James defines an angle as "a figure consisting of two rays." His statement is not precise enough because he should specify that

the rays must be collinear
the rays must form a right angle
the rays must have a common endpoint
the rays must continue in one direction forever

Statement: If two noncollinear rays join at a common endpoint, then an angle is created. Which geometry term does the statement represent?

Defined term
Postulate
Theorem
Undefined term

Step-by-step explanation:

150=45

150 -25=x

:150=45

125=x

cross multiply

150x/150=5625/150

x=38 days

Answer:

The two bottom angles of this triangle are both represented by the same variable, in this case, an x. This means, that both of the bottom angles are equal to each other.

So we have:

32 + x + x = 180 (since the TOTAL angles of a triangle adds up to 180)

32 + 2x = 180 (combine the 2 x's together)

2x = 148 (subtract a 32 from both sides)

x = 74

Let me know if this helps!

Answer:

e. is incorrect

sin (x)= f/e

Answer:

The number is -6.

Step-by-step explanation:

Variable x = a number

Set up an equation:

3x + 12 = -6

Isolate variable x:

3x = -18

x = -6

Check your work:

3(-6) + 12 = -6

-18 + 12 = -6

-6 = -6

Correct!

Answer:

3x +12=-6

3x=-6-12

3x=-18

x=-18/3

x=-6

Answer:

The correct answer is

D) e and l

Given:

The temperature on a mountain peak was 7°F at 6:00 p.m.

By 8:00 p.m., the temperature had dropped to 0°F.

To find:

The temperature at 11:00 p.m. if the temperature continued to drop at about the same rate.

Solution:

Time between 6:00 p.m. to 8:00 p.m. is 2 hours.

Change in temperature in 2 hours is -7°F.

Change in temperature in 1 hours is [tex]-\dfrac{7}{2}^\circ[/tex]F.

Time between 8:00 p.m. to 11:00 p.m. is 3 hours.

Change in temperature in 3 hours is [tex]3\times \dfrac{-7}{2}^\circ[/tex]F, i.e., [tex]-\dfrac{21}{2}^\circ[/tex]F.

Now, the temperature at 11:00 p.m is:

[tex]0-\dfrac{21}{2}=-10.5[/tex]

Therefore, the temperature at 11:00 p.m. is -10.5°F.

Note: All options are incorrect.

I'm sorry but there's not enough info

Step-by-step explanation:

Answer:

The triangle with vertices A (2 , 0) , B (3 , 2) , C (5 , 1) is isosceles right Δ

The triangle with vertices A (-3 , 1) , B (-3 , 4) , C (-1 , 1) is right Δ

The triangle with vertices A (-5 , 2) , B (-4 , 4) , C (-2 , 2) is acute scalene Δ

The triangle with vertices A (-4 , 2) , B (-2 , 4) , C (-1 , 4) is obtuse scalene Δ

Answer:

I think the shape above has an order of 5 because it has a reflectional symmetry of 5.

I hope this helps

Answer:

1) x= 7 and y =2

Step-by-step explanation:

mark me as brainliest please

Answer:

x =7

y =2

eqn 1 - eqn2

5x-2x=3x

3y-3y=0

41-20=21

3x=21

x=7

in eqn 1;

5×7)+3y=41

35+3y=41

3y=6

y=2

Answer: x = 7°

Explanation:

We know that sum of angles of a quadilateral is = 360°

Therefore ATQ

⇒ (12x-4)+(18x+4)+(15x+10)+(5x) = 360

⇒ (12x + 18x + 15x + 5x) + (-4+4+10) = 360

⇒ 50x + 10 = 360

⇒ 50x = 360-10

⇒ 50x = 350

⇒ x = 350/50

⇒ x = 7

Therefore value of x is 7°

Must click thanks and mark brainliest

numerator = top part of the fraction

denominator = bottom part of the fraction

* means multiply

a.

you can only add the numerator when the denominator is the same

cant add the denominator

denominator has to be the same

1/5 = 4/20

4/20 + 7/20 = 11/20

b.

1 7/8 = 15/8

3/4 ÷ 15/8 =

3/4 * 8/15 =

24/60 = divide both top and bottom by 12 =

2/5

Step-by-step explanation:

a)1/5+ 7/20

1.find the CM of both denominators

2.multiply both the denominator and the numerator using the CM

=(1/5)×20 +(7/20)

=20/100 +35/100

since you multiply

3.Now add both numerators ( don't add the denominators)

=the answer is 55/100

Answer:

Step-by-step explanation:

You need to find the model for this situation using the points given. If you are given 13 mg immediately, the coordinate point for that is (0, 13), where the x coordinate is the time in minutes and the y coordinate is the amount of dye in mg.

If after 12 minutes, 4.75 mg remain, the coordinate point for that is (12, 4.75). Just so you know, the time unit always goes in for x, never for y.

Now that we have these coordinates we are going to use them as a system and find the model. Begin with the point (0, 13) in

[tex]A=a(b)^t[/tex] where A is the amount left in the body, a is the initial amount injected, b is the rate at which it decays, and t is the time in minutes. Plug in the first set of coordinates:

[tex]13=a(b)^0[/tex] and since anything raised to the power of 0 is equal to 1, we have

13 = a. Now we can use that and write another equation with the other set of coordinates to solve for b:

[tex]4.75=13(b)^{12}[/tex] and divide both sides by 13 (don't round anything yet) to get

.3653846154 = b¹². Now take the 12th root of both sides (you need a scientific calculator for this) to get that

b = .9195228407  Yikes.

Now for the model, using the fact that a = 13 and b = .9195228407:

[tex]A=13(.9195228407)^t[/tex]  

We are told that the amount that we are allowed to leave with still remaining in our system cannot be more than 2 mg, so we sub in a 2 for A:

[tex]2=13(.9195228407)^t[/tex] and begin by dividing away 13 to get

[tex].1538461538=.9195228407^t[/tex]  Take the natural log of both sides, which allows us to bring the t out front:

ln(.1538461538) = t ln(.9195228407) and finally divide by ln(.9195228407) to get

t = 22.3 minutes

Answer:

no A

Step-by-step explanation:

sqrt13 is the ans

hope it helps

Look at the attachment

The line bisects the cord which we have to find

Its a right angle triangle

[tex]\boxed{\sf P^2=H^2-B^2}[/tex]

[tex]\\ \Large\sf\longmapsto P=\sqrt{H^2-B^2}[/tex]

[tex]\\ \Large\sf\longmapsto P=\sqrt{10^2-6^2}[/tex]

[tex]\\ \Large\sf\longmapsto P=\sqrt{100-36}[/tex]

[tex]\\ \Large\sf\longmapsto P=\sqrt{64}[/tex]

[tex]\\ \Large\sf\longmapsto P=8cm[/tex]

Distance of the chord from centre is 8cm.

Answer:

a)

Step-by-step explanation:

Answer:

3:15 hours

Step-by-step explanation:

i don't know I just took the test

Answer:

4.75 or 4 3/4

Step-by-step explanation:

rate = distance/time

Multiply both sides by time:

time * rate = distance

Divide both sides by rate:

time = distance/rate

We are given:

distance = 76 km

rate = 16 km/h

time = ?

time = distance/rate

time = 76 km/(16 km/h)

time = 4.75 h = 4 3/4 h

Answer:

Step-by-step explanation:

Let the initial velocity of the ball is u.

At the maximum height the speed is zero.

Let the time is t.

Use first equation of motion.

v = u - gt

0 = u - g t

t = u/g

Let the maximum height is H.

Use third equation of motion

[tex]v^2 = u^2 - 2 gh\\\\0 = u^2 - 2 gH\\\\H = \frac{u^2}{2 g}[/tex]

Answer:

These are the intervals of the people who are at least adults and are mature enough to take the survey seriously and answer correctly

Step-by-step explanation:

Answer:

Step-by-step explanation:

2371 x1.84 = 4362

4362 ÷ 36.92 = 118

the answer would be 118.1646804 but since the lowest sig fig in the question is 3 (1.84), we would have to round the answer to 3 SIG figs.

Final answer: 118

Answer:

x=2

Step-by-step explanation:

We can use the Pythagorean theorem since this makes a right triangle

a^2+b^2 = c^2

The radius is 1.5

1.5^2 + x^2 = (1+1.5)^2

1.5^2 +x^2 = 2.5^2

2.25+x^2=6.25

Subtract 2.25 from each side

x^2 = 4

Taking the square root of each side

x= 2

Answer:A

Step-by-step explanation:Took quiz

Answer:

Step-by-step explanation:

x+2y=-2

2y=-x-2

y=-x/2-2/2

y=-x/2-------(1)

y=1/2x-5-----(2)

(1)=(2)

-x/2=1/2x-5

-x=x-10

-2x=-10

x=5

substitute in 2

         y=(1/2)*5-5

           =5/2-5

          =-2.5

Make note of the coefficients in the first and fourth equations. They've been conveniently picked so that subtracting one equation from the other eliminates every variable but t. We have

(3r + 2s + t + 2u + 3v) - (3r + 2s + 3t + 2u + 3v) = 7 - 17

-2t = -10

t = 5

Answer:

Probably the first three answers

Step-by-step explanation:

The rest are

4) 3×5=15 (which is not 8)

5) 6×2=12 (≠8)

So it's just the first three

Answer:

The associative property

Step-by-step explanation:

In brief terms, the associative property states that when one has like operations, or an operation and its inverse, one can add parenthesis to the equation without changing the final answer. One can also change the place in which the parenthesis stands in this expression without altering the result. remember, an operation and its inverse refers to any operation and the operation that is done to undo the operation. The following is a list of such operations:

[tex]x^n=b[/tex]        [tex]\sqrt[n]{b}=x[/tex]

[tex]a*b[/tex]            [tex]a[/tex] ÷ [tex]b[/tex]

[tex]a+b[/tex]           [tex]a-b[/tex]

Answer:

just add a small amount and and square the new number

between 2.82 and 2.83 seems a bit closer

Step-by-step explanation:

x      x^2

2.8         7.84

2.81         7.8961

2.82 7.9524

2.83 8.0089

2.84 8.0656

2.85 8.1225

2.86 8.1796

2.87         8.2369

Answer:

4/3 inches, or 1.33333 inches

Step-by-step explanation:

In terms of the volume of a cube, its side length is the cube root of it. Therefore, for a cube with a volume of 512/216 cubic inches, its side length is equal to ∛(512/216) = ∛(512)/∛(216) = 8/6 = 4/3 inches*

* we know that 8/6 = 4/3 because we can multiply both the numerator and denominator by 1/2 to get this result. If we multiply/divide the numerator or denominator by the same values, the fraction is still the same

Answer:

1. ⅓*m = m - 12

2. 2(a + 5) = 20

Step-by-step explanation:

1. Let the number be represented by m

Let one-third of the number m, be ⅓*m

If there is 12 less of an amount of something, it implies 12 is to be subtracted from the initial amount.

Thus, 12 less than the number, m is (m - 12)

》⅓*m = m - 12

2. Let the number be represented by a

The sum of the number and 5 is (a+5)

》2(a+5) = 20

We know

[tex]\boxed{\Large{\sf Circumference=\pi d}}[/tex]

[tex]\\ \Large\sf\longmapsto Circumference=\dfrac{22}{7}\times 23.4[/tex]

[tex]\\ \Large\sf\longmapsto Circumference=\dfrac{514.8}{7}[/tex]

[tex]\\ \Large\sf\longmapsto Circumference=73.5in[/tex]

Answer:

Step-by-step explanation:

[tex]\Large \boldsymbol{}\bf \dfrac{p^{^/is \ an \ integer}}{q^{ / natural}} -irreducible \ \ fraction[/tex]