Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.

Answers

Answer 1

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]


Related Questions

When are zeros significant when found in front of (to the left) of the decimal point?

Answers

Answer:

If a zero is found between important digits, it is important. Zeros are also used as (not salient) holders to the left of digits if the number is in fact a decimal. Example from www.rpi.edu: , a mass of 42 g has two significant digits. Expressed in kilograms, the mass of 0.042kg should still have two significant digits.

Explanation:

Zeros are also used as (not salient) holders to the left of digits if the number is in fact a decimal. Example from www.rpi.edu: "A mass of 42 g has two significant digits. Expressed in kilograms, the mass of 0.042kg should still have two significant digits."

Hope this comes in handy, have a great day!

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Answers

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