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The length of the y component shown is C. 2.0.
How to find the length ?We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.
To solve for the length of the y - component therefore, the useful operation would be the Sin function.
The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse
Sin 42 ° = y component / Hypotenuse
y - component = Sin 42 ° x Hypotenuse
y - component = Sin 42 ° x 3
y - component = 0. 6691 x 3
y - component = 2. 0
In conclusion, the y - component is 2.0.
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Full question is:
What is the length of the y-component of the vector shown below?
A. 2.2 B. 3 c. 2.0 D. 2.7
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aphasia
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience:
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Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience: aphasia.
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for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
Answers
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
Answers
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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