Answer:B. Microwaves
Explanation:
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Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
What Does Tensile Force Mean?Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
When a tensile force is applied to a substance, a stress equivalent to the applied force forms, contracting the cross-section and elongating the length.
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a battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?
A battleship simultaneously fires two shells in parabolic projectile motion and no information about initial speeds at enemy ships. The ship B got hit first. So, the correct choice for answer is option (c).
Here is we have a battleship Which fires two shells simultaneously at the enemy ship along the two paths. The initial speed of projection may be same or different. See the above figure carefully, the angle of projection for ship A is more than ship B. Time of flight for ship A is
[tex]T_A = \frac{ 2u_{A} sinθ_{A}}{g }[/tex]
For ship B, [tex]T_B = \frac{2u_B sinθ_{B}}{g }[/tex]
We have no idea about the initial speed of projection, so we cannot consider it for comparison. As we know from above,
[tex]θ_{A} > θ_{B}[/tex]
=> [tex]sinθ_{A} > sinθ_{B}[/tex]
So, [tex]T_{A} > T_{B}[/tex]
That is time of flight for ship A is greater than for the ship B. Therefore, ship B gets hit first.
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Complete question:
A battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?
a) A
b) both simultaneously
c) B
d) None
Use the work energy theorem to rank the final kinetic energy of a ball based on the initial kinetic energy Ki, the magnitude of a constant force F on the ball, the displacement of the ball, d and the angle, theta between the displacement of the ball and the net force on the ball. Rank from greatest kinetic energy (1) to least kinetic energy (4).
a) Ki=150J F=10N d=15m theta=90 degrees
b) Ki=300J F=200N d=1.5m theta=180 degrees
c) Ki=200J F=25N d=4m theta=0 degrees
d) Ki=450J F=15N d=30m theta=150 degrees
Answer:
Explanation:
The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to calculate the final kinetic energy of the ball in each case.
We know that the work done by a constant force is given by the equation W = Fd cos(theta), where F is the magnitude of the force, d is the displacement of the ball, and theta is the angle between the force and displacement vectors.
Using the work-energy theorem, we can write:
W = ΔK = Kf - Ki
where ΔK is the change in kinetic energy, Kf is the final kinetic energy, and Ki is the initial kinetic energy.
We can rearrange this equation to solve for Kf:
Kf = Ki + W = Ki + Fd cos(theta)
a) Kf = 150 J + (10 N)(15 m)cos(90°) = 150 J
b) Kf = 300 J + (200 N)(1.5 m)cos(180°) = 0 J
c) Kf = 200 J + (25 N)(4 m)cos(0°) = 300 J
d) Kf = 450 J + (15 N)(30 m)cos(150°) = 112.5 J
Ranking from greatest to least final kinetic energy:
c) Ki=200J F=25N d=4m theta=0 degrees
a) Ki=150J F=10N d=15m theta=90 degrees
d) Ki=450J F=15N d=30m theta=150 degrees
b) Ki=300J F=200N d=1.5m theta=180 degrees
A uniform disk with a mass of 190 kg and a radius of 1.1 m rotates initially with an angular speed of 950 rev/min. A constant tangential force is applied at a radial distance of 0.5 m. How much work must this force do to stop the wheel? Answer in units of kJ.
Answer:
Explanation:
We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:
W = ΔK
where W is the work done, and ΔK is the change in kinetic energy.
Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:
ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s
The initial kinetic energy of the disk is:
K_initial = (1/2) I ω_initial^2
where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:
I = (1/2) m R^2
where m is the mass of the disk, and R is the radius. Substituting the given values, we get:
I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2
Therefore, the initial kinetic energy of the disk is:
K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J
To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:
τ = F r
where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:
Δω = τ / I
The work done by the applied force is:
W = ΔK = - (1/2) I Δω^2
Substituting the given values, we get:
W = - (1/2) (115.5 kg m^2) [(F r) / I]^2
The force F can be eliminated using the equation for torque:
F = τ / r = (Δω) I / r
Substituting this into the equation for work, we get:
W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2
= - (1/2) (115.5 kg m^2) (Δω / r)^2
Substituting the values for Δω and r, we get:
W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2
= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2
= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2
= - 90609 J
where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).
A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the bottom, and the car’s mass is 1,000 kg What is the power output of the car?
Answer:
the power output of the car is 29.43 kW (rounded to two decimal places).
Explanation:
To find the power output of the car, we need to use the formula:
power = work / time
where work is the change in potential energy of the car as it climbs the hill, which can be calculated using the formula:
work = force x distance
where force is the force required to lift the car against gravity, which is given by:
force = mass x gravity
where mass is the mass of the car, and gravity is the acceleration due to gravity (9.81 m/s^2).
So, the force required to lift the car against gravity is:
force = 1000 kg x 9.81 m/s^2 = 9810 N
The distance the car travels up the hill is 30 m.
Therefore, the work done by the car is:
work = force x distance = 9810 N x 30 m = 294300 J
The time taken by the car to climb the hill is 10 s.
Therefore, the power output of the car is:
power = work / time = 294300 J / 10 s = 29430 W
what are the difference between a planetary fly by and a planter orbit insertion. list 6 thing for each, find the answer for NASA.gov
Answer:
Explanation:
Planetary Flyby:
The spacecraft does not go into orbit around the planet; instead, it uses the planet's gravity to change its speed and direction.
The spacecraft's closest approach to the planet is usually brief, ranging from a few minutes to a few hours.
The spacecraft is able to capture images and data during the brief encounter with the planet.
The spacecraft's trajectory can be adjusted to perform multiple flybys of different planets or moons.
The spacecraft does not require a large amount of fuel to perform a flyby, making it a cost-effective option for exploration.
Flybys are useful for studying a planet's atmosphere, magnetic field, and gravitational field.
Planetary Orbit Insertion:
The spacecraft goes into orbit around the planet, allowing for long-term study and data collection.
The spacecraft's orbit can be adjusted to achieve different scientific objectives, such as mapping the planet's surface or studying its atmosphere.
The spacecraft must have enough fuel to slow down and enter orbit, making it a more expensive option than a flyby.
The spacecraft's orbit can be stable or elliptical, depending on the scientific objectives and mission requirements.
The spacecraft may require several trajectory adjustments to achieve the desired orbit.
Orbit insertion allows for more detailed and comprehensive study of a planet's geology, climate, and magnetic field.
A metal wire, fixed at one end, has length l and cross-sectional area A. The wire extends a distance e which mass m is hung from the other end of the wire.What is an expression for the Young Modulus E of the metal?
The expression for the Young Modulus E of the metal is E = mgl / Ae. The Young Modulus E of the metal is calculated using the equation E = (F l) / (A e2 m), where F is the force applied to the wire.
To find the expression for the Young modulus E of a metal wire with length l, cross-sectional area A, and mass m hung from the other end of the wire, we need to use the following formula:Stress (σ) = Load (F) / Area (A)Strain (ε) = Extension (Δl) / Original length (l)Young Modulus (E) = Stress (σ) / Strain (ε)We know that the metal wire is fixed at one end and the wire extends a distance e when a mass m is hung from the other end of the wire. Therefore, the extension Δl is equal to e.
Let's assume that g is the acceleration due to gravity. Therefore, the load F is equal to m * g.Substituting the values of F, A, and Δl in the above formula, we get:Stress (σ) = F / A = (m * g) / AStrain (ε) = Δl / l = e / lYoung Modulus (E) = Stress (σ) / Strain (ε)= (m * g) / (A * e / l) = mgl / AeTherefore, an expression for the Young Modulus E of the metal is E = mgl / Ae.
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125cm³ of a gas was collected at 15 °C and 755 mm of mercury pressure. Calculate the volume of the gas that will be collected at standard temperature and pressure
Answer:
119,2 см³
Explanation:
по формуле Клопейрона (P1×V1):T1=(P2×V2):T2
если из этой формулы найти V2, ответ будет равен примерно на 119,2 см³
Pete needs to be at work for 9.00am. He leaves his house at 7.30am and drives to the gym which is 12.5 miles away. Pete spends 45 minutes in the gym then drives the reaming 9 miles to work.
To determine the time Pete arrives at work, we can start by calculating the total time he spends on his commute and gym routine:
What time will Pete get to work?Time spent driving to the gym = 12.5 miles ÷ average speed
We don't know Pete's average speed, so we cannot calculate this.
Time spent in the gym = 45 minutes
Time spent driving from the gym to work = 9 miles ÷ average speed
Again, we don't know Pete's average speed, so we cannot calculate this.
Total time spent on commute and gym routine = time spent driving to gym + time spent in gym + time spent driving from gym to work
= Unknown + 45 minutes + Unknown
Next, we can convert the total time to hours and minutes:
Total time = (Unknown + 45 minutes + Unknown) ÷ 60
= (Unknown + Unknown) ÷ 60 + 45/60
= (2Unknown) ÷ 60 + 0.75
= (Unknown) ÷ 30 + 0.75
We know that Pete needs to arrive at work by 9.00am, so we can set up an equation:
Arrival time = 7.30am + Total time
9.00am = 7.30am + (Unknown/30) + 0.75
Solving for Unknown:
1.5 hours = Unknown/30
Unknown = 45 minutes
Therefore, Pete will arrive at work at 8.15am.
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Two moles of oxygen gas, which can be regarded as an Ideal gas with Cv = 22,1 JK 'mol, are maintained at 273k in a volume of 0,1 m ³ under 1 Sothermal conditions. Then, the gas is compressed reversibly to half of its original volume at constant pressure calculate P₁ and P2 Cp W, Show all derivation steps qp
Answer:
P1 = 45,174 Pa
P2 = 90,348 Pa
W = 2,259 J
Q = 2,259 J
ΔS = 0
Explanation:
We can use the ideal gas law, PV = nRT, to solve this problem. Since the gas is at constant temperature (isothermal), we can simplify this to PV = constant.
Given that there are two moles of oxygen gas in a volume of 0.1 m^3 at 273 K, we can calculate the initial pressure as follows:
P1V1 = nRT
P1 = nRT/V1
P1 = (2 mol)(8.31 J/mol.K)(273 K)/(0.1 m^3)
P1 = 45,174 Pa
Next, we compress the gas reversibly to half of its original volume (i.e. V2 = 0.05 m^3) at constant pressure. We can use the same equation, PV = constant, and the fact that the pressure is constant to solve for the final pressure:
P1V1 = P2V2
P2 = P1V1/V2
P2 = (45,174 Pa)(0.1 m^3)/(0.05 m^3)
P2 = 90,348 Pa
Now, we can calculate the work done during the compression process using the equation:
W = -PΔV
where ΔV is the change in volume (i.e. V2 - V1 = -0.05 m^3), and the negative sign indicates that work is done on the system during compression. Substituting the values, we get:
W = -(45,174 Pa)(-0.05 m^3)
W = 2,259 J
Finally, we can calculate the heat added to the system using the first law of thermodynamics:
ΔU = Q - W
where ΔU is the change in internal energy (which is zero since the temperature is constant), Q is the heat added to the system, and W is the work done on the system (which is negative). Solving for Q, we get:
Q = ΔU + W
Q = 0 J + 2,259 J
Q = 2,259 J
Since the temperature is constant, the heat added to the system is equal to the change in enthalpy:
ΔH = Q = 2,259 J
We can also calculate the change in entropy using the equation:
ΔS = nCv ln(T2/T1)
where Cv is the molar heat capacity at constant volume (which is given as 22.1 J/K.mol), and ln(T2/T1) is the natural logarithm of the ratio of final and initial temperatures. Since the temperature is constant, ΔS = 0.
Therefore, the final answers are:
P1 = 45,174 Pa
P2 = 90,348 Pa
W = 2,259 J
Q = 2,259 J
ΔS = 0
clock a remains in place and clock b is carried around the earth ( 40,000 km). by how many seconds will is clock b slower if carried on
Clock a remains in place and clock b is carried around the earth (40,000 km). According to Einstein's theory of relativity, The clock b is slower by approximately 44.6 seconds.
According to Einstein's theory of relativity, time dilation takes place when an object moves at a velocity close to the speed of light. The closer the velocity is to the speed of light, the more time slows down. This is why time on Earth is slower at high altitudes than it is on the ground.
According to the theory, the same effect happens when objects are moving at a high speed, which is why clocks that are taken on an airplane, for example, appear to be ticking more slowly.
1. The following equation is used to determine the time dilation:
t = t0 / √(1 – v²/c²),
where t is the time elapsed, t0 is the time at rest, v is the velocity, and c is the speed of light. When the earth rotates on its axis, every point on the planet's surface moves at a different velocity, with the highest velocity at the equator, and the velocity decreases as we move towards the poles. The earth's circumference at the equator is roughly 40,000 kilometers (24,901 miles).
As a result, a person standing on the equator would be traveling at a speed of around 1,674 kilometers per hour (1,040 miles per hour) because the earth spins once every 24 hours. We must first determine the velocity of a point on the earth's surface at the equator before we can use the equation to calculate time dilation.
2. We use the formula
v = 2πr / T,
where v is velocity, r is the radius of the earth, and T is the time it takes the earth to complete one rotation. The formula is as follows:
v = 2πr / Tv
= 2 x 3.14 x 6,378 km / 24 hv
= 1,674 km/h
3. Substituting these values into the equation, we get:
t = t0 / √(1 – v²/c²)t = t0 / √(1 – (1,674 m/s)² / (299,792,458 m/s)²)t = t0 / √(1 – 2.8 x 10^-8)t = t0 / 0.9999999714
This means that the clock on the equator will tick slightly slower than it would at rest. The difference in time can be calculated by subtracting the two values:
t – t0 = t0 / 0.9999999714 – t0t – t0 = t0 (1 – 0.9999999714)t – t0 = 0.0000000286 t0
4. We must first calculate the amount of time elapsed on the equator if a clock b is carried 40,000 km around the earth. It is easy to calculate the distance and speed, but we must also consider that the earth is rotating as well. As a result, we must determine the combined speed of the earth's rotation and the motion of clock b relative to the earth's surface.
5. To calculate this combined velocity, we can use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. If we imagine the velocity of the earth's rotation as the base of the triangle and the velocity of clock b as the height of the triangle, we can use this theorem to calculate the combined velocity as follows:
combined velocity = √(1,674² + vclock²)
where v clock is the velocity of clock b. Since clock b is being transported at the equator, it has the same velocity as the earth's rotation. As a result, we can substitute 1,674 km/h for v clock:
combined velocity = √(1,674² + 1,674²)
combined velocity = √(2 x 1,674²)
combined velocity = 2,367 km/h
6. Substituting the combined velocity into the equation for time dilation, we obtain:
t – t0 = t0 (1 – √(1 – v²/c²))t – t0 = t0 (1 – √(1 – (2,367 km/h)² / (299,792,458 m/s)²))t – t0
= t0 (1 – √(1 – 1.579 x 10^-11))t – t0
= t0 (1 – 0.999999999920215)t – t0
= 0.000000000079785 t0
Converting this value to seconds, we get:
0.000000000079785 t0 = 79.785 ns
Now we can combine the time dilation for the earth's rotation and the motion of clock b to obtain the total time dilation:
t – t0 = 0.0000000286 t0 + 0.000000000079785 t0t – t0 = 0.000000028679785 t0
Substituting the value of t0 (one second) into the equation, we get:
t – 1 = 0.000000028679785 seconds
Therefore, clock b will be approximately 44.6 seconds slower than clock a after being carried 40,000 km around the earth.
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Select the correct answer. In a given chemical reaction, the energy of the products is greater than the energy of the reactants. Which statement is true for this reaction? A. Energy is absorbed in the reaction. B. Energy is released in the reaction. C. No energy is transferred in the reaction. D. Energy is created in the reaction. E. Energy is lost in the reaction. Reset Next
Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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Adult brains are not capable of neurogenesiss . True False
Answer:
False. Adult brains are capable of neurogenesis, which is the process of generating new neurons (nerve cells) in the brain. Although it was previously believed that neurogenesis only occurred during early development, research has shown that certain regions of the brain, such as the hippocampus, continue to produce new neurons throughout adulthood. However, the rate of neurogenesis in adults is much lower than in developing brains
EX :SOMEONE FATHER TODAY YOUR FATHER DOES,T KNOW ABOUT TECH OR ANY SAMRT APPS BUT HE KNOW BETTER N HIS GENRATON
A beam consisting of five types of ions labeled A, B, C, D, and E enters a region that contains a uniform magnetic field as shown in the figure below. The field is perpendicular to the plane of the paper, but its precise direction is not given. All ions in the beam travel with the same speed. The table below gives the masses and charges of the ions. Note: 1 mass unit = 1.67 x 10â€"27 kg and e = 1.6 x 10â€"19 C
Which ion falls at position 2?
At position 2, ion B falls. It is less deflected because it has a lesser mass than ions C, D, and E and the same charge as ion A.
A force perpendicular to the charged particle's velocity and the magnetic field's direction is applied when it reaches the magnetic field. The right-hand rule asserts that the palm will face the direction of the force if the thumb of the right hand points in the direction of the particle's velocity and the fingers point in the direction of the magnetic field. The particle's charge, velocity, and magnetic field intensity all affect how much force is generated.
Since all ions are moving at the same speed in this scenario, the force exerted on each ion is proportional to its charge to mass ratio. Ion B has the smallest mass of all the ions, so the least force and is least deflected of the ions, falling at position 2.
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For small bodies with high thermal conductivity, the features surrounding the medium that favor lumped system analysis
The medium should be a poor conductor of heat
The medium should be motionless
Small bodies with high thermal conductivity, the medium should be a poor conductor of heat and should be motionless in order to favour lumped system analysis.
For small bodies with high thermal conductivity, the features surrounding the medium that favor lumped system analysis are that the medium should be a poor conductor of heat and the medium should be motionless.
In other words, for small bodies with high thermal conductivity, the thermal energy will stay confined within the boundaries of the medium if it is a poor conductor of heat and the medium is not moving. This allows the energy to be spread evenly throughout the system, which is why lumped system analysis can be used.
Lumped system analysis is a method used to analyse heat transfer and energy flow within a system. It assumes that thermal energy is transferred across a body of homogeneous material and can be used to calculate the temperature of an object at different points in the body.
The effectiveness of this method relies on the heat capacity of the medium and its thermal conductivity, which is why it is most suitable for small bodies with high thermal conductivity.
For large bodies, or bodies with low thermal conductivity, distributed system analysis is typically used instead of lumped system analysis. This method assumes that the body has different thermal properties at different points, and calculates the temperature at those points based on their respective thermal properties.
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A 1.5kg block is held in place and compresses a 150N/m spring by 30cm from its relaxed position. The block is then released. What speed will the block have at the instant when the spring is no longer compressed?
Answer: simple harmonic motion
Simple harmonic motion. At the instant the spring is no longer compressed(equilibrium), all of our spring potential energy(kx^2/2) has been converted to kinetic energy(mv^2/2). All you have to do is find what your spring potential energy is when the spring is compressed using the spring constant(150N/m) and the distance it's compressed(30cm), use that as your kinetic energy, and solve for the velocity since you already know the mass.
At one instant an object in free fall is moving downward at 50 meters per second. One second later its speed is about
A) 25 m/s. B) 50 m/s. C) 55 m/s. D) 60 m/s. E) 100 m/s.
The correct answer is C) 55 m/s. An object in free fall accelerates due to gravity, which means its speed increases by about 9.8 m/s2 every second. So in one second, its speed increased from 50 m/s to 50 + 9.8 = 59.8 m/s. Since it is impossible for the object to have a speed of 59.8 m/s, the closest answer is C) 55 m/s.
Given,An object in free fall is moving downward at 50 meters per second.At one-second later its speed is about.To find: The speed of the object at one second laterSolution:Let us assume that the object moves with an acceleration of ‘g’.Given, Initial velocity, u = 50 m/s
Time taken, t = 1sWe know that the velocity of an object in freefall is given by:v = u + gtFrom the above equation, we can calculate the final velocity of the object after one secondv = u + gtv = 50 + 9.8 × 1v = 50 + 9.8v = 59.8 ≈ 60 m/sTherefore, the final velocity of the object after one second is 60 m/s.Hence, the correct option is (D) 60 m/s.
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Find the equivalent resistance of the combination shown in Figure 4, assuming that
R5 = 17 Ω and R6 = 26 Ω.
Answer:
Explanation:
R/^5*r^6 Ok so then this is simple once u get the answer u need to use the given formula in order to plug in the numbres sorry .
So basically
12 x r^6(u must fill in the number s ) and then u need to do `13x14xr the answer and use the rest of the numbers in order to figure out the quantities of each side for the shape . Then ur answer would be the r^x + x = ???
So yeah hope this helped
I think
Kind of
K Thanks Bye
3. Large amplitude vibrations produced when the of receiver of the applied forced vibration matches the
An object's amplitude dramatically increases when the frequency of the applied forced vibrations matches the object's natural frequency. Resonance describes this behavior.
Theory A wave's amplitude directly relates to the quantity of energy it can carry. A wave with a high amplitude carries a lot of energy, whereas one with a low amplitude carries only a little. A wave's strength is determined by the typical energy that moves through a given area in a certain amount of time and in a particular direction.The sound wave's amplitude grows in proportion to its strength. We perceive louder noises to be of higher intensity. Comparative sound intensities are frequently expressed using decibels (dB)For more information on amplitude of vibration kindly visit to
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Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 27.5 m/s (about 62 mph ) around the turn, what is the race car's centripetal (radial) acceleration? What is the Coefficient of friction?
Answer:
Explanation:
The centripetal acceleration of the race car is given by the formula:
a = v^2 / r
where v is the speed of the race car and r is the radius of the turn.
Substituting the given values, we get:
a = (27.5 m/s)^2 / 57.0 m = 13.3 m/s^2
So the centripetal acceleration of the race car is 13.3 m/s^2.
To find the coefficient of friction, we need to use the formula:
f = μN
where f is the force of friction, μ is the coefficient of friction, and N is the normal force.
The normal force is equal to the weight of the car, which we can calculate as:
N = mg
where m is the mass of the car and g is the acceleration due to gravity (9.81 m/s^2).
Assuming the mass of the car is 1500 kg, we get:
N = 1500 kg × 9.81 m/s^2 = 14,715 N
The force of friction is equal to the centripetal force required to keep the car moving in a circle:
f = ma = (1500 kg)(13.3 m/s^2) = 19,950 N
Substituting the values of N and f into the formula for friction, we get:
19,950 N = μ(14,715 N)
Solving for μ, we get:
μ = 1.35
So the coefficient of friction is 1.35.
You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515
lb and was traveling eastward. Car B weighs 1125
lb and was traveling westward at 41.0
mph. The cars locked bumpers and slid eastward with their wheels locked for 18.5
ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750
.
What speed
(in miles per hour) was car A traveling just before the collision? (This problem uses English units because they would be used in a U.S. legal proceeding.)
Answer:
Solve for force:
Ff = UFn
Ff = 0.75(Fn)
Ff = 0.75(1515 + 1225 * g)
Ff = 20550N
Solve for acceleration:
F= ma
20550N = (1515 + 1225) a
a = 7.5m/s^2
solve for time:
a = d / t^2 ---> 7.5m/s^2 = 18.5/ t^2 ----> t = 0.85s
solve for velocity final
Impulse = F * t = 20550N * 0.85s
mv^2 = Impulse = 17467.5
(1515 + 1125)v^2 = 17467.5
vf = 2.5m/s
Plug in stuff:
1515 * v1 + 1125 * (-18.3m/s) = (1515 + 1125) * 2.5m/s
v1 = 9.23
Note: I converted 41mph(v2) to 18.3m/s, which is negative because "westward" is in the negative direction.
Explanation: Inelastic collision
I'm not sure but my guess is we can solve for the force of friction using the coefficient of friction. With that, we can solve for the acceleration in F = ma, and use that to solve for the time the two cars slide. And using that we can solve for the impulse, which is just the Force of friction times that time, which is also our momentum. Since we know the momentum, we can solve for the velocity of the two objects after the collision. Using that velocity, we can use the equation( m1v1 + m2v2 = (m1+m2)vf ), plug in the known quantities and solve for v1.(Note: don't forget to convert mph to mps and 18.5ft to meters)
Extra: I'm guessing because the two cars slide, the only force acting on them is the force of friction(so it's our net force), hence the Fnet = ma.
In this circuit, what is the potential difference across C4?
Use the following values in your calculation:
V = 12.0 V
C1 = 3.0 ?F
C2 = 2.0 ?F
C3 = 2.0?F
C4 = 1.0 ?F
C5 = 4.0 ?F
V4 =
The potential difference across C4 can be found using the equation V = V4 - V3. Using the given values, V = 12.0V, C1 = 3.0 ?F, C2 = 2.0 ?F, C3 = 2.0 ?F, C4 = 1.0 ?F, and C5 = 4.0 ?F, we can solve for V4.
V4 = 12.0V + (3.0 ?F + 2.0 ?F + 2.0 ?F + 1.0 ?F) / (1.0 ?F + 4.0 ?F)
V4 = 12.0V + (8.0 ?F / 5.0 ?F)
V4 = 12.0V + 1.6V
V4 = 13.6V
Therefore, the potential difference across C4 is 13.6V - 12.0V = 1.6V.
The potential difference across C4 can be determined using the formula Q = CV. Where Q represents the charge stored in the capacitor, C represents capacitance, and V represents the potential difference across the capacitorTo determine the potential difference across C4, we can use the formula Q = CV. To determine Q, we need to determine the equivalent capacitance of the circuit.
The equivalent capacitance of capacitors in parallel is equal to the sum of their capacitance. The equivalent capacitance of capacitors in series is equal to the reciprocal of the sum of their reciprocals.C1, C2, and C3 are in series, and their equivalent capacitance is given by:C_eq1=1/((1/C1)+(1/C2)+(1/C3))=1/(1/3+1/2+1/2)=3/7 μF{C_eq1=1/((1/C1)+(1/C2)+(1/C3))=1/(1/3+1/2+1/2)=3/7μF}C_eq2 is the equivalent capacitance of C4 and C5 in parallel.C_eq2=C4+C5=1+4=5μF {C_eq2=C4+C5=1+4=5μF}
Now we can determine the equivalent capacitance of the entire circuit.C_eq=C_eq1+C_eq2=3/7+5=38/7μF{C_eq=C_eq1+C_eq2=3/7+5=38/7μF}Now, we can determine the charge stored in the circuit.Q=C_eqV=38/7*12= 65.14μC{Q=C_eqV=38/7*12=65.14μC}To determine the potential difference across C4, we can use the formula Q = CV.V=C4Q/C4= 65.14/1 = 65.14V{V=C4Q/C4=65.14/1=65.14V}Therefore, the potential difference across C4 is 65.14 V.
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What are density and volume?
Simple explanation please
Answer:
Explanation:
Density is a measure of how much mass is contained in a given volume. It is the amount of matter (mass) in a given space (volume). Density is usually expressed in units of mass per unit of volume, such as kilograms per cubic meter (kg/m³) or grams per milliliter (g/mL).
Volume is the amount of space occupied by an object or substance. It is the measurement of the three-dimensional space occupied by an object, substance, or material. Volume can be measured in different units, such as liters (L), cubic meters (m³), or cubic feet (ft³), depending on the scale of the object being measured.
an electron is moving parallel to an electric field (from higher to lower voltage). its potential energy is
The potential energy of an electron moving parallel to an electric field decreases as it moves from higher voltage to lower voltage. The work done by the electric field on the electron is equal to the decrease in potential energy. The potential energy of the electron is proportional to its charge and the voltage difference between the two points.
When an electron moves parallel to an electric field, its potential energy is conserved. The potential energy of an electron is proportional to its charge and the voltage through which it moves. As the electron moves from higher voltage to a lower voltage, its potential energy decreases. The work done by the electric field on the electron is equal to the decrease in potential energy. When the electron is at rest, it has a certain potential energy due to its position in the electric field. If the electron is allowed to move freely, it will accelerate towards the lower voltage region, gaining kinetic energy. As it moves, the electric field continues to do work on the electron, converting its potential energy into kinetic energy. If the electric field is uniform, the potential energy of the electron will be given by the equation U = -qV, where q is the charge of the electron and V is the voltage difference between the two points. The negative sign indicates that the potential energy decreases as the voltage difference decreases.
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Two long parallel wires placed side by side on a horizontal table carry the same currents in opposite directions. The wire on your right carries current toward you, and the wire on your left carries current away from you. Determine the direction of the magnetic field at the point exactly midway between the two wires from your point of view. Explain your answer with the aid of labelled diagram. [5 marked
To find:-
Magnetic field at the centre between the wires.Answer:-
We are here given that two long current carrying wires are having same current. We need to find out the magnetic field at the centre between the wires .
We know that for a point between two ends of a wire , magnetic field is given by,
[tex]\implies B =\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}\\[/tex]
where ,
B is magnetic field.i is the current.d is the distance .Now since magnetic field is a vector quantity we need to find out the direction of the field . We can do so by using Right Hand thumb rule .
Right hand thumb rule :-
Hold the wire , in your hand with thumbs towards the direction of the current, then the curling of the fingers would give you the direction of the magnetic field.
For wire AB :-
The direction comes to be down the page .
For wire CD :-
The direction comes to be down the page .
Calculating net magnetic field:-
The net magnetic field will be the sum of both the fields .
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}+\dfrac{\mu_0}{4\pi}\dfrac{2i}{d} \\[/tex]
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{4i}{d}\\[/tex]
[tex]\implies \underline{\underline{\green{ B_{net}=\dfrac{\mu_0i}{ \pi d}}}}\\[/tex]
The direction is down the page .
and we are done!
A diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track. Determine the average power developed.
The average power developed by a diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track = 200 kW.
How to calculate average power?The first kinematic equation is v=v0+at , where v is the final velocity, v0 is the initial velocity, a is the constant acceleration, and t is the time
According to given information:
v = 10, v0= 0 , t= 100s, m=400
v=v0+at
10= 0+a(100)
a= 0.1 m/s²
∑ F =ma <==> F= 400(10 ³ )(0.1) = 40(10 ³)N
Pavg = F. Vavg = 40(10 ³)(10/2) = 200 kW
It represents the typical quantity of work completed or energy converted per unit of time. When the context clearly indicates it, the average power is frequently referred to as "power".
The instantaneous power overrides the average power as time interval t gets closer to zero.
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imagine that the blue light and orange light from the source were blocked. what color would how be present in the spectrum of light observed
Everything but blue & orange would now be present in the spectrum of light observed.
Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.
The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.
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Complete Question: -
Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?
Problem 23.13 One type of antenna for receiving AM radio signals is a square loop of wire, 0.16 m on a side, that has 20 turns. Part A If the magnetic field from the radio waves changes at a rate of 8.4 × 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop? Express your answer to two significant figures and include appropriate units. Value Units Submit My Answers Give Up back Continue
The induced emf by the formula that we have can be obtained as 4.3 * 10^-4 V.
What is the induced emf?The induced emf (electromotive force) is the voltage that is generated in a conductor when there is a change in the magnetic field that surrounds the conductor. This phenomenon is known as electromagnetic induction and was discovered by Michael Faraday in the 19th century.
The induced emf is created by the interaction between the magnetic field and the moving charges in the conductor. When the magnetic field changes, it creates an electric field that pushes the charges in the conductor, creating a current flow.
Using emf = NAdB/dt
= 20 * (0.16)^2 * 8.4 × 10-4 T/s
4.3 * 10^-4 V
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Estimat the number and wattage of lamps. which would be required to illuminate a workshop space 60x1.5 meteres by means of lamps mounted 5 metres above the working Plane The average illumination required is about 100 wt. coefficient of utilisation = 0.4 luminous efficiency 16 lumens per watt. Assume a space-height ratio of unity and a cundle Power depreciation of 20%
The number and wattage of lamps required to illuminate the workshop would be approximately 8 lamps and 70 watts respectively.
Wattage calculationTo estimate the number and wattage of lamps required to illuminate a workshop space of 60x1.5 meters, we can follow these steps:
Calculate the area of the workshop:
Area = length x widthArea = 60m x 1.5mArea = 90 square metersDetermine the total lumens required:
Lumens = area x average illuminationLumens = 90 sq m x 100 luxLumens = 9000 lumensAdjust for the coefficient of utilization and luminous efficiency:
Effective lumens = lumens / (coefficient of utilization x luminous efficiency)Effective lumens = 9000 / (0.4 x 16)Effective lumens = 1406.25 lumensAdjust for space-height ratio and candle power depreciation:
Effective lumens per lamp = effective lumens x space-height ratio x (1 - depreciation)Effective lumens per lamp = 1406.25 x 1 x (1 - 0.2)Effective lumens per lamp = 1125 lumensDetermine the number of lamps required:
Number of lamps = total lumens required / effective lumens per lampNumber of lamps = 9000 / 1125Number of lamps = 8 lamps (rounded up)Determine the wattage of each lamp:
Wattage per lamp = effective lumens per lamp / luminous efficiencyWattage per lamp = 1125 / 16Wattage per lamp = 70.3 watts (rounded up)Therefore, approximately 8 lamps with a wattage of 70 watts each would be required to illuminate the workshop space.
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