Use order of operations to solve the equation

Answer:

x = 37.3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan 63 = x /19

19 tan 63 =x

x=37.28959

To the nearest tenth

x = 37.3

Answer:

Step-by-step explanation:

In order to undo that e, you need to take the natural log of both sides:

[tex]ln(e^x)=ln(7.1)[/tex] the ln and the e cancel each other out, leaving us with

x = ln(7.1) so

x = 1.96

Answer:

a. it is arithmentic - this is because for each term there is a constant increase of 4, and the change between each term doesn't change

b. you need to find the nth term, by using the equation difference x n + 0th term: the difference is (+)4 and the 0th term is -9 (-5 is the 1st term, so to go one back we subtract 4 - the inverse operation), so the nth term is 4n -9. Now we do the inverse operation on 119 to see if it's a term (it is a term if it's an integer. So, first we do 119 plus 9 (inverse of - 9) to get 128, then divide it by 4 rather than multiplying. This gives us 32, and that tells us that 119 is the 32nd term of the sequence.

Answer:

i went with mean is less than median

Step-by-step explanation:

other website lol

Answer:

First, find the value of x:

[tex]h(5-x)=h(9)\\5-x=9\\-x=9-5\\-x=4\\x=-4[/tex]

Substitute the x-value in to the function [tex]x^{2}+x+1[/tex] and solve:

[tex](-4)^{2}+(-4)+1=16-4+1=12+1=13[/tex]

Therefore, the value of h(9) = 13.

Hope this is correct O-o

Answer:

A

Step-by-step explanation:

Since we need to find the value of h(9), we can substitute the (5-x) part from the original equation with 9 to get the value of x, which is 5-x = 9, x = -4. With that, we can go ahead and plug the x into the right side of the equation to get (-4)^2 + (-4) + 1, which equals 16 - 4 + 1, which equals 13.

I hope this helped! Please do let me know if you have further questions :D

Answer:

Step-by-step explanation:

[tex]\\ \sf\longmapsto 2x^2c^2+3xc^2-35c^2[/tex]

[tex]\\ \sf\longmapsto c^2(2x^2+3x-35)[/tex]

[tex]\\ \sf\longmapsto c^2(2x^2+10x-7x-35)[/tex]

[tex]\\ \sf\longmapsto c^2(2x(x+5)-7(x+5))[/tex]

[tex]\\ \sf\longmapsto c^2(2x-7)(x+5)[/tex]

Answer:

C. 12 for $6.00

Step-by-step explanation:

Answer:

C. 12 for $6.00

Step-by-step explanation:

better than $13.00 for 24. as that'd be $6.50 for 12..

Answer:

(4, -1)

Step-by-step explanation:

xB = -2+(-2-(-8)) = -2 +6 = 4

yB = 1+(1-3)=1+(-2) = -1

so, the coordinates of point B => (4, -1)

Answer: 43046721(t^8)

Step-by-step explanation:

So first, multiply 3 by t to get 3t. Then, multiply it again by 3 to get 9t. Raise it to the 8th power to get (9^8)(t^8). This gives you 43046721(t^8)

82.053°??

(Tried going as fast as I can)

Answer:

Diagonals of a rhombus intersect at right angles

Therefore, [tex]\angle AOD=90[/tex]

[tex]Now,in\: \bigtriangleup AOD[/tex]

[tex]\angle OAD+\angle AOD+\angle ADO=180[/tex]

[tex]x+90+3x+12=180[/tex] [tex]\leftarrow [combing \: like\: terms][/tex]

[tex]4x+102=180\\-102 \: -102[/tex] [tex]\leftarrow [subtracting \:102 ][/tex]

[tex]\frac{4x}{4} =\frac{78}{4} \leftarrow [dividing \: by\: 4][/tex]

[tex]x=19.5[/tex] [tex]\Longleftarrow[/tex]

OAmalOHopeO

Answer:

base = 3x - 1

height = x

area of triangle = (1/2)bh

22 = (1/2)(3x-1)(x)

44 = (3x-1)(x)

44 = 3x^2-x

0 = 3x^2-x-44

0 = 3x^2-12x+11x-44

0 = (3x^2-12x)+(11x-44)

0 = 3x(x-4)+11(x-4)

0 = (x-4)(3x+11)

x = {-11/3, 4}

throw out the negative solution (extraneous) leaving

x = 4 m (height)

.

Base:

3x - 1 = 3(4) - 1 = 12 - 1 = 11 

Step-by-step explanation:

I hope it will help you

Answer:

B

Step-by-step explanation:

The secant- tangent angle b is half the difference of the measures of the intercepted arcs , then

b = [tex]\frac{1}{2}[/tex] ( 180 - 35) = [tex]\frac{1}{2}[/tex] × 145° = 72.5° → B

Answer:

Bruce's tiles covered more area than Felicia's, so this means Bruce has the greater unit rate.

Step-by-step explanation:

Got it right

K = 5n/m

F=KE

K= F/E

= 10/5

K = 5n/m

Step-by-step explanation:

[tex]15)2n \\ 16)1 \times {10}^{7} \\ 17) {m}^{5} \\ 18)xy \\ 19)5 {n}^{2} - 6 \\ = - 6 \\ 20)9 {a}^{ 3} + 1 \\ = \frac{d}{da} (9a {}^{ 3} + 1) \\ 21) {x}^{3} . {y}^{3} \\ = (x.y) {}^{3} \\ = {x}^{3} {y}^{3} \\ 22)c {}^{4} .d {}^{6} \\ = {c}^{4} {d}^{6} \\ 23)3e + {e}^{2} \\ = e(e + 3) \\ \\ \\ hope \: it \: is \: help \: to \: you[/tex]

15 2 times n

16 10 race to the power 7

17 m race to the power 5

18 x times y

19 6 subtracted from 5 times n race to the power 2

20 1 added to 9 times a race to the power 3

21 x race to the power 3 times y race to the power 2

22 c race to the power 4 times d race to the power 6

23 3 times e added to 2 times e race to the power 2

Must click thanks and mark brainliest

Answer:

[tex]14 \frac{5}{1000} [/tex]

Step-by-step explanation:

[tex]14.005 = 14 \frac{5}{1000} [/tex]

proper frac 14 1/200

improper frac 2801/200

Answer:

(2,21)

Step-by-step explanation:

y = 10.5x

it says that x=2 and when you plug the 2 in the equation you would get

y = 10.5(2)

then multiply the 2 and 10.5

y=21

that is my answer

glad yo help

Answer:

24.83 hours

Step-by-step explanation:

Given that :

Let time taken by pumps be :

Pump A = 60 hours

Pump B = 80 hours

Pump C = 90 hours

Recall :

Rate = 1 / time taken

The rates of the pumps are :

Pump A rate = 1 / 60

Pump B rate = 1/80

Pump C rate = 1/90

Combined rate : 1/60 + 1/80 + 1/90

Combined rate = (12 + 9 + 8) / 720 = 29/720

Combined rate = 29/720

The time taken together will be :

1 / combined rate = 1/(29/720) = 720 / 29 = 24.827 hours

Answer:

number is 6

Step-by-step explanation:

let the number be x , then double the number is 2x and

2x - [tex]\frac{1}{3}[/tex] x = 10 ( multiply through by 3 to clear the fraction )

6x - x = 30

5x = 30 ( divide both sides by 5 )

x = 6

That is the number is 6

Answer:

2 1/2 miles = 1/6 hours 2 1/2 miles * 6 = 1/6 hours * 6 12 1/2 miles = 6/6 hours 12 1/2 miles = 1 hour 12 1/2 miles/hr

Answer:

[tex]\frac{\frac{5}{2} * 6 }{\frac{1}{6} * 6}[/tex] = [tex]\frac{\frac{30}{2} }{\frac{6}{6} }[/tex]

Step-by-step explanation:

Solution :

For the bigger rectangle

Width of bigger rectangle = W

Length of bigger rectangle, L = 2W

For the smaller rectangle

Width , w = W+4

Length, l = L = 2W

Area, a =120 [tex]m^2[/tex]

Now we know,

Area = length x width

[tex]$a=l \times w$[/tex]

[tex]$120=(2W) \times (W+4)$[/tex]

[tex]$120=2W^2 + 8W$[/tex]

[tex]$2W^2+8W-120=0$[/tex]

[tex]$W^2+4W-60=0$[/tex]

[tex]$(W+10)(W-6) = 0$[/tex]

We get, either [tex]W=-10[/tex]   (rejecting)

                or     [tex]W=6[/tex]

∴ length of the bigger rectangle, [tex]$L=2W $[/tex]

                                                          = 2(6)

                                                           = 12 m

 Length of the smaller rectangle, [tex]$L=2W$[/tex]

                                                            = 2(6)

                                                           = 12 m

Hence, the length of the two gardens is 12 m.                                                            

Answer:

No, it doesn't indicate that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company

Step-by-step explanation:

Let's first state the hypotheses.

Null hypothesis; H0: p = 0.68

Alternative hypothesis; Ha: p > 0.68

A random sample of 53 claims showed that 41 were made by single people under the age of 25.

Thus; p^ = 41/53 = 0.7736

Let's find the test statistic from the formula;

z = (p^ - p_o)/√(p_o(1 - p_o)/n)

z = (0.7736 - 0.68)/√(0.68(1 - 0.68)/41)

z = 0.0936/0.07285

z = 1.28

From online p-value from z-score calculator, using z = 1.28, one tail hypothesis and significance level of 0.05,we have;

P(z > 1.28) = 0.100273

The p-value gotten is greater than the significance value and so we fail to reject the null hypothesis and conclude that there is insufficient evidence to support the claim.

Answer:

I don't know ask to your teacher

Hi there!

Looking at the graph, the first intersection point is clear. The red parabola and  blue line clearing intersect at the point (0, -1).

Find the second intersection point by setting the equations of both graphs equal to each other.

Line: y = 3x - 1

Parabola: y = 4x² - 1

Find another intersection point by setting these two equations equal to each other:

4x² - 1 = 3x - 1

Bring all terms onto one side:

4x² - 3x = 0

Factor out x:

x(4x - 3) = 0

Set 4x - 3 to 0 and solve:

4x - 3 = 0

4x = 3

x = 3/4

Plug in this value of x into an equation to solve for the y-coordinate. Use the linear equation for ease:

y = 3(3/4) - 1

y = 9/4 - 1

y = 5/4

(3/4, 5/4)

Answer: A) 4

Explanation:

For any 30-60-90 triangle, the short leg is half as long as the hypotenuse.

The short leg is opposite the smallest angle (30 degrees), so we see that

x = 8/2 = 4.

Answer:

B

Step-by-step explanation:

A student correctly evaluated an expression where p = -2 and q = 3 and acquired 3 as the result.

And we want to determine which expression could the student have been evaluating.

Thus, we simply need to check each expression by letting p = -2 and q = 3 and see which one equals 3.

Checking the first one:

[tex]\displaystyle \begin{aligned} 3p^2 +2pq - 6q +2 &= 3(-2)^2+2(-2)(3)-6(3) + 2\\ &= (12)+(-12) +(-18) + 2 \\ &=-16\end{aligned}[/tex]

The result is not 3. Hence, A is not correct.

The second expression:

[tex]\displaystyle \begin{aligned} p^3 + 2p^2q-p^2+2pq+q &= (-2)^3+2(-2)^2(3)-(-2)^2+2(-2)(3)+(3)\\ &= (-8)+(24)-(4)+(-12)+(3) \\ &= 3\stackrel{\checkmark}{=}3\end{aligned}[/tex]

Therefore, we can conclude that our answer is B.

We can check the other two regardless.

The third expression:

[tex]\begin{aligned} p^2+q-4q^2 &= (-2)^2 + (3) - 4(3)^2 \\ &= (4) + (3) -(36) \\ &= -29\end{aligned}[/tex]

And the fourth:

[tex]\displaystyle \begin{aligned} p^2+3q^2-q^2+p &= (-2)^2+3(3)^2-(3)^2+(-2) \\ &= (4) + (27) - (9) + (-2) \\ &= 20\end{aligned}[/tex]

Thus, neither the third expression nor the fourth is also correct.

In conclusion, our answer is B.

56/64 = 7/8

7/8 x 120

105.