Answer:
I think A
Step-by-step explanation:
Please help!! The question is the image below VVV
Answers are also images after the picture.
Step-by-step explanation:
When adding two fractions with different bases (bottom numbers), we can use this function:
[tex]\frac{a}{b} + \frac{c}{d} = \frac{ad + cb}{bd}[/tex]
So, to apply this to the given question:
[tex]\frac{x+3}{x-6} +\frac{1}{x-2}[/tex]
= [tex]\frac{(x+3)(x-2)+(1)(x-6)}{(x-6)(x-2)}[/tex]
From the given answers, we see we don't need to simplify the resulting base number, which makes things a lot easier.
Multiply top using: (a + b)(c + d) = ac + ad + bc + bd= [tex]\frac{[(x*x) + (x*-2)+(3*x)+(3*-2)]+(x-6)}{(x-6)(x-2)}[/tex]
Simplify.= [tex]\frac{[x^2 -2x+3x-6]+(x-6)}{(x-6)(x-2)}[/tex]
Remove parentheses.= [tex]\frac{x^2 -2x+3x-6+x-6}{(x-6)(x-2)}[/tex]
Simplify again.= [tex]\frac{x^2 +2x-12}{(x-6)(x-2)}[/tex]
Now if we wanna be a little smart, we can see that from here, the only answer that has x^2 and something else, is A. But, just for show, lets factor.
Factor.= [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]
Answer:
A) [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]
Please help!!!!!!!!!!!!!!!
Step-by-step explanation:
[tex]\triangle{ABC}[/tex] is similar to [tex]\triangle{ADE}[/tex] so we can write the ratio
[tex]\dfrac{x}{6+4} = \dfrac{2}{6}[/tex]
Solving for x, we get
[tex]x = \left(\dfrac{2}{6}\right)(10) = \dfrac{10}{3}[/tex]
It has been claimed from previous studies that the average diameter of ball bearings from this manufacturing process is 2.30 cm. Based on the sample of 50 that you collected, is there evidence to suggest that the average diameter is greater than 2.30 cm? Perform a hypothesis test for the population mean at alpha = 0.01.
a. Define the null and alternative hypotheses in mathematical terms as well as in words.
b. Identify the level of significance.
c. Include the test statistic and the P-value.
d. Provide your conclusion and interpretation of the results. Should the null hypothesis be rejected? Why or why not?
Diameters data frame of the first sample (showing only the first five observations)
diameters
0 3.46
1 2.64
2 1.89
3 2.56
4 2.09
Diameters data frame of the second sample (showing only the first five observations)
diameters
0 3.10
1 2.04
2 2.18
3 2.60
4 2.76
test-statistic = 2.06
two tailed p-value = 0.0394
Data for all 50 samples cannot be obtained, however, the solution below uses the 10 samples below to show how the hypothesis can be tested.
Answer:
Step-by-step explanation:
Average diameter, μ = 2.30
H0 : Average diameter is equal to 2.30cm
H1 : Average diameter is greater than 2.30 cm
The hypothesis :
H0 : μ = 2.30
H1 : μ > 2.30
Using the readings from the data above :
3.46, 2.64, 1.89, 2.56, 2.09, 3.10, 2.04, 2.18, 2.60, 2.76
Sample size, n = 10
Mean, xbar = ΣX/ n = 25.32 / 10 = 2.532
Sample standard deviation, s = 0.4973 (from calculator)
The test statistic :
(xbar - μ) ÷ (s/√(n))
T = (2.532 - 2.30) ÷ (0.4973/√(10))
T = 1.475
The Pvalue :
Degree of freedom, df = n - 1 ; 10 - 1 = 9
Pvalue(1.475, 9) = 0.087
Decision region :
Reject H0 ; If Pvalue < α;
Since 0.087 > 0.01 ; we fail to reject the Null and conclude that there is no evidence to suggest that the average diameter is greater than 2.30 cm
Following are the published weights (in pounds) of all of the team members of Football Team A from a previous year.
177; 204; 211; 211; 232; 205; 185; 185; 178; 210; 206; 212; 184; 174;
185; 242; 188; 212; 215; 247; 241; 223; 220; 260; 245; 259; 278; 270;
280; 295; 275; 285; 290; 272; 273; 280; 285; 286; 200; 215; 185; 230;
250; 241; 190; 260; 250; 302; 265; 290; 276; 228; 265
Organize the data from smallest to largest value.
Part (a)
Find the median.
Part (b)
Find the first quartile. (Round your answer to one decimal place.)
Part (c)
Find the third quartile. (Round your answer to one decimal place.)
Part (d)
Construct a box plot of the data.
Answer:
im not sure but i do have a tip when you go to goo gle i want you to simplify your question (not what you asked on here) then copy your question as it is simple then search it on here because its slightly for others to understand
Step-by-step explanation:
.
Which expression corresponds to this graph?
Answer: Choice A
The number line graph is visually showing every number that is 19 or smaller; hence [tex]x \le 19[/tex]
Note the use of a closed or filled in circle at the endpoint (in contrast to an open circle). This indicates we are including the endpoint 19 as part of the solution set, and that's why we go for "or equal to" as part of the inequality sign.
Cyruer.
Pucic Or the
(a) The surface area and volume of a sphere are in the ratio of 3 : 7
cm. What is the circumference
of its great circle and volume ? Find it.
Answer:
Hello,
Step-by-step explanation:
Area of the sphere:
[tex]S=4*\pi *r^2[/tex]
Volume of the sphere:
[tex]V=\dfrac{4*\pi *r^3}{3}[/tex]
[tex]\dfrac{S}{3} =\dfrac{V}{7} \\\\\dfrac{4*\pi *r^2}{3} =\dfrac{4*\pi *r^3}{3*7} \\\\1=\dfrac{r}{7} \\\\\\r=7\\\\great \ circle: 2*\pi* r=14*\pi\\[/tex]
[tex]Volume=\dfrac{4*\pi *7^3}{3} =\dfrac{1372*\pi }{3} \approx{1436,7550...(cm^3)}[/tex]
London bought snacks for her team's practice. She bought a bag of apples for $2.25
and a 18-pack of juice bottles. The total cost before tax was $9.63. Write and solve an
equation which can be used to determine j, how much each bottle of juice costs?
Answer:
j = $7.38 / 18
Step-by-step explanation:
1. We have to find the total cost of a 18 juice bottles pack
= $ 9.63 - $ 2.25
= $ 7.38
2. To find how much each bottle of juice costs :
j = $ 7.38 / 18 #
3. You buy butter for $3 a pound. One portion of onion compote requires 2 oz of butter. How much does the butter for one portion cost?
Answer:
The butter for one portion cost $ 0.375.
Step-by-step explanation:
Given that you buy butter for $ 3 a pound, and one portion of onion compote requires 2 oz of butter, to determine how much does the butter for one portion cost, the following calculation must be performed:
2 oz = 0.125 lb
1 = 3
0.125 = X
3 x 0.125 = X
0.375 = X
Therefore, the butter for one portion cost $ 0.375.
please help me with this
please mark this answer as brainlist
Two angles of a triangle have the same measure.
If two sides have lengths 15 and 20, what is the
greatest possible value of the perimeter of the
triangle?
9514 1404 393
Answer:
55 units
Step-by-step explanation:
If two angles have the same measure, the triangle is isosceles. That means two sides have the same measure. Since the two given sides are different measures, the remaining side must be one of those. The perimeter will be greatest if the congruent sides are the longest. The greatest perimeter is ...
15 + 20 + 20 = 55 . . . units
Determine the indicated term in the following arithmetic sequences.
1.) a subscript 5: {2, 5, 8, ...}
2.) a subscript 20: {4, 8, 12, ...}
3.) a subscript 18: {0,20,40,60, ...}
Answer:
[tex]a_5= 14[/tex]
[tex]a_{20}= 80[/tex]
[tex]a_{18}= 340[/tex]
Step-by-step explanation:
Solving (a):
We have:
[tex]a_1=2[/tex] --- first term
[tex]d = 5 -2 = 3[/tex] common difference
The 5h term is:
[tex]a_n= a_1 + (n - 1)d[/tex]
[tex]a_5= 2+ (5 - 1)*3[/tex]
[tex]a_5= 14[/tex]
Solving (b):
We have:
[tex]a_1 = 4[/tex] --- first term
[tex]d = 8 -4 = 4[/tex] common difference
The 20h term is:
[tex]a_n= a_1 + (n - 1)d[/tex]
[tex]a_{20}= 4+ (20 - 1)*4[/tex]
[tex]a_{20}= 80[/tex]
Solving (c):
We have:
[tex]a_1 = 0[/tex] --- first term
[tex]d = 20 -0 = 20[/tex] common difference
The 18th term is:
[tex]a_n= a_1 + (n - 1)d[/tex]
[tex]a_{18}= 0+ (18 - 1)*20[/tex]
[tex]a_{18}= 340[/tex]
1. Đường kính của một loại trục máy là một đại lượng ngẫu nhiên có phân phối chuẩn N (μ = 250mm, σ2 = 25mm2). Trục máy được gọi là hợp quy cách nếu đường kính từ 245mm đến 255mm. Cho máy sản xuất 100 trục. Tính xác suất để:
a. Có 50 trục hợp quy cách.
b. Có không quá 80 trục hợp quy cách
Answer:
cannot understand the language man
but please follow
What is the value of m in the figure below? If necessary, round your answer to
the nearest tenth of a unit.
A. 18
B. 13.2
C. 12.5
D. 7
First
[tex]\\ \sf\longmapsto BD^2=AD\times DC[/tex]
[tex]\\ \sf\longmapsto BD^2=18^2+7^2[/tex]
[tex]\\ \sf\longmapsto BD^2=324+49[/tex]
[tex]\\ \sf\longmapsto BD^2=363[/tex]
[tex]\\ \sf\longmapsto BD=\sqrt{363}[/tex]
[tex]\\ \sf\longmapsto BD=19.2[/tex]
Now
Using Pythagorean theorem
[tex]\\ \sf\longmapsto BD^2+CD^2=m^2[/tex]
[tex]\\ \sf\longmapsto m^2=7^2+19.2^2[/tex]
[tex]\\ \sf\longmapsto m^2=49+363[/tex]
[tex]\\ \sf\longmapsto m^2=412[/tex]
[tex]\\ \sf\longmapsto m=\sqrt{412}[/tex]
[tex]\\ \sf\longmapsto m=20.3[/tex]
Nearest value in options is 18
Hence option a is correct
simplify√50-3√2(2√2-5) -5√32
Answer:
-12
Step-by-step explanation:
√50-3√2(2√2-5) -5√32
= 5√2 -12+15√2-5(4)√2
= 5√2 -12+15√2-20√2
= -12
Which expression is equivalent to RootIndex 4 StartRoot x Superscript 10 Baseline EndRoot?
Answer:x2.2
Step-by-step explanation:
Can someone work out this problem for me because I do not get it and it is due tomorrow for homework? 83.971 + 10.9 PLSS HELPPPP MEE!!!!
9514 1404 393
Answer:
94.9
Step-by-step explanation:
It is straightforward addition to find the sum of the two numbers to be 94.871. Perhaps you're interested in rounding to the appropriate precision.
Here, the number with the fewest digits right of the decimal point is 10.9. In order to round the addition result appropriately, that "exact" result must be rounded so it has this same number of digits to the right of the decimal point (1 digit).
94.871 ≈ 94.9
_____
Additional comment
When you're asked to round a sum (or difference) to the appropriate precision, always first compute the exact result using the full precision of all contributors. Then determine the contributor with the least precision (least significant digit is farthest to the left), and round the result to that same precision.
For the function in the graph, find the values of f(-4), f(-1), and f(1).
Answer:
f(-4) = -1
f(-1) = -4
f(1) = 4
Step-by-step explanation:
We need to find the y value for the x values
f(-4) means find the y value for x= -4
f(-4) = -1
f(-1) = -4
f(1) = 4
Find the missing segment in the image below
Answer: Missing segment = 45
Step-by-step explanation:
Concept:
Here, we need to know the idea of a similar triangle, ratio, and cross-multiplication.
In similar triangles, one can be obtained from the other by uniformly scaling (enlarging or reducing), possibly with additional translation, rotation and reflection. If two objects are similar, each is congruent to the result of a particular uniform scaling of the other.
A ratio is a quantitative relation between two amounts showing the number of times one value contains or is contained within the other.
Cross-multiplication means multiplying the numerator of each fraction by the other's denominator or the other way round.
If you are still confused, please refer to the attachment below for a graphical explanation.
Solve:
Let x be the length of missing segment
Step One: write the proportion ratio
56 / 56 + 24 = 105 / 105 + x
Step Two: Cross-multiplication
56 (105 + x) = 105 ( 56 + 24)
Step Three: Simplify parenthesis and expand it
56 ( 105 + x) = 105 (80)
5880 + 56x = 8400
Step Four: Subtract 5880 on both sides
5880 + 56x - 5880 = 8400 - 5880
56x = 2520
Step Five: Divide 56 on both sides
56x / 56 = 2520 / 56
x = 45
Hope this helps!! :)
Please let me know if you have any questions
What is the equation of the line that passes through (-3,-1) and has a slope of 2/5? Put your answer in slope-intercept form
A: y= 2/5x -1/5
B: y= 2/5x +1/5
C: y= -2/5x -1/5
Answer:
y = 2/5x + 1/5
Step-by-step explanation:
y = 2/5x + b
-1 = 2/5(-3) + b
-1 = -6/5 + b
1/5 = b
1. Coach Jensson wants to celebrate the final win of the
school's baseball season with a trip to the local fast food
place. The team buys 22 delicious tacos and 17 orders
of savory nachos for $71.05. A few of the players are still
hungry, so the coach buys 10 more tacos and 5 more
orders of nachos for $27.25. If you don't consider tax,
what is the price of a taco and the price of an
order of nachos ?
What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)? x= –y216+6y16–4116 y= –x216+6x16–4116 y=x216–6x16+4116 x=y216–6y16+4116
Answer:
y=x216–6x16+4116
Step-by-step explanation:
plato :)
The equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.
What is a parabola?It is defined as the graph of a quadratic function that has something bowl-shaped.
(x - h)² = 4a(y - k)
(h, k) is the vertex of the parabola:
a = √[(c-h)² + (d-k²]
(c, d) is the focus of the parabola:
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
It is given that:
The equation of a parabola that has a vertical axis, passes through the point (–1, 3)
The vertex of the parabola is at (3, 2)
As we know, in the standard form of the parabola (h, k) represents the vertex of the parabola.
h = 3
k = 2
Plug the above point in the equation:
[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]
x = 3
y = 2
[tex]\rm 2\ =\ \dfrac{3^{2}}{16}-\dfrac{6(3)}{16}+\dfrac{41}{16}[/tex]
= 9/16 - 18/16 + 41/16
= (9-18+41)/16
= 32/16
2 = 2 ( true)
The equation of the parabola is:
[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]
Thus, the equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.
Learn more about the parabola here:
brainly.com/question/8708520
#SPJ2
Am I right? Please help me out
Answer:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
Step-by-step explanation:
Given
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Required
Determine [tex]\cos(\theta)[/tex]
We have:
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Split
[tex]\tan(\theta) = -\frac{\sqrt{19}}{\sqrt{17}}[/tex]
tan is calculated as:
[tex]\tan(theta) = \frac{opposite}{adjacent}[/tex]
So:
[tex]Opposite = -\sqrt{19[/tex]
[tex]Adjacent = \sqrt{17[/tex]
And:
[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex] --- Pythagoras theorem
[tex]Hypotenuse^2 = (-\sqrt{19})^2 + (\sqrt{17})^2[/tex]
[tex]Hypotenuse^2 = 19 + 17[/tex]
[tex]Hypotenuse^2 = 36[/tex]
Take square roots
[tex]Hypotenuse = 6[/tex]
[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos(\theta) = \frac{\sqrt{17}}{6}[/tex]
Since it is in the second quadrant, then:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
- 18 = -3x + 6
Plz help
Answer:
8 =x
Step-by-step explanation:
- 18 = -3x + 6
Subtract 6 from each side
-18-6 = -3x+6-6
-24 = -3x
Divide each side by -3
-24/-3 = -3x/-3
8 =x
Answer:
x= 8
Step-by-step explanation:
[tex]\sf{}[/tex]
=> -3x+6 = -18
=> -3x+6-6= -8-6
=> -3x= -24
=> x= 8
Which answer shows y + 2x < 4x - 3, rewritten to isolate y, and its graph?
Answer:
j7kd4uzvinxru,en gg4ukfiebcjeictijxc7t
Step-by-step explanation:
mxrICE vxxn6rj CVT ryrf NYC cfkxkeuixx BBC xu BBC yfh
A copy machine makes 36 copies per minute How many copies does it make in 3 minutes and 45 seconds
Step-by-step explanation:
Hope it is helpful.
Thank you.
Identify the x-intercept point(s) of the parabola.
A) (0,3) and (-1,0)
B) (3,0)
C) (3,0) and (0,3)
D) (-1,0) and (3,0)
Answer:
D
Step-by-step explanation:
First of all, there are 2 different points. That lets out B.
The graph crosses the x axis at 3 and -1 Those two are x values. That lets out C and A.
So all you are left with is D. The y values have to be 0. The x values are 3 and - 1
a group of workers can plant 3/5 acres in 5/6 days. what is the unit rate per day?
Answer:
Workers can plant 0.72 acres per day.
What should you multiply the top equation by so that yis eliminated when the equations are added? | 3x – y = -2 15x + 2y = 15 A. 4 B. -2 C. 2 D. -1
Answer:
c. 2
Step-by-step explanation:
2 (3x – y = -2) 6x - 2y = -4
6x - 2y = -4
If the area A of a triangle is 60 m- (square meters) and the base b is 20 m, what is the altitude h?
Answer:
not sure
Step-by-step explanation:
a+B+C+=d
The length of a rectangle is 7 inches
more inan its width. the area of
the rectangle is eqaul to 4 inches less
than 4 times the perimeter. Find the
length and width of the rectangle
Answer:
length = 20 inches
width = 13 inches
Step-by-step explanation:
l = length
w = width
area = l×w
perimeter = (2×l) + (2×w)
l = w + 7
l×w = 4×(2×l + 2×w) - 4
(w+7)×w = 4×(2×(w+7) + 2×w) - 4
w² + 7w = 4×(2w + 14 + 2w) - 4
w² + 7w = 8w + 56 + 8w - 4 = 16w + 52
w² - 9w - 52 = 0
the solution for a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
here we use now w instead of x.
and a=1
b=-9
c=-52
w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =
= (9 ± sqrt(289))/2 = (9 ± 17)/2
w1 = (9+17)/2 = 26/2 = 13
w2 = (9-17)/2 = -8/2 = -4
and a negative length does not make any sense for a geometric shape.
so, only w1 = 13 applies.
l = w + 7 = 13 + 7 = 20
