what are the zeroes of f(x)=(x-7)(x+8)

Answer:

A, or 0.5

Step-by-step explanation:

Slope formula: Rise/run

([tex]y[/tex]₂[tex]-y[/tex]₁)/([tex]x[/tex]₂[tex]-x[/tex]₁)

Points: (-4,-4), and (2,-1)

Let's say that (-4,-4) is the first point, and (2,-1) is the second. It doesn't really matter which ones we choose.

[tex]\frac{-1-(-4)}{2-(-4)}[/tex][tex]=\frac{3}{6}=\frac{1}{2} = 0.5[/tex]

A

Hope this helped! Please mark brainliest :)

Answer:

c....................

Answer:

Step-by-step explanation:

i think if its -10 degrees i think the fahrenheit would be 50 degrees

AnsweStep-by-step explanation:

lol

Answer:

14

Step-by-step explanation:

2+2+82-72

86 - 72 = 14

9514 1404 393

Answer:

Step-by-step explanation:

The attached graph shows the various company costs for x number of hours. The graph nearest the x-axis represents the lowest cost.

We can see that cost is lowest using Company A for 2 hours or less, and Company C for 5 hours or more. For times between those, Company B has the lowest charges.

Of course, the equation for charges in each case is the sum of the service fee and the product of hourly charge and number of hours (x).

__

I find the graphing calculator to be the most efficient tool for solving these. The alternative is to compare the equations pairwise to see which gives lower rates. With a little practice, you learn that the "break even hours" will be the difference in service fees divided by the difference in hourly cost.

For example A will cost the same as B when the $20 service fee and the $10/hour cost difference are the same: for 2 hours. A and C will cost the same when the $45 service fee and the $15/hour cost difference are the same, after 3 hours. B and C will cost the same when the $25 difference in service fees and the $5/hour cost difference are the same, after 5 hours.

So B is cheaper above 2 hours, and C is cheaper than that above 5 hours. With no service fee, A is cheaper for small numbers of hours (<2).

Answer:

50.24 or 50.272

Step-by-step explanation:

Square radius and then times by 3.14 or 3.142

4^2*3.14 = 50.24

4^2*3.142 = 50.272

Answer:

nsnndjdjejke

dl,dmfkfkkio4krm

Step-by-step explanation:

irikrkrkfmfmmfmfmmfmg

Answer:

3/20

Step-by-step explanation:

By question it's given that ,

[tex]\implies \dfrac{a}{b}=\dfrac{2}{5}[/tex]

[tex]\implies \dfrac{b}{c}=\dfrac{3}{8}[/tex]

And we need to find out the value of a/c .For that Multiply both of them , we have ;

[tex]\implies \dfrac{a}{b} \times\dfrac{b}{c}=\dfrac{2}{5}\times \dfrac{3}{8} \\\\\implies \dfrac{a}{c}= \dfrac{3}{20}[/tex]

Hence the required answer is 3/20 .

Explanation:

The range is the set of y outputs of a relation. So we just list the y coordinates of the points shown.

We could sort the values to get {-1, 4, 11, 13}, but order doesn't matter in a set. So this step is optional.

Answer:

"0.0808" is the appropriate response.

Step-by-step explanation:

Given:

n = 524

[tex]\hat{P}[/tex] = 41%

or,

   = 0.41

[tex]1-\hat{P}=1-0.41[/tex]

         [tex]=0.59[/tex]

[tex]\mu \hat{P}=\hat{P}[/tex]

     [tex]=0.41[/tex]

Now,

⇒ [tex]6 \hat{P}=\sqrt{\frac{\hat {P}(1-\hat{P})}{n} }[/tex]

         [tex]=\sqrt{\frac{0.41\times 0.59}{524} }[/tex]

         [tex]=0.0215[/tex]

[tex]P(\hat {P}>44 \ percent)[/tex]

or,

[tex]P(\hat{P}>0.44)[/tex]

          [tex]=1-P(\hat{P}<0.44)[/tex]

          [tex]=1-P(\frac{\hat{P}-\mu \hat{P}}{6 \hat{P}} <\frac{0.44-0.41}{0.0215} )[/tex]

          [tex]=1-P(z<1.40)[/tex]

By using the standard normal table, we get

          [tex]=1-0.9192[/tex]

          [tex]=0.0808[/tex]    

Answer:

[tex]option \: d \: 4.2 \times {10}^{ - 3} [/tex]

Step-by-step explanation:

Multiplication,

[tex] = 8.4 \times {10}^{ 8 } \times 5 \times {10}^{ - 11} \\ = 8.4 \times 5 \times {10}^{8 + ( - 11)} \\ = 4.2 \times {10}^{8 - 11} \\ = 4.2 \times {10}^{ - 3} [/tex]

Answer:

she bought 5 berries in total

Step-by-step explanation:

3+2=5

Answer:

[tex]x = 5600 + 5600 * 0.042 * 1[/tex]

Step-by-step explanation:

Given

[tex]P = 5600[/tex] -- Principal

[tex]R = 4.2\%[/tex] -- Rate

[tex]T = 1[/tex] -- Time

Required

The amount (x) to be paid

This is calculated as:

[tex]x = P + I[/tex]

Where:

[tex]I = PRT[/tex]

So, we have:

[tex]x = 5600 + 5600 * 4.2\% * 1[/tex]

Express percentage as decimal

[tex]x = 5600 + 5600 * 0.042 * 1[/tex]

(c) is correct

Answer:

335%

Step-by-step explanation:

Answer:

The z-score for an ACT score of 16 is -1.23.

His ACT score was of [tex]X = 22.5 + 5.3Z[/tex], considering that Z is his z-score.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

ACT:

Mean of 22.5, standard deviation of 5.3, so [tex]\mu = 22.5, \sigma = 5.3[/tex]

The z-score for an ACT score of 16 is

Z when x = 16. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16 - 22.5}{5.3}[/tex]

[tex]Z = -1.23[/tex]

The z-score for an ACT score of 16 is -1.23.

Jose's ACT score had a Z-score of Z. What was his ACT score?

This is X, considering Z his z-score. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{X - 22.5}{5.3}[/tex]

[tex]X - 22.5 = 5.3Z[/tex]

[tex]X = 22.5 + 5.3Z[/tex]

His ACT score was of [tex]X = 22.5 + 5.3Z[/tex], considering that Z is his z-score.

Answer:

in 3 minutes ;

44 × 3 = 132 copies

and 45 soconds;

[tex]45 \: seonds \: = \frac{3}{4} \: mınutes[/tex]

44 × ¾ = 33 copies

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

Answer: Approximately 2.29 cm

Step-by-step explanation:

See a pattern?

Week 9 = [tex]1.67(1.04)^{9-1} =1.67(1.04)^{8} =1.67(1.3686)=2.2855[/tex]

Step-by-step explanation:

red=4/19

green2/1

i didnt get the qn prperly..was a marbke taken out second time？ and not replaced？

Answer:

-90.625

Step-by-step explanation:

Answer:

[tex]-90~5/8\\[/tex]

[tex]Decimal=-90.625[/tex]

-------------------------------

~HOPE IT HELP....~

~HAVE A GREAT DAY!!~

9514 1404 393

Answer:

  1240 in³

Step-by-step explanation:

The overall dimensions of the block are ...

  10 in by 11 in by 17 in

The volume of that space is ...

  V = LWH = (10 in)(11 in)(17 in) = 1870 in³

The volume of each of the three identical holes is similarly found:

  V = (10 in)(3 in)(7 in) = 210 in³

Then the volume of the block is the overall volume less the volume of the three holes:

  = 1870 in³ - 3(210 in³) = 1240 in³

Answer: Hi some data is missing attached below is the missing data

answer:

WMA = 174.53

Step-by-step explanation:

Determine the three-week weighted moving average with weights

( 1/2, 1/3, 1/6 )

Weighted moving average ( WMA ) = 174.53

MSE = ∑ (xi - WMA)^2 / n

        = 9.71

attached below is the detailed solution/table

Answer:

-4

Step-by-step explanation:

10(2+n)=5n

20+10n=5n

20=-5n

-4=n

The number is n = -4.

Given: the product of ten and the sum of two and a number exists five times the number.

Let x be the unknown number:

The product of 5 and the sum of two and the number = 10(2+n)

five times the number = 5n

10(2+n) = 5n

Expand 10(2+n) = 20+10n

20+10n = 5n

Subtract 20 from both sides

20+10n-20 = 5n-20

Simplify

10n = 5n-20

Subtract 5n from both sides

10n-5n = 5n-20-5n

Simplify

5n = -20

Divide both sides by 5

[tex]$\frac{5 n}{5}=\frac{-20}{5}[/tex]

n = -4

Therefore, the correct answer is n = -4.

To learn more about algebra

https://brainly.com/question/17427598

#SPJ2

Answer:

t = 13.56915448 hrs.

Step-by-step explanation:

500 = 300 [tex]e^{2k}[/tex]

5/3 = [tex]e^{2k}[/tex]

ln(5/3) = 2k ln(e)

k = ln(5/3)/2

k= 0.255412812

~~~~~~~~~~~~

9600 = 300 [tex]e^{0.255412812 t}[/tex]

32= [tex]e^{0.255412812 t}[/tex]

ln(32) = [tex]0.255412812 t[/tex] ln(e)

t = ln(32)/0.255412812

t = 13.56915448 hrs.

Answer:

We know that every number can be written as a product of prime numbers.

The method to find the factorized form of a number depends on the number, we just try to find the different factors by dividing by them, for example for the number 1000 we have:

1000 is an even number, then we can divide it by 2 (2 is a prime number)

1000 = 2*500   (so we already found a prime factor)

500 is also an even number, so we can divide it by 2

1000 = 2*500 = 2*2*250  (we found another prime factor)

dividing by 2 again we get:

1000 = 2*2*250 = 2*2*2*125

1000 = (2*2*2)*125

now we just need to factorize 125

we know that 125 is a multiple of 5, such that:

125 = 5*25 = 5*5*5

(5 is a prime number, so it is completely factorized).

Then the factorization of 1000 is:

1000 = (2*2*2)*(5*5*5) = 2^3*5^3

Now with another example, 1422

1422 is an even number, so we again start using the factor 2:

1422 = 2 = 711

then:

1422 = 2*711

we already found a factor.

711 is a multiple of 3 (the sum of its digits is a multiple of 3), then:

711/3 = 237

We can write our number as:

1422 = 2*3*237

237 is also a multiple of 3

237/3 = 79

then:

1422 = 2*3*3*79

and 79 is a prime number, so we already have 1422 completely factorized.

Step-by-step explanation:

Since an interior angle is 150 degrees, its adjacent exterior angle is 30 degrees.  Exterior angles of any polygon always add up to 360 degrees.  With the polygon being regular, we can just divide 360 by 30 to get 12 sides.

Given:

The average number of songs performed there in a 10 day period is 167.

To find:

The number of songs performed there in a year time.

Solution:

We have,

Number of songs performed in 10 days = 167

Number of songs performed in 1 day = [tex]\dfrac{167}{10}[/tex]

                                                              = [tex]1.67[/tex]

We know that 1 year is equal to 365 days. So,

Number of songs performed in 365 day = [tex]1.67\times 365[/tex]

Number of songs performed in 1 year     = [tex]609.55[/tex]

                                                                   [tex]\approx 610[/tex]

Therefore, the number of songs performed there in a year time is about 610.