What is the sum of the 15th square number and the 5th cube number?

Answer:

35 degrees

Step-by-step explanation:

50+35=85

Answer:

G

Step-by-step explanation:

you know its G just by the way it is

Answer:

94.5 yd^3

Step-by-step explanation:

The volume of a rectangular prism is given by the formula:

A = lwh

Where:

l = length

w = width

h = height

Volume is how much space a 3d figure occupies.

USE THE FORMULA WITH THE GIVEN DIMENSIONS:

A = (7)(4.5)(3)

= (31.5)(3)

= 94.5

Volume is measured in cubic yards, in this case.

Therefore your answer is 94.5 yd^3

I hope I helped!

Answer:

Step-by-step explanation:

length = 7 yd

Width = 4.5 yd

height = 3 yd

Volume of rectangular prism = length * width * height

                                                = 7 * 4.5 * 3 = 94.5 yd³

Answer:

The number is 135.

Step-by-step explanation:

1) Form an equation

Three is subtracted from a number

⇒ [tex]x-3[/tex] (where x is "the number")

The difference is divided by 11

⇒ [tex]\displaystyle \frac{x-3}{11}[/tex]

The result is 12

⇒ [tex]\displaystyle \frac{x-3}{11}=12[/tex]

2) Solve the equation

[tex]\displaystyle \frac{x-3}{11}=12[/tex]

Multiply both sides by 11

[tex]\displaystyle \frac{x-3}{11}*11=12*11\\\\x-3=132[/tex]

Add 3 to both sides

[tex]x-3+3=132+3\\x=135[/tex]

Therefore, the number is 135.

I hope this helps!

Answer:

Option A

Step-by-step explanation:

Dont let  the sample of 500 teachers fool you the 500 teachers opinion is on their students standardized testing experience. In this case the students are the test subjects(population).

Answer:

[tex]14\text{ liters}[/tex]

Step-by-step explanation:

Let the total amount of water the container can hold be [tex]t[/tex]. Currently, there are [tex]n[/tex] liters in the container. If Ito adds 10 liters of water, the container will be 60% full. We can express this statement in the following mathematical equation:

[tex]n+10=0.6t[/tex]

Next, we're given that if we add 6 more liters to this, the container will be 75% full.

Therefore, we have:

[tex]n+10+6=0.75t,\\n+16=0.75t[/tex]

This is a system of equations:

[tex]\begin{cases}n+10=0.6t,\\ n+16=0.75t\end{cases}[/tex]

Subtract both equations to conveniently get rid of [tex]n[/tex]:

[tex]10-16=0.6t-0.75t,[/tex]

Combine like terms:

[tex]-6=-0.15t[/tex]

Divide both sides by -0.15:

[tex]t=\frac{-6}{-0.15}=40[/tex]

Now substitute [tex]t=40[/tex] into any equation (I'll choose the first):

[tex]n+10=0.6(40),\\n+10=24[/tex]

Subtract 10 from both sides:

[tex]n=24-10=\boxed{14\text{ liters}}[/tex]

Answer:

GIVE ME BRAINLIEST

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

The average value of the Function f(x) by squeeze theorem states that no extreme or greater value will exist within the designated area for f(x)

Answer:

x = 40

Step-by-step explanation:

3-4-5 triangle scale factor by 10

Missing side is 4

4*10 = 40 | Multiply by 10 bc of scale factor

x = 40

Cot A=1/tan A=12/5

cos A= 12/13

sin A=5/13

Draw a right angled triangle

the hypotenuse is the longest side which is 13 using Pythagoras theorem

the side opposite the angle A is 5

the side closest to the angle A which is called the adjacent is 12

sinA =opp/hyp

cos A= adj/hyp

cotA =1/tanA=cos A/sinA

Note: Pythagoras theorem is

hyp²=opp²+adj²

Answer:

Step-by-step explanation:

[tex]tan \ A = \frac{5}{12}=\frac{opposite \ site}{adjacent \ side}[/tex]

hypotenuse² = (opposite side)² + (adjacent side)²

                      =  5² + 12²

                      = 25 + 144

                      = 169

hypotenuse = √169 = √13*13 = 13

[tex]Cot \ A = \frac{adjacent \ side}{opposite \ side}=\frac{12}{5}\\\\Cos \ A = \frac{adjacent \ side}{hypotenuse}=\frac{12}{13}\\\\Sin \ A = \frac{opposite \ side}{hypotenuse}=\frac{5}{13}[/tex]

Answer:    [tex]\fbox{C} \: \: \: \dfrac{4 \times 10^{4} }{3 \times 10^{4} }[/tex]

Step-by-step explanation:

36,070 = 3.607 · 10⁴ ≈ 4 · 10⁴

29,029 = 2.9029 · 10⁴ ≈ 3 · 10⁴

Let's how manytimes greater the distance to the bottom of Challenger Deep is than the distance to the top of Mount Everest:

[tex]\dfrac{4 \times 10^{4} }{3 \times 10^{4} }[/tex]

Answer:

C

Step-by-step explanation:

First, the question is asking how many times greater the distance to the Challenger Deep is compared to Mount Everest. This means that the Challenger Deep will be on top, with the distance to Mount Everest on the bottom.

Next, we can see that in our answers, we are only given one significant digit. This means that we have to round our original numbers to the nearest significant digit and work from there. For Challenger Deep, 36,070 must be rounded to the nearest ten thousandth as it is in the ten thousands. Therefore, it must be rounded to 40,000 or 30,000. As 36,070 is closer to 40,000 than 30,000 (we can tell this because the second number, 6, is greater than 5, so we round up), we can represent this as 40,000. For Mount Everest, we can round 29,029 to either 20,000 or 30,000. 30,000 is the appropriate choice here because 9, the second number, is greater than 5.

Therefore, our ratio is now 40,000 / 30,000 . Our answers are written in scientific notation, so we must convert our numbers to those values.

Let's start with 40,000 . Our one significant digit is 4, so we can write this as 4 * something. For each number in 10 to the power of x (x is a placeholder value), we add x amount of zeros. For example, for 4 * 10², we add 2 zeros, making it 400. There are 4 zeros here, so to write this in scientific notation, we have 4 * 10^4

Similarly, for 30,000 , we can write this as 3 * 10^4 as there are 4 zeros.

Our ratio is thus 40,000 = 4*10^4 , which is the Challenger Deep value rounded, over 30,000 = 3 * 10^4, which is the Mount Everest value rounded. We can write this as [tex]\frac{4*10^{4}}{3*10^{4}}[/tex], or C

Answer:

х=6

Step-by-step explanation:

[tex]7 + 5(x -3 ) = 22 \\ 7 + 5x - 15 = 22 \\ 5x = 22 - 7 + 15 \\ 5x = 30 \\ x = 6[/tex]

Answer:

C

x=6

Step-by-step explanation:

Answer:

(base x height x length)/2 = volume

6x8x8 = 384/2 = 192in^3

hope that answers your question

Bonsoir,

"Qui sont vos sportifs préférés ?

Je vais vous décrire mon athlète préférée et vous devrez prêter attention. À la fin, vous me direz de qui je parle, d'accord ?

Commençons

Question 1 : Quel sport pratique l'athlète ?

Football, basketball ou volleyball.

Elle joue au volley-ball

Ma sportive préférée, c'est une joueuse de volley-ball.

Elle est péruvienne et fait partie de l'équipe féminine du Pérou  de volley-ball.

Question 2 : Comment est-elle?

Moche, musclée ou petite?

Elle est musclée

Elle est brune et musclée.

Elle est grande et mince aussi.

Elle est très belle.

Question 3 : Comment sont ses cheveux

et ses yeux ?

Ses cheveux et ses yeux sont bruns.

Elle a les cheveux bruns ,  courts et frisés .

Ses yeux sont bruns( on dirait plutôt marron) comme ses cheveux.

Question 4 : Quel âge a-t-elle ?

Elle a vingt-quatre ans.

Question 5 : Est-elle de petite taille?

Non, elle est grande.

Elle fait 1, 85m!

Answer: b = 1

Step-by-step explanation:

= -32 + 10b = -22

-32 + 10 = -22

b = 1

Check: -32 + 10(1) = -22

= -22

Answer:

b=1

Step-by-step explanation:

Hello,

We would like to solve for b in the equation -32+10b=-22.

When we want to solve for a variable, we want to isolate it on one side (have it on one side by itself. No other numbers.)  

So to start, add 32 to both sides to remove it from the left side (-32+32=0).

-32+10b=-22

+32         +32

______________

10b=10

Now, there isn't anything with 10b, but we want the value of b by itself (1b), as 10b is 10 times the value of what b is.

So divide both sides by 10

b=1

Hope this helps!

Answer:

556

Step-by-step explanation:

Surface area=2*(lb+bh+lh)=2*(110+80+88)=556

Answer:

B

Step-by-step explanation:

22/33 = 0.667

14/21 = 0.667

Since both quantities both have the ratio of 2:3, they are proportional

The other choices are not proportional

25/28 = 0.893

5/7 = 0.714

16/13 = 1.231

13/16 = 0.813

48/60 = .8

35/42 = .833

Answer:

considering it was simple interest,

We have the formula:

I = PRT ÷ 100

where,

for the first part of the question,

Thus, I = (2160 × 20 × 4)÷ 100

I = Rs. 1728

Now, for the second part,

T = 100×I÷PR

T = 100 × 1728÷(1800 × 12)

T = 8 Years

Answer:

45 / 27 = 30 / 18 = x / 24

x = 40

Step-by-step explanation:

Hi there!

The question here states that the two polygons are similar

Polygons that are similar have similar side length ratios.

If we want to find a side length we must create a proportional relationship

We are already given a partial proportional relationship.

Which is...

45 / __ = __ / 18 = x / __

First let's fill in the blanks

The side that is corresponding to the side with a length of 45 has a length of 27. So it would be 45/27

The side that is corresponding to the side with a length of 18 has a length of 30. So it would be 30/18

The side corresponding to side labeled "x" has a length of 24. so it would be x/24

So we would have

45 / 27 = 30 / 18 = x / 24

Now let's find x

We only need 2 ratios ( the one including x of course, and the other one can either be 30/18 or 45/27)

30 / 18 = x / 24

Now let's solve for x

Cross multiply

30*24=720

18*x=18x

We now have 18x = 720

Divide both sides by 18

18x / 18 = x

720 / 18 = 40

x = 40

To check our answers we can see if the ratios are similar

If they are then we are correct

45/27 = 1.66

30/18 =1.66

40/24 = 1.66

They are all equivalent meaning that our answers are correct

Answer:

[tex] = \frac{ - xy + {y}^{4} + {y}^{3} + {x}^{3}y + {x}^{3} - {x}^{2} }{x {y}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} } [/tex]

Step-by-step explanation:

[tex]( \frac{x}{y} + \frac{y}{x - 1} ) + ( \frac{ {x}^{2} }{ {y}^{2} } - \frac{x}{y + 1} )[/tex]

[tex] \frac{xy \times (x - 1) \times (y + 1) + {y}^{3} \times (y + 1) + {x}^{2} \times (x - 1) \times (y + 1) - {xy}^{2} \times (x - 1)}{ {y}^{2} \times (x - 1) \times (y + 1)} [/tex]

[tex]\frac{( {x}^{2} y - xy) \times (y + 1) + {y}^{4} + {y}^{3} + ( {x}^{3} - {x}^{2} ) \times (y + 1) - {x}^{2} {y}^{2} + {xy}^{2} }{( {xy}^{2} - {y}^{2} ) \times (y + 1)}[/tex]

[tex] \frac{ {x}^{2} {y}^{2} + {x}^{2} y - {xy}^{2} - xy + {y}^{4} + {y}^{3} + {x}^{3} y + {x}^{3} - {x}^{2}y - {x}^{2} - {x}^{2} {y}^{2} + {xy}^{2} }{( {xy}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} ) } [/tex]

[tex] = \frac{ - xy + {y}^{4} + {y}^{3} + {x}^{3}y + {x}^{3} - {x}^{2} }{x {y}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} } [/tex]

Answer:

2

Step-by-step explanation:

When the Center of dilation is inside the figure

When the Center of dilation is outside the figure

    3. The original figure is closer to the the center of dilation

    4. The dilated figure is closer to the center of dilation

The center of dilation is the fixed point from which the distances in a dilation are measured

The scale factor is ratio of the side lengths of an original figure or preimage to  the side lengths of the newly formed image

Center of dilation is inside the figure

The distance of a point on the dilated figure, including the distances from the center of dilation is 3 times the distances of points on the original image from the center of dilation

Therefore, the original figure has a shorter distance to and is therefore closer to the the center of dilation than the dilated figure

     2. Where the center of dilation is inside the figure, and the scale factor is a fraction between 0 and 1 k = 1/2, we have;

The distance of a point on the dilated figure, including the distances from the center of dilation is 1/2 times the distances of points on the original image from the center of dilation

Therefore, the dilated figure has a shorter distance to and is therefore closer to the the center of dilation than the original figure

Center of dilation outside the figure

     3. Given that the center of dilation is outside the figure and the scale factor is larger than 1, k = 120% = 120/100 = 1.2 > 1, we have;

The distance of the dilated figure from the center of dilation is 120% of the distance of the original figure from the center of dilation, therefore, the original figure is closer to the the center of dilation than the dilated figure

     4. Where the center of dilation is outside the figure and the scale factor is a fraction between 0 and 1, k = 0.1 < 1

The distance of the dilated figure from the center of dilation is only 0.1 times the distance of the original figure from the center of dilation, and therefore, the dilated figure is closer to the center of dilation

Learn more about scale factors and center of dilation here;

https://brainly.com/question/12162455

Answer:

1. 39-14a

2. (21*x-5/4) to power of 1/2

3. 2(I9 +10rI+4)

4. 25xsquared -100x+76/4

Step-by-step explanation:

Answer:

Factors of 1458 are 1, 2, 3, 6, 9, 18, 27, 54, 81, 162, 243, 486, 729, 1458. There are 14 integers that are factors of 1458. The biggest factor of 1458 is 1458. Positive integers that divides 1458 without a remainder are listed below.

Answer:

geometric

x=number of terms

∑ 2(-5)^(k-1)

k=1

Step-by-step explanation:

the sequence has a ratio of -5 (2*-5=-10, -10*-5=50)

x=number of terms

∑ 2(-5)^(k-1)

k=1

for this i don't know what the last term is since it doesn't show in the question but just find 2(-5)^x and x will be the top term

Answer:

"t" is not a specific thing, this is just the sign of your variable.

t = 4 × 2.5

t = 10

Answer:

[tex]24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]

Step-by-step explanation:

[tex]2\sqrt{8x^{3} } (3\sqrt{10x^{4} } -x\sqrt{5x^{2} } )[/tex]

[tex]=2.2x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]

[tex]=4x\sqrt{2x} (3x^{2} \sqrt{10} -x^{2} \sqrt{5} )[/tex]

[tex]=12x^{3} \sqrt{2xx10} -4x^{3} \sqrt{2xx5}[/tex]

[tex]=24x^{3} \sqrt{5x} -4x^{3} \sqrt{10x}[/tex]

OAmalOHopeO