 students, 50 passed in English and 20 passed in both Nepali and English. The number of students who passed in Nepali is twice the number of students who passed in English. Using a Venn-diagram, find the number of students who passed in Nepali only and who didn't pass in both subjects.
Answer:
80 ;
10
Step-by-step explanation:
Given :
Total number of students = μ = 140
Let :
Number of students who passed in English = E
Number of students who passed in Nepali = N
n(NnE) = 20
n(E) only = n(E) - n(NnE) = 50 - 20 = 30
Students who passed English only = 30
Number of students who passed in Nepali is twice the number who passed in English
n(N) = 2 * n(E) = 2 * 50 = 100
Number of students who passed in Nepali only
n(N) only = n(N) - n(NnE) = 100 - 20 = 80
Students who passed Nepali only = 80
The number who didn't pass both subjects :
μ - (English only + Nepali only + English and Nepali)
140 - (30 + 80 + 20)
140 - 130
= 10
Can someone help me with this math homework please!
Answer:
The vertical line test can be used to determine whether a graph represents a function.
If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.
Someone tell me where everyone is going right please !!
9514 1404 393
Explanation:
The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.
t will not be negative because time moves forward. Here, we're only counting time after Riko leaves the house. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*
_____
* One might argue that Riko is behind Yuto for all values of time after Yuto leaves the house, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.
Answer:
again again again hello or merhaba(hello)
speed = path / time
so we can say this;
speed × time = path
note;
two speeds in different directions add up
and
two speeds in the same direction subtract
our speeds are in the same direction so we subtract
0.35 - 0.25 = 0.10 speed
and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico
when will they be in the same place now?
Let's solve with the formul;speed × time = path
0.10 × time = 5.25 miles
in this equation we find the time 52.5 minutes
After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind Yuto
When Riko was behind Yuto;0≤ t ≤ 52,5 ( this is our equation of time)
now the second question?Why can't t be less than 0?because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative value
GOOD LUCK :D
Step-by-step explanation:
greetings from Turkey (≧▽≦)
Write an equation for a quadratic function in factored form with
zeros at x = -4 and x = 0 that passes through the point (-3,6).
Answer:
[tex]f(x)=-2x(x+4)[/tex]
Step-by-step explanation:
We want to find the equation of a quadratic function in factored form with zeros at x = -4 and x = 0 that passes through the point (-3, 6).
The factored form of a quadratic is given by:
[tex]f(x)=a(x-p)(x-q)[/tex]
Where p and q are the zeros and a is the leading coefficient.
Since we have zeros at x = -4 and x = 0, let p = -4 and q = 0. Substitute:
[tex]f(x)=a(x-(-4))(x-0)[/tex]
Simplify:
[tex]f(x)=ax(x+4)[/tex]
And since we know that the function passes through the point (-3, 6), f(x) = 6 when x = -3. Thus:
[tex](6)=a(-3)(-3+4)[/tex]
Simplify:
[tex]6=a(-3)(1)[/tex]
Thus:
[tex]-3a=6\Rightarrow a=-2[/tex]
So, our quadratic function is:
[tex]f(x)=-2x(x+4)[/tex]
which shows the numbers 1/10, 0.9, 3/10 in order from least to greatest
Answer:
1/10, 0.9, 3/10
Step-by-step explanation:
#carryonlearning
Can someone help me with this math homework please!
Answer:
11.2
Step-by-step explanation:
[tex]p =\frac{160.16}{14.3}=\frac{160.16*10}{14.3*10}\\\\p = \frac{1601.6}{143}\\\\[/tex]
p = 11.2
Answer:
The person above me is correct I just did the work and I got the same answer as them :)
Step-by-step explanation:
It has been reported that the average credit card debt for college seniors is $3262. The student senate at a large university feels that their seniors have a debt much less than this, so it conducts a study of 50 randomly selected seniors and finds that the average debt is $2995, and the population standard deviation is $1100. At α = 0.05, is the student senate correct? a) State the hypotheses and identify the claim with the correct hypothesis
Answer:
Following are the solution to the given point:
Step-by-step explanation:
The formulated null hypothesis would be that the reported average do not differ significantly
[tex]H_o : \mu = \$3262\\\\H_a : \mu < \$3262 \ \text{(One tailed test)}[/tex]
Identify the equivalent expressions of 4(2x + x – 3) – 3x + 3.
Answer:
9x - 9
Step-by-step explanation:
4(2x + x - 3) - 3x + 3
Simplify the expression, combine like terms in the parenthesis,
4(3x - 3) - 3x + 3
Distribute, multiply every term inside the parenthesis by the number outside of it;
(4)(3x) + (4)(-3) - 3x + 3
Simplify,
12x - 12 - 3x + 3
Combine like terms,
12x - 12 - 3x + 3
9x - 12 + 3
9x - 9
HURRY NEED ASAP TRYNA FINISH SUMMER SCHOOL LOL, I WILL MARK BRAINLIEST :)) PICTURE IS THERE FOR U
Answer:
B.
Step-by-step explanation:
Since the numbers in the root is all the same, lets say [tex]\sqrt{2}[/tex] is a variable.
7x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex]
Group with like terms:
7x[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]
Combine like terms:
8x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]
There you have it! Since all the square roots are the same thing, we can treat them like variables.
the answer is B..................
Express tan J as a fraction in simplest terms
Answer:
SOH-CAH-TOA
tan = opposite/adjacent
tan J = 15/20 = 3/4
Step-by-step explanation:
Can anyone help with this
Step-by-step explanation:
I solved it in the diagram
a) y=4.9x
b)y=63.7
c)x=13
SOMEONE PLEASE HELP ME! IM SO CONFUSED, NEED THIS VERY BADLY!
Answer:
115°
Step-by-step explanation:
in a parallelogram vertically opposite angles are equal.
m∠MNK=m∠KLM=115°
A client has two refrigerators, one in the kitchen and one in the basement.The former is new and efficient. The latter is 30 years old and uses 120Kwh/month. If this client pays 0.15/kwh
Incomplete question: we assume figures to explain further
Answer and explanation:
Given that client pays $0.15/kwh
If old fridge is inefficient and consumes 120kwh/month
And new fridge is efficient and therefore consumes 50kwh/month
For the old fridge, client will be paying
120×0.15= $18 per month on electricity charges
For the new fridge, client will be paying
50×0.15= $7.5 per month on electricity charges
If 9^x = 81, then 3(3^x) =
A) 27
B) 3
C) 9
D) 81
E) 243
Answer:
A) 27
Step-by-step explanation:
[tex]9^{x}[/tex] = 81
x = 2
3([tex]3^{2}[/tex]) = 3(9) = 27
Please help. I don’t understand I rlly appreciate it if you help!
Hi there!
We know that the angles ∠B and ∠A are supplementary because they are both interior angles. Therefore:
180 = ∠A + ∠B
Rewrite:
180 = (6x - 48) + (4x + 38)
Combine like terms:
180 = 10x - 10
Solve for x:
190 = 10x
x = 19
Solve for ∠B by plugging in this value of x:
∠B = 4(19) + 38
∠B = 76 + 38
∠B = 114