what makes''emerging technologies'' happen and what impact will they have on individuals,society,and environment

Answer:

Computer ethics is a part of practical philosophy concerned with how computing professionals should make decisions regarding professional and social conduct. Margaret Anne Pierce, a professor in the Department of Mathematics and Computers at Georgia Southern University has categorized the ethical decisions related to computer technology and usage into three primary influences:

The individual's own personal code.

Any informal code of ethical conduct that exists in the work place.

Exposure to formal codes of ethics.

Explanation:

Answer:

a. True

Explanation:

Cloud computing can be defined as a type of computing that requires shared computing resources such as cloud storage (data storage), servers, computer power, and software over the internet rather than local servers and hard drives.

Generally, cloud computing offers individuals and businesses a fast, effective and efficient way of providing services.

In Computer science, one of the most essential characteristics or advantages of cloud computing is rapid elasticity.

By rapid elasticity, it simply means that cloud computing gives you the ability to expand and reduce resources according to your specific service requirement because resources such as servers can be used to execute a particular task and after completion, these resources can then be released or reduced.

Some of the examples of cloud computing are Google Slides, Google Drive, Dropbox, OneDrive etc.

Answer:

space management and buffering speed.

Explanation:

There are different types of file management systems in a computer system, examples of which are NTFS, FAT, WAFL, etc, and are governed by protocols like NFS, TFTP, FTP, etc.

These file systems are used in storages like the hard disk drive, CD and DVD, solid-state drive, etc, to organize or manage the files from boot setup, device drivers to permission-seasoned user files.

Files in storage range from small to large files, for which the schema of the file system must adjust to manage and allocate free space to other files in the future. The file system is also able to index the location of a file for retrieval to a cache memory, making buffering faster.

Answer:

Here is the Python program:

def scores(file):  # method scores that takes a file name as parameter and returns the sum and average of scores in a file

   with open(file, 'r') as infile:  # open the file in read mode

       lines = [score.split() for score in infile]  # split the scores into a list

       print("The scores are:",lines)  #print the scores

       for line in lines:  # loops through each score

           total= sum(int(score) for score in line)  # adds the scores

           average =total/len(line) # computes average by taking sum of scores and dividing by number of scores in file

       print("The sum is:", total)  #prints the sum of scores

       print("The average is:", "{:.2f}".format(average))   #prints the average

filename = input("Enter name of the file: ")  #prompts user to enter name of file

scores(filename) #calls scores method by passing the file name to it in order to compute sum and average of file contents i.e. scores

Explanation:

It is assumed that the scores in the file are separated by a blank space.

The scores() method takes a file name as parameter. Then it opens that input file in read mode using object infile.

split() method is used to split the scores in a file into a list. Suppose the scores are 1 2 3 4 5 6 . So after the split, they become ['1', '2', '3', '4', '5', '6']  

The loop iterates through each score in the file, splits them into a list and stores this list in lines. The next print statement prints these scores in a list.

The second loop for line in lines iterates through each score of the list and the statements: total= sum(int(score) for score in line)  and average =total/len(line) computes the total and average of scores.

total= sum(int(score) for score in line)  statement works as follows:

for loop iterates through each element of list i.e. each score

int() converts that string element into integer.

sum() method adds the integers to compute their total.

So if we have  ['1', '2', '3', '4', '5', '6']  each element i.e. 1,2,3,4,5,6 is converted to integer by int() and then added together by sum method. So this becomes 1+2+3+4+5+6 = 21. This result is stored in total. Hence

total = 21.

average = total/len(line) works as follows:

The computed sum of scores stored in total is divided by the number of scores. The number of scores is computed by using len() method which returns the length of the line list. So len() returns 6. Hence

average = total/len(line)

              = 21 / 6

average = 3.5

The next two print statement prints the value of sum and average and "{:.2f}".format(average)) prints the value of average up to 2 decimal places.

The screenshot of the program along with its output is attached.

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is  initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:  

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

f

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

m