Answer:
Mean = 2.33
Step-by-step explanation:
Given that,
conceded goals : 0 1 2 3 4
Frequency : 2 8 4 10 6
Mean,
[tex]M=\dfrac{\Sigma fx}{\Sigma f}\\\\M=\dfrac{0\times 2+1\times 8+2\times 4+3\times 10+4\times 6}{2+8+4+10+6}\\\\=\dfrac{70}{30}\\\\M=2.33[/tex]
So, the required mean is 2.33.
Line A is represented by the following equation: X + y = 2
What is most likely the equation for line B so the set of equations has no solution?
Answer:
x+y=3
Step-by-step explanation:
For an equation to have no solution, their slope needs to be same and y intercept needs to be different,
so in this case where x+y=2
doing simply, x+y=3 makes a set of equation which has no solution, you can take any real value which is not 2
In the picture below, which lines are lines of symmetry for the figure?
Which angles are adjacent to each other?
Angle 8 and Angle 4
Angle 3 and Angle 6
Angle 2 and Angle 7
Angle 4 and Angle 3
Answer:
<4 and <3
Step-by-step explanation:
Adjacent angles are two angles that have a common vertex and a common side but do not overlap.
I hope this helps.
Answer:
angles 4 and 3
Step-by-step explanation:
its the right answer
a triangle has a base measuring 6 feet and a height measuring 8.3 feet. How many triangles of this area would fit inside a rectangle with a width 12 feet and a length of 33.2 feet?
Area of the triangle = 1/2 x base x height
Area of triangle = 1/2 x 6 x 8.3 = 24.9 square feet.
Area of rectangle = length x width
Area of rectangle = 33.2 x 12 = 398.4 square feet.
To find the number of triangles that can fit in the rectangle divide the area of the rectangle by the area of the triangle:
398.4 / 24.9 = 16
Answer: 16 triangles
I need some help with math
#1 rewrite this in standard form, then state the center of the circle as an ordered pair and identify the radius. Show your work
y^(2)-14y+x^(2)-4x+37=0
#2 Write the equation of the circle with center (-2,15) and radius 3.
Answer:
[tex](y-7)^2+(x-2)^2=16[/tex]
and
[tex](x+2)^2+(y-15)^2 = 9[/tex]
Step-by-step explanation:
The standard equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex] where the coordinate (h,k) is the center of the circle.
Second Problem:
We can start with the second problem which uses this info very easily.(h,k) in this problem is (-2,15) simply plug these into the equation. [tex](x--2)^2+(y-15)^2=r^2[/tex] .We can also add the radius 3 and square it so it becomes 9. The equation.This simplifies to [tex](x+2)^2+(y-15)^2 = 9[/tex].First Problem:
The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.[tex]y^2-14y+x^2-4x+37=0[/tex] first subtract 37 from both sides so the equation is now [tex]y^2-14y+x^2-4x=-37[/tex].[tex]y^2-14y+x^2-4x+37=0[/tex] by adding [tex](-\frac{b}{2a} )^2[/tex] to both the x and y portions of this equation you can complete the squares. [tex](-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2[/tex] and [tex](-\frac{-4}{2(1)})^2[/tex] which equals 49 and 4.Add 49 and 4 to both sides and the equation is now:[tex]y^2-14y+49+x^2-4x+4=-37+49+4[/tex] You can simplify the y and x portions of the equations into the perfect squares or factored form [tex](y-7)^2[/tex] and [tex](x-2)^2[/tex].Finally put the whole thing together. [tex](y-7)^2+(x-2)^2=16[/tex].I hope this helps!
Which best describes the relationship between the lines with equations −6x+8y=−1 and −4x−3y=2?
Answer:
it is linear
Step-by-step explanation:
Both of these both lines are perpendicular to each other.
We have the two equations of straight lines :
− 6x + 8y = −1 and −4x − 3y = 2.
We have to identify the relation between these two lines.
What is the general equation of a straight line ?The general equation of a straight line is as follows -
y = mx + c
where -
m - slope of line
c - intercept of line on y - axis.
According to the question, we have -
−6x + 8y = −1 ...(1)
−4x − 3y = 2 ...(2)
Rearranging the terms of the equations we get -
y = [tex]\frac{3}{4} x - \frac{1}{8}[/tex] ...(3)
and
y = [tex]\frac{-4}{3}x - \frac{2}{3}[/tex] ...(4)
When compared -
The slope of line −6x + 8y = −1 is m(1) = [tex]\frac{3}{4}[/tex].
The slope of line −4x − 3y = 2 is m(2) = [tex]\frac{-4}{3}[/tex].
We can see that -
m(1) x m(2) = - 1
The product of the slopes of two perpendicular lines is -1.
Hence, these both lines are perpendicular to each other.
To solve more questions on relation between straight lines, visit the link below -
brainly.com/question/13792781
#SPJ2
please solve this please
Answer:
C) [tex]\frac{2z+15}{6x-12y}[/tex]
E) [tex]\frac{7d+5}{15d^2+14d+3}[/tex]
F) [tex]\frac{-7a-b}{6b-4a}[/tex]
Step-by-step explanation:
C)
One is given the following equation
[tex]\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}[/tex]
In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is ([tex]6x-12y[/tex]). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,
[tex]\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}[/tex]
[tex]\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}[/tex]
Simplify,
[tex]\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}[/tex]
[tex]\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}[/tex]
[tex]\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}[/tex]
[tex]\frac{6z+6-6z+9+2z}{6x-12y}[/tex]
[tex]\frac{2z+15}{6x-12y}[/tex]
E)
In this case, one is given the problem that is as follows:
[tex]\frac{2}{3d+1}-\frac{1}{5d+3}[/tex]
Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ([tex](3d+1)(5d+3)[/tex])
[tex]\frac{2}{3d+1}-\frac{1}{5d+3}[/tex]
[tex]\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}[/tex]
Simplify,
[tex]\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}[/tex]
[tex]\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}[/tex]
[tex]\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}[/tex]
[tex]\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}[/tex]
[tex]\frac{10d+6-3d-1}{(3d+1)(5d+3)}[/tex]
[tex]\frac{7d+5}{(3d+1)(5d+3)}[/tex]
[tex]\frac{7d+5}{15d^2+14d+3}[/tex]
F)
The final problem one is given is the following:
[tex]\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}[/tex]
For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is ([tex]6b-4a[/tex]). Multiply the first fraction by a certain value to attain this denomaintor,
[tex]\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}[/tex]
[tex]\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}[/tex]
Simplify,
[tex]\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}[/tex]
[tex]\frac{-6a}{6b-4a}-\frac{a+b}{6b-4a}[/tex]
[tex]\frac{(-6a)-(a+b)}{6b-4a}[/tex]
[tex]\frac{-6a-a-b}{6b-4a}[/tex]
[tex]\frac{-7a-b}{6b-4a}[/tex]
x>0, y>0, 2x+3y=8, smallest value of xy? pls help me
Answer:
where there is x in the equation we put 0
For y
=2(0)+3y=8
=0+3y=8 Group likely terms
=3y=8-0
=3y=8 Divide both sides by 3
=3y/3=8/3
Therefore y=2.6
For x
=2x+3y=8
=2x+3(0)=8
=2x+0=8 Group likely terms
=2x=8-0
=2x=8 Divide both sides by 2
=2x/2=8/2
Therefore x=4
The smallest numbers for x and y is 4 and 2.6 respectively
find the missing side.
Answer:
I htink x ≈ 8
Step-by-step explanation:
Answer:
X is approximately 7.8.
Step-by-step explanation:
You can use SOH-CAH-TOA to help figure out what function (sin, cos, tan) you need to use in order to figure out the missing side.
For this one, we can see the angle is pointing to the opposite side (x length), and we have been given the hypotenuse (18). So we want to use the sin function.
[tex]sin\ (angle)=\frac{opposite}{hypotenouse}[/tex]
[tex]sin (26)=\frac{x}{18}[/tex]
[tex]0.438=\frac{x}{18}[/tex]
[tex]7.890... = x[/tex]
Using Pythagorean theorm, you can figure out the other side if need be :)
For reference:
[tex]sin (angle)=\frac{opposite}{hypotenuse}[/tex]
[tex]cos(angle)=\frac{adjacent}{hypotenuse}[/tex]
[tex]tan(angle)=\frac{opposite}{adjacent}[/tex]
can a triangle have two right angles ?explain
Answer:
a triangle is a closed polygon that consists of three sides and three angles,and it's one of the basic shape that we basic shape that we knowing geometry.
What is the period of the graph of y=1/2 sin (2πx) -3?
A. 1
B. 1/2
C. 3
D. 2π
Answer:
A. 1
Step-by-step explanation:
Since this graph is in the form A sin (B(x+c))+d, where
the amplitude is the absolute value of AThe period is 2pi/BPhase Shift is CMidline is y=DTherefore, the values are
A=1/2
B=2pi
C=0
D=-3
So the period is 2pi/2pi which is 1.
Please help me solve this!
Answer:
Step-by-step explanation:
Reference angle = 27
height = 2
Sin(27) = opposite / hypotenuse
hypotenuse = opposite / sin(27)
opposite = 2
hypotenuse = 2 / sin(27)
hypotenuse = 4.405
The ramp has to be 4.41 feet long.
Complete the statement with always, sometimes, or never. Explain your reasoning.
An altitude is _____ the same line segment as an angle bisector.
Step-by-step explanation:
it's ur answers I hope it's helpful
Hola pordrian ayudarme con esto:
Resuelve las ecuaciones aplicando la fórmula general
a) 2xsobre2-7×+3=0
Hace mucho que ni hacia este tipo de problemas y por eso les pido su ayuda
Answer:
sorry I don't understand can somebody help him??
HELP PLS HELP MEEEEE IM FAILING PYTHAGOREAN THEOREM
7^2 + 6^2 = h^2
49 + 36 = h^2
85 = h^2
√85 = h
h = 9.21m
Answered by Gauthmath must click thanks and mark brainliest
Write the equation of the line with a slope of 4 that contains the point (5, 8).
Answer:
y = 4x - 12
Step-by-step explanation:
y = 4x + b
8 = 4(5) + b
8 = 20 + b
-12 = b
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \maltese \bf \: \: \: we \: know \: that \: \\ \sf \: if \: any \: equation\:of \: line \: which \: slope (m) \\ \sf \: and \: passes \: through \: (x_1,y _1) \: \: then \: its \\ \sf equation \: is \: : \\ \\ \red{ \boxed{ \bf y - y_1 = m(x - x_1)}}\bf\end{array}}}}[/tex]
Given that,
A equation of the line with a slope of m = 4 and that contains / passes through the point (5, 8).
So,
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: x_1 = 5 \: \: \: \\ \bf y_1 = 8 \\ \bf \: m \: = 4 \: \: \end{array}}}}[/tex]
NOW,
The equation is :
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: y - 8 = 4(x - 5) \\ \\ = > \bf \: y - 8 = 4x - 20 \\ \\ = > \pink{ \boxed{\bf\:4x - y - 12 = 0}} \end{array}}}}[/tex]
Step by step solution
Answer:
b is correct answer
Step-by-step explanation:
when we write logarithmic terms we change the result from number which is power of 3
Find the standarddeviation of 125, 136, 150, 119, 150, and 143.
Answer:
S.D=46.04
Step-by-step explanation:
steps are in the picture.
If you have question about it you can ask.Thanks
See pic below! Need help solving
Answer:
383.54 m
Step-by-step explanation:
The length of the training track running around the field = circumference of the circle formed by the two semicircles + 2(length of the rectangle)
The two semicircles forms a fill circle with diameter (d) = width of rectangle = 61 m
Length of rectangle (L) = 96 m
π = 3.14
The length of the training track running around the field = πd + 2(L)
Substitute the values
The length of the training track running around the field = 3.14*61 + 2(96)
= 191.54 + 192
= 383.54 m
Help anyone can help me do this question,I will mark brainlest.
Step-by-step explanation:
we first find area of the whole shape outer core which is
we use the fomulae of a circle 22/7 represent pie
=1/2 *22/7*8,5
=13,36
then we find the inner core of the shape which is
1/2*22/7*5,5
=8,64
then we substracte to get the shaded part 13,36-8,64
=4,72cm
Answer:
≈ 16.5 cm²
Step-by-step explanation:
The area of the bar (A) is
(area of outer circle - area of inner circle) ÷ 2
r₂ = 8.5 ÷ 2 = 4.25 , r₁ = 5.5 ÷ 2 = 2.75 , then
A = (πr₂² - πr₁²) ÷ 2
= (π(r₂² - r₁²) ) ÷ 2
= (π(4.25² - 2.75²) ) ÷ 2
= (π(18.0625 - 7.5625) ) ÷ 2
= (10.5π)÷ 2
≈ 16.5 cm² ( to the nearest tenth )
Could anyone please help me with this question, this is my last one?
#iamarookie
Giving away 15 points this time and I just need help on QUESTION B!
Answer:
28 = 2² x 7
Step-by-step explanation:
Factors of 28: 1, 2, 4, 7, 14, 28.
Prime factorization: 28 = 2 x 2 x 7, which can also be written 28 = 2² x 7.
If the graph of f(x) = x^2, how will the graph be affected if it is changed to f(x) = 3r^2?
Answer:
the graph curve will goes above f(x)=x^2.f(x)=3*x^2 curve will also give higher value same value of x .
Step-by-step explanation:
am thinking of a number multiplying it by 4 then subtracting 6 the answer is greater than 14. Write the inequality
plss answer hihihihihihihihiihihihihihihihihihihih
Answer:
C - 60
Step-by-step explanation:
4x^2 = 144
x = 6
p=10*6
P=60
Answer:
hi, thanks for asking! the answer to this question is, 108.
Step-by-step explanation:
first, you must think how much it adds up to if u add the numbers toghether. then, boom!
hope this helps<3
1. In a group of 500 students, 280 like bananas, 310 like apples, and 55 dislike both the fruits.
i) Find the number of students who like both the fruits.
ii) Find the number of students who like only one fruits.
iii) Show the result in venn-diagram
Answer:
Please see the attached images
Step-by-step explanation:
Michelle gets10rewards points for each of her purchases at Starbucks. With 500 rewards points, she can get a free smoothie. If she has 370 points saved, how many purchases will it take her to get her free smoothie?
she needs 130 points saved up
Answer:
13
Step-by-step explanation:
Please answer this!!
Answer:
C, 5/12
Step-by-step explanation:
The tangent of an angle is defined as the side opposite to that angle divided by the side adjacent to that angle. The tangent of angle A would be equal to the value of side BC divided by side AB. The value of side BC is 5, and the value of side AB is 12. The answer is 5/12.
Answer: ∠A=[tex]\frac{5}{12}[/tex]
Step-by-step explanation:
Tangent is opposite over adjacent.
The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the
sequence?
Answer:
53=-3+14d
56=14d
d=4 that is the common difference
Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
Answer:
m∠TRS = 6°
m∠U = 103°
Step-by-step explanation:
In the given figure,
O is the center
RS ∥ VU
m∠V = 103° &
m∠VRT = 71°
So,
m∠V + m∠R = 180° (∵ sum of co-interior angles)
⇒ m∠R = 180° - 103° (m∠V = 103° is given)
∵ m∠R = 77° ...(i)
Now,
m∠R = m∠TRS + m∠VRT
by putting the values given
⇒ m∠TRS = 77° - 71°
∵ m∠TRS = 6°
As we know that,
VURT is a cyclic quadrilateral. So,
m∠U + m∠R = 180°
⇒ m∠U + 77° = 180° (from equation (i)
∵ m∠U = 180° - 77° = 103°
I need help for this question 3 so can anyone help me please
