Step-by-step explanation:
x=4x+11
11=4x-x
11=3x
x=11/3
x=37
Create an exponential function, and then create a second exponential function that shifts your original function down 7 units
Answer:
A general exponential function is written as:
f(x) = A*e^(k*x)
Where A and k are real numbers.
Because we want to "create" a exponential function, we must assign numbers to A and k, let's assign:
A = 1
k = 1
then our function is just:
f(x) = e^(x)
Now we want to shift down 7 units.
So let's describe a general vertical shift.
For a general function f(x), a vertical shift is written as:
g(x) = f(x) + N
if N is positive, the shift is upwards
if N is negative, the shift is downwards.
Here we want to have a shift down of 7 units, then we would write:
g(x) = f(x) - 7
Replacing by the actual function f(x) we get:
g(x) = e^x - 7
Below you can see the graphs of both functions:
Where the orange one is f(x) and the purple one is g(x).
WRITE THE FUNCTION FOR THE GIVEN TABLE PLS
Answer:
y=X²-4x+5
Step-by-step explanation:
substitute all the left side values to get the outputs..
y=(5)²-4(5)+5 =10
Answer:
A
Step-by-step explanation:
In fact, if we try to substitute, we have:
10 = 5^2 -4(5) +5
10 = 25 - 20 + 5
10 = 10 (ok)
17 = -2^2 - 4(-2) + 5
17 = 4 + 8 + 5
17 = 17 (ok)
and so on
Please help me!!
I just don’t understand it!!
Answer:
(12, 2 )
Step-by-step explanation:
Given (x, y ) on the graph of f(x) , then on the inverse function
(x, y ) → (y, x ), then
(2, 12 ) → (12, 2 ) ← point on g(x) the inverse function
If 2 angles are both right angles then they are congruent. Would the converse of this statement be true?
Given:
The statement is: If 2 angles are both right angles then they are congruent.
To find:
The converse of the given statement and then check whether it is true or not.
Solution:
We know that,
Statement: If p, then q.
Converse : If q, then p.
The statement is: If 2 angles are both right angles then they are congruent.
So, the converse of this statement is:
If 2 angles are congruent then both are right angles.
This statement is not true because if 2 angles are congruent then it is not necessary that the angles are right angles.
Therefore, the converse of this statement is not true.
Determine whether the lines are parallel, perpendicular, or neither.
9x + 3y = 12
24x + 8y = 35
Answer:
parallel
Step-by-step explanation:
Let's rewrite each equation into the slope-intercept form so that we can easily identify the slope of each line.
slope-intercept form: y= mx +c, where m is the gradient and c is the y-intercept.
9x +3y= 12
3x +y= 4 (÷3 throughout)
y= -3x +4 -----(1)
24x +8y= 35
8y= -24x +35 (-24x on both sides)
[tex]y = - 3x+ 4 \frac{3}{8} [/tex] -----(2)
Thus, the slopes of the lines are both -3. Since both lines have the same gradient, they are parallel to each other.
Notes:
• parallel lines have the same gradient
• the product of the gradients of two perpendicular lines is -1
• gradient and slope has the same meaning and can thus be used interchangeably
Hi guys can please help me
using a calculator or otherwise evaluate each of the following giving Your answer to two decimal place .
(i) 73.18-5.23×90
Answer: 26.11
Step-by-step explanation:
73.18 - 5.23 × 90 = 73.18 - 47.07 = 26.11
According to class 8 please solve
Answer:
i) 2 + 2x
ii) 154 = 2(2 + 2x + x)
iii) Length = 52m
Breadth = 25m
Step-by-step explanation:
Perimeter of swimming pool = 154m
Breadth = x
Length = 2 + 2x
Formula for finding perimeter = P = 2(l + b)
Therefore,
154 = 2 ( 2 + 2x + x)
154 = 4 + 4x + 2x
154 = 4 + 6x
154 - 4 = 6x
150 = 6x
150/6 = x
25 = x
With the value of x,
we can fInd the length and the breadth
Breadth = x
= 25
Length = 2 + 2x
= 2 + 2(25)
= 2 + 50
= 52
Let ABCD and EFGH be two quadrilaterals such that ABCD ~ EFGH. If AB = 15 cm, EF = 18 cm and the perimeter of ABCD is 40 cm, find the perimeter of EFGH.
Step-by-step explanation:
this photo is correct answer of this question.
Kylie has only quarters and
nickels in a jar. The total value in
the jar is $2.00. If there are a total
of 20 coins, how many of each
type of coin are in the jar?
? Quarters. ? Nickels
Graph the line with slope -5 and y-intercept 1.
Answer:y=-5+1
Step-by-step explanation:
en el diagrama de venn donde van ubicados estos numeros?
0,88888....
1 sobre 7 pi
-6 sobre 3
4E
55 sobre 0
56 sobre 9
-0,65999999
Answer:
Step-by-step explanation:
Does (2, 1) make the equation y = 8x true? yes no
Answer:
No
Step-by-step explanation:
Because 1 don't equal to 16
Answer:
no
Step-by-step explanation:
* means multiply
(2,1)
x = 2
y = 1
just plug in the numbers
1 = 8*2 ?
1 = 16? no
These dot plots show the weights (in kilograms) from a sample of leopards
and tigers.
Leopards
000
0000+
000000
00018
00
20
40
60
80
160
180
200
220
100 120 140
Weight (kg)
Tigers
000
2000
000000
2000
ooe
O
20
40
60
80
160
180
200
220
100 120 140
Weight (kg)
What are the differences between the centers and spreads of these
distributions?
Select two choices: one for the centers and one for the spreads.
No
Answer: A.Spreads: The weights of the tigers are more spread out.
B.Centers:The leopards have a lower median weight than the tigers
Step-by-step explanation:
On analyzing the dot plots, we find that the weight of Leopards are more spread out and the weight of Leopards has a lower median than Tiger.
What is median?Median is a statistical measure that determines the middle value of a dataset listed in ascending order. The measure divides the lower half from the higher half of the dataset.
Median of Weight of Leopard = 50 kg
Median of Weight of Tiger = 125 kg
This implies that the Leopards have a lower median weight than Tigers.
What is spread of data?
Spread describes the variation of the data. One of the measures of spread is range.
Range of weight of Leopards= 40 kg
Range of weight of Tigers = 90 kg
This implies that the weight of Tigers are more spread out.
Learn more about median here
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#SPJ2
Linda had dinner at a restaurant for $56 and leaves behind a tip of 18%. What is the tip amount?
Answer:
[tex] = \frac{18}{100} \times 56 \\ = 10.08 \: dollars[/tex]
Answer:
$10.08
Step-by-step explanation:
To solve for the tip amount, we multiply 56 by 0.18.
56 · 0.18 = 10.08.
Linda tipped $10.08.
(e) Dhanu plays with his model railway from 06 50 to 11 15. He then rides his bicycle for 3 hours. Find the ratio time playing with model railway : time riding bicycle. Give your answer in its simplest form.
Answer:
53:36
Step-by-step explanation:
53:36
265:180
The ratio of time Dhanu spent playing with model railway to the time riding bicycle is 53 : 35.
What is the ratio of the time spent playing with model railway to the time riding bicycle ?Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).
Time spent playing with the model railway = 4 hours 25 minutes.
Converting the time to minutes = (4 x 60) + 25 = 265 minutes
Time in minutes spent riding a bicycle = 60 x 3 = 180
Ratio of the minutes - 265 : 180
53 : 35
To learn more about ratios, please check: https://brainly.com/question/25927869
The figure Jhows the graph of h(x) = px - 3+2 a translation of the parent function
g(x) = v. How is the graph of the parent function translated?
A) Right 3 units and up 2 units
OB) Right 2 units and up 3 units
C) Right 3 units and down 2 units
D) Left 3 units and up 2 units
if <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
Answer:
<BCO = <BAO = 20degrees
Step-by-step explanation:
If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
To get <BAO and <BCO, we need to get <AOC first.
From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;
<BAC + <BCA + 100 = 180
Since <BAC = <BCA
<BAC + <BAC = 180 - 100
2<BAC = 80
<BAC = 80/2
<BAC = 40
Also;
<BAO = <BCO and <BAO = <BAC/2
<BAO = 40/2 = <BCO
Hence <BCO = <BAO = 20degrees
does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?
Given equation of the Circle is ,
[tex]\sf\implies x^2 + y^2 = 25 [/tex]
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
inside the circle
Step-by-step explanation:
we want to verify whether (-4,2) lies inside or outside or on the circle to do so recall that,
if [tex]\displaystyle (x-h)^2+(y-k)^2>r^2[/tex] then the given point lies outside the circleif [tex]\displaystyle (x-h)^2+(y-k)^2<r^2[/tex] then the given point lies inside the circleif [tex]\displaystyle (x-h)^2+(y-k)^2=r^2[/tex] then the given point lies on the circlestep-1: define h,k and r
the equation of circle given by
[tex] \displaystyle {(x - h)}^{2} + (y - k) ^2= {r}^{2} [/tex]
therefore from the question we obtain:
[tex] \displaystyle h= 0[/tex][tex] \displaystyle k= 0[/tex][tex] {r}^{2} = 25[/tex]step-2: verify
In this case we can consider the second formula
the given points (-4,2) means that x is -4 and y is 2 and we have already figured out h,k and r² therefore just substitute the value of x,y,h,k and r² to the second formula
[tex] \displaystyle {( - 4 - 0)}^{2} + (2 - 0 {)}^{2} \stackrel {?}{ < } 25[/tex]
simplify parentheses:
[tex] \displaystyle {( - 4 )}^{2} + (2 {)}^{2} \stackrel {?}{ < } 25[/tex]
simplify square:
[tex] \displaystyle 16 + 4\stackrel {?}{ < } 25[/tex]
simplify addition:
[tex] \displaystyle 20\stackrel { \checkmark}{ < } 25[/tex]
hence,
the point (-4, 2) lies inside the circle
Miguel is trying to find the height of a radio antenna on the roof of a local building. He stands at a horizontal distance of 22 meters from the building. The angle of elevation from his eyes to the roof (point A) is 26 degrees , and the angle of elevation from his eyes to the top of the antenna ( oint B) is 31 degrees If his eyes are 1.53 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.
Given the 22 m. horizontal distance and the angles of elevation of 26°
and 31° gives the height of the building as approximately 2.49 meters.
How can the height of the building be found?Horizontal distance from the building = 22 m
Angle of elevation to the top of the roof = 26°
Angle of elevation to the top of the antenna = 31°
Height of his eyes from the ground = 1.53 m
Required:
The height of the antenna.
Solution:
In a right triangle, we have relative to an angle of the triangle, we have;
Opposite side = Adjacent side
Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75
Which gives;
Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26
Height of antenna = Height of the building + Height of antenna - Height of the buildingTherefore;
Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49
Height of the antenna ≈ 2.49 mLearn more about trigonometric tangent ratio here:
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En una radio, 1/8 del dia esta destinado a emitir publicidad. Del total de publucidad, 3/5 corresponden a comerciales de univercidades. En esta radio,¿que fraccion del tiempo diario corrsponde a publicidad de univercidades.
Respuesta:
3/40
Explicación paso a paso:
Dado :
Fracción de tiempo diario dedicado a publicidad = 1/8
Del tiempo diario dedicado a publicidad, 3/5 corresponde a comerciales de universidad
Fracción del tiempo diario dedicado a la publicidad de las universidades:
3/5 de 1/8
3/5 * 1/8 = (3 * 1) / (5 * 8) = 3/40
Solve the inequality.
k + 4 – 2(k – 12) > 0
k > 28
k > –20
k < –20
k < 28
k<28
Step 1: Simplify both sides of the inequality.
−k+28>0
Step 2: Subtract 28 from both sides.
−k+28−28>0−28
−k>−28
Step 3: Divide both sides by -1.
−k /−1 > −28 /−1
k<28
Answer:
k < 28
Step-by-step explanation:
Given inequality :-
k + 4 - 2( k - 12 ) > 0 k + 4 - 2k + 24 > 0-k + 28 > 0 28 > k k < 28Last Option is correct .
24 more than Holly's age is 67
Answer:
This question isn't really complete, but if you're asking what Holly's age is, then that's just 67 - 24, which is 43.
So Holly is 43, if that's the question.
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]h + 24 =67[/tex]
[tex]h = 43[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
We are given that 24 more than Holly's age is 67.⸻⸻⸻⸻
[tex]\boxed{\text{Setting up an equation:}}\\\\\text{'24 more than Holly's age'} \rightarrow h + 24\\\\\text{'is 67'} \rightarrow = 67\\\\\boxed{h + 24 = 67}[/tex]
⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'h'...}}\\\\h + 24 = 67\\-------------\\\rightarrow h + 24 - 24 = 67 - 24\\\\\rightarrow \boxed{h=43}\\\\\\\text{Holly should be 43 years old.}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
There are 25 employees in a office.22 have cell phones 19 have cars, and 2 have niether. How many employees have both.
Answer:
18
Step-by-step explanation:
Let the number of employees with both cell and car be b. Using a Venn diagram shown above,
19 + 22 - b + 2 = 25
43 - b = 25
b = 18
At the baseball stadium there are 548 seats that are divided into 14 rows how many seats are in each row
Answer:
There are 39 seats I think.
Step-by-step explanation:
548 divided by 14 is a decimal but rounded it to the nearest full number.
Given: ABCD is a parallelogram.
Prove: ∠A and ∠D are supplementary.
Parallelogram A B C D is shown.
By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are
angles. Because AB and DC are
, the same-side interior angles must be
by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.
Answer:
AB = DC So ∠A and ∠D are bigger then 90%
Answer:
E2020
Step-by-step explanation:
What is the total value of digit 7 in the number 32.8794
In London today, four times the high temperature was more than twice the high temperature plus
sixty-six. In interval form, what are the possible temperatures
Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)
What is the value of x?
1/2(x+6)=18
Answer:
30
Step-by-step explanation:
Multiply by 2 to 18, x+6=36
subtract 6 x=30
x=30
What value of g makes the equation true?
Answer:
[tex](x + 7)(x - 4) \\ = { \tt{ {x}^{2} + 7x - 4x - 28 }} \\ = { \tt{ {x}^{2} + 3x - 28 }} \\ { \boxed{ \bf{g \: is \: 3}}}[/tex]
Answer:
g=3
Step-by-step explanation:
Hi there!
To find the value of g, we can expand the two binomials using the distributive property:
[tex](x+7)(x-4)\\= x(x-4)+7(x-4)\\= x^2-4x+7x-28\\= x^2+3x-28[/tex]
Therefore, the value of g that makes the equation true is 3.
I hope this helps!
Solve the qn in attachment .
Answer:
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Step-by-step explanation:
The given expression to us is ,
[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]
Now take the LCM as ( x - 1 ) and Simplify , we have ,
[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]
Simplifying further , we get ,
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Hence the second option is correct .
Answer:
[tex] \frac{ \frac{3}{x - 1} - 4 }{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1) - 2}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2 - 2 } \\ \frac{7 - 4x}{2(x - 2)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]