What is the mean for the set of data shown below? (Careful mean and median are different measures)

27, 32, 14, 19, 24, 26, 22, 32, 29

Answer:

[tex]216\ km^2[/tex]

Step-by-step explanation:

1. Approach

The surface area of a three-dimensional figure is the two-dimensional distance around the figure.  The easiest way to find the surface area of a figure is to find the area of each of its facets, then add up the area to get the total surface area. The given pyramid is composed of four congruent triangles and a square. Find the area of one of the triangles, and then the area of the rectangle. Multiply the area of the triangle by four to account for the fact that there are four congruent triangles. Then add the area of the base to the result, the result attained is the surface area of the prism.

2. Find the area of the triangles

The formula to find the area of a triangle is the following:

[tex]A_t=\frac{b*h}{2}[/tex]

Where (b) represents the base and (h) represents the height of the triangle. Substitute the given values into the formula and solve for the answer.

[tex]A_t=\frac{b*h}{2}[/tex]

[tex]A_t=\frac{9*7.5}{2}[/tex]

[tex]A_t=\frac{67.5}{2}[/tex]

[tex]A_t=33.75[/tex]

3. Find the area of the rectangle

The formula to find the area of a rectangle is the following,

[tex]A_r=b*h[/tex]

Substitute the given values in and solve,

[tex]A_r=b*h[/tex]

[tex]A_r=9*9[/tex]

[tex]A_r=81[/tex]

4. Find the total surface area

Multiply the area of the triangle by four to account for the fact that there are four triangles. Then add its area to the area of the rectangle.

[tex]A_t+A_t+A_t+A_t+A_r=A[/tex]

[tex]4(A_t)+(A_r)=A[/tex]

[tex]4*33.75+81=A[/tex]

[tex]135+81=A[/tex]

[tex]216=A[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

1a. Vertical angles share a vertex and are composed of opposite rays. Here, angles 2 and 4 are vertical angles.

1b. Consecutively numbered angles are adjacent, as are angles 1 and 5. The pairs of interest can be chosen from ...

  1&2, 2&3, 3&4, 4&5, 5&1

__

2. Angles 1 and 3 have the same measure, because they are vertical angles. Then we have ...

  78° = (5x -2)°

  80 = 5x . . . . . . . divide by °, add 2

  16 = x . . . . . . . divide by 5

Answer:

2*3+5=11

Step-by-step explanation:

Answer:

[tex]\boxed {\boxed {\sf 11}}[/tex]

Step-by-step explanation:

We are given the following function and asked to find the output if the input is 3.

[tex]f(x)= 2x+5[/tex]

The input is what is plugged into the function and its variable is x. The output is the result of plugging in the input and its variable is y.

Substitute 3 in for x,

[tex]f(3)= 2(3)+5[/tex]

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. Multiply 2 and 3.

[tex]f(3)= 6+5[/tex]

Add.

[tex]f(3)= 11[/tex]

If the input is 3, then the output is 11.

Answer:

x=–2

Step-by-step explanation:

x-8=-10

x=-10-8

x=–2

Answer:

-8= -10

, = -10+8

, = -2

Answer:

y = 54/25 when x = 4.

Step-by-step explanation:

y is given by the equation:

[tex]\displaystyle y = p\times q^{x-1}[/tex]

Where p and q are numbers.

We are also given that when x = 1, y = 10 and when x = 6, y = 0.7776.

And we want to determine the value of y when x = 4.

Since y = 10 when x = 1:

[tex]\displaystyle (10) = p\times q^{(1)-1}[/tex]

Simplify:

[tex]10 = p \times q^0[/tex]

Any number (except for zero) to the zeroth power is one. Hence:

[tex]p=10[/tex]

Thus, our equation is now:

[tex]y = 10\times q^{x-1}[/tex]

When x = 6, y = 0.7776. Thus:

[tex](0.7776) = 10\times q^{(6)-1}[/tex]

Simplify and divide both sides by ten:

[tex]\displaystyle 0.07776 = q^5[/tex]

Take the fifth root of both sides:

[tex]\displaystyle q = \sqrt[5]{0.07776}[/tex]

Use a calculator. Hence:

[tex]\displaystyle q = \frac{3}{5} = 0.6[/tex]

Our completed equation is:

[tex]\displaystyle y = 10\times \left(\frac{3}{5}\right)^{x-1}[/tex]

Then when x = 4, y equals:

[tex]\displaystyle \begin{aligned} y &= 10\times \left(\frac{3}{5}\right)^{(4)-1} \\ \\ &= 10\times \left(\frac{3}{5}\right)^3 \\ \\ &= 10\times \left(\frac{27}{125}\right) \\ \\ &= \frac{54}{25}\end{aligned}[/tex]

Answer:

Step by step proof shown below.

Step-by-step explanation:

To prove the equation, you need to apply the Logarithm quotient rule and the Logarithm power rule. Here's how the quotient rule looks like.

[tex]log_b(x/y) = log_b(x) - log_b(y)[/tex]

And here's how the power rule looks like

[tex]log_a(x)^n = nlog_a(x)[/tex]

First let's apply the quotient rule.

[tex]\frac{f(x+h)-f(x)}{h} = \frac{log_a(x+h)-log_a(x) }{h} = \frac{log_a(\frac{x+h}{x} )}{h}[/tex]

Now we can do some quick simplification, and apply the power rule.

[tex]\frac{1}{h} log_a(1 + \frac{h}{x} ) = log_a(1+\frac{h}{x} )^\frac{1}{h}[/tex]

Answer:

Where is the rest?

Step-by-step explanation:

%7"7:7;9

A fraction means division.

To find the decimal equivalent of a fraction, divide the top number by the bottom number.

Answer:

114 cm²

Step-by-step explanation:

Surface area of the rectangular prism,

2×(wl+hl+hw)

=2×(3×8+3×8+3×3)

= 2×(24+24+9)

= 2×(57)

=114 cm²

9514 1404 393

Answer:

  0.06164

Step-by-step explanation:

The effective annual rate obtained by compounding nominal annual rate r monthly is ...

  eff rate = (1 +r/12)^12 -1

Then the value of r is ...

  r = 12×((eff rate) +1)^(1/12) -1)

For the given effective rate, that is ...

  r = 12×(1.06341^(1/12) -1) ≈ 0.06164 . . . . nominal annual interest rate

[tex] \frac{ {x}^{2} }{4} - \frac{ {y}^{2} }{21} = 1[/tex]

[tex] \frac{(x - h)^{2} }{ {a}^{2} } - \frac{(y - k) ^{2} }{ {b}^{2} } = 1 \\ [/tex]

[tex]distance = \sqrt{(x2 - x1) ^{2} + (y2 - y1) ^{2} } \\ c = \sqrt{(( - 5) - 0)^{2} + (0 - 0) ^{2} } \\ c = \sqrt{ {5}^{2} } \\ c = 5[/tex]

[tex]b = + \sqrt{21} , - \sqrt{21} [/tex]

[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{0 - 0}{0 - ( -5 )} = 0[/tex]

[tex] \frac{(x - h)^{2} }{ {a}^{2} } - \frac{(y - k) ^{2} }{ {b}^{2} } = 1 \\ [/tex]

[tex]\frac{(x - 0)^{2} }{ {2}^{2} } - \frac{(y - 0) ^{2} }{ { \sqrt{2} }^{2} } = 1 \\ [/tex]

[tex] \frac{ {x}^{2} }{4} - \frac{ {y}^{2} }{21} = 1[/tex]

I hope I helped you^_^

Answer: 15

Step-by-step explanation:

Answer:

Dependent event

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Step-by-step explanation:

Given

[tex]Total = 49[/tex]

[tex]Red = 5[/tex]

Solving (a): Are the events dependent?

Yes, they are.

When the first red candy is selected and eaten, the total number of candies reduced to 48 and the number of red candies also reduced to 4.

So, the probability of selecting a 2nd candy is dependent on the first candy selected.

Solving (b): P(Red = 2)

This is calculated as:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

The first selection has the following probability:

[tex]P(Red) = \frac{Red}{Total}[/tex]

[tex]P(Red) = \frac{5}{49}[/tex]

The second selection has the following probability:

[tex]P(Red|Red) = \frac{Red - 1}{Total - 1}[/tex]

[tex]P(Red|Red) = \frac{5 - 1}{49 - 1}[/tex]

[tex]P(Red|Red) = \frac{4}{48}[/tex]

So, we have:

[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]

[tex]P(Red = 2) = \frac{5}{49} * \frac{4}{48}[/tex]

Reduce fraction

[tex]P(Red = 2) = \frac{5}{49} * \frac{1}{12}[/tex]

Multiply

[tex]P(Red = 2) = \frac{5}{588}[/tex]

Answer:

"Members of a population are organized in clusters, each of which is representative of the population, and then whole clusters are randomly selected to make up the sample"

Step-by-step explanation:

In cluster random sampling, "the population is divided, usually geographically, into groups that generally have the same size.  A certain number of groups are randomly chosen, and every individual in the chosen groups are chosen for the sample."

In accord with this logic, the second choice, "Members of a population are organized in clusters, each of which is representative of the population, and then whole clusters are randomly selected to make up the sample" seems to be correct.

NOTE: This may not be the correct answer. I am simply basing my answer on the definition I have learnt.

Answer:

B

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

It is 8.6 because we are finding the difference and using subtraction.  

So I did 68.8-59.9 and I got 8.6

9514 1404 393

Answer:

   0.0056

Step-by-step explanation:

  f(x) = √(49 +x)

  f'(x) = 1/(2√(49 +x))

A linear approximation of f(x) expanded about x=0 is ...

  f(x) ≈ f(0) + f'(0)x = 7 +x/(2·7)

Then for √53, we have x=4

  f(4) ≈ 7 +4/14 = 7 2/7 . . . . . approximate √53 using differentials

__

The calculator value of √53 is about 7.280110, so the difference in results is ...

  approx - actual ≈ 7.285714 -7.280110 = 0.005604 ≈ 0.0056

Answer:

17.5ml- of 10 percent solution, 17.5ml- of 20 percent solution

Step-by-step explanation:

35:100*15=5.25- ml of alkali in the base solution

Suppose we need x ml of 10 percents solution and 35-x - of 20 percents.

Then The quantity of alkali in the first one (10 percents) is x/100*10=0.1x

when in the second one we have (35-x)/100*20= 7-0.2x of alkali

0.1x+7-0.2x=5.25

7-0.1x= 5.25

0.1x=1.75

x=17.5- 0f 10 percents

35-17.5=17.5 - of 20 percents

Answer:

9

Step-by-step explanation:

90+81+mising angle=180, missing angle is 9

Answer:

the union of l and m is minus 1,1,2,4,5,7,8.....and the intersection of l and m is 1.......

2/3 = 8/12

7/12 = 7/12

3/4 = 9/12

7/12 < 8/12 < 9/12

So, 7/12 < 2/3 < 3/4

Answer:

?

Step-by-step explanation:

Answer:

124,503 round to 125,000

Step-by-step explanation:

4 is in the thousands place

We look at the hundreds place

5 is in the hundreds place.  Since 5 is 5 or greater, we round the 4 up

124,503 round to 125,000

Answer:

i thank the ans id 450

Step-by-step explanation:

Answer:

67

Step-by-step explanation:

DM=JM-JD=84-17=67

Answer:

Step-by-step explanation:

Answer:

$54

Step-by-step explanation:

10% of $60 is $6

$60-$6=$54

Let f = ln(x + √(x ² + y ²)) ln(sin(y/x)).

Then the total differential is

[tex]\mathrm df = \dfrac{\mathrm d\left(x+\sqrt{x^2+y^2}\right)}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\mathrm d\left(\sin\left(\frac yx\right)\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{\mathrm d(x^2+y^2)}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\cos\left(\frac yx\right)\,\mathrm d\left(\frac yx\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{2x\,\mathrm dx+2y\,\mathrm dy}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}}\right)\dfrac{\cos\left(\frac yx\right)\frac{x\,\mathrm dy-y\,\mathrm dx}{x^2}}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\left(2x+\sqrt{x^2+y^2}\right)\,\mathrm dx +2y\,\mathrm dy}{x\sqrt{x^2+y^2}+x^2+y^2\right)\ln\left(\sin\left(\dfrac yx\right)\right) \\\\ \indent + \dfrac1{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}}\right)(x\,\mathrm dy-y\,\mathrm dx)[/tex]

[tex]\mathrm df = \left(\left(\dfrac{2x+\sqrt{x^2+y^2}}{x\sqrt{x^2+y^2}+x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) - \dfrac y{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dx \\\\ \indent + \left(\dfrac{2y}{x\sqrt{x^2+y^2}+x^2+y^2}\ln\left(\sin\left(\dfrac yx\right)\right)+\dfrac1x\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dy[/tex]

Answer:

C. The representative failed to have Tim initial by the fuel level on the Check-Out sheet.

Step-by-step explanation:

After reading the paragraph, we can eliminate B, by seeing that the representative did give him a copy of the Check-Out sheet, as quoted. "Since Tim didn’t have any questions, the clerk handed him the keys and a copy of the Check-Out sheet and wished him well.".

We can also eliminate A and D, as the contract stated nothing about dents or the oil level in the car.

The answer is C, as the representative failed to have Tim initial on the Check-Out sheet. That is a requirement for the contract to be valid, as stated. "The approximate fuel level will be recorded on the Check-Out sheet and verified with initials by the vehicle Renter.". However, Tim never initialed by the fuel level, as stated here. "...the agency representative turned on the car, took note of the fuel level, and indicated it on the Check-Out sheet. Since Tim didn’t have any questions, the clerk handed him the keys and a copy of the Check-Out sheet and wished him well.". No where here does it state that Tim initialed on the Check-Out sheet, meaning that he didn't. Him not doing so invalidates the contract.  

The partial fraction expansion takes the form

-6x/((x + 2) (x + 8)) = a/(x + 2) + b/(x + 8)

Both factors in the denominator are linear, so the numerators in the corresponding partial fractions have degree 1 - 1 = 0 and are thus constants.

Combine the fractions on the right side into one with a common denominator, then set the numerators on both sides of the equation equal to each other:

-6x = a (x + 8) + b (x + 2)

Expand the right side and collect terms by powers of x :

-6x = (a + b) x + (8a + 2b)

It follows that

a + b = -6   and   8a + 2b = 0

==>   a = -2   and   b = 8

So we end up with

-6x/((x + 2) (x + 8)) = -2/(x + 2) + 8/(x + 8)

Answer:

the correct answer is |x – 18| ≤ 4

just took the test

Step-by-step explanation: