Two forces PQ act on a body the maximum and minimum resultant forces that can act on the body are 13N and 7N respectively. The magnitude of PQ (|P|) = 10 N and (|Q|) is 3 N.
To find the magnitude of the forces PQ, we need to determine the maximum and minimum values for the individual forces.
Let's assume that the forces PQ are represented by vectors P and Q.
The maximum resultant force ([tex]F_m_a_x[/tex]) can be achieved when the forces P and Q are aligned in the same direction. In this case, the maximum resultant force is the sum of the magnitudes of the forces P and Q:
[tex]F_m_a_x[/tex] = |P| + |Q|
Given that [tex]F_m_a_x[/tex] is 13 N, we have:
13 N = |P| + |Q| (1)
Similarly, the minimum resultant force ([tex]F_m_i_n[/tex]) can be achieved when the forces P and Q are aligned in opposite directions. In this case, the minimum resultant force is the difference between the magnitudes of the forces P and Q:
[tex]F_m_i_n[/tex] = |P| - |Q|
Given that [tex]F_m_i_n[/tex] is 7 N, we have:
7 N = |P| - |Q| (2)
Now, we can solve the above two equations simultaneously to find the magnitudes of the forces P and Q.
From equation (1):
|P| = 13 N - |Q|
Substituting this into equation (2):
7 N = 13 N - |Q| - |Q|
Simplifying:
2|Q| = 6 N
|Q| = 3 N
Substituting the value of |Q| back into equation (1):
|P| = 13 N - 3 N
|P| = 10 N
Therefore, the magnitude of force P (|P|) is 10 N, and the magnitude of force Q (|Q|) is 3 N.
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Steam burns are pretty dangerous because there's often a lot of
thermal energy in the steam. When the steam hits you, it is going to
transfer some of that energy to you, cooling the steam. If a 6.4 kg cloud of
steam at 150 degrees, hits you and cools to 100 degrees, What is the loss
of heat energy? (no scientific notation)
The loss of heat energy when a 6.4 kg cloud of steam at 150 degrees Celsius hits you and cools to 100 degrees Celsius is 13,440,000 Joules.
To calculate the heat energy loss, we can use the formula:
Q = mcΔT
Where Q represents heat energy, m is the mass of the steam cloud (6.4 kg), c is the specific heat capacity of water (4,186 J/kg°C), and ΔT is the change in temperature (150°C - 100°C = 50°C).
Plugging in the values, we have:
Q = (6.4 kg) × (4,186 J/kg°C) × (50°C)
Q = 13,440,000 Joules
Therefore, the loss of heat energy when the steam cools from 150°C to 100°C is 13,440,000 Joules.
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Suppose the nozzle of the print head in an inkjet printer ejected ink droplets with a higher speed than normal. How would the strength of the field between the deflection plates need to be adjusted to accommodate this higher speed in order to ensure that the ink goes into the gutter?.
If the nozzle of the print head in an inkjet printer ejected ink droplets with a higher speed than normal, the strength of the field between the deflection plates would need to be adjusted to accommodate this higher speed to ensure that the ink goes into the gutter.
Inkjet printers utilize deflection plates to change the path of the ink droplets. In a situation where the nozzle of the print head ejects ink droplets at a higher velocity than normal, the deflection plates would require a stronger electric field to redirect the ink droplets to the gutter.
The electric field's strength applied to the deflection plates determines the ink droplets' direction, and the droplets can be directed to the print paper or gutter. The strength of the electric field is determined by the deflection plate's width and the voltage applied to it.
The force applied on the ink droplet depends on the charge of the droplet and the strength of the electric field applied to the deflection plates. The strength of the electric field must be adjusted to accommodate the droplets' increased velocity, and this would ensure that the ink goes into the gutter.
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The electron and proton of a hydrogen atom are separated by a distance of approximately 5.3 x 10^-11m. Find the magnitude of the electric and gravitational force between the two particles.
The magnitude of the electric force is 8.21 × 10⁻⁸ N and the gravitational force is 3.61 × 10⁻⁸ N. The electric force acting between the electron and proton of hydrogen atom is given by: Coulomb's Law of electrostatics, F = 1 / 4πε₀ × q₁q₂ / r².
Given that, Distance between the electron and proton of a hydrogen atom, r = 5.3 × 10⁻¹¹m, Mass of an electron, m₁ = 9.1 × 10⁻³¹ kg, Mass of a proton, m₂ = 1.67 × 10⁻²⁷ kg, Charge of an electron, q₁ = -1.6 × 10⁻¹⁹ C, Charge of a proton, q₂ = +1.6 × 10⁻¹⁹ C.
Where,ε₀ = permittivity of free space = 8.854 × 10⁻¹² C²/N m²
F = 1 / 4π (8.854 × 10⁻¹²) × (1.6 × 10⁻¹⁹)² / (5.3 × 10⁻¹¹)²
F = 8.21 × 10⁻⁸ N
The gravitational force acting between the electron and proton of hydrogen atom is given by:
Newton's Law of gravitation, F = G × m₁m₂ / r², Where, G = gravitational constant = 6.67 × 10⁻¹¹ N m²/kg²
F = (6.67 × 10⁻¹¹) × (9.1 × 10⁻³¹) × (1.67 × 10⁻²⁷) / (5.3 × 10⁻¹¹)²
F = 3.61 × 10⁻⁸ N
Therefore, the magnitude of the electric force is 8.21 × 10⁻⁸ N and the gravitational force is 3.61 × 10⁻⁸ N.
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Two rows of fluorescent lamps are installed in an office on the same branch circuit, with each row drawing 12.5 amperes. The source voltage is 277 volts, and the total line resistance of the circuit conductors is 0.5 Ω. The wire used has a constant (k) of 12.6. What is the percentage of voltage drop? (Round the FINAL answer to one decimal place.)
According to the solving the percentage of voltage drop is 2.8%
Let V = Source voltage
= 277 volts
Let R = Total line resistance of the circuit conductors
= 0.5 Ω
Let A = Each row drawing
= 12.5 amperes
Let k = 12.6
The voltage drop formula is given by:
Vdrop = kRA
Where; Vdrop = Voltage drop
= Constant of the wire
= Total line resistance
A = Load Current
Putting the given values in the voltage drop formula, we get;
Vdrop = 12.6 x 0.5 Ω x (12.5 + 12.5) amps
Vdrop = 12.6 x 0.5 Ω x 25 amps
Vdrop = 7.875 volts
Percentage of Voltage drop = (Vdrop / V) x 100%= (7.875 / 277) x 100%
Percentage of Voltage drop = 2.8427 % ≈ 2.8%
Therefore, the percentage of voltage drop is 2.8%.
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Question 5 (10 points)
The friction force depends on what two factors?
Question 5 options:
density and the spring constant
The normal force and distance
The coefficient of friction and the normal force
The coefficient of friction and height
The friction force depends on two factors: the normal force and the coefficient of friction. The normal force acts perpendicular to the surface of an object, while the coefficient of friction measures how difficult it is to slide one surface over another. F = N.
The friction force depends on two factors: the normal force and the coefficient of friction. The normal force is the force that acts perpendicular to the surface of an object, while the coefficient of friction is a measure of how difficult it is to slide one surface over another. The friction force depends on the coefficient of friction between the two surfaces in contact, which is given by the product of the coefficient of friction and the normal force. Mathematically, F = N, where F is the force of friction, is the coefficient of friction, and N is the normal force.
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Susie estimated that she can run for hours at a steady rate of 8mph. She enters a marathon, a distance of 26miles. How long should it take her to complete the race? Give answers in hours and minutes.
To determine the time it would take Susie to complete the marathon, we can use the formula: Time = Distance / Speed
Given that the distance of the marathon is 26 miles and Susie's steady rate is 8 mph, we can substitute these values into the formula. Time = 26 miles / 8 mph. To calculate the time, we divide 26 miles by 8 mph: Time = 3.25 hours. Since there are 60 minutes in an hour, we can convert the decimal part of the time to minutes: 0.25 hours * 60 minutes/hour = 15 minutes. Therefore, it would take Susie approximately 3 hours and 15 minutes to complete the marathon.
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If the magnetic field in an electromagnetic field is doubled, by what factor does the electric field change?.
If the magnetic field in an electromagnetic field is doubled, the electric field remains unaffected. Therefore, the factor by which the electric field changes is 1, i.e., there is no change in the electric field.
What is an electromagnetic field?An electromagnetic field refers to a combination of an electric field and a magnetic field. It is a field of energy produced by an electric charge in motion. These two fields are perpendicular to each other and exist perpendicular to the direction of the electromagnetic wave.
Magnetic fields can be generated from the presence of an electrical current. Conversely, a magnetic field may induce a current in a conductor if there is a time-varying magnetic flux that traverses a surface. On the other hand, an electric field is created by any charged particle, such as an electron, proton, or even a macroscopic charged object, like a balloon that has been rubbed on someone's hair.
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Josh is playing pool. During his shot, an orange billiard ball with a momentum of 135 g · m/s hits a green billiard ball at rest. After the collision, the orange billiard ball continues in the same direction with a momentum of 60 g · m/s. What is the momentum of the green ball right after the collision?
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision, assuming no external forces are acting on the system.
Let's denote the momentum of the orange ball before the collision as p1, and the momentum of the green ball after the collision as p2.
Given:
Initial momentum of the orange ball (p1) = 135 g · m/s
Final momentum of the orange ball (p1') = 60 g · m/s
Momentum of the green ball after the collision (p2) = ?
Since momentum is a vector quantity, we need to consider both the magnitude and direction. In this case, the orange ball continues in the same direction after the collision, so the magnitude of its momentum decreases from 135 g · m/s to 60 g · m/s.
Using the principle of conservation of momentum:
p1 + 0 = p1' + p2
Substituting the given values:
135 g · m/s + 0 = 60 g · m/s + p2
Simplifying the equation:
p2 = 135 g · m/s - 60 g · m/s
p2 = 75 g · m/s
Now, we need to convert the momentum of the green ball from grams to kilograms:
1 g = 0.001 kg
p2 = 75 g · m/s * 0.001 kg/g
p2 = 0.075 kg · m/s
Therefore, the momentum of the green ball right after the collision is 0.075 kg · m/s.
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Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. What is the approximate vertical component of the initial velocity? 0. 5 m/s 0. 87 m/s 12. 5 m/s 21. 7 m/s.
The approximate vertical component of the initial velocity is 21.7 m/s.
option D.
What is the approximate vertical component of the initial velocity?The approximate vertical component of the initial velocity is calculated by applying the following equation as follows;
Mathematically, the formula vertical component of velocity is given as;
Vy = V sinθ
where;
V is the magnitude of the initial velocityVy is the vertical component of the velocityθ is the direction of the initial velocityThe approximate vertical component of the initial velocity is calculated as;
Vy = 25 m/s x sin (60)
Vy = 21.7 m/s
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A projectile is launched horizontally from a height of 8. 0 m. The projectile travels 6. 5 m before hitting the ground. The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is m/s.
The initial velocity of a projectile launched horizontally can be calculated using the equation of distance covered horizontally (x) = Initial velocity (u) Time of flight (t). The horizontal component of the initial velocity can be determined by x = u t, t = 1.63 s, x = 6.5 mu = x / t = 6.5 m / 1.63 su = 3.99 m/s 4.00 m/s.
The initial velocity of the projectile that was launched horizontally can be calculated using the equation below: Distance covered horizontally (x) = Initial velocity (u) × Time of flight (t) where, Time of flight (t) can be found using the formula below: t = [2 × vertical height (h)] / g where ,g is the acceleration due to gravity = 9.8 m/s².The vertical height (h) of the projectile is 8.0 m. So the time of flight of the projectile will bet = [2 × 8.0 m] / 9.8 m/s²t = 1.63 s Therefore, the horizontal component of the projectile’s initial velocity can be determined by: x = u × tt = 1.63 s, x = 6.5 mu = x / t = 6.5 m / 1.63 su = 3.99 m/s ≈ 4.00 m/s. So, the projectile was launched horizontally with a velocity of 4.00 m/s (rounded to the nearest hundredth).Content loaded: The term “content loaded” is used to indicate that the contents of a webpage or app have finished loading and are ready for viewing or use.
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The international astronomical union has identified 88 what?.
The International Astronomical Union (IAU) has identified 88 constellations.
A constellation is an area of the celestial sphere as defined by the International Astronomical Union (IAU).
There are 88 constellations, each with a particular area and a list of stars associated with it. The majority of constellations are named after ancient Greek and Roman mythological characters, with a few named after animals, scientific instruments, and seasonal objects like planets and the zodiac, as well as a handful named after navigational tools and historical figures. The concept of constellations dates back thousands of years, and their use in astronomy has allowed astronomers to create a map of the sky and chart the motions of celestial objects.
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What is the energy of a photon with a frequency of 1. 7 × 1017 Hz? Planck’s constant is 6. 63 × 10–34 J•s. 1. 1 × 10–17 J 1. 1 × 10–16 J 8. 3 × 10–16 J 8. 3 × 10–15 J.
The energy of the photon is determined as 1.1 x 10⁻¹⁶ J.
What is the energy of the photon?The energy of the photon is calculated by applying the following formula as follows;
E = hf
where;
h is the Planck's constantf is the frequency of the photonThe given parameters include;
frequency of the photon = 1. 7 × 10¹⁷ Hz
Planck’s constant is 6. 63 × 10⁻³⁴ J•s
The energy of the photon is calculated as follows;
E = 6. 63 × 10⁻³⁴ J•s x 1. 7 × 10¹⁷ Hz
E = 1.1 x 10⁻¹⁶ J
Thus, the energy of the photon is determined as 1.1 x 10⁻¹⁶ J.
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3. A grating with 1555 lines/cm is illuminated with light of wavelength 565 nm. What
is the highest-order number that can be observed with this grating? (Hint:
Remember that sin can never be greater than 1 for a diffraction grating. )
important!
The highest-order number that can be observed with this grating using diffraction formula is 1/1555.
It is determined using the formula for diffraction: mλ = d sinθ. Where m is the order number, λ is the wavelength of light, d is the grating spacing, and θ is the angle of diffraction. In this case, the grating has 1555 lines/cm, which means the grating spacing is 1/1555 cm.
To determine the highest-order number, calculate m × (565 × 10^-9 meters) = (1/1555 cm) × sinθ, where θ must be less than or equal to 90 degrees to satisfy sinθ ≤ 1. Given the wavelength of light as 565 nm (or 565 × 10^-9 meters), we can proceed with the calculation. Since sinθ ≤ 1, the highest-order number (m) can be determined by substituting θ = 90 degrees into the equation: m = (1/1555 cm) × sin(90 degrees).
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Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. What is the approximate vertical component of the initial velocity? 0. 5 m/s 0. 87 m/s 12. 5 m/s 21. 7 m/s.
The approximate vertical component of the initial velocity is `21.7 m/s`. The vertical component of an initial velocity in a projectile motion is given by the equation: `Vy = V₀sin(θ)` where `V₀` is the initial velocity of the projectile, `θ` is the angle at which the projectile was thrown and `Vy` is the vertical component of the initial velocity.
The vertical component of an initial velocity in a projectile motion is given by the equation: `
Vy = V₀sin(θ)`
With the given values `V₀ = 25 m/s` and `θ = 60°`,
The vertical component of the initial velocity is:
Vy = V₀sin(θ)
Vy = (25 m/s) sin(60°)
Vy ≈ 21.7 m/s
Therefore, the approximate vertical component of the initial velocity is `21.7 m/s`.
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A web browser is open on yur screen. The lengh of the monitor is x+7. The area of the browser windw is 24 inches. The dimensions of the browser window are x-2 and x. Find the length of the browser window x. Part B. The browser covers 3/13 of the screen. What are the dimensions of the screen
The length of the browser window (x) is 6. The dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
Let's solve the equations step by step:
Part A:
The area of the browser window is given by the equation:
(x - 2) * x = 24
Expanding the equation:
[tex]x^{2}[/tex] - 2x = 24
Rearranging the equation to standard quadratic form:
[tex]x^{2}[/tex] - 2x - 24 = 0
Factoring the quadratic equation:
(x - 6)(x + 4) = 0
Setting each factor to zero:
x - 6 = 0 or x + 4 = 0
Solving for x:
x = 6 or x = -4
Since the length of the monitor cannot be negative, we discard the solution x = -4.
Therefore, the length of the browser window (x) is 6.
Part B:
The dimensions of the screen can be calculated using the length of the monitor (x+7) and the coverage ratio of the browser window (3/13).
The width of the screen is given by:
Width = (3/13) * (x + 7)
The height of the screen is given by:
Height = (3/13) * (x)
Substituting the value of x = 6:
Width = (3/13) * (6 + 7) = (3/13) * 13 = 3
Height = (3/13) * 6 = 18/13
Therefore, the dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
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A bookshelf is at rest in a room. A force of 35. 0 newtons is applied to a bookshelf. If the floor imparts a frictional force of 2. 90 newtons, what is the net force acting on the bookshelf?.
The net force acting on the bookshelf is 32.1 N. It is given that the net force acting on a bookshelf that is at rest in a room when a force of 35.0 N is applied to it and the floor imparts a frictional force of 2.90 N.
The force that is applied to an object minus the frictional force acting on it is called net force. This net force is responsible for causing motion in the object. Therefore, if the object is at rest, the net force is zero. If it is in motion, the net force is nonzero.
The formula for calculating net force is: Net force = Applied force - Frictional force
Given: Applied force = 35.0 N, Frictional force = 2.90 N
We know that, Net force = Applied force - Frictional force
= 35.0 N - 2.90 N
= 32.1 N
Therefore, the net force acting on the bookshelf is 32.1 N.
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A 20. Kilogram rock is lifted 7. 0 meters above the ground. What is the gravitational
potential energy of the rock?
The gravitational potential energy of the rock is 1,372 Joules.
The gravitational potential energy (PE) of an object can be calculated using the formula:
PE = m * g * h, where:
m is the mass of the object,
g is the acceleration due to gravity, and
h is the height or distance above the reference point.
In this case, the mass of the rock (m) is 20 kilograms, and the height (h) is 7.0 meters.
The acceleration due to gravity (g) is approximately 9.8 m/s².
Now we can calculate the gravitational potential energy:
PE = 20 kg * 9.8 m/s² * 7.0 m
PE = 1,372 Joules
Therefore, the gravitational potential energy of the rock is 1,372 Joules.
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A green laser pointer has a wavelength of 532 nanometers. Using the wave equation, what is the frequency of the light from the laser pointer?
1. 77 x 10^5 Hz
1. 88 x 10^14 Hz
5. 64 x 10^14 Hz
1. 60 x 10^4 Hz
(If you want to be in a physics B ig gc please cmmt)
The frequency of the light from the green laser pointer is [tex]5.64 x 10^14 Hz[/tex]. The correct option is C [tex]5.64 x 10^14 Hz[/tex].
The wave equation can be used to calculate the frequency of the light from a green laser pointer with a wavelength of 532 nanometers.
The wave equation is given by the formula: v = λfwhere v is the velocity of the wave, λ is the wavelength of the wave, and f is the frequency of the wave.
Rearranging the formula to solve for frequency: f = v/λwhere f is the frequency of the wave, v is the velocity of the wave, and λ is the wavelength of the wave. Since light travels at a constant speed in a vacuum (c), we can use this value for the velocity: v = c = 3.00 x 10^8 m/s (speed of light in vacuum)
To use this value, we need to convert the wavelength of the laser pointer from nanometers to meters.1 nanometer = 1 x 10^-9 meters532 nanometers = 532 x 10^-9 meters Substituting the values into the formula: f = v/λf = (3.00 x 10^8 m/s)/(532 x 10^-9 m)f = 5.64 x 10^14 Hz.
Therefore, the frequency of the light from the green laser pointer is 5.64 x 10^14 Hz. The correct option is 5.64 x 10^14 Hz.
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A person standing atop a building drops a coin. How fast will the coin be traveling 2 seconds after she drops it? 3 seconds?
The speed of the coin when dropped from the top of a building, using free fall formula after 2 and 3 seconds are, 19.6 m/s and 29.4 m/s.
The speed of an object in free fall can be determined by multiplying the acceleration due to gravity (which is approximately 9.8 m/s²) by the time elapsed. In this case, after 2 seconds, the coin will have fallen a distance of 19.6 meters and will be traveling at 19.6 m/s. Similarly, after 3 seconds, the coin will have fallen a distance of 44.1 meters and will be traveling at 29.4 m/s.
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A boy ties a stone to the end of a string which he then whirls above his head round a circular path of radius 2 metre. If the stone makes 10 oscillations in 4 seconds, calculate the angular and linear speed of the stone.
The angular and linear speed are 5π rads/ seconds and 10π meter/ seconds.
How to calculate the angular and the linear speedIn order to calculate the angular speed of the boy, we will use the equation below.
w =2πn/ T
Where
radius is 2 meter
number of oscillation is 10.
time is 4 s
So, we have
w = 2π * 10/4
w = 5π rads/ seconds.
To calculate the linear speed.
v = r *w
v = 2 * 5π
v = 10π meter/ seconds
Therefore, the angular and linear speed are 5π rads/ seconds and 10π meter/ seconds.
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If the surface of a moon is impacted by meteorites at a constant rate, the density, or quantity per unit of area, of impact craters on the moon’s surface will increase over time. How can this information be used to determine the relative age of a moon’s surface?.
The information about the increasing density of impact craters on a moon's surface over time can be used to determine the relative age of the moon's surface.
This concept is based on the principle of superposition, which states that in undisturbed layers of rock or regolith, the oldest layers are at the bottom, and the youngest layers are at the top. When meteorites impact the surface of the moon, they create craters. Over time, new craters form on top of older craters. Therefore, the density of impact craters on the moon's surface can be an indicator of its relative age. If a specific region of the moon has a high density of impact craters, it suggests that the region is older because it has been exposed to meteorite impacts for a longer time, accumulating more craters. On the other hand, a region with a lower density of impact craters indicates a relatively younger surface with less time for meteorite impacts to accumulate. By comparing the density of impact craters on different regions of the moon's surface, scientists can make relative age determinations. Areas with higher crater density are considered older, while areas with lower crater density are considered younger. It's important to note that this method of age determination assumes a constant rate of meteorite impacts over time and that there have been no major geological events or processes that could have reset or altered the surface. Additionally, the age determination based on crater density is a relative dating technique and does not provide an exact or absolute age for the moon's surface.
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An elastic wire expands by 2cm when load of 40g hangs from it. What additional load will be required to cause a further extension of 4cm
PLEASE ANSWER
Make the same observation of wave speed - the speed of the crest moving from left to right across the screen. Does this ten-fold increase in frequency - from
about 0. 1 Hz to about 10 Hz - have any noticeable and appreciable effect upon the wave speed? Explain
your answer and discuss your observations
While the frequency of a wave does not directly affect its wave speed, it can influence other wave properties.
The frequency of a wave is defined as the number of complete cycles or oscillations it completes in one second. The wave speed, on the other hand, refers to the speed at which the wave propagates through a medium.
In general, the frequency of a wave does not have a direct impact on its wave speed. Wave speed is primarily determined by the properties of the medium through which the wave is traveling, such as its density and elasticity.
Therefore, the ten-fold increase in frequency from about 0.1 Hz to about 10 Hz would not have a noticeable or appreciable effect on the wave speed itself. The wave speed would remain relatively constant unless there are changes in the properties of the medium.
However, it is worth noting that changes in frequency can affect other wave characteristics, such as wavelength and period. The wavelength is the distance between two consecutive crests or troughs of a wave, while the period is the time it takes for one complete cycle of the wave. These quantities are related to frequency through mathematical relationships.
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A small sphere of mass 2. 5 × 10–5 kg carries a total charge of 6. 0 × 10–8 c. The sphere hangs from a silk thread between two large parallel conducting plates. The excess charge on each plate is equal in magnitude, but opposite in sign. If the thread makes an angle of 30° with the positive plate as shown, what is the magnitude of the charge density on each plate?.
The magnitude of the charge density on each plate for the given mass, charge and angle is 1.38 × 10⁻⁴ C/m².
The angle at which the sphere makes with the vertical = 90 – 30 = 60°. Therefore, the force on the sphere is the weight of the sphere – the tension in the thread, Tsinθ which acts towards the negative plate.The force towards the positive plate is qE. Therefore we have,
Tsin60° = mg – qE ...(1)
qE = mg – Tsin60° ...(2)
E is the electric field at a point between the plates.
For the electric field between the plates, we have,d = 4.0 mm = 4.0 × 10⁻³ mV = 500 VQ = 6.0 × 10⁻⁸ C.
Electric field strength = V/d = 500/(4.0 × 10⁻³) = 1.25 × 10⁵ V/m
Charge density = σ
Charge density of the positive plate = charge density of the negative plate= σ
Charge on a sphere is given by q = 4πε₀r²σ
Sphere charge = q = 6.0 × 10⁻⁸ C
Radius of the sphere = r
Mass of the sphere, m = 2.5 × 10⁻⁵ kg
Charge density, σ = q/4πε₀r²
Therefore, σ = 6.0 × 10⁻⁸ / (4π × 8.85 × 10⁻¹² × (6.25 × 10⁻⁶)²)
σ = 1.38 × 10⁻⁴ C/m²
The charge density on the positive plate is the same as that of the negative plate.
Therefore, the magnitude of the charge density on each plate is 1.38 × 10⁻⁴ C/m².
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What is the approximate conduction velocity of motor nerves?.
The approximate conduction velocity of motor nerves is around 50 meters per second (m/s).
Explanation: The rate at which an electrical impulse travels along a nerve fiber is referred to as nerve conduction velocity. The nerve's myelin sheath's thickness and the diameter of the fiber determine this velocity. As a result, motor neurons' myelinated fibers have a quicker conduction velocity than sensory neurons.T
he velocity of nerve impulses is a measure of how quickly an impulse can travel along a nerve fiber's length. When the fiber is stimulated, the impulse travels along the fiber and is transmitted to the next nerve cell in the series, which can also be a muscle or gland cell. Therefore, conduction velocity determines the speed at which a reflex occurs or a muscle contracts.
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A stone is(4i+5j) find the height maximum and the range
The maximum height of the stone is approximately 1.27 meters and the range is approximately 2.04 meters.
To find the maximum height and range of a projectile, we need to consider the motion of the object in the x and y directions.
Given that the initial velocity of the stone is (4i + 5j), we can break it down into its x and y components:
Initial velocity in the x direction (Vx) = 4
Initial velocity in the y direction (Vy) = 5
The maximum height (H) can be determined using the formula:
H = (Vy^2) / (2 * g)
where g is the acceleration due to gravity. Assuming g = 9.8 m/s^2, we can calculate the maximum height:
H = (5^2) / (2 * 9.8)
H = 25 / 19.6
H ≈ 1.27 meters
The range (R) can be calculated using the formula:
R = (Vx * Vy) / g
R = (4 * 5) / 9.8
R = 20 / 9.8
R ≈ 2.04 meters
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PLEASE USE KINEMATIC EQUATION!
You are asked to do an experiment to measure g. You set up a device that drops a metal ball from
rest from a height of 1.650 m. Using an accurate timing device that detects the release of the ball
and its landing on the floor, you measure the average time of the falling ball to be 0.585s.
a. What do you measure the value of g as?
b. Write an explanation as to the error from the accepted value of 10 m/s^2 (or 9.8)
1. The value of g measured from the experiment is approximately 5.646 m/s^2.
How to solve for the experimentTo determine the value of acceleration due to gravity (g) using the given information, we can utilize the kinematic equation for the motion of a falling object:
h = 0.5 * g * t^2
where:
h is the height (1.650 m),
g is the acceleration due to gravity (what we want to find), and
t is the time taken (0.585 s).
a) To find the value of g, we rearrange the equation to solve for g:
g = 2h / t^2
Substituting the given values:
g = 2 * 1.650 m / (0.585 s)^2
g = 5.646 m/s^2
Therefore, the value of g measured from the experiment is approximately 5.646 m/s^2.
2. Air resistance: In real-world scenarios, the presence of air resistance can affect the motion of falling objects. The simplified equation used assumes no air resistance, which may result in a deviation from the accepted value.
Imperfect timing device: The accuracy of the timing device used in the experiment can introduce errors. Even small errors in measuring the time can lead to significant differences in the calculated value of g.
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Triangle FGH with vertices F(6, 6), G(8,8),
and H(8,3);
(a) Reflection: in the line. R = 5
(b) Translation: (x, y) - (x - 7, y-9)
The final image of the original triangle after reflection in the line R=5 and translation by (7,-9) is the triangle F"G"H" with vertices F"(11,-3), G"(9,-1), and H"(9,-12).
(a) Reflection is a transformation in which a shape is mirrored, or flipped over a line called the reflection line. In this problem, the reflection is to take place in the line, R = 5.
This line is vertical; therefore, it passes through points (5,0), (5,1), (5,2), and so on.
The reflection image of point F on the line R=5 is point F', where FF' is perpendicular to line R.
FF' intersects line R at point P, which is equidistant from F and F'.
Hence, the reflection image of F(6,6) on R=5 is F'(4,6).
Similarly, the reflection image of point G(8,8) on line R=5 is G'(2,8), and that of H(8,3) is H'(2,-3).
Therefore, the reflected triangle is F'G'H' with vertices F'(4,6), G'(2,8), and H'(2,-3).
(b) Translation: (x, y) - (x - 7, y-9)
Translation involves moving a shape to a new position without changing its size, shape, or orientation. The new position of each point is obtained by adding the translation vector (7,-9) to the coordinates of the corresponding point. The image of F'(4,6) after the translation is F"(11,-3).
Similarly, G'(2,8) maps to G"(9,-1), and H'(2,-3) maps to H"(9,-12).
The translated triangle is F"G"H" with vertices F"(11,-3), G"(9,-1), and H"(9,-12).
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A stevedore slides a crate along a dock with a 50 kg horizontal force of 175 N. The opposing force of friction is 120 N. If started from rest, what is the crates’s final velocity after 0.5s?
To determine the crate's final velocity after 0.5 seconds, we can use the concept of Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.
In this scenario, the stevedore applies a horizontal force of 175 N to move the crate along the dock. However, there is also an opposing force of friction acting in the opposite direction, which has a magnitude of 120 N. The net force is the difference between these two forces, so we can calculate it as follows:
Net force = Applied force - Frictional force
Net force = 175 N - 120 N
Net force = 55 N
Now, using Newton's second law of motion, we can determine the acceleration of the crate. Rearranging the equation, we have:
Net force = mass * acceleration
55 N = 50 kg * acceleration
Solving for acceleration:
acceleration = 55 N / 50 kg
acceleration = 1.1 m/s²
Since we know the initial velocity of the crate is zero (as it starts from rest), and we want to find the final velocity after 0.5 seconds, we can use the equation of motion:
final velocity = initial velocity + (acceleration * time)
Plugging in the values:
final velocity = 0 + (1.1 m/s² * 0.5 s)
final velocity = 0.55 m/s
Therefore, the crate's final velocity after 0.5 seconds is 0.55 m/s. This means that after being subjected to a 175 N force and experiencing 120 N of friction, the crate gains a velocity of 0.55 m/s in the direction of the applied force.
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A man weighing 70 kg runs alongside railroad tracks with a
velocity of 18 km/h, and jumps into a car of weight 100 kg
standing on the tracks. Calculate the velocity with which the
car and man will start moving.
a 2.06 m/s
b 1.47 m/s
С
2.31 m/s
d 3.02 m/s
The velocity with which the car and man will start moving is d.) 3.02 m/s. Hence, option d) is the correct answer. The formula for the momentum is p= mv.
Initially, the momentum of the man is given by: mv = 70 kg × (18 km/h) × (1 h/3600 s) × (1000 m/1 km)
= 35/18 m/s × 70 kg
= 1225/18 kg m/s
The momentum of the car is given by: p = mv
= 0 kg × v
= 0
Since the total momentum before the man jumps into the car is zero and the total momentum after the man jumps into the car is conserved, the total momentum is given by: mv + mv' = 0
where v' is the velocity of the car and man after they combine. Rearranging the equation above gives: v' = -mv / m' where m is the mass of the man and m' is the combined mass of the car and man: v' = -70 kg × 35/18 m/s / (70 kg + 100 kg)
= -35/26 m/s
≈ -1.35 m/s
Note that the negative sign implies that the velocity of the man is opposite to that of the car. The magnitude of the velocity is obtained by taking the absolute value: v' = 35/26 m/s ≈ 1.35 m/s
Therefore, the velocity with which the car and man will start moving is 3.02 m/s (to two decimal places).
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