Two cubic meters of a gas at 303 K are heated at constant pressure until the volume is doubled. What is the final temperature of the gas?

Answers

Answer 1

Answer:

[tex]V_1 = {2 \: m}^{3} [/tex]

[tex]T_1 = 303 \: k[/tex]

[tex]V_2 = 2(V_1) = 2(2) = 4 \: {m}^{3} [/tex]

[tex]T_2 = ?[/tex]

Here, it's mentioned that the pressure is constant.

By Charles law :

[tex]\implies V \propto T \\ [/tex]

[tex]\implies \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2} \\ [/tex]

[tex]\implies \dfrac{2}{4} = \dfrac{303}{T_2} [/tex]

[tex]\implies \dfrac{T_2}{4} = \dfrac{303}{2} [/tex]

[tex]\implies T_2 = \dfrac{303 \times 4}{2} [/tex]

[tex]\implies T_2 = \dfrac{1212}{2} [/tex]

[tex]\implies T_2 = 606 \: k [/tex]


Related Questions

Can someone please help a struggling physics student?

A Physics student is running an experiment to test the kinematic equations that she learned over the week. She is throwing a ball with an initial velocity of +12.0 m/s in the vertical direction. Assume that the ball is thrown from the ground (i.e., neglect the student's height)

a) What is the maximum height the ball will reach in the air? Express your answer in m

What is the the velocity of the ball when it hits the ground? Express your answer in m/s.

Later that day, the student decided to repeat the experiment. This time, the weather was a little rough outside and there was a strong wind blowing in the horizontal direction (see figure). As a result of the wind, the horizontal component of the ball's velocity is + 2.3 m/s throughout the time it is in air (pointing to the right).

b) Assuming that the student throws the ball with the same initial upwards velocity as in part a), what will be the maximum height that the ball with reach in the presence of wind? Express your answer in m.

What is the magnitude of the velocity of the ball when it hits the ground? Express your answer in m/s

What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).

Answers

Part A:

What is the maximum height the ball will reach in the air?

Kinematics equation used:

[tex]v_f^2=v_i^2+2ad[/tex], where [tex]v_f[/tex] is final velocity, [tex]v_i[/tex] is initial velocity, [tex]a[/tex] is acceleration, and [tex]d[/tex] is distance travelled. From SI units, velocity should be in [tex]m/s[/tex], acceleration should be in [tex]m/s^2[/tex], and distance should be in [tex]m[/tex]

We're given that the initial velocity is 12.0 m/s in the y-direction. At the maximum height, the vertical velocity of the ball will be 0 m/s, otherwise it would not be at maximum height. This is our final velocity.

The only acceleration in the system is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{ m/s^2}[/tex]. However, the acceleration is acting down, whereas the ball is moving up. To express its direction, acceleration should be plugged in as [tex]-9.8\:\mathrm{m/s^2}[/tex]. We have three variables, and we are solving for the fourth, which is distance travelled. This will be the maximum height of the ball.

Substitute [tex]v_i=12[/tex], [tex]v_f=0[/tex], [tex]a=-9.8[/tex] to solve for [tex]d[/tex]:

[tex]0^2=12^2+2(-9.8)(d),\\0=144-19.6d,\\-19.6d=-144,\\d=\frac{-144}{-19.6}=7.34693877551\approx \boxed{7.35\text{ m}}[/tex]

What is the velocity of the ball when it hits the ground?

This question tests a physics concept rather than a physics formula. The vertical velocity of the ball when it hits the ground is equal in magnitude but opposite in direction to the ball's initial vertical velocity. This is because the ball spends equal time travelling to its max height as it does travelling from max height to the ground (ball is accelerating from initial velocity to 0 and then from 0 to some velocity over the same distance and time). Since the ball has an initial vertical velocity of +12.0 m/s, its velocity when it hits the ground will be [tex]\boxed{-12.0\text{ m/s}}[/tex]. (The negative sign represents the direction. Because velocity is a vector, it is required.)

Part B:

**Since my initial answer exceeds the character limit, I've attached the first question to Part B as an image. Please refer to the attached image for the answer and explanation to the first question of Part B. Apologies for the inconvenience.**

What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).

This question uses a similar concept as the second question of Part A. The vertical velocity of the ball at launch is equal in magnitude but opposite in direction to the ball's final velocity. The horizontal component is equal in both magnitude and direction throughout the entire launch, since there are no horizontal forces acting on the system. Therefore, the angle below the horizontal of the ball's velocity when it hits the ground is equal to the angle of the ball to the horizontal at launch.

To find this, we need to use basic trigonometry for a right triangle. In any right triangle, the tangent/tan of an angle is equal to its opposite side divided by its adjacent side.

Let the angle to the horizontal at launch be [tex]\theta[/tex]. The angle's opposite side is represented by the vertical velocity at launch (12.0 m/s) and the angle's adjacent side is represented by the horizontal velocity at launch (2.3 m/s). Therefore, we have the following equation:

[tex]\tan \theta=\frac{12.0\text{m/s}}{2.3\text{ m/s}}[/tex]

Take the inverse tangent of both sides:

[tex]\arctan (\tan \theta)=\arctan (\frac{12.0}{2.3})[/tex]

Simplify using [tex]\arctan(\tan \theta)=\theta \text{ for }\theta \in (-90^{\circ}, 90^{\circ})[/tex]:

[tex]\theta=\arctan(\frac{12.3}{2.3}),\\\theta =79.14989537\approx \boxed{79.15^{\circ}}[/tex]

We can express our answer by saying that the direction of the velocity of the ball when it hits the ground is [tex]\boxed{\text{approximately }79.15^{\circ} \text{ below the horizontal}}[/tex] or [tex]\boxed{\text{approximately }-79.15^{\circ} \text{ to the horizontal}}[/tex].

What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V =
cm?

Answers

Explanation:

Volume of cone = πr² × h/3

Here,

Radius (r) = 13 cmHeight (h) = 27 cm

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ Volume of cone = 4780.28 cm³

Answer:

4,778.4 is correct

Explanation:

định luất bảo toàn động lực chỉ đúng trong trường hợp nào

Answers

Answer:

ᴀꜱ ᴡᴀʀᴍ ᴀꜱ ꜱᴜɴ

ᴀꜱ ꜱɪʟʟʏ ᴀꜱ ꜰᴜɴ

ᴀꜱ ᴄᴏʟᴅ ❄️ ᴀꜱ ᴀ ᴛʀᴇᴇ

ᴀꜱ ꜱᴄᴀʀʏ ᴀꜱ ꜱᴇᴀ

ᴀꜱ ʜᴏᴛ ᴀꜱ ꜰɪʀᴇ

ᴀꜱ ᴄᴏʟᴅ ᴀꜱ ɪᴄᴇ

ꜱᴡᴇᴇᴛ ᴀꜱ ꜱᴜɢᴀʀ

ᴀɴᴅ ᴇᴠᴇʀʏᴛʜɪɴɢ ɴɪᴄᴇ

ᴀꜱ ᴏʟᴅ ᴀꜱ ᴛɪᴍᴇ ⌛

ᴀꜱ ꜱᴛʀᴀɪɢʜᴛ ᴀꜱ ʟɪɴᴇ ➖

ᴀꜱ ʀᴏʏᴀʟ ᴀꜱ ᴀ ᴀɴɢᴇʟ☺️

ᴀꜱ ʙᴜᴢᴢᴇᴅ ᴀꜱ ʙᴇᴇ

ᴀꜱ ꜱᴛᴇᴀʟᴛʜ ᴀꜱ ᴛɪɢᴇʀ

ꜱᴍᴏᴏᴛʜ ᴀꜱ ɢʟɪᴅᴇʀ

ᴘᴜʀᴇ ᴀꜱ ʜᴇᴀʀᴛ ❤️

ᴘᴜʀᴇ ᴀꜱ ɪ ᴡᴀɴɴᴀ ʙᴇ

what will be the magnitude of work if a force of 25N pulls a stone through a distance of 5m in its direction?​

Answers

Explanation:

125 is your answer........

The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N

Answers

Answer:

c

Explanation:

Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iron

Answers

Chlorine is the smallest because up right extreme of the periodic table

the pages of a book are numbered 1 to 300. Each leaf is 0.1 mm thick . If each cover is 0.25 mm thick. what is the thickness of the book​

Answers

Answer:

30.5mm

Explanation:

There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm

Your answer is 30.5mm.

Answer:

15.5mm

Explanation:

there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers

page's thickness is 0.1mm, cover's thickness is 0.25

so books thickness = 150*0.1+0.25*2 = 15.5mm

Give reasons for the following,
a. Pascal is a derived unit.
b. Mass is a fundamental quantity,
c. Unit of power is a derived unit,
d. Unit of length is a fundamental unit. ​

Answers

Answer:

a) Pascal is a derived unit because it is derived from the unit of force and area

b)Mass is a fundamental quantity because it doesn't depends upon others physical quantity and made up of only one unit

c) unit of power is a derived unit because they are dependent quantities

D) unit of length is a fundamental unit because it cannot be expressed in terms of another quantity.

will mark brainliest. The speed of sound is 340 m/s where a tuning fork produces the second resonance position above a closed air column that is 49.8 cm in length. The frequency of the tuning fork is ___ Hz.

Answers

Answer:

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

Explanation:

Given:

Speed of sound = 340 m/s

Length of resonance position above a closed air column = 49.8 cm = 0.498 m

Find:

Frequency of the tuning fork

Computation:

Frequency of the tuning fork[second resonance] = 3v / 4l

Frequency of the tuning fork[second resonance] = 3(340) / 4(0.498)

Frequency of the tuning fork[second resonance] = 512.04

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

Answer:

The frequency is 512 Hz.

Explanation:

speed, v = 340 m/s

length, L = 49.8 cm = 0.498 m

let the frequency is f.

[tex]f =\frac{3 v}{4 L}\\\\f = \frac{3 \times 340 }{4\times 0.498}\\\\f = 512 Hz[/tex]


A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing

Answers

Answer:

Increasing

Explanation:

I Hope it Helps

satellite does not need any energy to revolve around the earth why​

Answers

Answer:

An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.

or maybe god:)))(

sinong personalidad ang bumuo ng pangkat militar na tinawag na black shirts na nagsagawa ng pagpupulong ng mga grupong sosyalista at komunista​

Answers

Answer:

Answer to the following answer is as follows;

Explanation:

In the northwestern city of Milan, Mussolini formed his nationalist regime in 1919. He organised black-shirted street warriors into teams. His "Blackshirts" raped and expelled socialists and communists from municipal administrations.

The Blackshirts, originally known as the Squadrismo, were formed in 1919 by a group of dissatisfied former soldiers.

A basketball is held over head at a height of 2.4 m. The ball is lobbed to a teammate at 8 m/s at an angle of 40'. If the ball is caught at the same height it was tossed at, how far away is the teammate?​

Answers

Explanation:

since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.

We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.

range can be calculated by the formula :-

[tex] \boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }} [/tex]

u is the velocity during its take off and [tex]\theta[/tex] is the angle at which its thrown

Given that

u = 8m/ s [tex]\theta[/tex] = 40°

calculating range using the above formula

[tex] = \frac{ {8}^{2} \sin2(40) }{10} [/tex]

[tex] = \frac{64 \times \sin(80) }{10} [/tex]

value of sin 80 = 0. 985

[tex] = \frac{64 \times 0.985}{10} [/tex]

[tex] = \frac{63.027}{10} [/tex]

[tex] = 6.3027[/tex]

Hence,

[tex] \mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } } [/tex]

C is not less than 0

Answers

Did you mean to put a picture with the question

Calculate the maximum absolute uncertainty for R if:

R = B - A
A = 32 +/- 2 seconds
B = 11 +/- 3 seconds

43 seconds


1 second


21 seconds


5 seconds


6 seconds

Answers

Answer:

 ΔR = 5 s

Explanation:

The absolute uncertainty or error in an expression is

       ΔR = | [tex]\frac{dR}{dB}[/tex] | ΔB + | [tex]\frac{dR}{dA}[/tex] | ΔA

the absolute value guarantees to take the unfavorable case, that is, the maximum error.

We look for the derivatives

       [tex]\frac{dR}{dB}[/tex] = 1

       [tex]\frac{dR}{dA}[/tex] = -1

we substitute

       ΔR = 1 ΔB + 1 ΔA

       

of the data

       ΔB = 3 s

       ΔA = 2 s

         

       ΔR = 3 + 2

       ΔR = 5 s

prepare for the module exam,
Question 1
1 pts
If a 6 ohm wire is connected to a 10 volt battery, what will the current be?
O 6 amperes
O ,67 amperes
O 1.67 amperes
60 amperes

Answers

Answer:

1.67 amperes

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex] V = IR [/tex]  ......equation 1

Where;

V represents voltage measured in voltage.I represents current measured in amperes.R represents resistance measured in ohms.

Making I the subject of formula, we have;

[tex] I = \frac {V}{R} [/tex]  .....equation 2

Given the following data;

Voltage = 10 VoltsResistance = 6 Ohms

To find the current flowing through the battery, we would use eqn 2;

[tex] I = \frac {10}{6} [/tex]  

Current, I = 1.67 amperes

What's a diode..??? How does it act as a rectifier??

Answers

A diode is a semiconductor device that essentially acts as a one-way switch for current. It allows current to flow easily in one direction, but severely restricts current from flowing in the opposite direction.

A rectifier is a device that converts an Alternating Current (AC) into a Direct Current (DC) by using one or more contact diodes. ... In simple words, a diode allows current in just one direction. This unique property of the diode allows it to act sort of a rectifier by converting an alternating current to a DC source

The current in a light bulb is 2 A. How long does it take for a total charge of 4 C to pass a point in the wire

Answers

Answer:

2min

Explanation:

i think it will be clear from photo

Answer: The formula for current is charge/time

so here we have to change subject so we are asked to look for time  

Explanation: so it would be T=Q/I

T=4/2

T=2s

hope this helpss

Una pelota de béisbol de 142g de masa, luego de ser arrojada por el pitcher lleva una velocidad de 90mph. Luego de ser bateada se mueve en sentido contrario a 54 m/s.

a. Calcular el impulso del bate sobre la pelota.
b. Si la pelota permanece en contacto con el bate 0,008 s ¿cuál es el módulo de
la fuerza del golpe?

Answers

Answer:

a)    I = 13.38 kg m / s, b)    F = 1,373 10³ N

Explanation:

The impulse is given by the relation

          I = ∫ F dt = Δp

          I = p_f -p₀

          I = m (v_f - v₀)

take the ball's exit direction as positive, whereby the ball velocities

v₀ = -90mph, the final velocity v_f = + 54 m / s

Let's reduce the units to

         I = 0.142 [54- (-40.23) ]

      the SI system

        v₀ = - 90 mph (1609.34 m / 1 mile) (1h / 3600 s = -40.23 m / s

        m = 142 g (1kg / 1000) = 0.142 kg

we calculate  

          I = 0.142 [54- (-40) ]

          I = 13.38 kg m / s

b) let's use the definition of momentum

         I = ∫ F .dt

         I = F ∫ dt

         F = I / t

         F = 13.38 / 0.008

         F = 1,373 10³ N

I’m steel, the solvent is And the solute is. .

Answers

iron is the solvent and carbon is the solute.

An electron travelling at 7.72 x 107 m/s [E] enters a force field that reduces its velocity to 2.46 x 107 m/s [E]. The acceleration is constant. The displacement during the acceleration is 0.478 m [E]. Determine (a) the electron’s acceleration (b) the time interval over which the acceleration occurs.

Answers

Answer:

Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].

Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].

Explanation:

Let [tex]u[/tex] denote the velocity of this electron before the change.Let [tex]v[/tex] denote the velocity of this electron after the change.Let [tex]x[/tex] denote the displacement.Let [tex]a[/tex] denote the acceleration.Let [tex]t[/tex] denote the time taken.

Apply the SUVAT equation that does not involve time:

[tex]v^{2} - u^{2} = 2\, a \, x[/tex].

Equivalently:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].

By this equation, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].

The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:

[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].

An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image ,its nature and size?​

Answers

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

[tex]\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm[/tex]

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

[tex]\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm[/tex]

4. A body in motion is said to be in equilibrium when it is
A moving with uniform velocity.
B at rest.
C accelerated by a force.
D moving in an indefinite path.​

Answers

Answer:

A. moving with uniform velocity.

Explanation:

Was this hepfull

Answer:

A

Explanation:

Equilibrium is a state in which opposing forces or influences are balanced hence A being correct

Drag each label to the correct location on the image. Identify the particles and characteristics on this model of an atom.
Positively charged
Electron
Proton
Neutron
Negatively charged

Answers

Answer:

cant see picture

Explanation:

Answer:

please add picture so i can help you

Explanation:

Why are simple everyday actions considered
thermodynamic reactions?

they transform energy

they destroy energy

they create energy

Answers

they create energy ……………….

Answer:

They transform energy

Explanation:

thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy

the resultant capacitance of four capacitorconnected in series is --------the smalest individual capacitance

Answers

Answer:

This question is misleading since

1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4

so it would have to be less than the smallest individual capacitance

Example to measure the interval of time of a small stone dropped from 1m height.

Answers

Answer:

The time required is 0.45 s.

Explanation:

Height, h = 1 m

initial velocity, u = m/s

Let the time is t.

Use second equation of motion

[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]

Convert 60 km/ hr into m/s

Answers

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second


State two sources of EMF cell other than the chemical cell
Answers​

Answers

Explanation:

A photodiode or solar cell may be considered as a source of emf, similar to a battery, resulting in an electrical voltage generated by charge separation driven by light rather than chemical reaction. Other devices that produce emf are fuel cells, thermocouples, and thermopiles.

What does the m stand for in the enthalpy equation?

Answers

Answer:

Use the formula ∆H = m x s x ∆T to solve.

Explanation:

Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.

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