What two factors determine how much potential energy an object has?

Answers

Answer 1

Answer:

The mass of the object and its height in the gravitational field of the Earth.

Explanation:

If we are talking about gravitational potential energy which is defined as:

[tex]U=m\,*\,g\,*\,h[/tex]

being "m" the object's mass, "g" the acceleration due to gravity, and "h" the height at which the object is located relative to the conventionally picked level for zero of potential energy.

As long as the value of "g" is constant, the only two variables that determine the gravitational potential energy are the mass (m) of the object and its relative height (h).

Answer 2

Answer:

The objects weight and height above Earth's surface

Explanation:

K12 :)


Related Questions

The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total momentum a collision or explosion is equal to the total momentum a collision or explosion.what is momentum

Answers

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass [tex]m[/tex] travelling at a velocity [tex]\vec{v}[/tex]. The momentum [tex]\vec{p}[/tex] of this object would be:

[tex]\vec{p} = m \cdot \vec{v}[/tex].

For the law of conservation of momentum, consider two objects: object [tex]\rm a[/tex] and object [tex]\rm b[/tex]. Assume that these two objects collided with each other.

Let [tex]m_{\rm a}[/tex] and [tex]m_{\rm b}[/tex] denote the mass of the two objects. Let [tex]\vec{v}_{\rm a}(\text{initial})[/tex] and [tex]\vec{v}_{\rm b}(\text{initial})[/tex] denote the velocity of the two object right before the interaction. Let [tex]\vec{v}_{\rm a}(\text{final})[/tex] and [tex]\vec{v}_{\rm b}(\text{final})[/tex] denote the velocity of the two objects right after the interaction. The momentum of the two objects right before the collision would be [tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial})[/tex] and [tex]m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})[/tex], respectively. The momentum of the two objects right after the collision would be [tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final})[/tex] and [tex]m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex], respectively.

The sum of the momentum of the two objects would be:

[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})[/tex] right before the collision, and[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex] right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex].

A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick together. The impulse exerted by one cart on the other has a magnitude of

Answers

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

A metal ring 4.30 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of 1.12 T between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at 0.230 T/s.(a) What is the magnitude of the electric field induced in the ring? (b) In which direction (clockwise or counterclockwise) does the current flow as viewed by someone on the south pole of the magnet?

Answers

Answer:

A)0.00966 N/C

B) counterclockwise direction

Explanation:

We are given;

Diameter of the metal ring; d = 4.3 cm

Radius;r = 2.15 cm = 0.021- m

Initial magnetic field, B = 1.12 T

Rate of decrease of the magnetic field;dB/dt = 0.23 T/s

Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :

∫E•dr = d/dt∫B.A •dA

This gives;

E(2πr) = dB/dt(πr²)

Gives;. 2E = dB/dt(r)

E = dB/dt × 2r

We are given;

E = 0.23 × 2(0.021)

E = 0.00966 N/C

The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C

B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet

If 5 complete oscillations of a sound wave pass through a point in 0.5 s and the speed of sound was recorded to be 10 m/s, then find the wavelength of the sound.

Answers

Answer:

Wavelength = 1 meters

Explanation:

Given that,

Number of oscillations is 5

It passes through a point in 0.5 s

The speed of sound was recorded to be 10 m/s.

We need to find the wavelength of the sound.

Firstly, we will find frequency of this wave. Total no of oscillations per unit time is called frequency. So,

[tex]f=\dfrac{5}{0.5}\\\\f=10\ Hz[/tex]

Now the speed of wave in terms of wavelength and frequency is given by :

[tex]v=f\lambda[/tex]

Here, [tex]\lambda[/tex] = wavelength

[tex]\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{10\ m/s}{10\ Hz}\\\\\lambda=1\ m[/tex]

So, the wavelength of the sound is 1 meters.

when do you use cos and sin in situations like these? is horizontal always cos and vertical always sin?

Answers

Answer:

yes

Explanation:

this is simple

the horizontal line is adjacent

the vertical line is opposite

recall that cos x=adj/hyp

adj=hyp(cos x)

while opp=hyp(sin x)

When is the net force on an object equal to zero? A. When the object is in motion B. When the object is changing direction C. When the forces acting on the object are balanced D. When inertia is not present pls i need the answers quick

Answers

Answer: C. when the forces acting on the object are balanced.

Answer:

c

Explanation:

Helpppp!!!ASAP!! THANK YOUUUU!

Answers

Answer:

F = 9.675Hz

Explanation:

pls for certain reasons let us make

wavelength = $frequency = FV = velocity

3 loops : 6$/4 = L

6$/4 = 2

$ = 4/3 = 1.333

V = F x $

F = V/$

F = 12.9/1.333 = 9.675Hz

F = 9.675Hz

How large is theta? Please help!!!!

Answers

Answer:

30°

Explanation:

The angle between the normal and the vertical is the same as the angle between the incline and the horizontal.  We can show this with geometry.

If we removed the producers from this food web, how would it affect the balance of the ecosystem?

Answers

Answer:

In a food web, the removal of any trophic level upsets the balance within the web and can cause its eventual collapse. Because producers capture solar energy and convert it to food energy, their loss would affect every other level of the food web.

Explanation:

The removal of the producers would cause the collapse of the entire food web. Primary consumers or herbivores, which feed on producers directly, would die off. The next to be affected would be the secondary consumers or carnivores that eat the primary consumers. Higher level consumers would suffer as organisms from lower trophic levels start to die off. Decomposers would break down the bodies of dead organisms, returning their basic elements and compounds to the environment. However, even these dead organisms would run out and the entire food web would collapse.

Hope you like the answer.

the unit of energy is a derived unit​

Answers

Explanation:

Hi, there!!

Energy is defined as the capacity or ability to do work. It's SI unit is Joule.

here,

Joule = (kg×m×m)/(s×s)

= kg×m^2/s^2.

Therefore, the derived unit is kg.m^2 by s^2.

Hope it helps...

HELP ME PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE A student uses a spring scale attached to a textbook to compare the static and kinetic friction between the textbook and the top of a lab table. If the scale measures 1,580 g while the student is pulling the sliding book along the table, which reading on the scale could have been possible at the moment the student overcame the static friction? 1,140 g 1,580 g 820 g 1,860 g

Answers

Answer:

1,860

Explanation:

WILLL GIVE 5 STARS BRAINIEST AND THANKS AND 20 POINTS EACH ANSWER!!!!
A diver performs a dive from a 10 m-platform. She
jumps vertically upwards at 3 m s initially.
Find the time she takes to reach the water surface​

Answers

Answer:

The time she takes to reach the water from when she jumps off the platform is 1.71 s

Explanation:

According to the equations of motion, we have;

v = u - g·t

v² = u² - 2·g·s

s₁ = u₁·t₁ + 1/2·g₁·t₁²

The given parameters are;

The height of the platform (assumption: above the water) = 10 m

The velocity with which she jumps, u = 3 m/s

The acceleration due to gravity, g = 9.81 m/s²

The height to which she jumps, s, is found as follows;

v² = u² - 2·g·s

At maximum height, v = 0, which gives;

0 = 3² - 2×9.81×s

2×9.81×s = 3² = 9

s = 9/(2×9.81) = 0.4587 m

s = 0.4587 m

The time to maximum height, t, is found as follows;

v = u - g·t

0 = 3 - 9.81×t

9.81×t = 3

t = 3/9.81 = 0.3058 s

The total distance, s₁ from maximum height to the water surface = s + 10 = 0.4587 + 10 = 10.4587 m = 10.46 m

The time to reach the water from maximum height, t₁, is found as follows;

s₁ = u₁·t₁ + 1/2·g₁·t₁²

Where;

s₁ =  The total distance from maximum height to the water surface = 10.46 m

u₁ = The initial velocity, this time from the maximum height = 0 m/s

g₁ = The acceleration due to gravity, g (positive this time as the diver is accelerating down) = 9.81 m/s²

t₁ = The time to reach the water from maximum height

Substituting the values gives;

s₁ = u₁·t₁ + 1/2·g₁·t₁²

10.46 = 0·t₁ + 1/2·9.81·t₁²

t₁²= 10.46/(1/2×9.81) = 2.13 s²

t₁ = √2.13  = 1.46 s

Total time = t₁ + t = 1.46 + 0.3058 = 1.7066 ≈ 1.71 s.

Therefore, the time she takes to reach the water from when she jumps off the platform = 1.71 s.

A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end is allowed to fall. What is the angular acceleration as it is released

Answers

Answer:

The angular acceleration α = 14.7 rad/s²

Explanation:

The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod  and L = length of rod = 4.00 m. α = angular acceleration of rod

Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.

So Iα = Wr

Substituting the value of the variables, we have

mL²α/12 = mgL/2

Simplifying by dividing through by mL, we have

mL²α/12mL = mgL/2mL

Lα/12 = g/2

multiplying both sides by 12, we have

Lα/12 × 12 = g/2 × 12

αL = 6g

α = 6g/L

α = 6 × 9.8 m/s² ÷ 4.00 m

α = 58.8 m/s² ÷ 4.00 m

α = 14.7 rad/s²

So, the angular acceleration α = 14.7 rad/s²

Explain why stellar parallax cannot be used to measure the distance to other galaxies.

Answers

Answer:

1. a) Astronomers use the parallax method to measure the distance to nearby stars, but

we can’t use it to measure the distance to stars in other galaxies. Why not? Why isn’t the

parallax method useful for measuring the distances to stars in other galaxies?

They are so distant that the parallax is too small to be measured since parallax varies

inversely with distance.

b) Instead of the parallax method, we use the standard candle method to measure the

distance to stars in other galaxies. In particular, we use the standard candle method to

measure the distances to Cepheid variable stars in other galaxies. What is special about

Cepheid variable stars that makes them useful for this purpose?

We can figure out their luminosities from their periods of variation. Then if we measure

their fluxes we can calculate their distances.

2. a) From what were the protons and electrons in your body made, and roughly when

were they made?

They were made from energy (or gamma rays) very soon after the big bang (in the first

second). 400,000 years later they got together to make hydrogen atoms.

b) From what were the carbon atoms in your body made, and where were they made?

They were not made in the big bang. They were made much later inside of stars or in

supernovae. They were made by fusion from lighter atoms.

3. Make two sketches of the Milky Way Galaxy, one an edge-on view and one a face-on

view, labeling the various parts of the galaxy.

You should have labeled the

Matter must have two physical properties 1. Have mass, and 2
∆ Must move
∆ Use energy
∆ Take up space
∆ Be measure
able

Answers

Answer:

Take up space

Explanation:

Actually we know this by the definition of matter which states that "matter is any substance that has mass and takes up space by having volume."

hope it helped you:)

. Mass of a man is 40 kg. find his weight (g=9.8 m/s?)​

Answers

Answer:  392N

Explanation: W=mg

                 W= 40x9.8

                     = 392N

Answer:

[tex]\large \boxed{\sf 392.4 \ N}[/tex]

Explanation:

[tex]\sf Weight \ (N) =mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)[/tex]

[tex]W=mg[/tex]

[tex]W=40 \times 9.81[/tex]

[tex]W= 392.4[/tex]

uestloh 1
Which is taller, a 20ft giraffe or a 240 inch pole?
(Show your conversion factor in fraction form!)

Answers

Answer:

Height of pole = Height of giraffe

Explanation:

Given:

Height of giraffe = 20 ft

Height of pole = 240 inch

Find:

Which is taller

Computation:

Height of giraffe = 20 ft

We know that 1 ft = 12 inch

So,

Height of giraffe = 20 × 12 inch

Height of giraffe = 240 inch

and

Height of pole = 240 inch

Height of pole = Height of giraffe

state three effects of malnutrition in farm animals​

Answers

Answer:

Cows,Pigs,Chicken. They are always in farm

Does the surface tension of water affect the rate of evaporation? If so, would adding a surfactant speed up evaporation?

Answers

Answer:

The evaporation time gradually increased with the increase in surfactant concentration, i.e., from water to the concentration level of 0.005%. Furthermore, the evaporation time is significantly reduced, even lower than that of water containing relatively high concentrations from 0.01% to 0.1%.

in the derivation of the time period of a pendulum in electric field when considering the fbd of bob to find the g effective why do we neglect tension

Answers

Answer:

we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.

The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.

that's what I know so far

An object of mass 25kg is at rest. What is its momentum ?

Answers

Answer:

[tex]\boxed{0}[/tex]

Explanation:

Momentum is the measure of mass in motion.

[tex]\sf momentum = mass \times velocity[/tex]

An object at rest has a velocity of 0.

[tex]p=mv[/tex]

[tex]p = 25 \times 0[/tex]

[tex]p=0[/tex]

The momentum of an object at rest is always 0.

0. It’s at rest dude

Jaiden is writing a report about the structure of the atom in her report,she says that the atom has three main parts and two subatomic particles. Do you agree with her?why or why not

Answers

Answer:

I do not agree with the answer.

Because in reality, the atom has 2 main parts and 3 subatomic particles.

Explanation:

The parts of an atom are:

- The crust: It is the outer part of the atom and is the place where the electrons are.

- The nucleus: It is the central part of the atom and is the place that contains the protons and neutrons.

The subatomic particles of the atom are:

- Electrons: They are negatively charged particles that go in the atom's crust and are divided into specific sections.

- Protons: They are particles with a positive electric charge, the number of protons in the nucleus of an atom is what determines the atomic number of an element.

- Neutrons: They are atoms with no electric charge.

A negative charge feels a force when stationary in an electric field. moving parallel to an electric field. moving parallel to a magnetic field. moving perpendicular to a magnetic field. stationary in a magnetic field. moving perpendicular to an electric field.

Answers

Answer:

stationary in an electric field.

moving perpendicular to a magnetic field.

moving perpendicular to an electric field.

Explanation:

Negative charge: In physics, the term "negative charge" is defined as a phenomenon that consists of a surplus or different electrons in any field i.e magnetic or electric field.

However, the correct answer in the question above, would be:

"stationary in an electric field".

"moving perpendicular to a magnetic field".

"moving perpendicular to an electric field".

A block is attached to the end of a spring. The block is then displaced from its equilibrium position and released. Subsequently, the block moves back and forth on a frictionless surface without any losses due to friction. Which one of the following statements concerning the total mechanical energy of the block-spring system this situation is true?
1. The total mechanical energy is dependent on the maximum displacement during the motion.
2. The total mechanical energy is at its maximum when the block is at its equilibrium position
3. The total mechanical energy is constant as the block moves back and forth.
4. The total mechanical energy is only dependent on the spring constant and the mass of the block.

Answers

Answer:

The correct option is;

3. The total mechanical energy is constant as the block moves back and forth

Explanation:

The total mechanical energy is the sum of the potential and kinetic energies of the system

For a system that is isolated from the effects of external forces, but being acted upon by the internal conservative forces within the system, the total mechanical energy is constant

For a black and spring system, we have total mechanical energy, E = 1/2×K×A².

Where;

K = Constant

A = The amplitude of motion

Therefore, where there is no loss to friction, with A, remaining constant, the total mechanical energy will be constant.

73Ge
32
has
neutrons.

Answers

It has 41 neutrons because 73 is sum of neutron number and proton number and we know that its proton number is 32 so you can just write 73-32 and it is equal to 41 neutrons

How many centimeters (cm) are in 1 mile? _
Knowns:
1.61 kilometer (km) = 1 mile
1000 meter (m) = 1 kilometer (km)
100 centimeter (cm) - 1 m

Answers

Answer:

161,000 cm

Explanation:

1 mi × (1.61 km/mi) × (1000 m/km) × (100 cm/m) = 161,000 cm

Monochromatic light of wavelength 649 nm is incident on a narrow slit. On a screen 2.25 m away, the distance between the second diffraction minimum and the central maximum is 1.99 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.

Answers

Answer:

a)0.51°

b)1.47×10^-4m

Explanation:

a)for a single slit experiment, the minima that has an angle of θ towards the centre needs to satisfy the expression below.

bsin(θ)= mλ.........................(*)

Where b= width of the slit

The distance on the screen from Central angle can be expressed as

Sin(θ)= y/d............. (**)

d and y is the horizontal distance between slit and screen

If we input eqn(**) into equation (*) we have

y= mλd/b................(z)

In order to find angle (θ) we have

(θ)= sin-(1.99×10^-2)/2.25

= 0.51°

Therefore, angle of diffraction θ of the second minimum is 0.51°

b)to find the width of the sloth using eqn(z) by substitute the values, we have

b= (2)(649×10^-9)(2.25)/1.99×10^-2

b= 1.47×10^-4m

Therefore, the width of the slit is 1.47×10^-4m

Why does it take a longer time for a kilogram of water than a kilogram of copper to reach the same temperature? ​

Answers

Answer:

Since water has a higher specific heat than copper.

Explanation:

Dimensionally speaking, the specific heat of a material ([tex]c[/tex]) is represented by:

[tex][c] = \frac{[Energy]}{[Mass]\cdot [Temperature]}[/tex]

The specific heats of water and copper are [tex]4186\,\frac{J}{kg\cdot ^{\circ}C}[/tex] and [tex]390\,\frac{J}{kg\cdot ^{\circ}C}[/tex], respectively. Let suppose that temperature change and masses of water and copper are the same. Then, a kilogram of water takes a longer time than a kilogram of copper since the first has a higher specific heat.

1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te queda por recorrer la mitad de la mitad de 1 km, ¿cuánto te falta? 3. ¿Qué pesa mas, un kilo y medio de hierro o tres medios kilos de paja? porfavor es urgente.

Answers

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

[tex] m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4} [/tex]

Ahora cuando te doy 3/4 kg te queda en total:

[tex] m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg [/tex]

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

[tex] d = \frac{1/2}{2} = \frac{1}{4} [/tex]

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

[tex] P = m*g [/tex]    

[tex] P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N [/tex]

Y el peso de la paja es:

[tex] P = 3/2 kg*9.81 m/s^{2} = 14.72 N [/tex]

Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

You have a hot reservoir held at 30°C and a cold reservoir held at 0°C. If you move 400 J of heat from the hot reservoir to the cold reservoir, what is the total change in entropy?

Answers

Answer:

Explanation:

Given the following :

Temperature (Th) of hot reservoir = 30°C (30 +273) = 303K

Temperature (Tc) of cold reservoir = 0°C (273K)

Quantity (Q) of heat transferred from hot reservoir = 400 J

Total change in entropy (ΔStotal) :

ΔStotal = ΔShot + ΔScold

ΔS = Q/T

Hot reservoir is losing 400J of heat ;

Q = - 400 J

ΔShot = Q/Th

ΔShot = - 400/303

ΔShot = - 1.32 J/K

ΔScold = Q/T

ΔScold = 400 / 273

ΔScold = 1.47 J/K

ΔStotal = ΔShot + ΔScold

ΔStotal = - 1.32 + 1.47

ΔS total = 0.15 J/K

Answer:

-400/303 = -1.32

400/273 = 1.47

-1.32 + 1.47 =

.15 J/K

Explanation:

a p e x

Other Questions
Situation Analysis: Barriers to Effective ListeningTyler sits in class and hears the professor lecturing, but he is not actually listening. He is thinking about the date he made with Gabrielle for the evening. In fact, he is mentally comparing several different places he might take her. Later that evening, Tyler is in his car on his way to pick up Gabrielle. Suddenly, three police cars go whizzing past him with their sirens blaring and lights flashing. Tyler turns to watch where the police are going and does not notice that his cell phone is vibrating.Which one of the following barriers to effective listening does Tyler experience in class?A. Information overloadB. NoiseC. The rebuttal tendencyD. Glazing over A 25-year-old accountant presents to your clinic complaining of intermittent lower right sided chest pain for several days. He describes it as knifelike and states it only lasts for 3 to 5 seconds taking his breath away. He states he feels like he has to breathe shallowly to keep it from recurring. The only thing that makes it better is lying quietly on his right side. It is much worse when he takes a deep breath. He has taken some Tylenol and put a heating pad on his side but neither has helped. He remembers that two weeks ago he had an upper respiratory infection with severe hacking cough. He denies any recent trauma. His past medical history is unremarkable. His parents and siblings are in good health. He has recently married and his wife has a baby due in two months. He denies any smoking or illegal drug use. He drinks two or three beers a month. He states that he eats a healthy diet and runs regularly but not since his recent illness. He denies any cardiac, gastrointestinal or musculo-skeletal symptoms. On examination he is lying on his right side but appears quite comfortable. His temperature, blood pressure, pulse and respirations are unremarkable. His chest has normal breath sounds on auscultation. Percussion of the chest is unremarkable. During palpation the ribs are non-tender. What disorder of the chest best describes his symptoms?a. Pericarditisb. Chest wall painc. Pleural paind. Angina pectoralis Which of the following do we need to know in order to calculate pH during an acid-base titration of a strong monoprotic acid with a strong monoprotic base? Select all that applya. the concentration of the acid b. the concentration of the base titrant c. the initial volume of the acid solution d. the volume of the titrant used Jerry, a partner with 30 percent capital and profits interest, received his Schedule K-1 from Plush Pillows, LP. At the beginning of the year, Jerry's tax basis in his partnership interest was $44,000. His current-year Schedule K-1 reported an ordinary loss of $9,000, long-term capital gain of $4,600, qualified dividends of $3,600, $2,100 of non-deductible expenses, a $26,000 cash contribution, and a reduction of $5,600 in his share of partnership debt. What is Jerry's adjusted basis in his partnership interest (outside basis) at the end of the year Activation of the parasympathetic branch of the autonomic nervous system:______a. enhances digestion.b. causes conversion of glycogen to glucose.c. triggers release of epinephrine.d. increases heart rate. How are Math, Physics, Chemistry, and Biology all related? A company completes construction of a $400 million offshore oil platform and places it into service on January 1. State law requires that the platform be dismantled and removed at the end of its useful life, which is estimated to be 10 years. The company estimates that the cost of dismantling the platform will be $20 million. The discounted value of the liability is $9 million using the company's credit-adjusted, risk-free rate. The company has already capitalized the $400 million construction cost of the platform. What amounts should the company record as liability and expense when the asset is placed into service Can u guys answer question 2 pls Helpppppppppppppppp plzzz What is the correct evaluation of x2 - y2 - z2, when x is equal to -2, y is equal to 3 and z is equal to 4? g When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 3.2 10-15 m before interacting. From this information, find the time interval required for the strong interaction to occur. a college entrance exam company determined that a score of 25 on the mathematics portion of the exam suggests that a student is ready for When is the net force on an object equal to zero? A. When the object is in motion B. When the object is changing direction C. When the forces acting on the object are balanced D. When inertia is not present pls i need the answers quick Which of the following statements are true? Select all that apply.If the equation were graphed, it would be a horizontal line.Both functions have the same slope.The origin is the y-intercept for the function expressed in the table.The linear equation does not have a y-intercept.The table and the graph express an equivalent function. Please help me... Atoms of elements X, Y and Z have 16, 17 and 19 electrons, respectively. Atoms of argon have 18 electrons. a Determine the formulae of the compounds formed by the combination of the atoms of the elements: (i) X and Z (ii) Y and Z (iii) X with itself. b In each of the cases shown in A (i)(iii) above, name the type of chemical bond formed. c Give two properties you would expect to be shown by the compounds formed in an (ii) and an (iii). For the rational equation,[tex]\frac{x^{2}+5x+6}{x+3}=1[/tex] , what is a valid value of x? Write TRUE or FALSE(a)A 'system' is the part of an organism that carries out a certain function. FACTOR THIS EXPRESSION AS FAR AS POSSIBLE -385y IM GIVING THANKS AND BRAINLIST IF CORRECT. PLEASE HELP ME GUYS What command would you use to place the cursor in row 10 and column 15 on the screen or in a terminal window Webb, Inc. uses a flexible budget for manufacturing overhead based on machine hours. Variable manufacturing overhead costs per machine hour are as follows: Indirect labor $5.00 Indirect materials 2.50 Maintenance .50 Utilities .30 Fixed overhead costs per month are: Supervision $1,200 Insurance 400 Property taxes 600 Depreciation 1,800 The company believes it will normally operate in a range of 4,000 to 8,000 machine hours per month. During the month of August, 2019, the company incurs the following manufacturing overhead costs: Indirect labor $28,000 Indirect materials 16,200 Maintenance 2,800 Utilities 1,900 Supervision 1,440 Insurance 400 Property taxes 600 Depreciation 1,860 Prepare a flexible budget report, assuming that the company used 6,000 machine hours during August.