The quadratic formula can be used to solve any quadratic equation in standard form.
True or False

Step-by-step explanation:

Right now, we would solve everything within the parenthesis first.

(8 - 16) + (8 + 6)

(-8) + (14)

14 - 8

6

But if we remove the parenthesis, it doesn't matter what order we do things in.

8 - 16 + 8 + 6

8 + 8 - 16 + 6

16 - 16 + 6

6

The reason why both of these are the same, is because the only calculations we're doing are addition and subtraction, which don't care about parenthesis.

Answer:

A

Answer:

standard= 21.333%

prime= 42.666%

expedited= 6.666%

locker= 29.333%

Answer:

Step-by-step explanation:

L = 2 + sqrt(2)

W = 4 - 2sqr(2)

Area = L * W

Area = (2 + sqrt(2) )* (4 - 2sqrt(2) )

Use Foil

Result

Area = 8 - 4 - 4sqrt(2) + 4sqrt(2)

Area = 4

The rate of change is 7 because its 7 miles per hour

Answer:

m = 7 - 3n

Step-by-step explanation:

subtract 3n from both sides of the equation

Answer:

0,458$

Step-by-step explanation:

Answer:

X⁴–X²–2X –1=0

(X²+X+1)(X²–X–1)=0

[tex]x = - \frac{1 - i\sqrt{3} }{2} \\ x = - \frac{ 1 + i \sqrt{3} }{2} [/tex]

[tex]x = \frac{1 + \sqrt{5} }{2} \\ x = \frac{1 - \sqrt{5} }{2} [/tex]

I hope I helped you^_^

Answer:

-2

Step-by-step explanation:

The output of the chart and graph drops by 2 for every input.

Answer:

4

Step-by-step explanation:

The ratio of the area of similar figures is the ratio between corresponding sides squared. This means that 64/4 or 16 is the square of the ratio of corresponding sides. By taking the square root of 16, we get that ratio is 4.

This question is solved using a system of equations, and doing this, we get that: There are 9 quarters, 4 nickels and 12 dimes.

I am going to say that:

x is the number of nickels.

y is the number of dimes.

z is the number of quarters.

In all, they are worth $3.65.

A nickel is worth $0.05, a dime is worth $0.1 and a quarter is worth $0.25, so:

[tex]0.05x + 0.1y + 0.25z = 3.65[/tex]

Dimes: 3 times greater than nickels:

This means that:

[tex]y = 3x[/tex]

Quarters: One greater than double the number of nickels:

This means that:

[tex]z = 2x + 1[/tex]

Value of x:

We have y and z as function of x, so we can replace into the equation and find the value of x, so:

[tex]0.05x + 0.1y + 0.25z = 3.65[/tex]

[tex]0.05x + 0.1(3x) + 0.25(2x+1) = 3.65[/tex]

[tex]0.05x + 0.3x + 0.5x + 0.25 = 3.65[/tex]

[tex]0.85x = 3.4[/tex]

[tex]x = \frac{3.4}{0.85}[/tex]

[tex]x = 4[/tex]

y and z:

[tex]y = 3x = 3(4) = 12[/tex]

[tex]z = 2x + 1 = 2(4) + 1 = 9[/tex]

There are 9 quarters, 4 nickels and 12 dimes.

A similar question is found at https://brainly.com/question/17096268

Answer:

x = -1 y = 3

Step-by-step explanation:

x = 2y-7

2x + 3y = 7

Substitute x =2y-7 in 2y + 3y = 7

2(2y-7) + 3y = 7

4y-14+3y = 7

7y - 14 = 7

7y = 7 + 14

7y = 21

7y/7 = 21/7

y = 3

Substitute 3 for y in x = 2y-7

x = 2(3) - 7

x = 6 -7

x = -1

Answered by Gauthmath

Answer:

9

Step-by-step explanation:

r/3  +5 ≤ 8

Subtract 5 from each side

r/3  +5 -5≤ 8-5

r/3   ≤ 3

Multiply each side by 3

r/3  *3 ≤ 3*3

r   ≤ 9

The only value that is less than or equal to 9 is 9

Answer:

x = 1 and y =5

Step-by-step explanation:

[tex]8x -2y= -2\\Divide by -2\\-4x+y = 1\\add 4x\\y= 1+4x\\[/tex]

Substitute this value of y in the next equation.

[tex]9x+5(1+4x) = 34\\9x+5+20x=34\\29x+5=34\\29x=29\\x=1[/tex]

Solve for y using x.

[tex]y=4x+1\\y=4(1)+1\\y=5[/tex]

Answer:

Step-by-step explanation:

369 = x + (x+2) + (x+4)

369 = 3x + 6

363 = 3x

121 = x

now that we know that x = 121, we can solve the equation by plugging in the variable

369 = x + (x+2) + (x+4)

369 = 121 + 123 + 125

369 = 369

The smallest three integers are 121,123 and 125.

Let, the smallest odd integers be n

Then according to the given condition,

[tex]n+(n+2)+(n+4)=369\\3n+6=369\\3n=363\\n=121[/tex]

So, the numbers are,

[tex]n=121\\n+2=121+2=123\\n+4=121+4=125[/tex]

Learn More:https://brainly.com/question/2254193

Transformations are operators that can act on functions, modifying them in different ways. In this particular problem, we see the translations.

The correct option is B:

g(x) can be graphed by translating the basic rational function ƒ(x)=  1∕x left by 3 units and downward by 5 units.

Let's describe the transformations:

Horizontal translation:

For a general function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N)

If N is positive, the shift is to the left.

If N is negative, the shift is to the right

Vertical translation:

For a general function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

If N is positive, the shift is upwards.

If N is negative, the shift is downwards.

Now that we know this, let's see the problem.

We have:

[tex]g(x) = \frac{1}{x + 3} - 5[/tex]

So, the original function is:

[tex]f(x) = \frac{1}{x}[/tex]

Now from f(x) we can apply translations to create g(x).

If first, we apply a translation of 3 units to the left, we get:

[tex]g(x) = f(x + 3) = \frac{1}{x + 3}[/tex]

If now we apply a translation of 5 units downwards, we get:

[tex]g(x) = f(x + 3) - 5 = \frac{1}{x + 3} - 5[/tex]

So we can conclude that the correct option is B:

g(x) can be graphed by translating the basic rational function ƒ(x) 1∕x left by 3 units and downward by 5 units.

If you want to learn more about translations, you can read:

https://brainly.com/question/12463306

Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.

✧ Let us assume :

Seena's age be x

Her mother's age be 4x

✧ After 5 years :

Seena's age = x + 5

Her mother's age = 4x + 5

✧ Ratio of age after 5 years :

Seena's mother = 3

Seena's ratio = 1

Hence, the equation is :

[tex] \looparrowright\frak{ \frac{4x + 5}{x + 5} = \frac{3}{1} }[/tex]

By cross multiplying we get

[tex] \looparrowright \frak{3(x + 5) = 4x + 5}[/tex]

[tex] \looparrowright \frak{3x + 15 = 4x + 5}[/tex]

[tex] \looparrowright \frak{x = 10}[/tex]

Hence, the ages are

Seena's age = x = 10 yrs

Her mother's age = 4x = 4 × 10 = 40 years

∴ Seena's age is 10 and her mother's is 40 respectively

Answer:

a) 450 gravel   b)1250 sand

Step-by-step explanation:

:)

Answer:

Its the first one

Step-by-step explanation:

A dump truck that is 1/10 is less full than a 7/10 one.

Answer:

b. 8

Step-by-step explanation:

Simplify the left side by dividing the top and bottom by 5

35/5 = 7

40 /5 = 8

7/8

Hey there!

35/40 = 7/x

Cross Multiply the fraction

35(x) = (7)(40)

→ 35x = 280

DIVIDE 35 to BOTH SIDES

35x/35 = 280/35

CANCEL out: 35/35 because that gives you 1

KEEP: 280/35 because that helps solve for the x-value

→ x = 280/35

x = 8

Therefore, your answer is most likely: 8 (Option B)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

x=4

Step-by-step explanation:

f(x) = x^2 - 8x+16

Set equal to zero

0 = x^2 -8x +16

Factor

what 2 numbers multiply to 16 and add to -8

-4*-4 = 16

-4+-4 = -8

0= (x-4)(x-4)

Using the zero product property

x-4 = 0  x-4 =0

x=4  x=4

Answer:

but what to do in do I have to find the area of the particular Region or a length of that

Answer:

64

Step-by-step explanation:

4^4*4^-1      

4^4*1/4

256*1/4

256/4

64

Answer:

Step-by-step explanation:

The general form of this equation is

[tex]A=Pe^{rt}[/tex] where P is the initial population, e is Euler's number (a constant), r is the rate of decay, and t is the time in years.

Therefore, filling in:

[tex]A=45000e^{-.02t[/tex]

Answer:

Step-by-step explanation:

Mean of the data = sum of the data / number of frequencies:

Correct choice is d

Answer:

x=0       x=8          x = -1/10

Step-by-step explanation:

- 2x(x − 8)(10x + 1) = 0

Using the zero product property

-2x =0   x-8 = 0    10x+1= 0

x= 0    x= 8             10x = -1

x=0       x=8          x = -1/10

Answer:

y= [tex]\frac{c-2x}{3}[/tex]

Step-by-step explanation:

2x+3y=C

isolate y

3y=C-2x

y= [tex]\frac{c-2x}{3}[/tex]

Answer:

6y = -5x + 6

y = -5/6 x + 1

Step-by-step explanation:

y = -5/6 x + b

1 = b

Answer:  3

Step-by-step explanation:                                                                                                          

[tex]\displaystyle\ \Large \boldsymbol{} We \ have \ a \ square\ function \\\\ f(x)=ax^2+bx+c \\\\And \ we \ know \\\\ \left[\left \[ {{f(0)=a\cdot 0+b\cdot0+c=0} \atop {f(-4)=a(-4)^2+-4b+c=-24}} \right.=>[/tex]                                                [tex]\displaystyle\ \Large \boldsymbol{} \left[ \ {{c=0} \atop {16a-4b=-24}} \right. =>\boxed{4a-b=-6} \\\\\\ and \ x_0 =-\frac{b}{2a}=1 =>\boxed{ b=-2a} \\\\\\ \left \{ {{4a-b=-6} \atop {b=-2a}} \right. =>4a+2a=-6=> a=-1 \ ; \ b=2 \\\\\\then \ b-a=2-(-1)=\boxed{3}[/tex]