what is an example of reactivity?

Answers

Answer 1
reactivity is an impetus For which a chemical substance undergoes A chemical either by itself or with another materialWith an overall release of energy

Related Questions

What is the price coke difference between a strong and weak acid?

Answers

Explanation:

Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.

H2 CO3 (acid)↔H+ + HCO3- (base)

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Calculate the number of representative particles of 0.0391 mol Neon gas.


i need help ASAP !

Answers

Answer:

2.35 × 10²² particles

Explanation:

To get the number of particles in a substance, we multiply the number of moles (n) of that substance by Avogadro's number (nA).

That is, we say;

number of atoms = n × 6.02 × 10²³

In this question, Neon gas is said to have 0.0391 moles. The number of atoms in that field.

number of particles = 0.0391 × 6.02 × 10²³

number of particles = 0.235 × 10²³

number of particles = 2.35 × 10²² particles

Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)

Answers

Answer:

3.6124 m/kg

Explanation:

Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us  35.4 g of H3PO4 and 100 g of solution to work with.

To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.

Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:

35.4 g x 1 mol / 97.9952 g = 0.3612422 mol

Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.

To find the molality, divide the moles of solute and kilograms of solution.

0.3612422 mol / 0.1 kg = 3.6124 m/kg

la. A man was traveling by sie is allowed a maximum of 20kg luggage. The man
weighing 3.5kg, 15kg.2kg and 15kg
Find the excess weight of his luggage.
Express the excess weight as a percentage of the maximum weight allowed

Answers

Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%

Explanation:

Given values:

Maximum amount of luggage allowed = 20 kg

Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg

Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed

Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg

To calculate the percentage of excess weight, we use the equation:

[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]

Putting values in above equation, we get:

[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]

Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%

What is the molar mass of Na2SO4?
O A. 142.04 g/mol
O B. 71.05 g/mol
O c. 238.22 g/mol
O D. 94.04 g/mol

Answers

I believe its D due to my thinking

Answer: A. 142.04 g/mol

Explanation:

An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
How many milliliters of this suspension should be given to an infant weighing 13 lb.

Answers

Answer:

0.8853 mL

Explanation:

First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:

13 lb * [tex]\frac{0.454kg}{1lb}[/tex] = 5.902 kg

Then we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:

15 mg/kg * 5.902 kg = 88.53 mg

Finally we calculate the required mL of suspension, using its concentration:

88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL

Over time, rocks break down into sediment by wind, water, ice, and/or gravity. This process is commonly referred to as
chemical change

Answers

Answer:

Explanation:

Chemical change

Explain how a scanning electron microscope (SEM) can be used in combination with an energy dispersive X-ray spectrometer (EDS) to perform elemental analysis on extremely small particles by placing the statements in the order that they occur.

Answers

Answer:

SEM provides detailed high resolution images of the sample by rastering a focussed electron beam across the surface and detecting secondary or backscattered electron signal. An Energy Dispersive X-Ray Analyzer (EDX or EDA) is also used to provide elemental identification and quantitative compositional information.

Energy Dispersive X-Ray Spectroscopy (EDS) is a chemical microanalysis technique used in conjunction with scanning electron microscopy (SEM).

The EDS technique detects x-rays emitted from the sample during bombardment by an electron beam to characterize the elemental composition of the analyzed volume.The SEM is an instrument that produces a largely magnified image by using electrons instead of light to form an image. A beam of electrons is produced at the top of the microscope by an electron gun. Once the beam hits the sample, electrons and X-rays are ejected from the sample. The electrons in the beam interact with the sample, producing various signals that can be used to obtain information about the surface topography and composition.

Learn more:

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Please write the right question. I’ll mark as brainliest if it’s right

Answers

Answer:

The correct answer is - A. alkane and E. Branched.

Explanation:

Alkane is saturated hydrocarbons that are combined with a single bond they can be either linear, branched, or cyclic hydrocarbons. A branched-chain or branched compound is a compound that has alkyl groups bonded to its central carbon chain.

Branched alkanes contain only carbon atoms and hydrogen atoms bonded with these carbon atoms in different branches, with carbons connected to other carbons by single bonds only, but the molecules contain branches.

What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid a 0° C?​

Answers

The total number of joules released when a 5.00 gram sample of water changes from liquid to solid a 0

Look at this picture.
Which process in the water cycle is shown in the picture?
evaporation
transpiration
condensation
precipitation

Answers

Answer:

condensation

Explanation:

the water has condensed from the gaseous form into rain drops

Answer:

precipitation

Explanation:

Gaseous methane CH4 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.963 g of methane is mixed with 1.2 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answers

Answer:

[tex]m_{H_2O}=0.676gH_2O[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:

[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]

Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:

[tex]0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O[/tex]

Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:

[tex]m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O[/tex]

Regards!

What must happen for ice to melt at a given pressure?
A. The average kinetic energy of the water molecules must decrease.
B. Thermal energy must be transferred to the ice from its
surroundings.
C. The orderliness of the water molecules must decrease.
D. Thermal energy must be transferred from the ice to its
surroundings.

Answers

Answer:

D

Explanation:

thermal energy must be transferred from the ice to it's surroundings

Thermal energy is the heat and energy present in the system. The thermal energy must be dissipated from ice to the surroundings to melt and produce liquid. Thus, option D is correct.

What is thermal energy?

Thermal energy is present in any substance in the form of energy and heat that depends on kinetic energy, orderliness, randomness, temperature, etc. It is passed from a substance to the surrounding at a lesser temperature.

The ice can melt into a liquid when it loses its thermal energy and heat to the surrounding with increased kinetic energy and releases the temperature to the area with a temperature less than the ice.

Therefore, the heat from ice will get dissipated to the outer environment to melt.

Learn more about thermal energy here:

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What is the mass (g) of 1.00 L water if the density is 1.000 g/mL.

Answers

Answer:

1000g

Explanation:

1 * 1000 = 1000

1. Determine the volume of SO2 (at STP) formed from the reaction of 96.7 mol FeS2 and 55.0 L of O2 at 358 K and 1.20 atm.
4 FeS2(s) + 11O2(g)  2Fe2O3(s) + 8SO2(g)

Answers

Answer:

40.0L of SO2 are produced

Explanation:

To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:

Moles O2:

n = PV/RT

n = 1.20atm*55.0L / 0.082atmL/molK*358K

n = 2.25 moles of O2.

Clearly, limiting reactant is O2.

The moles of SO2 produced are:

2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2

Volume SO2:

V = nRT/P

V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm

V = 40.0L of SO2 are produced

Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) --> 2 Na(s) 3 N2(g) What mass in grams of NaN3(s) must be reacted in order to inflate an air bag to 79.5 L at STP

Answers

Answer:

154 g

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

79.5 L × 1 mol/22.4 L = 3.55 mol

Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.

Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.37 mol × 65.01 g/mol = 154 g

Wat are representative elements

Answers

In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements

Answer:

the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.

Explanation:

=)

1 What direction do
molecules move in?

Answers

Answer:

The majority of the molecules move from higher to lower concentration, although there will be some that move from low to high. The overall (or net) movement is thus from high to low concentration.

hope this helps!<3

identify the organ system pictured below and state two functions of this system in the body​

Answers

Answer:

skeletal system

Explanation:

to create and fliter blood and provide frame-work to the human body and support

Write the structural formula for a primary, a secondary, and a tertiary constitutionally isomeric alcohol of the molecular formula C5H12O.

Answers

Answer:

The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.

Their classification of primary, secondary, and tertiary alcohols are -

1-pentanol -

2-pentanol -

3-pentanol

2-methylbutan-1-ol

2-methylbutan-2-ol

3-methylbutan-2-ol

3-methylbutan-1-ol

2,2-dimethylpropanol

Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?

Answers

Answer:

Explanation: hell noo

Emily must notify the Instructor of the Lab/Classroom.

You are an intermediate product of an industrial process which intends to separate iron from its ore. A well known iron ore is hematite. Which of these ores does not contain iron?
Goethite
Malachite
Siderite
Limonite

Answers

Answer:

Malachite

Explanation:

Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!

Convert speed of 581 miles an hour to units of feet per minute Also so the unit analysis by dragging components into the unit factor factor's

Answers

Explanation:

answer is in photo above

Identify the alkene obtained on dehydration of each of the following alcohols:

a. 3-Ethyl-3-pentanol
b. 1-Propanol
c. 2-Propanol
d. 2,3,3-Trimethyl-2-butanol

Answers

Answer:

Explanation:

The information below explains how dehydration of alcohol occurs to produce alkene.

Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.

The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.

What is its density in kilograms per cubic meter?

Answers

Copper has a density of 8950 kg/m3 = 8.95 kg/dm3 = 8.95 g/cm3. Water has a density of 1000 kg/m3 = 1000 g/L = 1 kg/dm3 = 1 kg/L = 1 g/cm3 = 1 g/mL.

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Gizmo Warm-up Just like students sharing markers, atoms sometimes share or swap electrons. By doing this, atoms form bonds. The Ionic Bonds Gizmo allows you to explore how ionic bonds form. To begin, check that Sodium (Na) and Chlorine (Cl) are selected from the menus at right. Click Play ( ) to see electrons orbiting the nucleus of each atom. (Note: These atom models are simplified and not meant to be realistic.) 1. Each atom consists of a central nucleus and several shells that contain electrons. The outermost electrons are called valence electrons. How many valence electrons does each atom have

Answers

Answer: Sodium element has 1 valence electron and chlorine element has 7 valence electrons.

Explanation:

Valence electrons are defined as the electrons that are present in the outermost shell.

An ionic compound is formed when the complete transfer of electrons takes place from one element (usually metals) to another element (usually non-metals).

To know this, we need to write the electronic configuration of each element.

Sodium is the 11th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^1[/tex]

It has 1 valence electron

Chlorine is the 17th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^23p^5[/tex]

It has 7 valence electrons

Hence, sodium element has 1 valence electron and chlorine element has 7 valence electrons.

For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase in GPS of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information“ button in the last column. Note for advanced students: you may assume ideal gas and ideal solution behavior.

Answers

Answer:

For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column

What is erosion?
A) Weathered materials staying in one place
B) The movement of weathered materials by wind, water or ice
C) New materials on a land form

Answers

the process of eroding or being eroded by wind, water, or other natural agents.

I hope this helps!

Answer:

B. The movement of weathered materials by wind, water or ice.

A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?

Answers

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:

P = 2.4 atmV = 250 mL ⇒ 250 / 1000 = 0.250 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 15 °C ⇒ 15 + 273 = 288 K

We input the given data:

2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And solve for n:

n = 0.025 mol

Finally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:

0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates

Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2and 0.229 gof H2O and 0.407g of SO2are obtained.
Calculate its empirical formula.

Answers

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

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