What is the solution (x, y) to this system of linear equations? 2x – 3y = –6 x + 2y = 11

Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

5^3  y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2​

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2​​

Combine like terms

5 * 5^2  * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3  y^5

125 y^5

Answer:

B

Step-by-step explanation:

11q + 5 ≤ 49

Subtract 5 from each side

11q + 5-5 ≤ 49-5

11q ≤44

Divide each side by 11

q ≤44/11

q≤4

There is a close circle at 4 because of the equals sign and the lines goes to the left

Answer:

B

Step 1:

To solve this, we need to isolate the variable q. To do so, we will subtract 5 from both sides of the inequality.

[tex]11q+5(-5)\leq 49(-5)\\11q\leq 44[/tex]

Step 2:

We divide both sides by 11 to get our q.

[tex]\frac{11q}{11}\leq \frac{44}{11} \\q\leq 4[/tex]

q ≤ 4

Step 3:

To find the correct graph, we need to know that a close circle means a ≤ or ≥ and an open one means a < or >. Here, we are using a ≤ so C and D are not our answers. Also remember that if the "arrow" is pointing left (<), then the arrow on the graph should be facing the left side. If the arrow is facing the right side, then that means we are using > or ≥. Here, we are using ≤ (left), so that means the arrow on the graph should be on a 4, facing left, with a closed circle.

Our answer is B.

Answer:

Not a solution

Step-by-step explanation:

We want to check and see if 5 is a solution to the inequality. Therefore, we must substitute 5 into the inequality.

[tex]10+7g < 44[/tex]

Plug 5 in for g.

[tex]g=5[/tex]

[tex]10+7(5) < 44\\[/tex]

First, multiply 5 and 7.

[tex]10 + (7*5) < 44[/tex]

[tex]10 + 35 < 44[/tex]

Next, add 10 and 35.

[tex](10+35) < 44[/tex]

[tex]45 < 44[/tex]

This statement is not true. 45 is not less than 44. Therefore, 5 is not a solution.

Answer:

it is not a solution

Step-by-step explanation:

By replacing the letter g with a 5 the answer would be 45<44 which is not true

Answer:

The answer is "[tex]\bold{\frac{2}{n}}[/tex]".

Step-by-step explanation:

considering [tex]Y_1, Y_2,........, Y_n[/tex] signify a random Poisson distribution of the sample size of n which means is λ.

[tex]E(Y_i)= \lambda \ \ \ \ \ and \ \ \ \ \ Var(Y_i)= \lambda[/tex]

Let assume that,  

[tex]\hat \lambda_i = \frac{Y_1+Y_2}{2}[/tex]

multiply the above value by Var on both sides:

[tex]Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )[/tex]

            [tex]=\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\[/tex]

now consider [tex]\hat \lambda_2[/tex] = [tex]\bar Y[/tex]

[tex]Var (\hat \lambda_2 )= Var(\bar Y )[/tex]

             [tex]=Var \{ \frac{\sum Y_i}{n}\}[/tex]

             [tex]=\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\[/tex]

For calculating the efficiency divides the [tex]\hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2[/tex] value:

Formula:

[tex]\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}[/tex]

                  [tex]=\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}[/tex]

Answer:

Thomas should not reject the null hypothesis.

Step-by-step explanation:

The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value.  Here in this question the test value is -1.73346 and p-value is 0.0830. The p value is greater than the test value therefore the null hypothesis should be accepted.

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

Answer:

So first you do $0.50 x 3 = 1.5

then you add that to $12.00

$12.00 + 1.5 = 13.5

13.5 is the cost of one pizza.

Since they bought 12:

The total cost of the 12 pizza is $162 <== not important

13.5 divided by 8 is 1.687

round 1.56875 to the nearest cent 1.7 = $2

so each slice costs $2

Answer:

[tex]$\mathbf{\frac{1}{19} }[/tex]

Step-by-step explanation:

[tex]$$\bullet \Nth \ Term;\\$$$\frac{n+2}{2n^{2} +3n-2}[/tex]

[tex]$$\bullet U_{10} \ Term;\\\\$$\boxed{\frac{(10+2) }{2*10^{2} +3*10-2}= \frac{1}{19} }[/tex]

Answer:

[tex]\boxed{\displaystyle \frac{1}{19}}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{n+2}{2n^2 +3n-2}[/tex]

Replace n with 10 to find the 10th term.

[tex]\displaystyle \frac{10+2}{2(10)^2 +3(10)-2}[/tex]

Evaluate.

[tex]\displaystyle \frac{12}{2(100) +30-2}[/tex]

[tex]\displaystyle \frac{12}{200 +30-2}[/tex]

[tex]\displaystyle \frac{12}{228}[/tex]

Simplify.

[tex]\displaystyle \frac{1}{19}[/tex]

[tex]f(f(3))=2\cdot3^2+1=19\\f(f(f(f(3))))=2\cdot19^2+1=723[/tex]

Answer:

Segment LM Corresponds to RQ    

Segment R corresponds to angle M

Answer:

Step-by-step explanation:

six hundred men,six hundred men with big mouths to feed

Answer:

Option (D) : (3.5, 8.75)

Answer:

C. [tex] y = 3\sqrt{7} [/tex]

Step-by-step explanation:

Based on the right triangle altitude theorem, the altitude, y, in the diagram above, equals the geometric mean of 9 and 7.

This implies => [tex] y = \sqrt{9*7} [/tex]

Thus, solve for y.

[tex] y = \sqrt{9} * \sqrt{7} [/tex]

[tex] y = 3\sqrt{7} [/tex]

The answer is C. [tex] y = 3\sqrt{7} [/tex]

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf =  {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf  = 30184 / 1241

Δf  = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41  

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

Answer:

B) 2

/////////////////

Step-by-step explanation:

Let minimum score on the final exam to earn an A be X

[tex]mean \: = \frac{sum \: of \: observation}{number \: of \: observation} [/tex]

[tex]90 = \frac{83 + 97 + 89 + 82 + x}{5} [/tex]

Further solving :

X = 99 marks

Answer:

-6

Step-by-step explanation:

-18 + 2k    wherre k = 6

=> -18 + 2(6)

=> -18 + 12

=> -6

Answer:

x=3

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x(x)

Divide each side by x

3x(x+1)/x = 4x(x)/x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x

3x+3-3x= 4x-3x

3 =x

Answer:

x = 3

Step-by-step explanation:

0 is a rediculas answer 9 and 12 are to big.

The lines are supposed to have a simular length:

3(3) + 4 = 13

4(3) + 3 = 15

These are the best answers that fit.

Hey there! I'm happy to help!

When rotating a point 90 degrees clockwise about the origin, our original point (x,y) becomes (-y,x), because it is now at a negative y-value.

We see that our point P is at (1,2). We can use this rotation formula to find the coordinates of P' (the new spot where P is)/

(x,y)⇒(-y,x)

(1,2)⇒(-2,1)

Therefore, the coordinates of the point P' are (-2,1).

Have a wonderful day! :D

Answer:

V = 523 in^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

V = 4/3 ( 3.14) * 5^3

V = 523.33333repeating

Rounding to the nearest inch^3

V = 523 in^3

Answer:

[tex] 523.6 {in}^{3} [/tex]

Step-by-step explanation:

[tex]v = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi \times 5 \times 5 \times 5 \\ = 523.6 {in}^{3} [/tex]

Answer:

Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].

Step-by-step explanation:

Equivalent fractions are set of fractions in which when simplified, they have the same answer.

Given: [tex]\frac{3}{11}[/tex]

i. multiply the numerator and denominator of [tex]\frac{3}{11}[/tex] by 2,

          = [tex]\frac{3*2}{11*2}[/tex] = [tex]\frac{6}{22}[/tex]

i. multiply both the numerator and denominator of [tex]\frac{6}{22}[/tex] by 4,

          = [tex]\frac{6*4}{22*4}[/tex]= [tex]\frac{24}{88}[/tex]

ii. multiply the numerator and denominator of [tex]\frac{24}{88}[/tex] by 6,

          = [tex]\frac{24*6}{88*6}[/tex] = [tex]\frac{144}{528}[/tex]

So that;

             [tex]\frac{3}{11}[/tex] = [tex]\frac{6}{22}[/tex] = [tex]\frac{24}{88}[/tex] = [tex]\frac{144}{528}[/tex].

Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].

Answer:

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions

Step-by-step explanation:

set = {0,1,2,3,4,5,6,7,8,9}

setting up a one-to-one correspondence between the set of real numbers between 0 and 1

The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1

hence The power set of (n) is uncountable and is equivalent to the set of real numbers given

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions

Answer:

= - 54

Step-by-step explanation:

- 99 + 3^2•5

- 99 + 9 × 5

- 99 + 45

= - 54

Answer:

(A) 1

(B) -2

(C) 3.5

(D) -0.5

Step-by-step explanation:

We can treat each thermometer like a vertical number line and read the values on each.

A is right on 1.

B is right on -2.

C is in the middle of 3 and 4, so 3.5

D is in the middle of 0 and -1, so -0.5

Hope this helped!

Answer:

[tex]-1 \frac{3}{4}[/tex]

Step-by-step explanation:

Using this number line, we can plot our original number - [tex]\frac{3}{4}[/tex] (see picture attached)

Adding a negative is the same thing as subtracting - so we are subtracting [tex]2\frac{1}{2}[/tex] from  [tex]\frac{3}{4}[/tex].

To subtract this, we can break up [tex]2\frac{1}{2}[/tex]  into 3 parts: 1, 1, and [tex]\frac{1}{2}[/tex]. We can subtract each of these from the current number and see where we land up. (again see picture)

We land up at [tex]-1 \frac{3}{4}[/tex].

Hope this helped!

Answer:

Multiply using the distributive property.

D is the best answer.

Step-by-step explanation:

The simplified form of expression 3x (4x - 3) is 12x² - 9x.

An algebraic expression is consists of variables, numbers with various mathematical operations,

The given expression is,

3x (4x - 3).

Simplify the expression by solving bracket term,

3x × (4x) - 3 x (3x)

12x² - 9x

The given expression can be simplified as 12x² - 9x.

Hence, option (D) is correct.

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Answer:

13

Step-by-step explanation:

let the number be x

how Cindy worked it out :

(x -6) ÷ 3 = 25

x -6 = 75

x = 81

How she should have worked it out:

(x - 3) ÷ 6

(81 - 3) ÷ 6

78 ÷ 6 = 13

Answer:

-12

Step-by-step explanation:

-7+(-5)=

-7-5=

-12

Answer:

[tex] \boxed{f(x) = 2 {x}^{9} - 4 {x}^{2} + 4}[/tex]

Option B is the correct option

Step-by-step explanation:

By looking at the end behavior , we can say that the degree of the polynomial must be odd and leading coefficient will be positive.

Thus , the correct choice is B.

Hope I helped!

Best regards!

The polynomial function that could have created the given curve on the xy-plane is [tex]f(x)= 2x^9-4x^2+4[/tex]

Polynomial functions aree function having a leading degrees of 3 and greater.

The nature of the curve on the xy-plane depends on its end behaviour. From the given graph, the end behaviour shows that the equivalnt function has a positive leading coefficient and an odd degree.

From the listed option, the function that satisfies both criteria is [tex]f(x)=2x^9-4x^2+4[/tex].

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Answer:

a

Step-by-step explanation:

its a

The answer is m = 3000 - 40h

m = 1200 + 50h.

The answer is option A.

Problem-solving is the act of defining a problem; figuring out the reason for the hassle; identifying, prioritizing, and selecting options for an answer; and enforcing an answer.

Problem-solving begins with identifying the issue. For example, a teacher would possibly need to parent out a way to enhance scholar performance on writing scalability take a look at it. To do this, the trainer will assess the writing tests seeking out regions for improvement.

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