Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length of N K is 6. Law of cosines: a2 = b2 + c2 – 2bccos(A) What is the value of n to the nearest whole number? 10 13 18 21

Answer: x = 3

Step-by-step explanation:

Sqrt(x+7) - 1  = x

Sqrt(x+7) = x + 1

x+7 = x^2 + 1

x = x^2 - 6

x=3

Answer:

Base area is 36 square meters

Step-by-step explanation:

The volume of a rectangular prism is V = (height)(length)(width).  We know all of these dimensions except for the area of the base, which is (length)(width).

Solving this equation for (length)(width), we get:

                                                       volume        72 m^3

(length)(width) = (area of base) = -------------- = -------------  = 36 m^2

                                                         height          2 m

Answer:

For "Negative 23 greater-than x" , highlight the left half of the number line starting at -23 and use a parenthesis ) on -23.

For "x greater-than-or-equal-to negative 23", highlight the right half of the number line starting at -23, and use a square bracket [ on -23.

Step-by-step explanation:

Start by locating the number -23 on the number line. Please see attached image to accompany the explanation.

In the first case:  "Negative 23 greater-than x" , which is expressed mathematically as:

[tex]-23 >x[/tex]

notice that "x" has to be strictly smaller than the number -23, therefore those sought x values must reside to the left of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself shouldn't be considered as part of the set, that symbol is by convention a parenthesis ).

In the second case: "x greater-than-or-equal-to negative 23", which is expressed mathematically as:

[tex]x\geq -23[/tex]

notice that "x" has to be greater than or equal to the number -23, therefore those sought x values must reside to the right of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself should be considered as part of the set, that symbol is by convention a square bracket [.

Answer:

the answer is A

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

j(x) = 4/5(-5) + 7

= -4 + 7

= 3

Answer:

15

Step-by-step explanation: -4/5 x has to be -12 because -12+7 equals 5. Since we want to figure out x, we have to flip -4/5 x to 4/5x which would change the -12 to 12. What is a fourth of 12? It is three. 12+3 equals 15. This is the first right answer on all of the internet for this question!

Answer:

6 pepper fruits

Step-by-step explanation:

Given the following :

Fraction of pepper in terms of tomato = 2/3

Number of fruits on pepper plant = 9

Therefore number of pepper fruits on pepper plant:

2/3 * number of tomato fruits

2/3 * 9

(2 * 3) = 6

6 pepper fruits.

Write it out as an equation:

(48 /(5+(11-8))) -7

Simplify:

(48/(5+3))-7

(48/8)-7

6-7 = -1

The answer is -1

Answer:

c

Step-by-step explanation:

i did the quiz

Answer:

8(a + b)

Step-by-step explanation:

Sun of a and b = a + b

8 times of (a + b) = 8(a + b)

Answer:

the answer is ; Never

Hope this answer correct :)

Answer:

the answer is never

Step-by-step explanation:

Answer:

f(x) = 5 * ( 8/5) ^x

Step-by-step explanation:

f(x) = a b^x

Let x = 0

5 = a * b^0

5 = a*1

a = 5

Let x = 1

8 = 5 * b^1

Divide each side by 5

8/5 = b

f(x) = 5 * ( 8/5) ^x

Answer:

5x(25)

Step-by-step explanation:

Answer: 15

Step-by-step explanation:

General terms in AP

f, f+d, f+2d, f+3d, ....  , where f= first term and d= common difference.

The given A.P. : 18, a, b, - 3

here, f= 18    

[tex]f+d= a ...(i)\\\\f+2d = b ...(ii)\\\\f+3d= -3 ...(iii)\\\\[/tex]

Put f= 18 in (iii) ,

[tex]18+3d=-3\\\\\Rightarrow\ 3d= -3-18\\\\\Rightarrow\ 3d= -21\\\\\Rightarrow\ d=-7[/tex]

Put f= 18 and d= -7 in (i) and (ii) , we get

[tex]a=18+(-7)=11\\\\b=18+2(-7)\\\\\Rightarrow\ b=18-14\\\\\Rightarrow\ b=4[/tex]

Now, [tex]a+b= 11+4=15[/tex]

Hence, the correct answer is "15".

Answer:

C. [tex]x[/tex] and $(x-6)$

Step-by-step explanation:

The roots of the quadratic equation are $0$ and $6$.

Hence the equation is $(x-0)(x-6)=x(x-6)$

Answer:

See below

Step-by-step explanation:

Answer:

3053.5517 cm^3 ; 1/8

Step-by-step explanation:

Given the following :

Volume (V) of sphere = (4/3)πr^3 where r = radius

Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm

V = (4/3) × π × 9^3

V = 1.3333 × π × 729

V = 3053.5517 cm^3

When diameter(d) is reduced to half

d = d/2

Volume (V1) of sphere with diameter 'd' =

V1 = (4/3)π(d/2)^3

Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4

V2 = (4/3)π(d/4)^3

V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]

V1 / V2 = (d/2)^3 / (d/4)^3

V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]

V1 / V2 = 8 / 64

V1 / V2 = 1 / 8

Answer:

first blank is 972

second blank is 1/8

yup

Step-by-step explanation:

Answer:

the other factor is (x+7)

Step-by-step explanation:

Given x^2+11x+28

factor into

x^2+7x + 4x + 28

=x(x+7) + 4(x+7)

= (x+4)(x+7)

Answer: the other factor is (x+7)

Answer:

5(12 : 3) -8

Step-by-step explanation

when you solve the first half of the equation you get 1.

so 9-1 is 8.

Answer:

The total amount left by Manavi and Kuber is: (1) 399

Step-by-step explanation:

Manavi

saving account +  amount spent at the mall:  1/'2 + 1/4 =  3/4

left over: 1 - 3/4 = 4-3/4 = 1/4

1260 ( 1/4) = 315

The total leftover for Manavi is Rs.315.

Now do the same steps with Kuber.

Kuber

saving account +  amount spent at the mall: 1/3+ 3/5 = 14/15

left over: 1- 14/15 = 15-14/15 = 1/15

1260 (1/15) = 84

The total leftover for Kuber is Rs.84.

Lastly, just add both left over amount together.

315+84 = 399

The total amount left by Manavi and Kuber is: (1) 399

Answer:

[tex]\huge\boxed{f = 5\ Hz}[/tex]

Step-by-step explanation:

Given:

Time period = T = 0.2 sec

Required:

Frequency = f = ?

Formula:

f = 1/T

Solution:

f = 1/0.2

f = 5 Hertz

Answer:

[tex] \boxed{\sf Frequency \ (f) \ of \ the \ wave = 5 \ Hz} [/tex]

Given:

Time Period (T) = 0.2 s

To Find:

Frequency (f) of the wave

Step-by-step explanation:

[tex] \sf Frequency (f) = \frac{1}{Time Period (T)} [/tex]

[tex] \sf f = \frac{1}{0.2} [/tex]

[tex] \sf f = \frac{1}{0.2} \times \frac{10}{10} [/tex]

[tex] \sf f = \frac{10}{2} [/tex]

[tex] \sf f = \frac{ \cancel{2} \times 5}{ \cancel{2}} [/tex]

[tex] \sf f = 5 \: Hz[/tex]

Answer:

n = 5

Step-by-step explanation:

To start off, we know that whenever the bases are the same, their exponents are equal to each other. Therefore, since both of the numbers bases are the same (both are z), we know that they will be equal.

The n can be distributed to the [tex]z^2[/tex] so that it now reads to be:

[tex]z^2^n = z^{10}[/tex]

Exponents are equal, so:

2n=10

Divide the 2 on both sides:

n=5

Answer:

n =5

Step-by-step explanation:

z^2^n

We know that a^b^c = a^ (b*c)

z^(2n)

This is equal to z^10

Since the bases are the same, the exponents are the same

2n = 10

Divide by 2

2n/2 = 10/2

n = 5

Answer:

The function is not one-to-one

Step-by-step explanation:

This is a quadratic function.

[tex]f(x)=x^2-2[/tex]

A function is one-to-one

[tex]\text{if } f(x_1)=f(x_2) \Leftrightarrow x_1=x_2[/tex]

The function given is not one-to-one because there are values of the input [tex]x[/tex], which leads to the same output.

For example.

[tex]y=f(2)=2^2-2=\boxed{2}[/tex]

[tex]y=f(-2)=(-2)^2-2=\boxed{2}[/tex]

Answer:

Below

Step-by-step explanation:

All figures are squares. The area of a square is the side times itself

Let A be the area of the big square and A' the area of the small one in all the 5 exercices

51)

● (a) = A - A'

A = c^2 and A' = d^2

● (a) = c^2 - d^2

We can express this expression as a product.

● (b) = (c-d) (c+d)

■■■■■■■■■■■■■■■■■■■■■■■■■■

52)

● (a) = A-A'

A = (2x)^2 = 4x^2 and A'= y^2

● (a) = 4x^2 - y^2

● (b) = (2x-y) ( 2x+y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

53)

● (a) = A-A'

A = x^2 and A' = y^2

● (a) = x^2-y^2

● (b) = (x+y) (x-y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

54)

● (a) = A-A'

A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2

● (a) = 25a^2 - 4b^2

● (a) = (5a-2b) (5a+2b)

■■■■■■■■■■■■■■■■■■■■■■■■■■

55)

● (a) = A - 4A'

A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2

● (a) = 9x^2 - 4 × 4y^2

● (a) = 9x^2 - 16y^2

● (a) = (3x - 4y) (3x + 4y)

Answer:

n = 24

Step-by-step explanation:

Given the fraction:

[tex]$\frac{n}{n+101}$[/tex]

To find:

Smallest positive integer [tex]$n$[/tex] such that the fraction is equal to a terminating decimal.

Solution:

The rule that a fraction is equal to a terminating decimal states that, the denominator must contain factors of only 2 and 5.

i.e. Denominator must look like [tex]2^m\times 5^n[/tex], only then the fraction will be equal to a terminating decimal.

Now, let us have a look at the denominator, [tex]n+101[/tex]

Let us use hit and trial method to find the value of [tex]n[/tex] as positive integer.

n = 1, denominator becomes 102 = [tex]2 \times 3 \times 17[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 4, denominator becomes 105 = [tex]5 \times 3 \times 7[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 9, denominator becomes 110 = [tex]2 \times 5 \times 11[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 14, denominator becomes 115 = [tex]5 \times 23[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 19, denominator becomes 120 = [tex]5 \times 3 \times 2^3[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 24, denominator becomes 125 = [tex]2^0 \times 5 ^3[/tex] It is of the form [tex]2^m\times 5^n[/tex].

So, the answer is n = 24

Answer:

fifth option

Step-by-step explanation:

Given

- 2(x - 5) ≤ 6x + 18 ← distribute left side

- 2x + 10 ≤ 6x + 18 ( subtract 6x from both sides )

- 8x + 10 ≤ 18 ( subtract 10 from both sides )

- 8x ≤ 8

Divide both sides by - 8, reversing the sign as a result of dividing by a negative quantity, thus

x ≥ - 1

Answer:

Step-by-step explanation:

Adding both equations

4x+5y+5y-4x=19+38

10y = 57

y= 5.7

Subtracting equation i from ii

5y-4x-4x-5y=38-19

-8x=9

x= -0.9

Answer:

The correct option is;

B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t

Step-by-step explanation:

The given parameters are;

The number of T-shirts, t, and shorts, s, Tim must design a day = 12

The maximum number of T-shirts and shorts Tim can design a day = 30

The maximum number of hours Tim can work = 18 hours

Therefore, we have;

The number of shorts Tim designs in a day is ≥ The minimum number of T-shirts and shorts Tim must design a day less the number of T-shirts Tim designs

Which gives;

s ≥ 12 - t

Also the number of shorts Tim designs in a day is ≤ The maximum number of T-shirts, and shorts, Tim can design a day less the number of T-shirts Tim designs

Which gives;

s ≤ 30 - t

The number of 45 minute period for the design of shorts in 18 hours = 18×60/45 = 24

The fraction of 36 minutes in 45 minutes = 36/45 = 0.667

Therefore we have;

The number of shorts Tim designs in a day is ≤ The number of 45 minute periods in 18 hours less the number of 36 minutes periods used to design T-shirts

Which gives;

s ≤ 24 - 0.66·t

The correct option is s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t.

Answer:

B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0

Step-by-step explanation:

Hope this helps!!

Answer:  D. (-2, -1)

Step-by-step explanation:

Here we do two reflections to the point (-1, 2).

First, we do a reflection over the line x = y.  Remember that a reflection over a line keeps constant the distance between our point and the given line, so we have that for a pint (x, y), the reflection over the line y = x is:

Ry=x (x, y) = (y, x)

so for our point, we have:

Ry=x (-1, 2) = (2, -1)

Now we do a reflection over the y-axis, again, a reflection over a line keeps constant the distance between our point and the given line, so if we have a point (x,y) and we do a reflection over the y-axis, our new point will be:

Ry-axis (x,y) = (-x, y)

Then in our case:

Ry-axis (2, -1) = (-2, -1)

The correct option is D.

Answer:

[tex] \boxed{13}[/tex]

Step-by-step explanation:

Arranging the data in ascending order:

8 , 8 , 10 , 11 , 13 , 13 ,13 , 14 , 14 , 15 , 16 , 17 , 18 , 18 ,

In the case of discrete data, mode can be found just by inspection, i.e just by taking an item with highest frequency.

Here, 13 has the highest frequency

So, Mode = 13

Extra information

Mode

The mode of a set of data is the value with the highest frequency. A distribution that has two modes is called bimodal. The mode of a set of data is denoted by Mo.

Hope I helped!

Best regards!

Answer:

≈ 36.1%

Step-by-step explanation:

In any circle the following ratio is equal

[tex]\frac{arc}{circmference}[/tex] = [tex]\frac{centralangle}{360}[/tex] = [tex]\frac{130}{360}[/tex] , thus

percentage = [tex]\frac{130}{360}[/tex] × 100% ≈ 36.1%

an arc measuring 130° is approximately 36.11% of the circumference of the circle.

To find the percentage of the circumference that an arc measuring 130° represents, we need to calculate the ratio of the arc length to the circumference of the circle and then convert it to a percentage.

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle.

Let's assume the radius of the circle is r.

The circumference of the circle is C = 2πr.

To find the length of the arc corresponding to 130°, we need to calculate the fraction of the total angle (360°) that 130° represents:

Fraction of the angle = (130° / 360°) = (13/36).

Since the fraction of the angle is equal to the fraction of the arc length to the circumference, the length of the arc can be calculated as:

Arc length = Fraction of the angle * Circumference = (13/36) * (2πr).

Now, to find the percentage of the circumference that the arc length represents, we divide the arc length by the circumference and multiply by 100:

Percentage = (Arc length / Circumference) * 100

Percentage = [(13/36) * (2πr)] / (2πr) * 100

Percentage = (13/36) * 100

Percentage = 36.11%

Therefore, an arc measuring 130° is approximately 36.11% of the circumference of the circle.

Learn more about arc length here

https://brainly.com/question/10266974

#SPJ2

Answer:

  842, 743, 394, 305, 836

Step-by-step explanation:

We arbitrarily chose the ones digit to start with as 2. (It must be 5 or less.) The other two digits are chosen by a random number generator, as shown in the attached.

The 5 three-digit numbers we chose are ...

  842, 743, 394, 305, 836

Answer:

The only criteria the question gives are that there must be 5 numbers, and the numbers must have 3 digits. The ones digit in the numbers should go up by 1.

So, we can have 111, 112, 113, 114, and 115.

Hope this helps!

Answer:

(- 1/2,5/3)

Step-by-step explanation: