what is the formulas for Calcium Chloride,Aluminium Sulphate and Sodium hydroxide. *

Answers

Answer 1

Answer:

Explanation:

Why is there a star * behind the question.

CaCl2

Al2(SO4)3

NaOH


Related Questions

WM "Please write the molecular formula for the following by criss cross method. 1. Calcium nitrate 2. Sodium bicarbonate 3. Magnesium nitrite 4. Sodium chloride 5. Hydrogen sulphate 6. Hydrogen chloride T-Aluminium bisulphate 8 Aluminium chloride 9. Aluminium sulphate 10. Hydrogen Nitrate​

Answers

Answer:

1 Ca(NO3)2

Calcium- Ca, Valency 2

Nitrate- NO3, Valency 1

AFTER CRISS CROSS:

Ca1(NO3)2

Ca(NO3)2

2 sodium bicarbonate = NaHCO3

Na = Sodium = (Na)+

HCO3 = bicarbonate = (HCO3) -

Na HCO3

3 magnesium   nitrite

   +2                 _ 1

Mg2(NO3)2

4 Na    Cl

    +1    _1

formula NaCl

5 hydrogen         sulphide  

H                       SO4

+1                       _2

formula H2SO4

6  H    Cl

  +1     _1

HCl

7 AL2     HSO4

  +2        -2

AL2(HSO4)3

8  NH4   Cl

   +1      _1

NH4Cl

9 NH4     SO4

  +1           _2

(NH3)2SO4

10  H   NO3

    +1    _1

HNO3

in a galvanic cell, if a concentration of an electrolyte is added does it affect the electron potential of that electrolyte?​

Answers

Answer:

Changing the concentration of one solution in the cell will increase the voltage potential of the cell because you are putting the system further out of equilibrium. Because the concentration in only one side of the cell has changed, the concentration gradient across both sides of the cell becomes steeper. In order for this experiment to work, the salt bridge must be concentrated enough to effectively separate the two electrolyte solutions, but it must also be porous enough to allow ionic flow.

Explanation:

think so you like it

1 atm is equal to
O 1 mmHg
• 14.7 mmHg
• 76 mmHg
© 760 mmHg

Answers

Answer:

C 760 mm of hg

because this is the atmospheric pressure at sea level

4.1 shows a plant cell. g For Examiner's Use n. C D Fig. 4.1 (i) Name the type of plant cell shown in Fig. 4.1. [1]​

Answers

Answer:

palisade cell due to presence of chloroplasts

The velocity of an electron that is emitted from a metallic surface by a photon is 3.6E3 km*s^-1. (a) What is the wavelength of the ejected electron? (b) No electrons are emitted from the surface of the metal until the frequency of the radiation reaches 2.50E16 Hz. How much energy is required to remove the electron from the metal surface? (c) What is the wavelength of the radiation that caused photoejection of the electron? (d) What kind of electromagnetic radiation was used?

Answers

(a) The wavelength of the electron is 202.25885 nm

(b) The minimum energy required to remove the electron is 1.6565 × 10⁻¹⁷ J

(c) The wavelength of the causing radiation is approximately 8.84 nm

(d) X-ray

The question parameters are;

The given parameters of the electron are;

The velocity of the electron, v = 3.6 × 10³ km/s

(a) de Broglie wavelength is given as follows;

λ = h/(m·v)

Where;

λ = The wavelength of the wave

h = Planck's constant = 6.626 × 10⁻³⁴ J·s

m = The mass of the electron = 9.1 × 10⁻³¹ kg

Therefore, we get;

λ = 6.626 × 10⁻³⁴/(9.1 × 10⁻³¹ × 3.6 × 10⁶) = 202.25885 × 10⁻⁶

The wavelength, λ, of the electron is 202.25885 × 10⁻⁶ m = 202.25885 nm

(b) The energy required to remove the electron from the metal surface is known as the work function, W₀, which is given by the following formula

W₀ = h·f₀

Where;

f₀ = The threshold frequency

Given that the threshold frequency, f₀ = 2.50 × 10¹⁶ Hz, we have;

W₀ = 6.626 × 10⁻³⁴ J·s × 2.50 × 10¹⁶ Hz = 1.6565 × 10⁻¹⁷ J

The energy required to remove the electron from the metal surface, W₀ = 1.6565 × 10⁻¹⁷ J

(c) The wavelength of the radiation that caused the photoejection of the electron is given as follows;

The energy of the incoming photon, E = W₀ + (1/2)·m·v²

Where;

v = The velocity of the electron, and m = The mass of the electron

Therefore;

E = 1.6565 × 10⁻¹⁷ + (1/2) × 9.1 × 10⁻³¹ kg × (3.6 × 10⁶ m/s)² = 2.24618 × 10⁻¹⁷ J

We have;

E = h·f

∴ f = (2.24618 × 10⁻¹⁷ J)/(6.626 × 10⁻³⁴ J·s) = 3.38994869 × 10¹⁶ Hz

The speed of light, c = 299,792,458 m/s

From the equation for the speed of light, we have;

λ = c/f

∴ λ = (299,792,458 m/s)/(3.38994869 × 10¹⁶ Hz) = 8.84356919 nm ≈ 8.84 nm

The wavelength of the radiation that caused photoejection of the electron, λ[tex]_{causing \ radiation}[/tex] ≈ 8.84 nm

(d) The kind of electromagnetic radiation used which has a wavelength of 8.84 nm is the X-Ray which are electromagnetic radiation having wavelengths that extend from 10 picometers to 10 nanometers.

Learn more about De Broglie wavelength here;

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Water is super soluble and this solubility is incredibly helpful for life. Tell me how this solubility helps maintain different processes when it comes to life.

Answers

Answer: Water is SUPER soluble and regarded as an universal solvent because it is polar in nature and dissolves most inorganic solutes and some polar organic solutes to form aqueous solutions.

Explanation:

WATER is a substance which is composed of the elements such as hydrogen and oxygen that are combined in the ratio of 2:1. The physical properties of water include:

--> it is a colourless, odourless and tasteless liquid and

--> the boiling point of water is 100°C(this is due to the presence of hydrogen bonding).

The solubility of a solute in a solvent at a particular temperature is the maximum amount of solute in moles or grams that will saturate 1000 dm³ or grams of the solvent.

Water is regarded as a universal solvent BECAUSE it is capable of dissolving many substances. This solubility helps maintain different processes in life such as acting as the solvent which helps cells transport and use substances like oxygen or nutrients.

Unknown # 41
Flame Test Color: Lilac
Addition of HCl(aq): NR (No reaction)
Addition of HCl(aq) and BaCl2(aq): NR (No reaction)
Addition of HNO3(aq) and AgNO3(aq): Yellow precipitate

What is the unknown ionic compound molecular formula?

Answers

Answer: Potassium Iodide, KI

Explanation:

Flame test colors:

Li+ = Crimson Red
Na+ = Bright Orange-Yellow
K+ = Lilac

Addition of nitric acid and silver nitrate (HNO3 and AgNO3),

Cl- = White precipitate
Br- = Creamy precipitate
I- = Yellow Precipitate

Hope this helps, brainliest would be appreciated :)

How do I unscramble
kgiueneoseph

Answers

Answer:

d

Explanation:

Housekeeping is the answer :)

I hope this answer helps you out. Brainliest would be appreciated. Have a good day/night :).

Calculate the amount of mole(s) of CoF2 required to react with 12.8 moles of HCI.
CoCl2 + 2HF --> CoF2 + 2HCI

Answers

Explanation:

here's the answer to your question

The electron configuration for Helium (He) is shown below.

1s2

Which diagram shows the correct distribution of electrons in the electron shells of a helium atom?

Answers

DOESNT show the pics sorry

what are the useful of carbon dioxide?​

Answers

Carbon Dioxide is used by green plants in photosynthesis .Carbon Dioxide is used in fire extinguisher to keep fire away .CARBON Dioxide is used to bake cakes ,Pasteries etc Extra shots:-

Carbon Dioxide is known as CO_2

(True or false) Two or more atoms combine to form a molecule ____

Answers

Answer:

false tjytyjiy

Explanation:

cnruujrkyrryyrkkurk

A drink that contains 4 1/2 ounces of a proof liquor… approximately how many drinks does this beverage contain?

Answers

Complete Question

A guest orders a drink that contains 4 1/2 ounces of 80-proof liquor. Approximately how many drinks does this beverage contain?

Answer:

[tex]No\ of\ drinks =3[/tex]

Explanation:

From the question we are told that:

Ordered drink 4 1/2 ounces of 80-proof liquor

Generally

80-proof liquor contains 40\% alcohol

Giving the drink a standard 1.5 ounce of distilled spirit

Therefore

[tex]No\ of\ drinks =\frac{4.5}{1.5}[/tex]

[tex]No\ of\ drinks =3[/tex]

please help me it's urgent​

Answers

C3H8 + 5 O2 = 3CO2 + 4H20

Answer:

a) NaSO4+Bacl2 -> Baso4+2Nacl

b) 4C3H3+15O2 -> 12CO2+6H2O

Explanation:

The atoms at the reactants is equal with the product.

If the hydrogen ion concentration, (H+), in a solution is 5.39 x 10-8 M,

what is [OH-]?

A.1.86 x 1021 M

B. 1.86 x 10-7 M

Answers

Answer: 1.86*10^-7M

Explanation:

Answer:

B. 1.86 x 10^-7 M

Explanation:

are standard electrode potential and standard hydrogen potential same?​

Answers

Answer:

Potentials of any other electrodes are compared with that of the standard hydrogen electrode at the same temperature. Hydrogen electrode is based on the redox half cell: 2 H+(aq) + 2 e− → H2(g)..

Heat transfer takes place when:
A. there is a temperature difference.
B. conduction or convection occurs, but not radiation.
OC. thermal energy is present.
D. None of these

Answers

Answer:

A. There is a temperature difference

Explation:

Whenever there is a temperature difference, heat transfer occurs. Heat transfer may occur rapidly, such as through a cooking pan, or slowly, such as through the walls of a picnic ice chest.

Answer:

A.) there is a temperature difference

Explanation:

I got it correct on founders edtell

why does increasing the pressure of a gas increase the reaction rate?
A. it increases the temperature of the gas.
B. it increases the reaction-rate constant.
C. it increases the activation energy.
D. if increases the number of collisions

Answers

Answer:

d it increase the number of collisions

Explanation:

cos collision is a type reaction to other particles

Hope that helps you

Please follow

Option A may be I think!!!!!

Precipitate WILL form if Silver Nitrate reacts with Iron (III) chloride
-true or false

Answers

Answer:

yes

Explanation:

3Ag(No3) (aq) +FeCl3(aq) -->Fe(NO3)3(aq)+3AgCl(s)

Plzzz help do your best to answer these questions

Answers

The empirical formula is the simplest formula of a chemical compound.

To find the empirical formula, we take the following steps;

Divide the percentage by mass of each element by its relative atomic mass.Divide the quotient of each by the lowest value obtained instep 1 aboveWrite the result of step 2 above as the subscript following each atom.

1) O - 88.10/16,      H - 11.190/1

  O - 5.5,               H - 11.19

  O - 5.5/5.5,        H - 11.19/5.5

  O -  1,                 H - 2

Empirical formula = OH2

2) C - 41.368/12  H - 8.101/1,   N - 32.162/14,   O - 18.369/16

   C - 3,               H - 8,           N - 2,                  O - 1

   C - 3/1,            H - 8/1          N - 2/1                 O - 1/1

    C - 3,             H - 8,           N - 2,                   O - 1

Empirical formula = C3H8N2O

To obtain the molecular formula where n = number of atoms of each element;

Molecular weight = 174.204 g/mol

[ 3(12) + 8(1) + 2(14) + 16]n = 174

n= 174/88

n = 2 (to the nearest whole number)

Hence, we have;

[C3H8N2O]2

The molecular formula is C6H16N4O2

3)  C - 19.999/12,  H - 6.713/1,   N - 46.646/14,   O - 26.641/16

    C - 2,                H - 7,            N -  3,                 O - 2

    C - 2/2,            H - 7/2,         N -   3/2,             O - 2/2

    C - 1,                H - 4,            N -  2,                  O - 1

Empirical formula - CH4N2O

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state boyl"s law and Charle's law​

Answers

Answer:

hey mateee

Boyle's law :-  the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

Boyle's law can also be formularized as P1V1 = P2V2

Charle's law :-  the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Charle's law can also be formularized as V1/T1 = V2/T2  

Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb
calorimeter has a mass of 1.20 kg and a specific heat of 3.55 J/(g;°C).
If the initial temperature of the calorimeter is 22.5°C, what is its final temperature?
Use 0= mCOAT

Answers

Answer:

i cant understand what you wrote

Explanation:

it's a blank screen

What happens when The vapour obtained by dropping conc. H2SO4 in a mixture of KI and MnO2 is treated with hypo solution​

Answers

The reaction between H2SO4 in a mixture of KI and MnO2 yields iodine which reacts with hypo solution​ by titration and the iodine is decolorized.

Iodine is decolorized.

The first reaction stated in the question occurs as follows;

2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)

The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.

The equation of the titration reaction is;

2Na2S2O3 + I2→ Na2S4O6 + 2NaI

When this reaction takes place, iodine is decolorized due to its reduction to I^-.

For more information see https://brainly.com/question/16857360

Define atomic number and atomic mass

Answers

Answer:

Atomic number ---> number of protons in the nucleus of an atom

Atomic mass ----> the total mass of protons, neutrons, and electrons in an atom

During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
How many ml of a solution of Ba(OH)2 0.230M do you need to neutralize all the HCl produced?

Answers

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

What are isotopes_???​

Answers

Answer:

Below!

Explanation:

Isotopes are elements with a similar chemical makeup and the same atomic number, but a different atomic mass and number of neutrons . An example of this would be carbon-12, carbon-13, and carbon-14. Three isotopes of the element carbon that have the same 6 protons but have a different neutron count. A simple way to explain isotopes would be to say that they are just different "versions" of an element.

Hope this helps ya! Best of luck <3

What is the concentration of a solution formed by diluting 25.0 ml of a 3.8M glucose solution to 250ml

Answers

Explanation : số mol glucose 3.8M là :

n = Cm . V = 3.8 . 25 =95

=> Cm khi pha loãng = [tex]\frac{n}{V}[/tex] = [tex]\frac{95}{250}[/tex] = 0.38M

According to molar concentration, the  concentration of a solution formed by diluting 25.0 ml of a 3.8 M glucose solution to 250 ml is 0.38 M.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.In case of 2 solutions given it is calculated as M₁V₁=M₂V₂,on substitution, M₂=3.8×25/250=0.38 M.

Thus,  the  concentration of a solution formed by diluting 25.0 ml of a 3.8 M glucose solution to 250 ml is 0.38 M.

Learn more about molar concentration,here:

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All three states of matter can be ____________ or a solvent in a solution.

Answers

The answer is: solute.

All three states of matter can be “solute” or a solvent in a solution.

4. what reaction fuels the burning of the sun? A.fission B.fusion C.combustion D.transmutation​

Answers

Answer:

A

Explanation:

Answer:

fusion is what fuels the burning of the sun,it's the combining of light elements into heavier elements to produce energy.the sun produces a large amount of energy by combining very light elements with heavier elements.

I hope this helps

Dissolve 27.2 grams of CaO and Fe203 mixture with an excess of 500ml dd HCl 2M. a) Calculate each substance in the original mixture b) Calculate the mass of each anhydrous salt obtained after the reaction​

Answers

Answer:

nutrion jsbsjsb. wjjshsjs. wjsh

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