The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.
What are domain and range?
The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.
From the given question, and the above definition of domain and range,
the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value
Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.
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There are currently 25 frogs in a (large) pond. The frog population grows exponentially, tripling every 10 days.
How long will it take (in days) for there to be 150 frogs in the pond?
Time to 150 frogs: days
The pond's ecosystem can support 1400 frogs. How long until the situation becomes critical?
Time to 1400 frogs: days
There are 21 days for there to be 150 frogs in the pond.
There are 37 days for there to be 1400 frogs in the pond.
What is exponential growth?
Quantity increases over time through a process called exponential growth. When a quantity's instantaneous rate of change with respect to time is proportional to the quantity itself, it happens.
Given:
There are currently 25 frogs in a (large) pond. The frog population grows exponentially, tripling every 10 days.
The exponential equation for the given problem is,
[tex]A(t) = Ar^t^/^1^0[/tex]
To find the number of days for there to be 150 frogs in the pond.
Here,
A(t) = 250, A = 25, r = 3
⇒
[tex]250 = 25(3)^t^/^1^0\\10 = 3^t^/^1^0\\t = 20.97[/tex]
t ≈ 21
Hence, there are 21 days for there to be 150 frogs in the pond.
Now to find how long for there to be 1400 frogs in the pond, we solve:
[tex]1400 = 25(3)^t^/^1^0\\56 = (3)^t^/^1^0\\t = 36.64[/tex]
t ≈ 37
Hence, there are 37 days for there to be 1400 frogs in the pond.
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What is 157 cm to m as whole numbers or decimal
Answer: 1.57 meters
Step-by-step explanation:
takes 2 places to get from cm to meters
157 / 100
1.57 m
