What do we need to know to understand the formation of a chemical bond?​

Answer:

Its atomic number is 14 and its atomic mass is 28. The most common isotope of uranium has 92 protons and 146 neutrons. Its atomic number is 92 and its atomic mass is 238 (92 + 146).

Noble gas elements are almost always found as a single atom in nature.

An inert gas is a gas that does not undergo chemical reactions under a set of given conditions. The noble gases often do not react with many substances and were historically referred to as inert gases.

All noble gases have the maximum number of electrons in their outer shell; i.e. 2 electrons for helium and 8 for the other five.

Noble gases are monoatomic, which means they exist as single atoms. This is because of their electronic stability.

Thus, noble gas elements are almost always found as a single atom in nature. Hence, option C is correct.

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Explanation:

the carbon would be sp3 hybridized, and it doesn't matter which carbon, since either of them have a full octet

Answer: The balanced equation for the complete oxidation reaction of ethanol is [tex]C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O[/tex]

Explanation:

Combustion is the chemical process where an organic molecule reacts with oxygen gas present in the air to produce carbon dioxide and water molecules.

It is also known as an oxidation reaction because oxygen is getting added.

The chemical equation for the oxidation of ethanol follows:

[tex]C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O[/tex]

By stoichiometry of the reaction:

1 mole of ethanol reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas and 3 moles of water molecules.

Answer:

the answer is d.) potassium

Explanation:

D.22

is my answer than welcome

Answer:

they are the end results so they are after the yields symbol

Explanation:

Answer:

sosksjsjjs

Explanation:

even i know how to type şïllily

Answer: 0.085 (Ms)⁻¹

Explanation: Half life = 12 s

is the initial concentration = 0.98 M

Half life expression for second order kinetic is:

k = 0.085 (Ms)⁻¹

The rate constant for this reaction is 0.085 (Ms)⁻¹ .

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

[tex]= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6[/tex]

Answer:

Explanation:

a) Ionic

Lithium oxide

b) Covalent

[tex]$\ce{N_2O_3}$[/tex]

c) Covalent

Phosphorus trichloride

d) Ionic

[tex]Mn_2O_3[/tex]

Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

Answer:

False

Explanation:

Because Elaidic acid is an isomer of oleic acid. I really hope this helps you.

Answer:

[tex]d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

[tex]d=\frac{m}{V}[/tex]

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

[tex]m=552.4g-464.7g=87.7g[/tex]

So that we are now able to calculate the density in g/mL first:

[tex]d=\frac{87.7g}{27.8mL}=3.15g/mL[/tex]

Now, we proceed to the conversion to lb/in³ by using the following setup:

[tex]d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Regards!

Answer:

56.8%

Explanation:

The reaction of the problem is 1:1. That means 1 mole of 2-methylcyclohexanone produce 1 mole of 2-methylcyclohexanol.

Percentage yield is defined as 100 times the ratio between actual yield of the reaction (5.14g) and the theoretical yield.

The theoretical yield (All reactant produce products) is obtained from the mass of the reactant as follows:

Theoretical Yield:

8.89g 2-methylcyclohexanone * (1mol/112.17g) = 0.07925 moles 2-methylcyclohexanone

Assuming all reactant produce the product in a 100% of yield, the moles of 2-methylcyclohexanol are 0.07925 moles and the mass (Theoretical yield) is:

0.07925 moles 2-methylcyclohexanol * (114.19g/mol) = 9.05g

Percentage yield:

5.14g / 9.05g * 100 = 56.8%

The percentage of the mass successfully converted into a new product is 57.2%.

The mass of the reactant (2-methylcyclohexanone) before the reduction is given as 8.89 g.

The mass of the product ( 2-methylcyclohexanol) produced is given as 5.14 g.

The percentage of the mass successfully converted into a new product is calculated as follows;

[tex]= \frac{5.14}{8.99} \times 100\% \\\\= 57.2 \ \%[/tex]

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Answer:

a

Explanation:

Beer-Lambert Law shows the relationship between the factors affecting the absorbance of a sample in relation to the concentration. These factors are:

the concentration c, path length (l), and the molar absorptivity (ε).

As a result, more radiation is assimilated as the concentration rises, and the absorbance rises as well. However, the longer the path length, the increase in the number of molecules and the higher the absorbance.

Thus, the straight-line equation for Beer-Lambert's law is:

A = εcl

From the above explanation, the option that doesn't relate to the deviations from linearity of Beer's law plot is in Option (a).

Answer:

the weakest base will have a higher Kb value since it will be closer to an acid than a base

7 kb values represents the weakest base.

Kb is the base dissociation constant which is a measure of how completely a base dissociates into its component ions in water. pKb is define as the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

Ka is define as the acid dissociation constant while pKa is the -log of this constant. Kb is define as the base dissociation constant, while pKb is the -log of the constant.

The acid and base dissociation constants are usually expressed in terms of moles per liter (mol/L).

Thus, 7 kb values represents the weakest base.

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Answer:

Density of liquid = 1.59 g/cm³

Explanation:

We'll begin by converting 0.610 L to cm³. This can be obtained as follow:

1 L = 1000 cm³

Therefore,

0.610 L = 0.610 L × 1000 cm³ / 1 L

0.610 L = 610 cm³

Finally, we shall determine the density of the liquid. This can be obtained as follow:

Volume of liquid = 610 cm³

Mass of liquid = 972 g

Density of liquid =?

Density = mass / volume

Density of liquid = 972 / 610

Density of liquid = 1.59 g/cm³

The density of any given liquid is equivalent to the mass of the liquid divided by the volume of the liquid.

From the given information, we have:

The mass of the unknown liquid to be = 972 g

The volume of the unknown liquid to be = 0.610 L = 610 cm³

If the formula for calculating [tex]\mathbf{Density = \dfrac{Mass}{Volume}}[/tex]

Then;

[tex]\mathbf{Density \ of \ the \ unknown \ liquid = \dfrac{972 \\ g}{610 \ cm}}[/tex]

[tex]\mathbf{Density \ of \ the \ unknown \ liquid = 1.593442623 \ g/cm}[/tex]

The Density of the unknown liquid ≅ 1.593  g/cm³

In conclusion, the density of the unknown liquid is 1.593  g/cm³ to 3 significant figures.

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Answer:

1. RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)

2. Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)

3. (NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)

Explanation:

Let's consider the dissolving equations for the following compounds.

1. Rubidium hydroxide

RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)

2. Sodium carbonate

Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)

3. Ammonium selenite

(NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)

Answer:

Four common types of reactions involving carbonyl reactions: 1) nucleophilic addition; 2) nucleophilic acyl substitution; 3) alpha substitution; 4) carbonyl condensations. The first two were previously discussed and the second two involve the properties of the carbon directly adjacent to the carbonyls, α carbons.

Alpha-substitution reactions results in the replacement of an H attached to the alpha carbon with an electrophile.  

The nucleophile in these reactions are new and called enols and enolates.

Explanation:

The carbon in the carbonyl is the reference point and the alpha carbon is adjacent to the carbonyl carbon.  

Hydrogen atoms attached the these carbons denoted with Greek letters will have the same designation, so an alpha hydrogen is attached to an alpha carbon.  

Aldehyde hydrogens not given Greek leters.  

α hydrogens display unusual acidity, due to the resonance stabilization of the carbanion conjugate base, called an enolate.  

Tautomers are readily interconverted constitutional isomers, usually distinguished by a different location for an atom or a group, which is different than resonance.  

The tautomerization in this chapter focuses on the carbonyl group with alpha hydrogen, which undergo keto-enol tautomerism.  

Keto refers to the tautomer containing the carbonyl while enol implies a double bond and a hydroxyl group present in the tautomer.  

The keto-enol tautomerization equilibrium is dependent on stabilization factors of both the keto tautomer and the enol tautomer, though the keto form is typically favored for simple carbonyl compounds.  

The 1,3 arrangement of two carbonyl groups can work synergistically to stabilize the enol tautomer, increasing the amount present at equilibrium.

The positioning of the carbonyl groups in the 1,3 arrangement allows for the formation of a stabilizing intramolecular hydrogen bond between the hydroxyl group of the enol and the carbonyl oxygen as well as the alkene group of the enol tautomer is also conjugated with the carbonyl double bond which provides additional stabilization.

Aromaticity can also stabilize the enol tautomer over the keto tautomer.

Under neutral conditions, the tautomerization is slow, but both acid and base catalysts can be utilized to speed the reaction up.  

Biological enol forming reactions use isomerase enzymes to catalyze the shifting of a carbonyl group in sugar molecules, often converting between a ketose and an aldose in a process called carbonyl isomerization.

Answer:

The correct approach is "12.25°C".

Explanation:

Given:

Mass of lead,

mc = 245 g

Initial temperature,

tc = 300°C

Mass of Aluminum,

ma = 150 g

Initial temperature,

ta = 12.0°C

Mass of water,

mw = 820 g

Initial temperature,

tw = 12.0°C

Now,

The heat received in equivalent to heat given by copper.

The quantity of heat = [tex]m\times s\times t \ J[/tex]

then,

⇒ [tex]245\times .013\times (300-T) = 150\times .9\times (T-12.0) + 820\times 4.2\times (T-12.0)[/tex]

⇒             [tex]3.185(300-T) = 135(T-12.0) + 3444(T-12.0)[/tex]

⇒             [tex]955.5-3.185T=135T-1620+3444T-41328[/tex]

⇒                         [tex]43903.5 = 3582.185 T[/tex]

⇒                                  [tex]T = 12.25^{\circ} C[/tex]

Answer:

The pH is greater than 7 at the equivalence point.

Explanation:

Equivalence point is the point where the acid reacts with the base as stipulated in the equation of the reaction.

When a weak acid and a strong base are titrated, the pH of the solution at equivalence point is actually found to be around about pH ~ 9.

Hence, for a weak acid and strong base titration, The pH is greater than 7 at the equivalence point.

A titration between a weak acid and a strong base yields a solution whose pH is greater than 7 at the equivalence point.

Weak acids are acids which only ionize partially in aqueous solutions.

When weak acids are dissolved in water, they produce only few hydrogen ions.

A strong base on the other hand ionizes completely to produce hydroxide ions in aqueous solutions.

The titration of a weak acid and a strong base gives a solution whose pH is greater than 7 at equivalence point.

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Answer:

I think you can make 26, hope this helped.

Explanation:

Answer:

2

Explanation:

Lead(|V) fluoride

Ammonium Nitrate

Lithium sulfide

For the rules, I don't know what you were taught. I just do it intuitively since I have done so much chemistry.

The first one the roman numerals represents the charge of the lead which much match the 4- charge from the 4 fluorides.

The second one is just two polyatomic ions which you just have to remember.

The last one is the typical ionic compound naming technique i guess.

Answer:

Acids react with most metals to form hydrogen gas and salt. ... When an acid reacts with metal, salt and hydrogen gas are produced

Answer:

Cu+(aq)--->Cu2+(aq) + e- : oxidation

reason: there is loss of electrons.

I2(s) + 2e--->2I-(aq) : reduction

reason: There is reduction of electrons.

Answer:

Explanation:

The reaction between 2 chloro- 2 methyl pentane and sodium iodide takes place through SN2 mechanism . iodide ion is the nucleophile which attacks the substrate . The rate of such reaction depends upon concentration of both the nucleophile and the substrate .

Hence rate of reaction will be increased by 2 x 2 = 4 times.

option D ) is correct.

Explanation:

The given reaction represents the reaction between a tertiary alkyl halide that is 2-chloro-2-methylpentane and a nucleophile that is NaI.

This reaction favors SN1 mechanism which has order one.

So, the given reaction follows first-order kinetics.

For a first-order reaction, the rate law is:

rate =k [A]

That means the rate of the reaction is dependent on the concentration of reactants.

So, when the concentration of the reactant is doubled then, the rate of the reaction is also doubled.

Among the given options the correct answer is option B) It would double the rate.

Answer:

D. all of the above

Explanation:

A and C are verified by Keplar's laws of planetary motion.

B is verified by the equatorial and polar aces of the Planet.

Answer:

c

Explanation:

they dont have to orbit the sun specifically and are commonly more ovoid than spherical

Answer:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to write the complete molecular equation as shown below:

[tex]Pb(NO_3)_2(aq)+Ni(s)\rightarrow Ni(NO_3)_2(aq)+Pb(s)[/tex]

Now, we can separate the nitrates in ions as they are aqueous to obtain:

[tex]Pb^{2+}(aq)+2(NO_3)^-(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+2(NO_3)^-(aq)+Pb(s)[/tex]

And then, we cancel out the nitrate ions as the spectator ones, for us to obtain the net ionic equation:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Best regards!

Answer:

19.3 g of NaCl can be produced

Explanation:

We state the reaction:

Cl₂ (g) + 2NaI (s) →  2NaCl (s) + I₂ (s)

We need to determine limiting reagent:

15.4 g . 1mol /70.9g = 0.217 moles of chlorine

49.6 g . 1mol / 149.89g = 0.331 moles of NaI

Ratio is 1:2. 1 mol of chlorine reacts to 2 moles of NaI

0.217 moles may react to (0.217 . 2)/1 = 0.434 moles of NaI

It is ok to say the NaI is the limting reactant because we need 0.434 moles of it and we only have 0.331.

Ratio is 2:2.

0.331 moles of NaI can produce 0.331 moles of NaCl

We convert mass to moles: 0.331 mol . 58.45g /mol = 19.3 g