Answer:
Kindly check explanation
Step-by-step explanation:
Ordered data:
54, 55, 56, 57, 58, 58, 58, 59, 61, 63, 63, 63, 64, 65, 75
Sample size, n = 15
Q1 = 1/4(n+1)th term
Q1 = 16/4 = 4th term = 57
Q2 = 1/2(n+1) th term
Q2 = 16/2 = 8th term = 59
Q3 = 3/4(n+1)th term
Q3 = 3/4(16) = 12 th term = 63
Interquartile range = Q3 - Q1 = 63 - 57 = 6
Outlier :
LOWER = Q1 - (1.5 * IQR) = 57 - (1.5*6) = 48 ; values below 48
UPPER = Q3 + (1.5 * IQR) = 63 + (1.5*6) = 72 ;
Values above 72
Outlier = 75
2x2-1/3x2+7/3x2 plzzzzzzzzzzzz fast
Answer:
8
Step-by-step explanation:
8 is the correct answer
Answer:
12 2/3
Step-by-step explanation:
Drag each tile to the correct box.
Arrange the numbers as they appear from left to right on a horizontal number line.
-2.5
-2.57
-1.85
2.5
-2.76
-1.58
2.85
I
Answer:
-2.76
-2.57
-2.5
-1.85
-1.58
2.5
2.85
Hopefully this is what you mean. Have a nice day!
Step-by-step explanation:
If two events are complementary, then we know that: Multiple Choice the sum of their probabilities is one. the joint probability of the two events is one. their intersection has a nonzero probability. they are independent events.
Answer:
The joint probability of the two events is one.
Step-by-step explanation:
Complementary events:
If two events are complimentary, these three following things are true:
They are dependent.
The intersection of them is zero.
The joint probability of the two events is one.
The last one is the correct choice.
HELP PLZZZZZZZZZZZ I NEED ITTT OMG
I hope this is help full to you
[tex]3) \: \: \: 4(2y + z) - 3(3y + z) \\ \\ = 8y + 4z - 9y + 3z \\ \\ = - y + 7z[/tex]
[tex]4) \: \: \: \: x(4x - 2) - 3x(x + 1) \\ \\ = 4x {}^{2} - 2x - 3 {x}^{2} - 3x \\ \\ = {x}^{2} - 5x[/tex]
[tex]5) a> \: \: 3(2 + c) \\ \\ = 6 + 3c[/tex]
[tex]b> \: \: \: 2a(b - 4) \\ \\ = 2ab - 8a[/tex]
[tex]c> \: \: \: ab(b + c) \\ \\ = ab {}^{2} + abc[/tex]
Hope This Helps You ❤️Which of the following graphs shows a pair of lines that represents the equations with the solution (3, −6)? (1 point)
Given:
The solution of two equation is (3,-6).
To find:
The graphs that shows a pair of lines that represents the equations with the solution (3, −6).
Solution:
In first graph, both line intersect each other at point (-6,3). So, the solution of the pair of lines is (-6,3).
In second graph, both line intersect each other at point (-3,6). So, the solution of the pair of lines is (-3,6).
In third graph, both line intersect each other at point (3,-6). So, the solution of the pair of lines is (3,-6).
In forth graph, both line intersect each other at point (6,-3). So, the solution of the pair of lines is (6,-3).
Therefore, the correct option is C.
Which expression is equivalent to 1/2x + 8
Answer:
1/2( x+16)
Step-by-step explanation:
1/2x + 8
Factor out 1/2
1/2*x + 1/2 *16
1/2( x+16)
2x - y - 4 = 0
3x + y - 9 = 0
What is the solution set of the given system?
Answer:
[tex](\frac{13}{5};\frac{6}{5}).[/tex]
Step-by-step explanation:
[tex]1)\left \{ {{5x=13} \atop {y=2x-4}} \right. \ 2)\left \{ {{x=\frac{13}{5} } \atop {y=\frac{6}{5} }} \right.[/tex]
short explanation: 1) to add the 1st equation to the 2d; 2) to calculate the value of 'x', then to substitute x=13/5 into the 2d equation and calculate the value of 'y'.
Hello. I need help with creating a normal distribution for a pre-made dataset in excel? I mainly confused with the steps to complete the process.
Let's say your data is all in column A. Furthermore, we'll say we have 21 items in this column. Make sure this data column is sorted from smallest to largest. If this isn't done, then weird things will happen when it comes to connecting the dots later on.
Column B will be used later, but for now, let's move to cell C1. In this cell, type =AVERAGE(A1:A21)
The equal sign is important to tell Excel that we have a function here, and not just plain text. As the function implies, we're finding the average (aka mean) of values A1,A2,...,A20,A21. This computes the arithmetic mean.
In cell D1, type in =STDEV(A1:A21) to compute the sample standard deviation
There's nothing special about C1 or D1. We just need something off to the side. Think of it like scratch work.
-------------------------
Now move back to column B. In cell B1, type =NORMDIST(A1,$C$1,$D$1,FALSE)
The $C$1 and $D$1 refer to cells C1 and D1 respectively. The dollar signs lock in those rows and columns so they don't change. We don't want the mean and standard deviation to alter. The "False" at the end tells Excel that we don't want a cumulative normal distribution.
The first parameter A1 is the x value. Much like the curve y = x^2, we plug in various x values to find corresponding y values. We'll plot various (x,y) points to connect them with a curve. The more points, the more accurate the curve. Instead of the x^2 function, we're using the NORMDIST function.
Once cell B1 is filled out, click on the bottom right corner of the cell. You should see a very small square at this corner. Dragging this square down until you reach cell B21 will fill in the remaining 20 cells with the formula mentioned in bold; however, the A1 will change depending on what row you're on. Everything else stays the same hence the use of the dollar signs.
-------------------------
In figure 1 below, I'm showing an example of what I've discussed so far. Figure 1 shows the formulas in each cell. This is before they are evaluated.
Figure 2 shows what the formulas evaluate to. The data in column A can be anything you want. I randomly generated the data values between 2 and 17.
Once column B is figured out, you would insert a chart of (x,y) scatter points. Make sure to connect the dots so that a curve forms. This will complete the normal distribution graph. Again, the data in column A must be sorted or else the dots won't be connected properly.
To be perfectly honest, Excel doesn't really do a good job at drawing curves like this. In my opinion, programs like GeoGebra are better suited for the task. Though spreadsheet programs like Excel are still used in a lot of settings, which is why this is good practice.
Will pick brainliest. How would I do this?
Undefined
Order of matrix Q is 4 by 3
whereas order of R is 4by 4
In order to add two matrices , they should be of same order.
Answer:
DOES NOT EXIST.
Step-by-step explanation:
The sum of two matrices exists only if the matrices are of the same order.
Here Q is 3x3 and R is 4x4, so they do not have the same order, hence the sum DOES NOT EXIST.
what is the answer to tjis question? 7 more than h
Answer:
7>h
Step-by-step explanation:
Find the midpoint of the segment that has endpoints at
(a+b, a-b) and (a, b).
Answer:
((2a+b)/2 , a/2)
Step-by-step explanation:
The midpoint is the mean/average of both the x and y values.
Our x values are a+b and a
Our y values are a-b and b
The midpoint x value is (a+b + a ) /2 = (2a + b)/2
The midpoint y value is (a-b + b) /2 = (a)/2
The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint
What are the coordinates of the point plotted on this graph?
Plzzz help asap i need a correct answer
Answer:
838
Step-by-step explanation:
556--282 negative minus a negative is a positive
Answer:
838
Step-by-step explanation:
556 - ( - 282 )
= 556 + 282
= 838
Write a statement that indicates that the triangles in each pair are congruent. NO LINKS!!
Answer:
23
UVW congruent to WFG
and
24
FHG congruent to LMN
Answer:
23 ) UVW is congruent to WGF
24 ) FHG is congruent to LMN
After 4 pm, the rides are 50% off. If the price is $7, how much will it cost after 4 pm?
Answer:
answer is 3.5 dollar
dividing 7 ÷ 2 = 3.5 dollar
as we have to take 50 percent
What is the length of Line segment H A? 7 units 8 units 24 units 48 units
dogs alpha an 125789 SMS Skoda Eloisa 124579 harm Occam
Answer:
48
Step-by-step explanation:
correct on Edge 2021
A man leaves the town of Elmsville at 8:00 am and drives to Oak City at a constant rate of 50 miles per hour. Two hours later, a woman leaves Elmsville following the same route to Oak City. The man and woman arrive in Oak City at 3:00 p.m. What was the rate of the woman
Answer: 70 mph
Step-by-step explanation:
Given
A man leaves the town of Elmsville at 8:00 am and reach oak city at 3 Pm
Rate of driving is 50 miles per hour
time taken by man [tex]t=7\ hr[/tex]
Woman leaves 2 hour later and reach by 3 Pm, so time taken is [tex]5\ hr[/tex]
Distance traveled by both the person is same
[tex]\therefore 50\times 7=v\times 5\quad[v=\text{rate of woman}]\\\\\Rightarrow v=\dfrac{50\times 7}{5}\\\\\Rightarrow v=70\ mph[/tex]
Thus , the rate of woman is 70 miles per hour.
Write the equation of the line passing through the point (−3,−4) that is perpendicular to y=8/3x+5.
Answer:
y = -3/8x -41/8
Step-by-step explanation:
Perpendicular lines intersect at 90° and their slopes are opposite reciprocals.
Therefore the slope changes from 8/3 to -3/8.
Now we must solve for the new y-intercept (b) by plugging in the given coordinate (-3,-4).
The result is b = -41/8 so our new equation is:
y = -3/8x -41/8
Help me please I NEED to pass this
OPTION C is the correct answer.
Hope it helps you.
I need help ASAP pls! I hate geometry
Let P(x, y) denote the point where the terminal side of an angle θ meets the unit circle. If P is in Quadrant II and x = − 5⁄8 , evaluate the six trigonometric functions of θ.
The six trigonometric function of [tex]\theta[/tex] are [tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex], respectively.
In this question, we assume that x-component of the terminal point is part of a unit circle. Then, we can find the value of y by means of the Pythagorean theorem:
[tex]y = \sqrt{1-x^{2}}[/tex] (1)
If we know that [tex]x = -\frac{5}{8}[/tex] and P is in the second quadrant, then the value of y is:
[tex]y = + \sqrt{1-\left(-\frac{5}{8} \right)^{2}}[/tex]
[tex]y \approx 0.781[/tex]
By trigonometry, we remember the following definitions for the six basic trigonometric functions:
[tex]\sin \theta = \frac{y}{1}[/tex] (1)
[tex]\cos \theta = \frac{x}{1}[/tex] (2)
[tex]\tan \theta = \frac{y}{x}[/tex] (3)
[tex]\cot \theta = \frac{1}{\tan\theta}[/tex] (4)
[tex]\sec \theta = \frac{1}{\cos \theta }[/tex] (5)
[tex]\csc \theta = \frac{1}{\sin \theta}[/tex] (6)
If we know that [tex]x = -\frac{5}{8}[/tex] and [tex]y \approx 0.781[/tex], then the six basic trigonometric functions are, respectively:
[tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex]
The six trigonometric function of [tex]\theta[/tex] are [tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex], respectively.
We kindly invite you to check this question related to trigonometric functions: https://brainly.com/question/6904750
A random sample of 30 patties that were inspected over the course of the last week revealed that the average weight was 95.0 grams. The standard deviation was 0.25 grams. What percentage of the deliveries is likely to be outside the specification limits (outside the interval of [94.5, 95.5])
Answer:
4.56% of the deliveries are likely to be outside the specification limits.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The average weight was 95.0 grams. The standard deviation was 0.25 grams.
This means that [tex]\mu = 95, \sigma = 0.25[/tex]
What percentage of the deliveries is likely to be outside the specification limits (outside the interval of [94.5, 95.5])?
Less than 94.5, or more than 95.5. Since the normal distribution is symmetric, these probabilities are the same, so we can find one of them and multiply by two.
The probability that it is less than 94.5 is the p-value of Z when X = 94.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{94.5 - 95}{0.25}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a p-value of 0.0228
2*0.0228 = 0.0456
0.0456*100% = 4.56%
4.56% of the deliveries are likely to be outside the specification limits.
Complete each congruence statement by naming the corresponding angle or side. NO LINKS!!!
Answer:
Solution given:
19
<JKL=<KLS
20
FD=GD
9514 1404 393
Answer:
19) ∠JKL ≅ ∠SLK
20) FD ≅ GD
Step-by-step explanation:
It works well to identify the locations of the letters in the congruence statement, then use the letters in the same order from the other part of the congruence statement.
19) Letters JKL have the order 312 in the first part of the congruence statement ΔKLJ ≅ ....
The last part of the congruence statement is ... ≅ ΔLKS. The letters in order 312 from that part are SLK, so we want our angle congruence to read ...
∠JKL ≅ ∠SLK
__
20) The letters we're given (FD) are in positions 31 of the first part of the triangle congruence statement. The letters in those positions in the second part are GD, so our segment congruence is ...
FD ≅ GD
the multiplicative inverse of 5 2/3
Answer:
Step-by-step explanation:
5[tex]\frac{2}{3}[/tex]
first chnge to improper or proper fraction
5*2/3
10/3
multiplicative inverse of 10/3 = 3/10
Find the volume of the composite solid. Round your answer to the nearest
tenth.
Answer:
452.4 in³
Step-by-step explanation:
Volume half sphere = 1/2 volume sphere
Volume sphere = 4/3πr²
Volume = 4/3*3.14*27 Radius = 1/2(6) . 3³ = 27
Volume ≈ 113.1
Volume Cylinder = Area circle x hieght
Area circle = πr²
Area circle = 3.14 * 9
Area circle = 28.26
Volume cylinder = 28.26 * 12 = 339.12
339.12 + 113.1 = 452.22
Because of rounding it would be ≈ 452.4
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
what are the prime factors of the greatest 4 digit number?
Answer:
The prime factors of the greatest 4 digit number are 3, 11 and 101.
Step-by-step explanation:
Hope it helps
1.(06.05 MC)
Albiologist is comparing the growth of a population of flies per week to the number of flies a lizard will consume per week. She has devised an equation to solve for which day (x) the lizard
would be able to eat the entire population. The equation is 2* - 3 = 4x + 2.
Explain to the biologist how she can solve this on a graph using a system of equations. (10 points)
The diameter of the stem of a wheat plant is an important trait because of its relationship to breakage of the stem. An agronomist measured stem diameter in eight plants of a particular type of wheat. The mean of these data is 2.275 and the standard deviation is 0.238. Construct a 80% confidence interval for the population mean.
Answer:
7.79771≤x≤8.20229
Step-by-step explanation:
Given the following
sample size n = 8
standard deviation s = 0.238
Sample mean = 2.275
z-score at 980% = 1.282
Confidence Interval = x ± z×s/√n
Confidence Interval = 8 ± 1.282×0.238/1.5083)
Confidence Interval = 8 ± (1.282×0.15779)
Confidence Interval = 8 ±0.20229
CI = {8-0.20229, 8+0.20229}
CI = {7.79771, 8.20229}
Hence the required confidence interval is 7.79771≤x≤8.20229
What is the value of x?
O A. x=15
O B. x=10
O C. x=20
D. x=5
In a group of five students, there are two boys and three girls. The instructor randomly selects one student to record for the group and another student to spy on the other groups. Find P(boy first and girl second), the probability of selecting one of the boys first, and then selecting a girl for the second role
Answer: The instructor randomly selects one student to record for the group and another student to spy on the other groups.
[tex]\color{yellow}{}[/tex]
