Unique buys 918 Spyder Porsche worth $845,000 every year that he owns the car
the car depreciates in value at a rate of 32% per year.
Write a function that models the value of the Porsche after t years.
*

Definitions:

The given angles are:

Answer: To solve this problem, we need to set the two equations equal to each other and solve for the number of text messages that were sent by each person. We know that the cost of Jack's plan is c = 0.30t + 9 and the cost of Jill's plan is c = 0.60t. To find the number of text messages they each sent, we can set these two equations equal to each other and solve for t:

0.30t + 9 = 0.60t

0.30t = 0.60t - 9

0.30t = 0.60t - 9

-0.30t = -9

t = 30

Therefore, if Jack and Jill paid the same amount for their text plans, they each sent 30 text messages.

Answer: 15 / 18

Step-by-step explanation:

9 / 18 + 1/3

1/3 = 6 / 18

9 / 18 + 6/ 18

15 / 18

Answer:

5/6.

Step-by-step explanation:

Step 1: Rewrite 9/18

9/18 = 1/2

Step 2: Rewrite problem

1/2 + 1/3

Step 3: Find (Greatest common denominator)

6

Step 4: Rewrite fractions

3/6 + 2/6

Step 5: Add

5/6

The following conditions must be met in order to test hypotheses using proportions: np ≥ 5 and nq ≥ 5

To test hypotheses using proportions, the following requirements are necessary:

np ≥ 5 and nq ≥ 5: It is necessary to have a sufficient number of samples in each group being compared.

The rule of thumb is to have at least 5 observations in each group, where n is the sample size and p is the proportion in that group.

This ensures that the sampling distribution of the proportion is approximately normal, which is necessary for hypothesis testing.

Hence, the correct answer would be an option (A).

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The equation of the regression line is y = 4 + x and the regression analysis of the given data need not be done.

Straight line equation is y = a + bx.

The normal equations are

∑y = a·n + b ∑x ∑ xy = a ∑x + b∑x² Hence the regression analysis of the data :

The values are calculated using the following table

x y x²             x⋅y

58 62 3364 3596

47 51 2209 2397

84 88 7056 7392

62 66 3844 4092

57 61 3249 3477

72 76 5184 5472

69 73 4761 5037

hence :

∑x = 449

∑y = 477

∑x² = 29667

∑x⋅y = 31463

Substituting these values in the normal equations

7a+449b=477

449a+29667b=31463

Solving these two equations using Elimination method,

7a+449b=477

and 449a+29667b=31463

7a+449b=477→(1)

449a+29667b=31463→(2)

equation(1)×449

⇒3143a+201601b=214173

equation(2)×7

⇒3143a+207669b=220241

Substracting

⇒-6068b = -6068

⇒6068b = 6068

⇒b = 1

Putting b = 1 in equation (1), we have

7a+449(1) = 477

⇒7a = 477  - 449

⇒7a = 28 or a  = 4.

Now Estimate y for x=50

y = a + bx , we get

y = 4 + 1×50

y = 4 + 50

y = 54

At x equals 50 we get the value of y as 54 .

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Option a) 90% confidence interval for the population proportion of successes = 0.402

Option b) 90% confidence interval for the population proportion of failures = 0.598

According to the question given,

Critical values of Standard deviations are to be used to construct the proportions for the confidence interval.

The formula of a confidence interval that we will be using for the solution will be,

p = [tex]z_{a} * \sqrt{\frac{p(1-p)}{n} }[/tex]

In the above expression,

p = observed population.

n = sample size

[tex]z_{a}[/tex] = critical value of confidence interval

Now the given observations in question = 115

That result in success = 46

The resultant sample proportion = [tex]\frac{46}{115}[/tex]

⇒ 0.40 and it is for both success and failure

Here we can see that the answer for both parts will be identical.

The critical value of z at 90% confidence = 1.64

a) Lower bound = [tex]0.4 - 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]

⇒ 0.402

b) Upper bound = [tex]0.4 + 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]

⇒ 0.598

Confidence interval = 0.402 to 0.598

Therefore,

Option a) 90% confidence interval for the population proportion of successes = 0.402

Option b) 90% confidence interval for the population proportion of failures = 0.598

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The probability that their mean length is less than 17.4 inches is 28.26%

Given :

A manufacturer knows that their items have a normally distributed length, with a mean of 19.7 inches, and standard deviation of 4 inches , If 25 items are chosen at random .

z = ( X - μ ) / σ, where X = date , μ = mean , σ = standard deviation .

substitute the values

z = 17.4 - 19.7 / 4

= -2.3 / 4

= -0.575

P - value at z = -0.575 is 0.2826

Converting into percentage :

= 0.2826 * 100%

= 28.26 %

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The data form a 2x4 frequency matrix and the ratio of each cell represents the result. Each participant's rating is a birth order category (1, 2, 3, 4). The Mann-Whitney test can assess the significance of differences between groups.

The chi-square test of independence determines whether the proportions are significantly different for each birth order group. Effect sizes are measured in Cramer's V. Alternatively, the data form two sets of ratings, one for each personality group. Each participant's rating is a birth order category (1, 2, 3, 4). The Mann-Whitney test can assess the significance of differences between groups.

The chi-square test (also called chi-square or chi-square test) is a statistical hypothesis test used in contingency table analysis when the sample size is large. Simply put, the main purpose of this test is to test whether two categorical variables (the two dimensions of the contingency table) independently affect the test statistic (the values ​​in the table) . The test is valid when the test statistic is a chi-square distribution based on the null hypothesis, specifically Pearson's chi-square test and variants thereof. Use Pearson's chi-square test to determine whether there is a statistically significant difference between the expected and observed frequencies for one or more categories in the contingency table. For contingency tables with small sample sizes, Fisher's exact test is used instead.

In statistics, the Mann-Whitney U test (also known as the Mann-Whitney-Wilcoxon (MWW/MWU), Wilcoxon rank sum test, or Wilcoxon-Mann-Whitney test) is a test of the null hypothesis used at random. It is a non-parametric test. Values ​​X and Y selected from two populations where the probability of X being greater than Y is equal to the probability of Y being greater than X.

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The height of the pile increasing when the pile is 16 feet high is 5/32 ft/min.

We are given dV/dt=10 cubic ft/min and we want to find dh/dt. Therefore, first we need to write a formula relating v and h.

V=pi*r^2*h/3  since d=h at any moment, we know that r=h/2 at any moment and if we substitute h/2 for r, we get

V=pi(h/2)^2*h/3 and if we simplify this,  we get

V=pi*(h^3)/12

Now we need to take the derivative of both sides with respect to t

dV/dt = pi * ( 3 * h^2 ) */12 * dh/dt

= pi * h^2 / 4 * dh/dt, substitute 40 for dV/dt and 16 for h and solve for dh/dt and we get

40 = pi * 16^2/4*dh/dt

dh/dt = 40 * 4 / ( 256 * pi )

= 40/(256*pi) ft/min,

= 10/64

= 5/32 ft/min

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Answer:

X = 3, Y = -6

Step-by-step explanation:

y = -2x

y = -9x + 21

Bring Y and X on the same side (alone).

0 = -2x – y

-21 = -9x – y

Multiply the top equation by -1 so we can cancel out y later on (to make it easier to solve for x).

0 = 2x + y

-21 = -9x – y

Add the equations.

-21 = -7x

Divide by -7.

X = 3

Solve for Y and check.

Y = -2(3)

Y = -6

Use the other equation to make sure.

(-6) = -9(3) + 21

-6 = -27 + 21

Have a nice day :D

[tex]V=4\pi b^{2}(5b+3)[/tex].

[tex]V=\pi r^{2} h[/tex]

[tex]V=\pi r^{2} h\\ \\V=\pi (2b)^{2} (5b+3)[/tex]

[tex]V=\pi (2^{2} b^{2} ) (5b+3)\\ \\V=\pi (4 b^{2} ) (5b+3)[/tex]

Use the distributive property of multiplication in order to operate.

[tex]V=\pi (4 b^{2} ) (5b+3)\\ \\V=\pi ((4 b^{2})(5b)+(4 b^{2})(3))\\ \\V=\pi ((20b^{3} )+(12 b^{2}))\\ \\V=4\pi (\frac{20b^{3}}4} +\frac{12 b^{2}}{4} )\\ \\V=4\pi (5b^{3} +3b^{2})\\ \\V=4\pi b^{2}(\frac{5b^{3}}{b^{2}} +\frac{3b^{2}}{b^{2}} )\\ \\V=4\pi b^{2}(5b+3)[/tex]

[tex]V=4\pi b^{2}(5b+3)[/tex].

Answer:

Step-by-step explanation:

Explanation:

As you know, each electron that's part of an atom has its own unique set of four quantum numbers that describes its position and spin.

This means that looking for the number of unique sets of quantum numbers is equivalent to looking for the number of electrons that can occupy the third energy level.

As you know, the number of orbitals you get per energy level is given by the equation

no. of orbitals

=

n

2

, where

n

- the principal quantum number, the ones that gives the energy level.

So, if you're dealing with the third energy level, you can say that it will contain a total of

no. of orbitals

=

3

2

=

9

distinct orbitals.

Now, each orbital can contain a maximum of

2

electrons of opposite spins. This means that the third energy level will contain a maximum number of

no. of electron

=

9

⋅

2

=

18 e

−

So, if each electron is described by an unique set of quantum numbers, you can conclude that

18

sets of quantum numbers are possible for the third energy level.

ok maybe that will help!

At least means less than or equal to.

Fewest means the smallest number of boxes.

12 3/4 +x ≥ 29 5/8

x ≥ 16 7/8

The fewest number of boxes would be almost ≅ 42 boxes

Part A:

Let x denote the amount of fudge at the shop.

Helena prepares 12 3/4 pounds of fudge containing nuts.

Mathematically, the total amount of fudge on Monday will be

12 3/4 +x

Of this amount of fudge  there are at least 29 5/8 pounds of fudge containing nuts at the fudge shop on Monday

12 3/4 +x ≥ 29 5/8

Part B:

The inequality can be solved

12 3/4 +x ≥ 29 5/8

x ≥ 29 5/8- 12 3/4

x ≥  29- 12     5/8- 3/4    

The whole numbers are subtracted and the fractions are solved separately to avoid long calculations.

x ≥  17  (5-6)/8

x ≥  17 - 1/8

x ≥  (136-1)/8

x ≥  (135)/8

x ≥  16 7/8

Part C :

To find the number of boxes we divide the equal number of pounds .

12 3/4 + 29 5/8

12 + 29   3/4 + 5/8

41  11/8

42 3/8

The fewest number of boxes would be almost ≅ 42 boxes

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Label a ray with endpoint Y. An appropriate name for a ray whose endpoint is XY displays a ray with the endpoint Y.

A line with a single defined endpoint that continuously moves away from another is known as a ray (endpoint B in this case).

A segment of a line that lacks an endpoint but has a specified starting point. It can go on forever in a single direction. A ray cannot be measured since it has no end point.

In mathematics, a ray is a segment of a line with a definite starting point but no ending. It can go on forever in a single direction. A ray cannot be measured since it has no end point. Two rays with the same terminal are united to form an angle. The vertex of the angle is referred to as the common endpoint of the rays, while the sides of the angle are referred to as the rays themselves.

The ray in the hypothetical situation has one endpoint B and an endlessly extending endpoint A. (as shown by the arrowhead).

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The lowest common multiple (LCM) of the numbers 22 and 38 is 418.

The L.C.M. defines the least common multiple number which is exactly divisible by two or more numbers, while H.C.F. defines the highest common factor present in between given two or more numbers,

Given the numbers 22 and 38, we can express them as products of their prime factors and thus derive their LCM as follows;

22 = 2 × 11

38 = 2 × 19

LCM = 2 × 11 × 19

LCM = 418

Therefore, the LCM of 22 and 38 is 418 using prime factor method.

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Answer:

5x+x=90

Step-by-step explanation:

5 times the other = 5x

the other piece is x

Answer: the small pipe is 15 inches long

Step-by-step explanation: since the larger pipe is 5 times larger than the small pipe, the 90 inch pipe would have too be divided by 6 to make sure the 5 times of the large pipe and the 1 small pipe. so, you would do 90/6=15. so the small pipe is 15 inches long. the large pipe is 75 inches long.

The 95% confidence interval for the mean reduction in cholesterol level is given as follows:

(51.3, 96.7).

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the following rule:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the variables of the equation are presented as follows:

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 7 df, is t = 2.3646.

From the image given at the end of the answer, the sample of the differences is given as follows:

37, 72, 86, 78, 60, 47, 124, 88.

Hence the parameters are given as follows:

[tex]\overline{x} = 74, s = 27.1, n = 8[/tex]

Then the lower bound of the interval is of:

74 - 2.3646 x 27.1/square root of 8 = 51.3.

The upper bound of the interval is of:

74 + 2.3646 x 27.1/square root of 8 = 96.7.

The table is given by the image shown at the end of the answer.

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They should sell at least 40 items to make a profit of at least $65.

Inequality is a relationship between two expressions which are not equal and connected by the signs, ≤, ≥, <, and >

Given that, the students of a class want to make a profit of at least $65 by selling items they spent $55 for the materials to make the items they will sell each item for $3

Since, they want $65 at least profit,

Therefore, selling price for the profit = 55+65 = $120

Profit = Selling price - cost price

Since, selling price of each item = $3

Let they are selling x items, Therefore, selling price for x items = 3×x = $3x

Now, establishing the inequality,

3x ≥ 120

x  ≥ 120/3

x  ≥ 40

Hence, there should be 40 or more items to be sold.

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The expression Salina created using the greatest common factor in addition and distributing the property is

9(4 + 6)

9x4 + 9x6

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

36 + 54

Taking out the greatest common factor.

9(4 + 6)

Using the distributive property over addition

9 x 4 + 9 x 6

Thus,

9 x 4 + 9 x 6 is the expression Salina created.

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The number of hours it will take the student to complete the project is 5 / 6 hours.

A student completes ⅘ of a math project in ⅔ hour. If the student continues at the same rate,  the time it will take the student to complete the project can be calculated as follows:

Therefore,

let

x = time it will take the student to complete the project

Hence

if 4 / 5 x = 2 / 3 hours

x = ? hours

cross multiply

Therefore,

number of hours to complete the whole math project = x × 2 / 3 ÷ 4 / 5 x

number of hours to complete the whole math project = 2 / 3 x × 5 / 4x

number of hours to complete the whole math project = 10x / 12x

number of hours to complete the whole math project = 10 / 12

number of hours to complete the whole math project = 5 / 6 hours

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A total of 3 cups of vinegar goes into 27 total cups

From the question, we have the following parameters that can be used in our computation:

1/4 cups of vinegar

2 cups of water

So, we have

Water : Vinegar = 2 : 1/4

Rewrite as

Water : Vinegar = 8 : 1

Multiply by 3

Water : Vinegar = 24 : 3

The sum of 24 and 3 is 27

So, we have

Vinegar = 3

Hence, the number of cups of vinegar is 3

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The average rate change of the function is -4.

What is a function?

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.

Given function is f(x) = 1x² + 1x - 8.

Find the average rate change of the function in the interval [-4, -1]

For this compute the value of f(x) at x = -4 and x = -1.

Then find the difference the value of f(x) and divide it by the difference the value of x.

The average rate change of function f(x) in the interval [a,b] is [f(b) - f(a)]/(b-a).

Putting x = -4 in the given function:

f(-4) = 1(-4)² + 1(-4) - 8

f(-4) = 4

Putting x = -1 in the given function:

f(-1) = 1(-1)² + 1(-1) - 8

f(-1) = -8.

The rate change of x is -1 - (-4) = 3

The average rate change of the function is

[f(-1) - f(-4)] /3

= -8 - 4/3

= - 12/3

= -4

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z = -1.34 <  (a - 70)/9

And if we solve for we got

a = 70 - 1.34 * 9 = 57.95 = 98

So, the value of height that separates the bottom 9% of data from the top 91% is 58.

And the answer for this case would be:

a) 58

What is the Normal distribution and Z-score?

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The solution to the problem

Let X be the random variable that represents the scores of a population, and for this case we know the distribution for X is given by:

X ~ N (70, 9)

Where μ = 70, and σ = 9

For this case, the figure attached illustrates the situation for this case.

We know from the figure that the lower limit for D accumulates 9% or 0.09 of the area below and 0.91 or 91% of the area above.

we want to find a value a, such that we satisfy this condition:

 P(X > a) = 0.91  (a)

 P(X < a) = 0.09 (b)

Both conditions are equivalent in this case. We can use the z score again in order to find the value a.  

As we can see in the figure attached the z value that satisfies the condition with 0.09 of the area on the left and 0.91 of the area on the right it's z=-1.34. On this case P(Z<-1.34)=0.09 and P(z>-1.34)=0.91

If we use condition (b) from the previous we have this:

P(X < a) = P(X - μ)/σ < (a - μ)/σ) = 0.09

P(z < (a - μ)/σ) = 0.09

But we know which value of z satisfies the previous equation so then we can do this:

z = -1.34 <  (a - 70)/9

And if we solve for we got

a = 70 - 1.34 * 9 = 57.95 = 98

Hence, the value of height that separates the bottom 9% of data from the top 91% is 58.

And the answer for this case would be:

a) 58

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Answer: Religion reinforces and promotes social inequality and social conflict. It helps convince the poor to accept their lot in life, and it leads to hostility and violence motivated by religious differences. This perspective focuses on the ways in which individuals interpret their religious experiences.

Step-by-step explanation:

The correct option that describes the vertical asymptote is; A: At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote

A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graph, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0, and the function approaches infinity for these values of x.

We are given the function;

f(x) = 8(x - 1)/(x² + 2x - 3)

Simplifying the denominator gives;

(x² + 2x - 3) = (x + 3)(x - 1)

Thus, our function is;

f(x) = 8(x - 1)/[(x + 3)(x - 1)]

(x - 1) will cancel out to give;

f(x) = 8/(x + 3)

Vertical asymptote:

Point in which the denominator is 0, so:

(x + 3) = 0

x = -3

Thus, we conclude that x = -3 is the vertical asymptote

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Eric typed 15 words more than Dae per minute.

Linear equations are equations whose highest power of the variables is 1. The graph of a linear equation is a straight line. A nonlinear equation is an equation whose highest power of the variables is not 1 and the graph is not a straight line.

To find the amount of words typed in 1 minute for both;

Dae = 333/9

Dae = 27 words per minute

Eric = 252/6

Eric = 42 words per minute

Therefore 42 - 27 = 15 words per minute

Eric typed 15 more words per minute.

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A savings account with just an APR of 5.2% compounded quarterly on a balance of $2,000 will yield $16.61 more interest than a similar account with just an APR of 4.8% compounded monthly on the same balance.

Assume we had two different sorts of savings accounts, each with a deposit of $2,000 in it.

We must now determine the earnings for both accounts.

The following formula will be used to determine the earning:

Here,

Put the values for Account A now.

5.2 % in decimal form = 5.2/100= 0.052

v = 2000 x ( 1 + (0.052/4) )^(4*2)

v = 2217.71

Total earning for account A =  $ 2217.71.

For Account B:

4.8 % in decimal form = 4.8/100= 0.048

v = 2000*( 1 + (0.048/12) )^(12*2)

v = 2201.10

Total earning for account A = $ 2201.10

We will now deduct B's earnings from A's earnings to see how much more A earned than B.

2217.71 - 2201.10 = $16.61

Consequently, account A made $16.61 more so than account B.

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The reasons that complete the statements are:

From the question, we have the following parameters that can be used in our computation:

Triangles = RST, and TUR

From the question, we have the following given parameters

∠SRT ≅ ∠UTR

This means that

Statement 2: ∠SRT ≅ ∠UTR ------ Given

At this point, we have

RS ≅ TU --- Congruent side (S)

∠SRT ≅ ∠UTR ------ Congruent angle (A)

RT ≅ TR --- Congruent side (S)

When these congruent sides and angles are combined, we have

SAS congruence property

The SAS congruent theorem implies that the corresponding sides of the triangles in question are congruent and the angles between the corresponding sides are also congruent

Hence, the additional information on the congruency of the triangles are Given and SAS congruence property

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A reaction that acts to amplify or reinforce an initial change is termed a positive feedback.

The positive-feedback mechanism is used in climatic change, any effect that acts to reinforce the initial change.

In Asian philosophy, yin and yang are viewed as forces that interact and are connected to one another and are crucial parts of a dynamic system. Positive and negative feedbacks function something like yin and yang in the Earth system; they are integral parts of the total system that eventually help to maintain a more or less stable state. While negative feedback mechanisms stabilize a system and keep it from reaching extreme states, positive feedback mechanisms increase or magnify an original change. The evolution of Earth's climate system can be viewed in many ways as a kind of conflict between these two feedback mechanisms.

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