Answer:
U = x + 4 and V = 2y^5.
Step-by-step explanation:
Square root of (x + 4)^2 = x + 4
Square root of 4y^10 = 2y^5
U = x + 4 and V = 2y^5.
(U - V)^2 = U^2 - 2UV + V^2
= (x + 1)^2 - 2 (2y^5 (x + 1) + 4y^10
= (x + 1)^2 - 4y^5 (x + 4) + 4y^10
Answer:
U = x + 4 and V = 2y^5.
Step-by-step explanation:
Jake ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday he ran 1 fewer miles then he ran on Monday. How many miles did he run in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINLIEST AND PLEASE EXPLAIN
Answer:
Jake ran 10 1/6 miles in total
Step-by-step explanation:
4 1/4 + 2 2/3 - (4 1/4-1).
v
6 11/12 + 3 1/4
v
6 11/12 + 3 3/12 = 10 1/6
Jake ran 10 1/6 miles in total (Mon, Tues, Wed).
Answer:
61/6 or 10.1666666667
Step-by-step explanation:
Monday = 4 1/4
Tuesday = 2 2/3
Wednesday = Monday - 1
=> Monday = 17/4 miles
=> Tuesday = 8/3 miles
=> Wednesday = 17/4 - 4/4 = 13/4 miles.
=> (17/4 + 13/4) + 8/3
=> 30/4 + 8/3
=> Take the LCM of the denominators.
=> LCM = 12
=> 90/12 + 32/12
=> 122/12
SImplify 122/12
=> 61/6 or 10.1666666667
The Nguyen family and the Reed family each used their sprinklers last summer. The Nguyen family's sprinkler was used for 15 hours. The Reed family's sprinkler was used for 25 hours. There was a combined total output of 1175L of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour? Nguyenfamily'ssprinkler:Lperhour Reedfamily'ssprinkler:Lperhour
Answer:
Nguyen family's sprinkler: 20 L per hour Reed family's sprinkler: 35 L per hourStep-by-step explanation:
Let n and r represent the output in liters per hour of the Nguyen and Reed family sprinklers, respectively. Then we have ...
15n +25r = 1175 . . . . total sprinkler output
n + r = 55 . . . . . . . . . sum of two output rates
The second equation tells us we can substitute n = 55 -r into the first equation:
15(55 -r) +25r = 1175
10r = 1175 -825 . . . . . . subtract 825
r = 350/10 = 35 . . . . . . divide by 10
n - 55 -35 = 20 . . . . . . find n from r
Nguyen family's sprinkler: 20 L per hour
Reed family's sprinkler: 35 L per hour
Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?
Answer:
m∠D = 97.34°
Step-by-step explanation:
Concept used"
sum of all angles of Quadrilateral is 360 degrees.
If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees
________________________________________________
Given
Quadrilateral ABCD is inscribed in a circle
thus,
pair of opposite angles will be
m∠A and m∠C
m∠B and m∠D
thus,
m∠B + m∠D = 180
Thus,
m∠A + m∠C = 180
64+ (9x - 1) = 180
9x = 180 - 63 + 1 = 118
x = 118/9 = 13.11
thus, value of
m∠B is (6x + 4)°
m∠B = (6*13.11 + 4)° = 82.66°
m∠B + m∠D = 180
82.66 + m∠D = 180
m∠D = 180 - 82.66 = 97.34°
Thus,
m∠D is 97.34°
Drag each label to the correct location on the table. Each label can be used more than once. A cross country coach records the number of miles his athletes on the Junior Varsity and Varsity teams ran today and displays the data in the provided dot plots. Given the shape of each distribution, determine which measures of center and spread are appropriate for him to use to summarize the data from each team. mean mean interquartile range interquartile range standard deviation standard deviation median median
Answer:
a.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed.
For the Junior Varsity Team, the mean would be the appropriate measure of the center since the data is symmetric or well-proportioned .
What is median?Median represents the middle value of the given data when arranged in a particular order.
Since the data for the Junior Varsity Team is symmetric or well-proportioned, the mean would be the best way to determine the center, and standard deviation, which also measures the center and how far the values deviate from the mean, should be used to determine the spread.
The median could be utilized for the Varsity Team since the data is not evenly distributed and skewed to the left, and it does not take into account outliers.
We can use the interquartile range (IQR) to quantify the spread of the data because IQR does not take into account the skewed data.
Therefore, the varsity squad competes in intercollegiate or international competitions on behalf of the high school or institution while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
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What is the tangent ratio of KJL? (Question and answers provided in picture.)
Answer:
Option (1)
Step-by-step explanation:
The given triangle JKL is an equilateral triangle.
Therefore, all three sides of this triangle will be equal in measure.
Side JK = JL = KL = 48 units
Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.
By applying tangent rule in ΔJML,
tan(∠KJL) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{\text{LM}}{\text{JM}}[/tex]
= [tex]\frac{\text{LM}}{24}[/tex]
Since, Sin(K) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
Sin(60)° = [tex]\frac{\text{LM}}{48}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\text{LM}}{48}[/tex]
LM = 24√3
Now, tan(∠KJL) = [tex]\frac{\text{LM}}{24}[/tex]
= [tex]\frac{24\sqrt{3} }{24}[/tex]
Therefore, Option (1) will be the answer.
The sum of the numerator and denominator of a
fraction is 12. If the denominator is increased by 3,
the fraction becomes 1/2.
Find the fraction.
plz answer step by step
[tex]x+y=12\\\dfrac{x}{y+3}=\dfrac{1}{2}\\\\x=12-y\\2x=y+3\\\\2(12-y)=y+3\\24-2y=y+3\\3y=21\\y=7\\\\x=12-7=5\\\\\dfrac{x}{y}=\dfrac{5}{7}[/tex]
NEED IN 10 MIN. WILL GIVE BRAINLEST Solve the triangle. B = 36°, a = 41, c = 17
Answer:
Yes this is a Triangle
36 degrees of any side then 41 would connct to 36 and 17 would connects to 36 and 41! If this is Khan Academy your asking out of its a Yes, it is a Triangle
HOPE IM THE BRANLIESS UwUAnswer:
It is a triangle:
Step-by-step explanation:
b² = a² + c² - 2(a)(c)cos(B)
b² = 41² + 20² - 2(41)(20)cos(36)
b² = 754.2121292
b = 27.46292281
b = 27.463
A = 41, B = 27.4, C = 17
The temperature in Anchorage, Alaska at 6:00 am was 2°C. If the temperature drops 2 degrees each hour, what is the temperature in degrees celsius at 2:00 pm
Answer:
-12°C
Step-by-step explanation:
6AM = 2°C
8AM= -2°C
10AM= -6°C
12AM= -8°C
2PM= -12°C
the temperature in degrees Celsius at 2:00 pm would be -14°C.
To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.
From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).
Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):
Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees
Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:
Temperature at 2:00 pm = 2°C - 16°C = -14°C
Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.
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If you draw a rectangle that has a width of 12 centimeters and an area of 48 centimeters, what is the length of the rectangle?
Answer:
length=4 cm
Step-by-step explanation:
Area of rectangle= length * width
48=l*12
length=48/12
length=4 cm
Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle, M, O, N, equals, 8, x, minus, 13, degrees \qquad m \angle LOM = 7x - 17^\circm∠LOM=7x−17 ∘ m, angle, L, O, M, equals, 7, x, minus, 17, degrees Find m\angle MONm∠MONm, angle, M, O, N:
Answer:
[tex] \boxed{99°}[/tex]Step-by-step explanation:
m<MON = 8x - 13°
m<LOM = 7x - 17°
To find : m <MON
First, we have to find the value of x :
Create an equation
[tex] \mathrm{8x - 13 + 7x - 17 = 180}[/tex] ( sum of angle in straight line )
Collect like terms
[tex] \mathrm{15x - 13 - 17 = 180}[/tex]
Calculate
[tex] \mathrm{15x - 30 = 180}[/tex]
Move constant to R.H.S and change its sign
[tex] \mathrm{15x = 180 + 30}[/tex]
Calculate the sum
[tex] \mathrm{15x = 210}[/tex]
Divide both sides of the equation by 15
[tex] \mathrm{ \frac{15x}{15} = \frac{210}{15} }[/tex]
Calculate
[tex] \mathrm{x = 14}[/tex]
Now, let's find the value of m<MON
[tex] \mathrm{8x - 13}[/tex]
Plug the value of x
[tex] \mathrm{ = 8 \times 14 - 13}[/tex]
Calculate the product
[tex] \mathrm{ = 112 - 13}[/tex]
Calculate the difference
[tex] \mathrm{ = 99}[/tex] °
Hope I helped!
Best regards!
Answer:
48
Step-by-step explanation:
because i say so
\large 6\cdot\frac{6+2^2}{6+2-6}
Answer:
30Step-by-step explanation:
Given the expression [tex]\large 6\cdot\frac{6+2^2}{6+2-6}[/tex], on simplification we have;
[tex]= \large 6\cdot\frac{6+2^2}{6+2-6}\\\\= \large 6\cdot\frac{6+4}{8-6}\\\\= \large 6\cdot\frac{10}{2}\\\\= 6* 5\\\\= 30[/tex]
Hence the equivalent value of the expression is 30
What is the 1st mistake...
Answer:
[tex]\huge\boxed{Step \ 3}[/tex]
Step-by-step explanation:
In Step # 3, We need to divide rather than to subtract. So, the first mistake is done in step 3.
Answer:
[tex]\Large \boxed{\mathrm{Step \ 4}}[/tex]
Step-by-step explanation:
[tex]20 +20 \div 4-2[/tex]
Division should be performed first, not subtraction.
[tex]20+5-2[/tex]
Hello, a quick question which number is least to greatest 0.359, 0.35, 1
Answer:
0.35, 0.359, 1
Step-by-step explanation:
0.359 = 359 thousandths
0.35 = 0.350 = 350 thousandths
1 = 1.000 = 1000 thousandths
Since 350 < 359 < 1000, then from least to greatest you get
0.35, 0.359, 1
Bismah is building 5 raised garden beds in a community garden. Each raised garden bed will need 1 7 8 bags of soil. How many bags of soil will Bismah need for all 5 raised garden beds?
Answer:
890 if it’s 178 bags per garden bed
Step-by-step explanation:
since 1 raised garden bed is supposedly 178 bags, 5 would be 890 since it’s just 5x178. if it’s not 178 bags (which would make sense since 178 is a big number), just multiply 5 by that number and if it’s a decimal round up to the next whole number if it’s about how many bags Bismah needs to buy, since you can’t by 1/2 of a bag
Bismah will need a total of 890 bags of soil for all the 5 raised garden. beds.
What is Multiplication?.Multiplication is one of the basic operations in mathematics where a number is added repeatedly to itself up to the times as the value of the other number.
That is, if a number p is multiplied to another number q, p × q, implies that p is added repeatedly to itself q times or q is added repeatedly to itself up to p times.
Number of garden beds Bismah has raised = 5
Number of bags of soil needed for a garden bed = 178 bags
Number of bags of soil needed for 5 garden bed = 178 × 5 bags
= 890 bags
Hence Bismah would need 890 bags of soil for the 5 raised garden beds in the community garden.
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someone help me really quick
Answer:
u^18
Step-by-step explanation:
(u^3)^6
=
u^(3*6)
=
u^18
Hope this helps!
solve equation show all steps what is 2x-3x+5=18
Answer:
x = -13
Step-by-step explanation:
2x-3x+5=18
Combine like terms
-x +5 = 18
Subtract 5 from each side
-x +5-5 = 18-5
-x = 13
Multiply each side by -1
x = -13
Answer:
[tex]\huge \boxed{{x=-13}}[/tex]
Step-by-step explanation:
[tex]2x-3x+5=18[/tex]
[tex]\sf Combine \ like \ terms.[/tex]
[tex]-1x+5=18[/tex]
[tex]\sf Subtract \ 5 \ from \ both \ sides.[/tex]
[tex]-1x+5-5=18-5[/tex]
[tex]-1x=13[/tex]
[tex]\sf Multiply \ both \ sides \ by \ -1.[/tex]
[tex]-1x \times (-1)=13 \times (-1)[/tex]
[tex]x=-13[/tex]
What is 51⁄6 as an improper fraction? For Seneca Learning:
Answer:
Step-by-step explanation:
[tex]5\frac{1}{6}=\frac{(5*6)+1}{6}=\frac{31}{6}[/tex]
Answer:
31/6 (improper fraction).
Step-by-step explanation:
5 1/6 = (6 × 5) + 1/6 = 31/6
31/6 is the improper fraction.
In the figure shown, what is the measure of angle x? (5 points) 115 degrees 130 degrees 145 degrees 150 degrees
Answer:
x=115
Step-by-step explanation:
180 - (115) =65(triangle)
65 + x = 180(on a line)
x=180-65
x = 115
Answer:
115 degrees
Step-by-step explanation:
the person above me is right, but there is an easier way.
Just add 50 and 65 degrees and boom you have your answer.
Jess receives a $15000 salary for working as an engineer. If Jess has to spend $6000 of her salary on expenses each year, then what percent of Jess's money does she have to spend? Round your answer to the nearest whole number if necessary.
Answer:
Jess will have to spend 40% of her salary
Step-by-step explanation:
Jess salary = $15,000
Jess expenses = $6,000
what percent of Jess's money does she have to spend
Percentage of Jess expenses = Jess expenses / Total salary × 100
= 6,000 / 15,000 × 100
= 0.4 × 100
= 40%
Jess will have to spend 40% of her salary
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
[tex]Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds[/tex]
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
[tex]\frac{200}{60} = \frac{10}{3} \approx 3.33[/tex] loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
[tex]\frac{200}{65} = \frac{40}{13} \approx 3.08[/tex] loops per minute
then the period is:
[tex]\frac{13}{40} =0.325\,\,\,minutes[/tex]
Therefore runner B has the smaller period
Solve two-step equations. -5/2 a + 5 = 25
Answer:
a = -8
Step-by-step explanation:
-5/2 a + 5 = 25
Subtract 5 from each side
-5/2 a + 5-5 = 25-5
-5/2 a = 20
Multiply each side by -2/5
-2/5 *-5/2 a = 20*-2/5
a = -8
What is the center of the circle with the equation (x+4)2 + (y - 2)2 = 16?
Answer:
The center of the circle is
( - 4 , 2)Step-by-step explanation:
Equation of a circle is given by
(x - h)² + ( y - k)² = r²where r is the radius
(h, k) is the center of the circle
The center of a circle is given by
( - h , - k)
From the question equation of the circle is
( x + 4)² + ( y - 2)² = 16
Comparing with the general equation above
( h , k) = ( 4 , - 2)
The center of the circle is
( - h , - k) = ( - 4 , -(-2))
We have the final answer as
( - 4 , 2)Hope this helps you
What’s up guys, pls help 19b)
Thanks
Answer:
90°
Step-by-step explanation:
As given in the figure:
[tex]AC \perp CE\\
\therefore m\angle ACE = 90\degree \\ [/tex]
6x-1=11 solve equation
Answer:
x = 2
Step-by-step explanation:
6x-1=11
Add 1 to each side
6x-1+1=11+1
6x = 12
Divide by 6
6x/6 = 12/6
x = 2
Answer:
x = 2Step-by-step explanation:
[tex]6x-1=11 \\\\Collect \: like \:terms\\\\6x = 11+1\\\\Simplify\\\\6x =12\\\\Divide\:both\:sides\:by\:6\\\\\frac{6x}{6} = \frac{12}{6}\\ x = 2[/tex]
A rectangular box with a square base contains 24 cubic feet. if the height of the box is 18 inches, how many feet are there in each side of the base?
Answer:
4
Step-by-step explanation:
V = Lwh
the volume (given) = 24 ft^3
the height (given) = 18" = 1.5'
24 = L*w*1.5
divide both sides by 1.5
16 = Lw
You need to find the number of feet in each side of the base
since the box has a square base
L = W
AND, found above, L*w = 16
so 4*4= 16
Answer - 4
Help? It hard I try my best on a Separate picese
============================================
Work Shown:
3 & 1/2 = 3 + 1/2 = 3 + 0.5 = 3.5
3.5% = 3.5/100 = 0.035
r = 0.035 is the decimal form of [tex]3\frac{1}{2}\%[/tex] which is used along with
P = 500 (principal deposit)n = 12 (compounding 12 times a year)t = 0.5 (6 months is half a year)to get the following
A = P*(1+r/n)^(nt)
A = 500*(1+0.035/12)^(12*0.5)
A = 508.81405074594
A = 508.81
Extra info: Gabe earned A-P = 508.81 - 500 = 8.81 dollars in interest.
Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB
Answer: m∠DEA = _________, m∠ADB =_______
Answer:
The values of the angles are;
m∠DEA = 62°, m∠ADB = 45°
Step-by-step explanation:
Specify an arc or an angle three letters
Angle opposite an arc on the circumference
m DA ≅ m CB = 62° (Arc between parallel lines are congruent)
∠CAB = 1/2 × m CB = 1/2 × 62° = 31° (Angle at the center = 2 × Angle st the circumference)
∠DBA = 31° (Angle at the center m DA = 2 × Angle st the circumference)
m∠DAB = 104° (Given)
∠ADB = 180° - m∠DAB - ∠DBA = 180° - 104° - 31° = 45° (Interior angles of triangle ΔADB
m∠ADB = 45°
∠AEB = 180 - ∠CAB - ∠DBA = 180° - 31° - 31° = 118°
∠AEB ≅ ∠COD (Vertically opposite angles)
∠DEA ≅ ∠CEB (Vertically opposite angles)
∠AEB + ∠COD + ∠DEA + ∠CEB = 360° (Sum of angles at a point)
118° + 118° + ∠DEA + ∠CEB = 360°
∠DEA + ∠CEB = 360° - 118° - 118° = 124°
Given that ∠DEA = ∠CEB we have;
2 × ∠DEA = 124°
∠DEA = 124°/2 = 62°
m∠DEA = 62°.
Write each fraction as a decimal and a percent. A) 7/8 B) 9/75 C/ 120/75
Answer:
A) 0.875, 87.5%
B) 0.12, 12%
C) 1.6, 160%
Step-by-step explanation:
Answer:
A) 0.875, 87.5%
B) 0.001, 0.1%
C) 1.6, 160%
Step-by-step explanation:
I honestly just used a calculator, but it could also be solved using the butterfly technique. For percentages just move the decimal to the left two places.
A certain pole has a cylinder-like shape, where the base's radius is 10 centimeters and the height is 2 meters. What calculation will give us the estimated surface area of the pole in square centimeters?
Answer:
2 pi •10•210
Step-by-step explanation:
Khan academy
Which statement best explains why the sine of an acute angle is equal to the cosine of the angles complement
Answer:
Option (B)
Step-by-step explanation:
From the figure attached,
ΔABC is a right triangle.
Cosine and Sine ratios from the given triangle will be,
SinA = [tex]\frac{\text{Opposite side}}{Hypotenuse}[/tex]
= [tex]\frac{a}{c}[/tex]
CosB = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{a}{c}[/tex]
Therefore, both the ratios (Sine and Cosine) will be equal as [tex]\frac{a}{c}[/tex]
Option (B) will be the correct option.
