What inequality does this number line show?​

What Inequality Does This Number Line Show?

Answers

Answer 1
x>5
Because the arrow is pointing towards the numbers that are less than 5, (1,2,3,4)

Related Questions

Find the center, vertices, and foci of the ellipse with equation 4x2 + 9y2 = 36. Center: (0, 0); Vertices: (-3, 0), (3, 0); Foci: Ordered pair negative square root 5 comma 0 and ordered pair square root 5 comma 0 Center: (0, 0); Vertices: (-9, 0), (9, 0); Foci: Ordered pair negative square root 65 comma 0 and ordered pair square root 65 comma 0 Center: (0, 0); Vertices: (0, -3), (0, -3); Foci: Ordered pair 0 comma negative square root 5 and ordered pair 0 comma square root 5 Center: (0, 0); Vertices: (0, -9), (0, 9); Foci: Ordered pair 0 comma negative square root 65 and ordered pair 0 comma square root 65

Answers

Answer:

Option A.

Step-by-step explanation:

The given equation of ellipse is

[tex]4x^2+9y^2=36[/tex]

Divide both sides by 36.

[tex]\dfrac{4x^2}{36}+\dfrac{9y^2}{36}=1[/tex]

[tex]\dfrac{x^2}{9}+\dfrac{y^2}{4}=1[/tex]

[tex]\dfrac{x^2}{3^2}+\dfrac{y^2}{2^2}=1[/tex]    ...(1)

The standard form of an ellipse is

[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]    ...(2)

where, (h,k) is center, (h±a,k) are vertices and (h±c,k) are foci.

On comparing (1) and (2), we get

[tex]h=0,k=0,a=3,b=2[/tex]

Now,

Center [tex]=(h,k)=(0,0)[/tex]

Vertices [tex]=(h\pm a,k)=(0\pm 3,0)=(3,0),(-3,0)[/tex]  

We know that

[tex]c=\sqrt{a^2-b^2}=\sqrt{3^2-2^2}=\sqrt{5}[/tex]

Foci [tex]=(h\pm c,k)=(0\pm \sqrt{5},0)=(\sqrt{5},0),(-\sqrt{5},0)[/tex]

Therefore, the correct option is A.

help please! I need this ASAP Find the value of x

Answers

Answer:

The value of x is 30°

Step-by-step explanation:

We are given that the outer angle of the parallelogram is 60 degrees. Therefore it's respective inner angle will be 180 - 60 = 120 degrees. And, by properties of a parallelogram, the angle opposite to this angle will be 120 degrees as well.

If we draw extend the line creating angle 2x, then we will make ( 1 ) a vertical angle to 2x, ( 2 ) a 90 degree angle, and ( 3 ) and angle that we can let be y. Therefore, 2x + y = 90, and 3x + y = 120.

[tex]\begin{bmatrix}2x+y=90\\ 3x+y=120\end{bmatrix}[/tex] ,

[tex]\begin{bmatrix}6x+3y=270\\ 6x+2y=240\end{bmatrix}[/tex] ,

[tex]6x+2y=240\\-\\\underline{6x+3y=270}\\y=30[/tex],  

[tex]2x + (30) = 90,\\2x = 60,\\x = 30[/tex]

Solution : x = 30°

Lynn estimates roof jon 1500,bo estimates 2400. What's the ratio to lynn to bo

Answers

Answer:

5:8

Step-by-step explanation:

If I understand your question correctly, we have 1500/2400=15/24=5/8, so we have Lynn:Bo is 5:8, however, in the future please be more clear.

What is "estimates roof jon"? And, instead of saying "ratio to lynn to bo" say "What is the ratio of the estimates?" or whatever you're asking. If this answer is wrong, you only have yourself to blame.

A 95% confidence interval for the mean number of television per American household is (1.15, 4.20). For each of the following statements about the above confidence interval, choose true or false.
a. The probability that u is between 1.15 and 4.20 is .95.
b. We are 95% confident that the true mean number of televisions per American household is between 1.15 and 4.20.
c. 95% of all samples should have x-bars between 1.15 and 4.20 televisions.
d. 95% of all American households have between 1.15 and 4.20 televisions
e. Of 100 intervals calculated the same way (95%), we expect 95 of them to capture the population mean.
f. Of 100 intervals calculated the same way (95%), we expect 100 of them to capture the sample mean.

Answers

Answer:

a. False

b. True

c. False

d. False

e.True

f. True

Step-by-step explanation:

The 95% is confidence interval its not a probability estimate. The probability will be different from the confidence interval. Confidence interval is about the population mean and is not calculated based on sample mean. Every confidence interval contains the sample mean. There is 95% confidence that the number of televisions per American household is between 1.15 to 4.20.

Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is confident that Tweed residents are more concerned about the environment than the residents of Ledee. He knows that the average electricity consumption of Tweed households last February was 854.11 kWh and decides to test if Ledee residents used more electricity that month, on average. He collects data from 65 Ledee households and calculates the average electricity consumption to be 879.28 kWh with a standard deviation of 133.29 kWh. There are no outliers in his sample data. Neal does not know the population standard deviation nor the population distribution. He uses a one-sample t-test with a significance level of α = 0.05 to test the null hypothesis, H0:µ=854.11, against the alternative hypothesis, H1:μ>854.11 , where μ is the average electricity consumption of Ledee households last February. Neal calculates a t‑statistic of 1.522 and a P-value of 0.066.

Based on these results, complete the following sentences to state the decision and conclusion of the test.

Neal's decision is to__________ the __________ (p 0.066). There is_________ evidence to _________ the claim that the average electricity consumption of ____________ is _________ , ________

Answers

Complete Question

The option to the blank space are shown on the first uploaded image

Answer:

Neal's decision is to fail to reject the null hypothesis   (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all  Ledee household is greater than , 854.28 kWh

Step-by-step explanation:

From the question we are told that

   The population mean is  [tex]\mu = 854.11[/tex]

   The sample size is  [tex]n = 65[/tex]

    The sample mean is  [tex]\= x = 879.28 \ kWh[/tex]

    The standard deviation is  [tex]\sigma = 133.29 \ kWh[/tex]

    The level of significance is  [tex]\alpha = 0.05[/tex]

     The  null hypothesis is  [tex]H_o: \mu = 854.11[/tex]

     The  alternative hypothesis is  [tex]H_a : \mu > 854.11[/tex]

     The  t-statistics is  [tex]t = 1.522[/tex]

      The  p-value is [tex]p-value = 0.066[/tex]

Now from the given data we can see that

         [tex]p-value < \alpha[/tex]

Generally when this is the case , we fail to reject the null hypothesis

   So

Neal's decision is to fail to reject the null hypothesis   (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all  Ledee household is greater than , 854.28 kWh            

     

What is the probability of the spinner landing on an odd number? A spinner is split into 4 equal parts labeled 1, 2, 3, and 4. One-fourth One-third One-half Three-fourths

Answers

Answer:

One half, or 1/2.

There are an equal amount of odd numbers as there are even numbers on the spinner.

Answer:

C. 1/2

One-half

which operation should you perform first when evaluating the expression 3²+ 2​

Answers

Answer:

You should calculate 3² first.

Step-by-step explanation:

In PEMDAS, E (which stands for exponents) comes before A (which stands for addition) so therefore you should calculate 3² first.

Answer: Exponents is done first (evaluate [tex]3^2[/tex] first)

Explanation:

The acronym PEMDAS helps determine the order of operations

P = parenthesis

E = exponents

M = multiplication

D = division

A = addition

S = subtraction

With the expression [tex]3^2+2[/tex] we have two operations going on here: exponents and addition.

Since exponents comes before addition (E comes before A in PEMDAS), this means we evaluate [tex]3^2[/tex] first, then add later.

Solve this problem using the Trigonometric identities (secA+1)(SecA-1)= tan^2A

Answers

Step-by-step explanation:

( secA + 1)( sec A - 1)

Using the expansion

( a + b)( a - b) = a² - b²

Expand the expression

We have

sec²A + secA - secA - 1

That's

sec² A - 1

From trigonometric identities

sec²A - 1 = tan ²A

So we have the final answer as

tan²A

As proven

Hope this helps you

Step-by-step explanation:

Here,

LHS

= (SecA+1)(secA -1)

[tex] = {sec}^{2} A - 1[/tex]

[tex]{as{a}^{2} - {b}^{2} =(a + b)(a - b)[/tex]

Now, we have formula that:

[tex] {sec}^{2} \alpha - {tan \alpha }^{2} = 1[/tex]

[tex] {tan}^{2} \alpha = {sec }^{2} \alpha - 1[/tex]

as we got ,

[tex] = {sec}^{2} A- 1[/tex]

This is equal to:

[tex] = {tan}^{2} A[/tex]

= RHS proved.

Hope it helps....

Jonah read 5 1/2 chapters in his book in 90 minutes how long did it take him to read one chapter

Answers

Answer:

around 16 minutes. you partition an hour and a half (all out) by what number of sections he read (5.5

Step-by-step explanation:

I
Ifm DGF = 72, what equation can you use to find mZEGF?

Answers

Answer:

see explanation

Step-by-step explanation:

∠ DGE + ∠ EGF = ∠ DGF , that is

∠ EGF = ∠ DGF - ∠ DGE

∠ EGF = 72° - ∠ DGE

You plan to conduct a marketing experiment in which students are to taste one of two different brands of soft drink. Their task is to correctly identify the brand tasted. You select a random sample of 200 students and assume that the students have no ability to distinguish between the two brands. The probability is 90% that the sample percentage is contained within what symmetrical limits of the population percentage

Answers

Answer:

the probability is 90% that the sample percentage is contained within 45.5% and 54.5% symmetric limits of the population percentage.

Step-by-step explanation:

From the given information:

Sample size n = 200

The standard deviation for a sampling distribution for two brands are equally likely because the individual has no ability to discriminate between the two soft drinks.

The population proportion [tex]p_o[/tex] = 1/2 = 0.5

NOW;

[tex]\sigma _p = \sqrt{\dfrac{p_o(1-p_o)}{n}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.5(1-0.5)}{200}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.5(0.5)}{200}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.25}{200}}[/tex]

[tex]\sigma _p = \sqrt{0.00125}[/tex]

[tex]\sigma _p = 0.035355[/tex]

However, in order to determine the symmetrical limits of the population percentage given that the z probability is 90%.

we use the Excel function as computed as follows in order to determine the z probability  = NORMSINV (0.9)

z value = 1.281552

Now the symmetrical limits of the population percentage can be determined as: ( 1.28, -1.28)

[tex]1.28 = \dfrac{X - 0.5}{0.035355}[/tex]

1.28 × 0.035355 = X - 0.5

0.0452544= X - 0.5

0.0452544 + 0.5 = X

0.5452544 = X

X [tex]\approx[/tex] 0.545

X = 54.5%

[tex]-1.28 = \dfrac{X - 0.5}{0.035355}[/tex]

- 1.28 × 0.035355 = X - 0.5

- 0.0452544= X - 0.5

- 0.0452544 + 0.5 = X

0.4547456 = X

X [tex]\approx[/tex] 0.455

X = 45.5%

Therefore , we can conclude that the probability is 90% that the sample percentage is contained within 45.5% and 54.5% symmetric limits of the population percentage.

−(−49) = −49 true or false?

Answers

False.

Whenever you see a negative sign next to another negative sign, you will always get a positive. So -(-49) is equal to +49
With that information we can determine that it is not equal to negative 49.

Please answer this correctly without making mistakes

Answers

Step-by-step explanation:

Option A and B are the correct answer because it equal to 688.5 and 688.05

Answer:

it is 1377/2 and 688 1/17 thats the answer

Step-by-step explanation:

Evaluate 2/3 + 1/3 + 1/6 + … THIS IS CONTINUOUS. It is NOT as simple as 2/3 + 1/3 + 1/6.

Answers

[tex]a=\dfrac{2}{3}\\r=\dfrac{1}{2}[/tex]

The sum exists if [tex]|r|<1[/tex]

[tex]\left|\dfrac{1}{2}\right|<1[/tex] therefore the sum exists

[tex]\displaystyle\\\sum_{k=0}^{\infty}ar^k=\dfrac{a}{1-r}[/tex]

[tex]\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{1}{6}+\ldots=\dfrac{\dfrac{2}{3}}{1-\dfrac{1}{2}}=\dfrac{\dfrac{2}{3}}{\dfrac{1}{2}}=\dfrac{2}{3}\cdot 2=\dfrac{4}{3}[/tex]

Find the product . Write your answer in exponential form 8^-2•8^-9

Answers

Answer:

  8^-11

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

Then we have ...

  (8^(-2))·(8^(-9)) = 8^(-2-9) = 8^-11

Two samples from the same population both have M = 84 and s2 = 20, but one sample has n = 10 and the other has n = 20 scores. Both samples are used to evaluate a hypothesis stating that μ = 80 and to compute Cohen’s d. How will the outcomes for the two samples compare?

Answers

Complete Question

Two samples from the same population both have M = 84 and s2 = 20, but one sample has n = 10 and the other has n = 20 scores. Both samples are used to evaluate a hypothesis stating that μ = 80 and to compute Cohen’s d. How will the outcomes for the two samples compare?

a.

The larger sample is more likely to reject the hypothesis and will produce a larger value for Cohen’s d.

b.

The larger sample is more likely to reject the hypothesis, but the two samples will have the same value for Cohen’s d.

c.

The larger sample is less likely to reject the hypothesis and will produce a larger value for Cohen’s d.

d.

The larger sample is less likely to reject the hypothesis, but the two samples will have the same value for Cohen’s d.

Answer:

The Cohen's d value is  [tex]d = 0.895[/tex]

The  correct option is b

Step-by-step explanation:

From the question we are told that

   The  sample mean of  each population is  [tex]M = 84[/tex]

    The  variance of each  population is  [tex]s^2 = 20[/tex]

    The  first sample size is  [tex]n_1 = 10[/tex]

    The  second  sample size is  [tex]n_2 = 20[/tex]

 

The  null hypothesis is  [tex]H_o : \mu = 80[/tex]

   Generally the standard deviation is mathematically evaluated as

            [tex]s = \sqrt{20 }[/tex]

=>         [tex]s = 4.47[/tex]

  The first test statistics is evaluated as

            [tex]t_1 = \frac{M - \mu }{ \frac{\sigma }{ \sqrt{n_1} } }[/tex]

    =>    [tex]t_1 = \frac{84 - 80 }{ \frac{4.47 }{ \sqrt{10} } }[/tex]

   =>     [tex]t_1 = 2.8298[/tex]

  The second  test statistics is evaluated as

           [tex]t_2 = \frac{M - \mu }{ \frac{\sigma }{ \sqrt{n_2} } }[/tex]

=>       [tex]t_2 = \frac{84 - 80 }{ \frac{4.47 }{ \sqrt{20} } }[/tex]

=>       [tex]t_2 = 4.0[/tex]

The sample with the larger test statistics (sample  size) will more likely reject the null hypothesis

Generally the Cohen's d value is mathematically evaluated as

          [tex]d = \frac{M - \mu }{s }[/tex]

  =>     [tex]d = \frac{ 84 - 80 }{4.47 }[/tex]    

=>         [tex]d = 0.895[/tex]

Given that the the sample mean and  sample size are the same for both sample the Cohen's d value will be  the same      

Solve x/10 = -7 A. x = 3 B. x = -0.7 C. x = -17 D. x = -70

Answers

Answer:

x = -70

Step-by-step explanation:

x/10 = -7

Multiply each side by 10

x/10*10 = -7*10

x = -70

URGENT, PLEASE HELP! (4/5) -50 POINTS- ! please no wrong answers for the points.! A) y = -3x + 2 B) y = -x + 2 C) y = 3x + 2 D) y = x + 1

Answers

Answer:

D  y= x+1

Step-by-step explanation:

The line has a positive slope since it goes up from left to right

We can eliminate A and B

3 is a fairly steep slope for line C

Lets check with point x=7

y = 3*7 +2 = 21+2 = 23

Way too steep

Lets check 2

y = 3*2+2 = 6+2 = 8

Still above the points

Checking D

y = x+1

x=7

y = 7+1 =8  A little high

x=2

y = 2+1 =3  A little low    but much better than C

Answer:

[tex]\huge \boxed{y=x+1}[/tex]

Step-by-step explanation:

Using a graph,

we can see the line y=x+1 is best fit for the data.

Molly’s house is located at point X. Molly wants Sophia and Cole to meet at her house because she thinks it is the same distance from Sophia’s house and Cole’s house. Which could prove that Molly’s house is the samedistance from Sophia’s and Cole’s houses?

Answers

Answer:

Cole's House

Step-by-step explanation:

Cole house is closer because molly and Sophia can go there together because there both girls

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

21, 14, 13, 24, 17, 22, 25, 12

Required:
a. Calculate the sample mean and the sample standard deviation.
b. Construct the 90% confidence interval for the population mean.
c. Construct the 95% confidence interval for the population mean

Answers

Answer:

a

   [tex]\= x = 18.5[/tex]  ,  [tex]\sigma = 5.15[/tex]

b

 [tex]15.505 < \mu < 21.495[/tex]

c

 [tex]14.93 < \mu < 22.069[/tex]

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        [tex]\= x = \frac{\sum x }{n}[/tex]

        [tex]\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}[/tex]

         [tex]\= x = 18.5[/tex]

Generally the standard deviation is mathematically evaluated as

         [tex]\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}[/tex]

[tex]\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}[/tex]

[tex]\sigma = 5.15[/tex]

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         [tex]\alpha = 100-90[/tex]

         [tex]\alpha = 10\%[/tex]

         [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex]  from the normal distribution table the value is  

     [tex]Z_{\frac{ \alpha }{2} } = 1.645[/tex]

The margin of error is mathematically represented as

      [tex]E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

=>    [tex]E =1.645 * \frac{5.15 }{\sqrt{8} }[/tex]

=>     [tex]E = 2.995[/tex]

The 90% confidence interval is evaluated as

       [tex]\= x - E < \mu < \= x + E[/tex]

substituting values

       [tex]18.5 - 2.995 < \mu < 18.5 + 2.995[/tex]

       [tex]15.505 < \mu < 21.495[/tex]

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         [tex]\alpha = 100-95[/tex]

         [tex]\alpha = 5\%[/tex]

         [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex]  from the normal distribution table the value is  

     [tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]

The margin of error is mathematically represented as

      [tex]E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

=>    [tex]E =1.96 * \frac{5.15 }{\sqrt{8} }[/tex]

=>     [tex]E = 3.569[/tex]

The 95% confidence interval is evaluated as

       [tex]\= x - E < \mu < \= x + E[/tex]

substituting values

       [tex]18.5 - 3.569 < \mu < 18.5 + 3.569[/tex]

       [tex]14.93 < \mu < 22.069[/tex]

2(2^3+7)^3+2(7^2+5)2

Answers

If this is what you meant...

Which is the graph of g(x) = (0.5)x + 3 – 4?

Answers

Answer:

Graph (A)

Step-by-step explanation:

Given question is incomplete; find the question in the attachment.

Given function is g(x) = [tex](0.5)^{x+3}-4[/tex]

Parent function of the given function is,

f(x) = [tex](0.5)^{x}[/tex]

When the function 'f' is shifted by 3 units left over the x-axis, translated function will be,

h(x) = f(x+3) = [tex](0.5)^{x+3}[/tex]

When h(x) is shifted 4 units down, translated function will be,

g(x) = h(x) - 4

g(x) = [tex](0.5)^{x+3}-4[/tex]

g(x) has a y-intercept as (-4).

From the given graphs, Graph A shows the y-intercept as (-4).

Therefore, Graph A will be the answer.

Answer:

The Answer A is correct

Step-by-step explanation:

I took the edg2020 test

Help Quick Please. Will give brainliest.

Answers

Answer:

72[tex]\sqrt{3}[/tex] units²

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

Here b = ST = a = 12 and h = RS

To calculate RS use the tangent ratio in the right triangle and the exact value

tan60° = [tex]\sqrt{3}[/tex] , thus

tan60° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{RS}{ST}[/tex] = [tex]\frac{RS}{12}[/tex] = [tex]\sqrt{3}[/tex] ( multiply both sides by 12 )

RS = 12[tex]\sqrt{3}[/tex]

Thus

A = [tex]\frac{1}{2}[/tex] × 12 × 12[tex]\sqrt{3}[/tex] = 6 × 12[tex]\sqrt{3}[/tex] = 72[tex]\sqrt{3}[/tex] units²

Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately Normally distributed with a mean of 2.45 microns and a standard deviation of 0.35 micron. What is the standardized score for a binding site position of 2.03 microns? (Enter your answer rounded to one decimal place.)

Answers

Answer:

The values is  

Step-by-step explanation:

From the question we are told that

  The population mean is  [tex]\mu = 2.45[/tex]

    The  standard deviation is  [tex]\sigma = 0.35 \ mi[/tex]

     The random value is  [tex]x = 2.03[/tex]

The standardized score for a binding site position of 2.03 microns is mathematically represented as

       [tex]z-score = \frac{x - \mu}{ \sigma }[/tex]

=>      [tex]z-score = \frac{2.03 - 2.45}{ 0.35}[/tex]

=>    [tex]z-score = -1.2[/tex]

Could someone help me pls! And could you explain if possible? Thanks you

Answers

Answer:

3%

Step-by-step explanation:

1. Set up the equation

6(0.18) + 12x = 18(0.08)

2. Simplify

1.08 + 12x = 1.44

3. Solve

12x = 0.36

x = 0.03

0.03 = 3%

The regular hexagon ABCDEF rotates 240º counterclockwise about its center to form hexagon A′B′C′D′E′F′. Point C′ of the image coincides with point
of the preimage. Point D′ of the image coincides with point
of the preimage.

Answers

Answer:

Point C: G

Point D: F

Step-by-step explanation:

A hexagon has 6 sides.

360/6=60

Every 60°, it moves one section.  

240/60=4.

So it moves 4 sections.

C would move 4 sections BACK (B, A, F, G)

D would also move 4 sections back (C, B, A, F)

Answer:

Point C is: E

point D is : F

Step-by-step explanation:

x
Find the value
of x. Show
3
10
your work.

Answers

Step-by-step explanation:

Hello, there!!!

Let ABC be a Right angled triangle,

where, AB = 3

BC= 10

and AC= x

now,

As the triangle is a Right angled triangle, taking angle C asrefrence angle. we get,

h= AC = x

p= AB = 3

b= BC= 10

now, by Pythagoras relation we get,

[tex]h = \sqrt{ {p}^{2} + {b}^{2} } [/tex]

[tex]or ,\: h = \sqrt{ {3}^{2} + {10}^{2} } [/tex]

by simplifying it we get,

h = 10.44030

Therefore, the answer is x= 10.

Hope it helps...

What is the value of this expression when x = -6 and y = — 1/2? 4(x^2+3) -2y A. -131 B. -35 C. 57 1/2 D. 157

Answers

Answer:

D

Step-by-step explanation:

[tex]4(x^2+3)-2y\\\\=4((-6)^2+3)-2(\frac{-1}{2} )\\\\=4(36+3)+1\\\\=4(39)+1\\\\=156+1\\\\=157[/tex]

The value of the expression 4(x² + 3) - 2y is 157, when x = -6 and y = -1/2.

What is an algebraic expression?

An algebraic expression is consists of variables, numbers with various mathematical operations,

The given expression is,

4(x² + 3) - 2y

Substitute x = -6 and y = -1/2 to find the value of expression,

= 4 ((-6)² + 3) - 2(-1/2)

= 4 (36 + 3) + 1

= 4 x 39 + 1

= 156 + 1

= 157

The required value of the expression is 157.

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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.966 grams and a standard deviation of 0.315 grams. Find the probability of randomly selecting a cigarette with 0.305 grams of nicotine or less.

Answers

Answer:

The  probability is  [tex]P(X \le 0.305 ) = 0.01795[/tex]

Step-by-step explanation:

From the question we are told that

      The population mean is  [tex]\mu = 0.966 \ grams[/tex]

       The standard deviation is  [tex]\sigma = 0.315 \ grams[/tex]

Given that the amounts of nicotine in a certain brand of cigarette are normally distributed

    Then the probability of randomly selecting a cigarette with 0.305 grams of nicotine or less is mathematically represented as

        [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(\frac{X - \mu }{\sigma } > \frac{0.305 - \mu }{\sigma } )[/tex]

Generally

              [tex]\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ of X )[/tex]

So  

      [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(Z > \frac{0.305 - 0.966 }{0.315} )[/tex]

      [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(Z >-2.0984 )[/tex]

From the z-table(reference calculator dot  net  ) value of   [tex]P(Z >-2.0984 ) =0.98205[/tex]

So  

     [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - 0.98205[/tex]

=>  [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 0.01795[/tex]

=> [tex]P(X \le 0.305 ) = 0.01795[/tex]

HELPP PLEASEE ��2222 is the diameter of a circle. The coordinates are �(−2, −3) and �(−12, −5). At what coordinate is the center of the circle located? A. (5, 1) B. (−5, −1) C. (−4, −7) D. (−7, −4)

Answers

Answer:

(-7, -4)  which is your answer D in the list of options

Step-by-step explanation:

The center of the circle should be located half way in between the given points on the plane.

Then the center ahs to be located half way for the x coordinates of both points:

half way between -12 and -2 (notice that there is a difference of 10 units between them), therefore half way would be at 5 units to the right from the furthest point, that is  -12 + 5 = -7

Similarly, for the y coordinate, we see that the difference is between -5 and -3 (a difference of two units) therefore the center point will be located half way  (that is one unit) up from the lowest y coordinate: -5 + 1 = -4

Then the center of the circle is located at (-7, -4)

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