The wavelength of visible light compare to radio waves in the sense that visible light waves have a shorter wavelength than radio waves.
What is wavelength?The wavelength is described as the spatial period of a periodic wave which is the distance over which the wave's shape repeats.
Radio waves are electromagnetic waves that are produced by man with an oscillating circuit.
Radio waves are used in broadcasting, the waves used in television are those of shorter wavelength and those of radio are those of longer wavelength.
Longer radions are reflected in the ionosphere and can be detected in antennas which is located at great distances from the emitting source. The medium waves are less reflected in the ionosphere, due to their large wavelength they can overcome obstacles, so they can travel great distances.
It is known that the visible radiation waves have a wavelength between approximately 400 and 700 nanometers, the radio waves range from 1 centimeter to 1 km, so they have longer wavelengths than the waves belonging to the visible spectrum.
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disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.
If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.
Which definition of distance suits you best?How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.
Horizontal force acting on the cart, F = 11 N
Mass of the cart, m = 35 kg
To find,
Distance covered by the cart in 3.5 seconds if it starts from rest.
Solution,
Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :
s = 1.925 meters
What is the definition of a distance?In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."
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1.
KNOW the UNITS!!!!!! SHOW YOUR WORK
What is the net force exerted on a 150.0kg race-car driver while the race car is accelerating from 0 to 58.7m/s i
3.50s?
Answer:
2515.7N
Explanation:
First step is to find the acceleration:
U = 0 and V =58.7 m/s
a = (V-U)/t
where, t = 3.5s
a = 58.7/3.5
so, in order to find the net force,
F= ma
= 150kg × 58.7/3.5
= 2515.7 N
A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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Study the following systems: SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radio. SYSTEM B: Electricity is used to power a radio. Which system (A or B) is more energy efficient and explain why.
The system that is more energy efficient is system A because it makes use of electricity to produce more results.
What is energy efficiency?Energy efficiency is the use of less energy to perform the same task or produce the same result.
Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.
Energy efficiency has the following benefits:
It saves moneyIt increases the resilience and reliability of the electric gridIt provides environmental, community, and health benefitsAccording to this question, the following applies:
SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radioSYSTEM B: Electricity is used to power a radioBased on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.
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A student wants to make a simple model of the solar system to help him compare how long it would take for a spaceship to travel between different planets.
Which of the following things is essential for him to do in order to think about how long it would take?
this are the opions
He must make sure that the model of each planet looks like the planet it represents, but he does not need to accurately represent the relative distances between the planets because the most important thing is that models look like the thing they are modeling.
He must accurately represent the relative distances between the planets, but he does not need to make sure that the model of each planet looks like the planet it represents because only the relevant aspects of the thing being modeled need to be modeled accurately.
He must accurately represent the relative distances between the planets and also make sure that the model of each planet looks like the planet it represents, because a model should be as much like the thing being modeled as possible.
He does not need to accurately represent the relative distances between the planets, and he does not need to make sure that the model of each planet looks like the planet it represents, because there are always some differences between a model and the thing being modeled.
Answer:
To make a simple model of the solar system that can be used to compare the time it would take for a spaceship to travel between different planets, the student must accurately represent the relative distances between the planets. This is because the time it would take for a spaceship to travel between two planets depends on the distance between those planets, so accurately representing the distances between the planets is essential for thinking about how long it would take for a spaceship to travel between them.
It is not necessary for the student to make sure that the model of each planet looks like the planet it represents, although this may help make the model more understandable. The most important thing is that the model accurately represents the relative distances between the planets.
In summary, the student must accurately represent the relative distances between the planets in order to think about how long it would take for a spaceship to travel between different planets in the solar system.
The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'
Answer:
Here is answer
Explanation:
a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.
b) The characteristics of the weight of solid 'S' are:
It acts in the downward direction.
It is a gravitational force that is exerted by the Earth on the solid 'S'.
It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).
c) The weight of solid 'S' can be represented by a vector as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
[/asy]
a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.
b) These forces can be represented by vectors as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));
label("$N$", (7.5sqrt(2),7.5), NE);
draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));
label("$F_f$", (-7.5sqrt(2),-7.5), SW);
[/asy]
c) The characteristics of these forces are:
The normal force acts perpendicular to the surface of the inclined plane.
The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.
The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.
The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.
a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.
b) The characteristics of the gravitational force are:
It acts in the downward direction.
It is a force that is exerted by the Earth on the solid 'S'.
Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):
[asy]
unitsize(1cm);
draw((0,0)--(0,-1.3),Arrow(6));
label("$W$", (0,-0.65), S);
[/asy]
a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
which sentence correctly describes when the triple-alpha process occurs in the life cycle of an average-mass star
Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.
What results from the triple-alpha procedure as the finished product?
The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.
Which statement concerning alpha particles in an atom is accurate?
Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.
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a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?
The work done by the dog is 0.81J.
What is work done?Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.
It is said that no work is done if the object does not move.
The work done on an object is the amount of energy transferred to an object through work.
According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:
Force = mass × acceleration
Force = 0.75kg × 9.8m/s²
Force = 7.35N
Work done = 7.35N × 0.11m = 0.81J
Therefore, 0.81J is the work done by the dog.
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a uniform meter stick of mass 24 g with two weights hanging from it is balanced on a knife edge at the 40 cm mark. a weight of mass 96 g hangs from the 9 cm mark. at which cm mark must the other weight of mass 96 g be located to keep the meter stick balanced?
The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.
The weight of the meter stick can be calculated as follows:
Weight of meter stick = mass * acceleration due to gravity
= 24 g * 9.8 m/s^2
= 235.2 N
The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.
The sum of the forces acting on the meter stick is equal to zero when:
235.2 N + 1.92 N = 0
This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.
To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.
The moment of the weight of the meter stick about the pivot point is calculated as follows:
Moment of the weight of meter stick = force * distance from pivot point
= 235.2 N * 0.4 m
= 94.08 N*m
The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:
Moment of weight hanging from 9 cm mark = force * distance from pivot point
= 1.92 N * 0.09 m
= 0.1728 N*m
To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:
Moment of second weight = force * distance from pivot point
= 1.92 N * distance from pivot point
Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:
1.92 N * distance from pivot point = -0.1728 N*m
Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.
Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?
a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar
The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.
What is velocity?
The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
A car travels down a road at a certain velocity, is Vcar.
Let the initial velocity of the car travel downward be -V car
It is also, given, that the driver slows down so that the car is traveling only half as fast as before.
Resulting velocity = -1/2 vcar
Therefore, the correct option is c. -1/2vcar.
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a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s
The required values are a) T = 2.3 seconds, b) f = 0.434 Hz, c) ω = 2.7 rd/s.
Which of the following motions is simply harmonic?Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.
According to question:Given,
Time = 11.5 seconds to five complete vibrations.
a) Time period is time taken to complete one vibration,
So T = 11.5/5 = 2.3 seconds
b) Frequency(f) = 1/T
f = 1/2.3 = 0.434 second inverse.
c) By using formula of angular frequency ω = 2π/T
ω = 2π/2.3 = 2.7 hz
Thus, final values are a) T = 2.3 seconds, b) f = 0.434 second inverse, c) ω = 2.7 rd/s.
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a simple pendulum is 4.00 m long. (a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2?
The time period of the small oscillations for the simple pendulum is found to be 3.14 seconds.
The pendulum is located in an elevator that is accelerating upwards with an acceleration of 6m/s² and length of the pendulum is 4m.
Because the elevator is accelerating in the upper direction the net acceleration of the pendulum will be (10 + 6)m/s².
The period of small accelerations for this pendulum will be given by the relation,
T = 2π(l/a)
Where, l is the length of pendulum and a is the net acceleration.
Putting values,
T = 2π(4/16)
T = 2π(1/2)
T = π seconds.
T = 3.14 seconds.
So, the time period of this small oscillations for this pendulum is 3.14 second.
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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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what are the magnitude and location (with respective to point a) of the resultant force on the horizontal gate? the gate width is w. fluid density is r. you can leave your answer in terms of variables (w, r, and g).
The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
What is magnitude?Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.
The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
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sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)
(a) The normal force is 267.7 N and frictional force is 980 N.
(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.
(c) The direction of the contact force is 1016 N.
∈(t) = 0
N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )
N₂ = 267.7 N
(a) Normal force F(d) = N₂ = 267.7 N
Frictional force N = 800 + 180
N = 980 N
(b) The minimum coefficient of static friction,
F(d) = μ N₁
μ = F / N₁
μ = 267.7 / 980
μ = 0.27
(c) The direction of the contact force,
R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]
R = 1016 N
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Which choice below explains what is happening in a liquid as it turns into a gas?
a. The particles speed up and spread apart
b. The particles speed up and come closer together
c. The particles slow down and spread apart
d. The particles slow down and come closer together
Answer:
a
Explanation:
As you add thermal energy the particles spread apart and are moving faster ..... a certain volume of water produces a much larger volume of steam as energy is added.....that is how steam engines work !
A 100 kg car starts from 20 m/s and speeds up to 41 m/s in 7 seconds. Determine the car's
acceleration.
Answer: 3 m/s^2
Explanation:
Acceleration equals change in velocity (speed) divided by total time.
a = (v2-v1)/t
a = (41 m/s - 20 m/s) / 7 s
a = 3 m/s^2
Mass is irrelevant in this question.
a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is
Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N
Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.
Let us find first the forces at 1, 2 & 3 points.
We know that ke= 8.99 * 109N.m2 / C2
The forces are: -
F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2
F1 = 359.6 N
F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2
F2 = 29.96 N
F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2
F3 = 269.7 N
Now,
The net force on q1 is F1 – F2,
i.e. F1 + F2 = 359.6 + 29.96
F(q1) = 389.56 N to the left
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boat moves north at a velocity of 2.5 m/s while the current moves downstream at 6.0 m/s east. What is the resultant velocity of the boat, relative to an observer on the shore?
A) 4.5 m/s, NE
B ) 4.5 m/s, SE
C ) 6.5 m/s, NE
D ) 6.5 m/s, SE
E) 8.5 m/s, NE
Relative to the observer in on the shore, the velocity of the boat is 6.5 m/s, NE.
What is relative velocity?
The velocity of an object in relation to another observer is known as its relative velocity.
We cay say that the relative velocity is equal to the vector difference between the velocities of two objects. The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.
The diagram below shows the calculation where AC is relative speed, AB is speed of the boat and BC is the speed of stream.
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what is the kinetic energy of a 60.0 g tennis ball traveling at 177.0 kilometers per hour? report your answer in joules (j).
The kinetic energy is 939.87 J.
what is kinetic energy?Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.
A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.
Kinetic energy = 1/2mv²
Kinetic energy = 1/2×0.06×177²
Kinetic energy = 939.87 J.
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1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)
We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.
what an acceleration is?acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.
What prompts accelerating?An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.
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based on its surface temperature of 6,000 k, most photons that leave the sun's surface lie in which region of the electromagnetic spectrum?
Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.
The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.
The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.
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which is a major difference between what we've seen in discovered exoplanets and our own solar system?
The major difference between what we've seen in discovered exoplanets and our own solar system is that extrasolar planet orbits tend to be closer and more eccentric than in our Solar System.
Exoplanet:
Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.
All of the planets in our solar system orbit around the Sun. Planets that orbit around other stars are called exoplanets.
Exoplanets are very hard to see directly with telescopes. They are hidden by the bright glare of the stars they orbit.
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how long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot?
4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.
What is the center of the gravity?The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.
Briefing:T=2π√(l/g)
T=2π√(5.53/9.81)
T=4.71
T =4.71 s
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consider the harmonic oscillator with dynamics written as with parameters . if the initial position and velocity of the oscillator are given by , what is the position of the oscillator at seconds?
The position of the oscillator at seconds is ( A cos ( ω t + ϕ ) where A is the amplitude and ϕ is the initial phase and f = 1/T = ω/2π.
What is the mean position in oscillation?Equilibrium or Mean Position: It is a state in which the body is in when there is no net force pushing against it. When a particle is oscillating, it is in its phase This is a representation of the particle's vibrational state at a particular instant.
Is the oscillation period measured in seconds?The period of an oscillating system is the length of time it takes for a cycle to be completed. A system's period is a time measurement, and in physics, it's typically represented by the capital letter T. Although seconds are the most common, period is measured in time units relevant to that system.
What is the equation for an oscillating period?Time, or T, is the oscillation's period, hence ωT = 2π or T = 2π/ω. The formula f = 1/T = ω/2π. gives the reciprocal of the period, or the frequency f, in oscillations per second.
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