What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)? x= –y216+6y16–4116 y= –x216+6x16–4116 y=x216–6x16+4116 x=y216–6y16+4116

Answer:

Step-by-step explanation:

Answer:  0.50, which is choice b

Explanation:

The interval [tex]1 \le x \le 5[/tex] covers 5-1 = 4 units in the horizontal direction.

This is out of 8 units that span from x = 0 to x = 8 (we could say 8-0 = 8).

So we get the final result of 4/8 = 0.50

In other words, the interval from x = 1 to x = 5 covers exactly half of the interval from x = 0 to x = 8.

9514 1404 393

Answer:

  (x, y) = (0, 0), (1/3, 0), (1/4, 5/24)

Step-by-step explanation:

It is often helpful to write equations in general form. That way, factoring and use of the zero product rule can find solutions.

  x = 1.5x(1 -x) -0.6xy . . . . given

  1.5x -1.5x² -0.6xy -x = 0 . . . . . subtract x

  0.5x -1.5x² -0.6xy = 0 . . . . . . . collect terms

  0.1x(5 -15x -6y) = 0 . . . . . . . . factor; [eq1]

__

  y = y +2xy -0.5y . . . . . . given

  y +2xy -0.5y -y = 0 . . . . . subtract y

  -0.5y +2xy = 0 . . . . . . . . . . collect terms

  -0.5y(1 -4x) = 0 . . . . . . . factor; [eq2]

__

Solutions to [eq1] will be ...

  x = 0

  15x +6y = 5 . . . . . . a set of possible solutions

Solutions to [eq2] will be ...

  y = 0

  1 -4x = 0   ⇒   x = 1/4

Then (x, y) pairs that will satisfy both equations simultaneously are ...

  (x, y) = (0, 0), (1/3, 0), (1/4, 5/24)

__

In the attached graph, solutions to [eq1] are the red lines; solutions to [eq2] are the green lines. Then simultaneous solutions to both equations are found at the intersection points of red and green lines.

Answer:

4.5

Step-by-step explanation:

Given the data :

Score, x ____: 1, 2, 3, 4, 5, 6, 7, 8

Frequency, F : 1, 5, 1, 4, 4, 1, 5, 1

This is a grouped data: The mean of a grouped data is given as :

Mean (xbar) = ΣFx / ΣF

ΣFx = (1*1)+(2*5)+(3*1)+(4*4)+(5*4)+(6*1)+(7*5)+(8*1) = 99

ΣF = (1+5+1+4+4+1+5+1) = 22

Mean (xbar) = ΣFx / ΣF = 99 / 22 = 4.5

Answer:

False

Step-by-step explanation:

4x + y < 2

y > –2

Substitute the point into the inequalities and see if they are true

4(4) + 2 < 2

16+2 < 2

18 <2  False

2 > –2  True

Since one is false the point is not a solution

Answer:

60 is the larger number

Step-by-step explanation:

Let the two numbers be a and y

x+y = 90

x-y = 30

Add the two equations together

x+y = 90

x-y = 30

-----------------

2x = 120

Divide by 2

2x/2 =120/2

x = 60

x+y =90

60+y = 90

y = 90-60

y = 30

The numbers are 60 and 30

Answer: See Below

Step-by-step explanation:

Concept:

Here, we need to know the idea of alternative interior angle, alternative exterior angle, and corresponding angles.

Alternative interior angle: a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal.

Alternative exterior angle: a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.

Corresponding angle: A pair of angles that occupy the same relative position at each intersection where a straight line crosses two others.

All three kinds of angles above occur to be congruent (equal) when the lines are parallel to each other.

If you are still confused, please refer to the attachment below for a graphical explanation

Solve:

PART ONE

a) Name two pairs of alternative exterior angles: ∠1 and ∠7 / ∠2 and ∠8

b) Name two pairs of corresponding angles: ∠1 and ∠5 / ∠2 and ∠6

c) Name two pairs of alternative interior angles: ∠4 and ∠6 / ∠3 and ∠5

PART TWO

a) If the measure of angle 7 is 52°, what is the measure of angle 1?

b) If the measure of angle 8 is 112°, then what is the measure of angle 3?

Hope this helps!! :)

Please let me know if you have any questions

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements:                                                Reasons:

[tex]\displaystyle 1)\, F\text{ is the midpoint of } AE[/tex]                           Given

[tex]\displaystyle 2) \, \overline{FA} \cong \overline{FE}[/tex]                                                  Definition of Midpoint

[tex]\displaystyle 3) \, AB\parallel DE[/tex]                                                   Given

[tex]\displaystyle 4)\, \angle B \cong \angle D[/tex]                                                  Alt. Int. Angles Are Congruent  

[tex]\displaystyle 5)\, \angle A \cong E[/tex]                                                     Alt. Int. Angles Are Congruent      

[tex]\displaystyle 6) \, \Delta BFA \cong \Delta DFE[/tex]                                      AAS Congruence

Discounted price = $60

Discount = 60%

Let the usual price be x.

So, x - (60% of x) = $60

=> x - [(60/100) × x] = $60

=> x - (60x/100) = $60

=> x - (3x/5) = $60

=> (5x/5) - (3x/5) = $60

=> 2x/5 = $60

=> 2x = $60 × 5

=> 2x = $300

=> x = $300/2

=> x = $150

So, the usual price is $150.

Answer:

Red on the 5th draw = 0.0907

Step-by-step explanation:

The first to fourth selections are all the same.

Blue + white = 12 + 6 = 18

The total number of marbles is 11 + 12 + 6 = 29

P(~ red) for the first four times = (18/29)^4 = 0,1484

Now on the 5th time, the first red is 11/18

So the Probability is 0.1484 * 11/18 = 0.0907

Answer:

The manufacturer should advertise 11720 pages.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 12450, standard deviation of 570:

This means that [tex]\mu = 12450, \sigma = 570[/tex]

How many pages should the manufacturer advertise for each cartridge if it wants to be correct 90 percent of the time?

They should advertise the 10th percentile, which is X when Z has a p-value of 0.1, so X when Z = -1.28. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 12450}{570}[/tex]

[tex]X - 12450 = -1.28*570[/tex]

[tex]X = 11720[/tex]

The manufacturer should advertise 11720 pages.

Answer:

f(3) = g(3)

General Formulas and Concepts:

Algebra I

Functions

Step-by-step explanation:

We can see from the graph that the lines intersect at (3, 6). If this is the case, then that means that when x = 3 for both functions, it outputs f(x) = 6.

Rewriting this in terms of function notation:

f(3) = 6, g(3) = 6

∴ f(3) = g(3)

Answer:

graph a is the correct answer

Step-by-step explanation:

Answer:

[tex]P = 24k-6m[/tex]

Step-by-step explanation:

The correct expressions are:

[tex]W = 7k - 2m[/tex]

[tex]L = 5k - m[/tex]

Required

The perimeter (P)

This is calculated as:

[tex]P = 2 *(L + W)[/tex]

So, we have:

[tex]P = 2 *(5k - m + 7k -2m)[/tex]

Collect like terms

[tex]P = 2 *(5k + 7k- m -2m)[/tex]

[tex]P = 2 *(12k-3m)[/tex]

Open bracket

[tex]P = 24k-6m[/tex]

Answer:

Step-by-step explanation:

I posted a pic to show you what this looks like so you have some idea of what it is I'm talking about in the explanation of how to find the side length of the rhombus. Knowing that this is a rhombus, all the sides are the same length.

Looking at the pic below, you can see that I divided the length of AC in 2 equal parts to get that the base of the right triangle I extracted below that is 8; the height is 6. We can find the side marked with a ? by using Pythagorean's Theorem; namely:

[tex]??^2=6^2+8^2[/tex] and

[tex]??^2=36+64[/tex] and

[tex]??^2=100[/tex] so

? = 10

The length of the sides of the rhombus is 10.

Answer:

Solution given:

f(x)=5x-3

let

y=f(x)

y=5x-3

interchanging role of x and y

x=5y-3

x+3=5y

y=[tex]\frac{x+3}{5}[/tex]

$o,

f-¹(x)=[tex]\frac{x+3}{5}[/tex]

we conclude that

f-¹(x)≠g(x)

Each pair of function are not inverses.

g(x)=x/5+3

let g(x)=y

y=x/5+3

interchanging role of x and y

x=y/5+3

x-3=y/5

doing crisscrossed multiplication

5(x-3)=y

y=5x-15

g-¹(x)=5x-15

So

g-¹(x)≠f-¹(x)

Each pair of function are not inverses.

Given that,

→ f(x) = 5x-3

Then y = f(x),

→ y = 5x-3

Now we can interchange role of x and y,

→ x = 5y-3

Then use the cross multiplication,

→ x+3 = 5y

→ y = x+3/5

Now the inverse is,

→ f-¹(x) = x+3/5

We can go to the conclusion that,

→ f-¹(x) ≠ g(x)

So, each pair of function is not inverse.

Answer:

C 4,12,36 108

Step-by-step explanation:

the answer is above.

Answer:

C

Step-by-step explanation:

G.P= a,ar,ar^2,ar^3,...,

a1=4

a2=4×3=12

a3=4×9=36

a4=4×27=108

Answer:

a) IQ scores of 94.2 and below represent the bottom 35%.

b) An IQ score of 110.1 represents the 3rd quartile.

c) IQ scores of 124.7 and higher are in the top 5%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 100 and a standard deviation of 15.

This means that [tex]\mu = 100, \sigma = 15[/tex]

(a) Find the IQ scores that represent the bottom 35%.

The 35th percentile and below, in which the 35th percentile is X when Z has a p-value of 0.35, so X when Z = -0.385.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.385 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = -0.385*15[/tex]

[tex]X = 94.2[/tex]

IQ scores of 94.2 and below represent the bottom 35%.

(b) Find the IQ score that represents the 3rd Quartile.

This is the 100*3/4 = 75th percentile, which is X when Z has a p-value of 0.75, so X when Z = 0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.675 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = 0.675*15[/tex]

[tex]X = 110.1[/tex]

An IQ score of 110.1 represents the 3rd quartile.

(c) Find the IQ score for the top 5%.

IQ scores of at least the 100 - 5 = 95th percentile, which is X when Z has a p-value of 0.95, so X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = 1.645*15[/tex]

[tex]X = 124.7[/tex]

IQ scores of 124.7 and higher are in the top 5%.

Answer:

24.5

Step-by-step explanation:

using Pythagorean theorem

[tex]a^{2} +b^{2} =c^{2} \\[/tex]

Since we know the hypotenuse, we can change up the theorem into [tex]c^{2} -b^{2} =a^{2}[/tex]

[tex]35^{2} -25^{2} =a^{2}[/tex]

1225-625=[tex]a^{2}[/tex]

[tex]\sqrt{a^{2} } =24.5[/tex]

Answer: (760 - 676. 40) × 100 ÷ 760 = 11%

Step-by-step explanation:

Answer:

11% decrease

Step-by-step explanation:

Concepts:

Solving:

Let's find the percent change by using the formula.

1. Formula for Percent Change

2. Plug in the values of NV and OV

3. Simplify

Therefore, our percent decrease is 11% decrease.

Answer: (a)

Step-by-step explanation:

Given

There are 5 squads for an athletic scrimmages

If each team played 2 matches

Total no of matches will be

[tex]\Rightarrow \dfrac{5(5-1)}{2}\times 2=20\ \text{matches}[/tex]

So, 20 matches are played in 2 hours

Each match takes

[tex]\Rightarrow \dfrac{120}{20}=6\ \text{minute}[/tex]

Option (a) is correct.

9514 1404 393

Answer:

  $122,040

Step-by-step explanation:

The interest is the difference between the mortgage value and the total amount paid.

  ($839/mo)×(12 mo/yr)×(30 yr) -180,000 = $302,400 -180,000 = $122,040

$122,040 will be paid in interest.

Answer:

[tex]P=\$276646.153[/tex]

Step-by-step explanation:

Time [tex]T=30years[/tex]

Rate [tex]r=0.325\%[/tex]

Payment per month [tex]P=\$ 900[/tex]

Generally the equation for Principle  is mathematically given by

[tex]M=\frac{P r}{1-(1+r)^{-n}}[/tex]

[tex]900=\frac{P \frac{0.325}{100}}{1-(1+( \frac{0.325}{100}))^{- 30*12}}[/tex]

[tex]P=\frac{900*100*0.99}{0.325}[/tex]

[tex]P=\$276646.153[/tex]

Answer:

Poisson, as we have the mean number and not a proportion.

Step-by-step explanation:

We have the mean number of vehicle deaths per year, thus, since it is a mean and not a proportion, we use the Poisson distribution.

If we were working with the proportion of accidents that end in death for example, or any other proportion, it would be a binomial random variable.

Answer:

Disjoint is the correct answer.

Answer:

[tex]LCM = 21[/tex]

Step-by-step explanation:

Given

[tex]-\frac{3}{5}y + \frac{1}{7}= \frac{1}{3}y -\frac{2}{3}[/tex]

Required

LCM of the constant terms

Collect like terms

[tex]\frac{1}{3}y+\frac{3}{5}y = \frac{1}{7}+\frac{2}{3}[/tex]

The constant terms are on the right-hand side

To combine them, we simply take the LCM of the denominator, i.e. 7 and 3

The prime factorization of 3 and 7 are:

[tex]3 = 3[/tex]

[tex]7 = 7[/tex]

So:

[tex]LCM = 3 * 7[/tex]

[tex]LCM = 21[/tex]

Answer:

see below

Step-by-step explanation:

We know that distance = rate * time

100 meters = 8 m/s * time

100 = 8t

Divide each side by 8

100/8 = 8t/8

12.5 = t

If we know the rate and the time, we can find the distance

d = rt

Answer:

1/11

Step-by-step explanation:

We are asked to find the natural log of

[tex] \sqrt[11]{e} [/tex]

Convert to fractional exponent

[tex] ln(e {}^{ \frac{1}{11} } ) [/tex]

Apply Log of Power rule

[tex] \frac{1}{11} ln(e) [/tex]

Natural log of e is 1 so

[tex] \frac{1}{11} \times 1 = \frac{1}{11} [/tex]

Answer:

[tex]\frac{1}{11}[/tex]

Step-by-step explanation:

First, remember that the ln function is just a log function with a base of e. Here's how it looks

[tex]ln(x) =log_{e}(x)[/tex]

[tex]ln(\sqrt[11]{e} ) = log_{e}(\sqrt[11]{e} )[/tex]

We can take this one step further if we realize that we can rewrite the square root as a simple power to a fraction!

[tex]log_{e}(e^{\frac{1}{11} } )[/tex]

Solving the equation above is really simple. All that function is really saying is can we raise e to some number, where the result would be e^(1/11)? In other words find x.

[tex]e^{x} = e^{\frac{1}{11} }[/tex]

Well x has to be 1/11 in that case. And that ends up being our final answer.

[tex]log_{e}(e^{\frac{1}{11} } ) = \frac{1}{11}[/tex]