Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $1.25 for a delivery made within 1 1/2 mi, $1.70 for a delivery of at least 1 1/2 mi but less than 1 3/4 mi, $2.15 for a delivery of at least 1 3/4 mi but less than 2 miles, and so on. If tim raised his rates by 10% what would he be paid to deliver a package 3 1/8 miles

Answers

Answer 1

Answer:

$4.84

Step-by-step explanation:

Given that

For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25

For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70

For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60

For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05

For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50

For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40

So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.

So actual charges after increase of 10%

[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]


Related Questions

An octagonal pyramid ... how many faces are there, how many vertices and how many edges? A triangular prism ... how many faces are there, how many vertices and how many edges? a triangular pyramid ... how many faces are there, how many vertices and how many edges?

Answers

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Wait times at a dentist's office are typically 21 minutes, with a standard deviation of 2 minutes. What percentage of people should be seen by the doctor between 17 and 25 minutes for this to be considered a normal distribution?

Answers

ANSWER: 95%

HOW:
95% of a group of data with a normal distribution is between two standard deviations to the right and left

Answer:

95%

Step by step explanation:

z = 17-21 / 2 and z = 25-21/2

z=-2 (2.28%) z=2 (97.72%)

97.72 - 2.28 = 5.44

100% - 5.44% is about equal to 95%

Which data set matches the box-and-whisker plot?
A) 12 13 15 19 23 23 25 26.5 28 30
B) 15 13 19 21 23 24 27 29 32
C) 11 31 13 15 19 21 21 25 27 29 31
D) 11 13 15 19 23 23 24 26.5 28 33​

Answers

Answer:

D) 11 13 15 19 23 23 24 26.5 28 33​

Step-by-step explanation:

The box-and-whisker plot displayed above has the following key values that we can use to identify which of the given data set it matches. It has:

Minimum value = 11

Q1 = 15

Median = 23

Q3 = 26

Maximum value = 33

From the options given, using just the max and min value, we can conclude that the data set in option D matches the box plot.

The data set in option D has a minimum value of 11, and a maximum value of 33.

For each of the following paralellogram calculate the unknown angles marked. x, y and z

Answers

Answer:

x = 50°, y = z = 40°

Step-by-step explanation:

x = 50° ( Alternate angle )

z = 180° - (110 + 30)° = 180° - 140° = 40° ( sum of angles in Δ )

y = z = 40° ( Alternate angles )

-7p+2(5p-8)=6(p+6)-7

Answers

Answer:

-15

Step-by-step explanation:

-7p+10p-16=6p+36-7

3p-16=6p+29

3p-6p=29+16

-3p=45

p=45/-3

p=-15

P=5

-7p+2(5p-8)=6(p+6)-7
Distribute
-7p+10p-16=6p+36-7
Add -7p and 10p together
3p-16=6p+36-7
Subtract 7 from 36
3p-16=6p+29
+6p (on both sides)
9p-16=29
+16 (on both sides)
9p=45
Divide both sides by 9
P=5

Henry gathered data about the types of nuts in five handfuls of mixed nuts. The data he gathered is shown in the table. Select the points that represent this data.

Answers

Answer:

Look below.

Step-by-step explanation:

The location of the coordinate plane will be shown in the graph.

What is coordinate geometry?

Coordinate geometry is the study of geometry using the points in space.

Henry gathered data about the types of nuts in five handfuls of mixed nuts.

The data he gathered is shown in the table.

Handful     Number of peanuts       Number of other nuts

  A                           9                                        7

  B                           6                                        5

  C                           8                                        9

  D                           5                                        7

  E                            7                                        4

The graph is shown below.

More about the coordinate geometry link is given below.

https://brainly.com/question/1601567

#SPJ2

What is the y−intercept of the line that passes through the point (4,9)and is parallel to the line y=12x+2?

Answers

Answer:

y- intercept = - 39

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 12x + 2 ← is in slope- intercept form

with slope m = 12

Parallel lines have equal slopes, thus

y = mx + c ← is the partial equation

To find c substitute (4, 9) into the partial equation

9 = 48 + c ⇒ c = 9 - 48 = - 39 ← y- intercept

Answer:

y-intercept = -39

Step-by-step explanation:

if two lines are parallel it means they have the same gradient so we compare the equation given to the default equation of a line

y=mx+c

y=12x+2

comparing we have the gradient m=12 now finding the equation of the line parallel to the given line we use

y-y1=m(x-x1)

y1=9 and x1=4

y-9=12(x-4)

y-9=12x-48

y=2x-48+9

y=2x-39

comparing to the default equation of a line y=mx+c where c is the y-intercept

therefore the y-intercept is -39

We want to build a swimming pool that is 2m by 6m. On our page it measured out to be 8cm by 24cm. What is tge scale that can be used

Answers

Answer:

1:25

Step-by-step explanation:

Given

Dimensions of swimming pool:

W = 2 mL = 6 m

Dimensions on paper:

w = 8 cml = 24 cm

Scale is the ratio of same measurements:

w/W = 8 cm/2 m = 8 cm / 200 cm = 1/25

So the scale is 1:25

Please answer quickly!

Answers

Answer:

T'(-1, -3)

U'(-8, -3)

V'(-9, -10)

W(1, -10)

Step-by-step explanation:

For each point, draw a segment from it to the line y = -x and perpendicular to the line, and extend it the same distance to the other side of the line.

T'(-1, -3)

U'(-8, -3)

V'(-9, -10)

W(1, -10)

Helppp meeeew pleaseeeee

Answers

Answer:

Hey there!

1 1/10=1.1

2/25=0.08

Each serving requires 0.08 kg, and he has 1.1 kg.

Thus, he can make 1.1/0.08, or 13.75 servings.

Let me know if this helps :)

Answer:

13 servings of tofu dish.

Step-by-step explanation:

First, convert the fractions to decimal numbers:

1 1/10 kg = 0.1 kg

2/25 kg = 0.08 kg

Now find how many servings of tofu dish will cover 0.1 kg of tofu:

2/25 kg = 1 serving

1 1/10 kg = ?

= 1 1/10 ÷ 2/25 kg

= 11/10 × 25/2

= 55/4

= 13.75 servings

Approximate it to a whole number:

13 servings.

Could anyone help me with number 25 THANK YOU!!!

Answers

Answer:

ΔABC ~ ΔQPR by the Angle-Angle (AA) similarity theorem of two triangles

Step-by-step explanation:

The coordinates of the vertices are given as follows;

A = (1, 2), B =(9, 8), C = (1, 8)

P= (5, -3), Q = (-7, 6), R = (-7, -3)

The given dimensions of AB and PQ are 10, and 15 respectively

The, l lengths of the sides of triangles are found as follows;

[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

For segment BC, we have;

B =(9, 8), C = (1, 8)

(x₁, y₁) = (9, 8), (x₂, y₂) = (1, 8), substituting gives;

Length BC = 8

For length CA, C = (1, 8) A = (1, 2)

(x₁, y₁) = (1, 8)

(x₂, y₂) = (1, 2)

The length found by substituting the values for (x₁, y₁), (x₂, y₂) in the length equation gives; Length CA = 6

Given that length  CA² + BC² = 8² + 6² = 64 + 36 = 100 = BA², we have by Pythagoras theorem, we have ΔABC is a right triangle

Similarly, for ΔQPR, we have;

Length QR, Q = (-7, 6), R = (-7, -3) = 9

Length PR, P= (5, -3), R = (-7, -3) = 12

QR² + PR² = 9² + 12² = 225 = 15² = PQ²

∴ ΔQPR is a right triangle

By comparing the ratio of the sides, we have;

cos(θ) = PR/PQ = 12/15 = 4/5, θ = cos⁻¹(4/5) = 36.9°

∠RPQ = 36.9°

sin(θ) = QR/PQ = 9/15 = 3/5

Similarly in triangle ΔABC, we have;

cos(θ) = BC/AB = 8/10 = 4/5

∠CBA = 36.9°

Therefore, ∠CBA ≅ ∠RPQ = 36.9°

Also ∠PRQ ≅ ∠BCA = 90° (Angle opposite hypotenuse side of right triangle

Therefore, ΔABC and ΔQPR are similar triangles by the Angle-Angle (AA) similarity theorem of two triangles.

When dividing polynomials using factorization, canceling identical factors in the denominator and the numerator will give the _______.

Answers

Answer:

quotient

Step-by-step explanation:

Answer:

quotient

Step-by-step explanation:

Cancelling identical factors in the numerator and the denominator will give the quotient. For example,x2+5x+6x+3=(x+2)(x+3)x+3 = x + 3

 

Which expressions are equivalent to 2(b+3c)2(b+3c)2, left parenthesis, b, plus, 3, c, right parenthesis ?

Choose all answers that apply:

Choose all answers that apply:


(Choice A)

A

3(b+2c)3(b+2c)3, left parenthesis, b, plus, 2, c, right parenthesis


(Choice B)

B

(b+3c)+(b+3c)(b+3c)+(b+3c)left parenthesis, b, plus, 3, c, right parenthesis, plus, left parenthesis, b, plus, 3, c, right parenthesis


(Choice C)

C

2(b)+2(3c)2(b)+2(3c)2,

Answers

Answer:

B. (b+3c)+(b+3c) C. 2(b)+2(3c)

Step-by-step explanation:

Given this expression 2(b+3c), its equivalent expression is derived by simply opening up the bracket as shown below;

Open the parenthesis by multiplying the constant outside the bracket with all the variables in parenthesis.

= 2(b+3c)

=  2(b)+ 2(3c)

= 2b +2*3*c

= 2b +6c

It can also be written as sum of b+3c in 2 places i.e (b+3c)+(b+3c) because multiplying the function b+3c by 2 means we are to add the function by itself in two places.

Hence the equivalent expression are (b+3c)+(b+3c) and 2(b)+2(3c) or 2b+6c

Which of the following symbols could correctly finish the statement. Select all that apply. 0___-8 = ≠ > < ≥ ≤

Answers

Answer:

>

Step-by-step explanation:

Even though its 0 its still greater than any negative number.

Answer:

Step-by-step explanation:

Please answer this question now

Answers

Answer:

30.9 cm²

Step-by-step explanation:

To find the surface area of this figure, we find the area of the base and the 3 identical sides.

The base is split into two identical right triangles. Let's find the area of one and multiply by two.

Half of 3: 1.5

[tex]1.5\cdot2.6=3.9\\3.9\div2=1.95[/tex]

There are two right triangles:

[tex]1.95\cdot2=3.9[/tex]

The area of one of the sides will be the same thing, except the height is 6.

[tex]1.5\cdot6=9\\9\div2=4.5\\4.5\cdot2=9[/tex]

There are 3 sides identical to this one:

[tex]9\cdot3=27[/tex].

Add 27 and 3.9:

[tex]27+3.9=30.9[/tex]

Hope this helped!

Answer:

30.9 square centimeters

Step-by-step explanation:

3 * 1/2(3)(6) + 1/2(3)(2.6) = 30.9

a second degree equation in one variable example how many solutions does it have ?a second degree equation in one variable example how many solutions does it have ? is it possible to have many solutions or no solutions tions give an example for each

Answers

Answer:

  0, 1, or 2 real solutions

Step-by-step explanation:

Including complex and repeated solutions, a polynomial with real coefficients, and of degree n, always has n solutions.

If you're only concerned about real solutions, a 2nd degree equation in one variable may have 0, 1, or 2 real solutions. Here are some examples.

0 solutions: x^2 +1 = 01 solution: x^2 = 02 solutions: x^2 -1 = 0

. Use the quadratic formula to solve each quadratic real equation. Round
your answers to two decimal places. If there is no real solution, say so.
a) x^2 - 5x + 11 = 0
b) -2x^2 - 7x + 15 = 0
c) 4x^2 - 44x + 121 = 0​

Answers

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex], with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}[/tex]

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}[/tex]

[tex]\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5[/tex]

So B has two solutions of 5 and -1.5.

Now to C!

[tex]\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}[/tex]

[tex]\frac{44}{8} = 5.5[/tex]

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

I am on a farm with pigs and horses. The ratio of pigs to horses is 4:1. The ratio of adult pigs to piglets is 1:5. The ratio of adult horse to foal is 3:1. What fraction of the farm are babies (foals and piglets)?

Answers

Answer:

EAT THIS ANDAD Which polynomial has (3x + 2) as a binomial factor?

6x3 + 3x2 + 4x + 2

12x2 + 15x + 8x + 10

18x3 – 12x2 + 9x – 6

21x4 + 7x3 + 6x + 2

Step-by-step explanation:

1. The cost of buying some books is partly constant and partly varies with the number of books bought. The cost is #4800 when 20 books are bought and #8000 when 40 are bought. Find the cost when 1000 books are bought

Answers

Answer:

Step-by-step explanation:

let the cost based on number of book bought be x and the constant be c:

4800 = 20x + c

8000 = 40x + c

c is common in both equations:

c =4800-20x

c = 8000-40x

equate the two:

4800-20x = 8000 - 40x

20x = 3200

x = 160

and c = 4800-20*160

c = 1600

Cost of 1000 books:

160*1000 + 1600

= 161600

Carey earns $9.75 working part time on weekends. The table below shows the amount, a, Carey earns for working h hours. Carey’s Earnings h 0 1 3 a $0 $9.75 ? Which value completes the table to show the amount Carey earns for working 3 hours?

Answers

Answer:

$29.25

Step-by-step explanation:

For every 1 hour, Carey earns $9.75.  Multiply $9.75 by 3 to find out how much she earns for 3 hours of work.

$9.75 × 3 = $29.25

Carey earns $29.25 for working 3 hours.

Answer:

29.25

Step-by-step explanation:

I got it right on edge!! trust me

**Yoxelt buys 4 1/2 gallons of soda. One-fourth of the soda he bought was Pepsi and the rest was Sprite. How many gallons of Pepsi did Yoxelt buy? Show all work below.

Answers

Answer:

  1 1/8

Step-by-step explanation:

1/4 of the 4 1/2 gallons were Pepsi, so the amount is ...

  (1/4)(9/2) = (1·9)/(4·2) = 9/8 = 1 1/8

Yoxelt bought 1 1/8 gallons of Pepsi.

The dosage for a certain drug calls for 20mg per kg per day and is divided into two doses(1every 12 hours) if a person weighs 197 pounds how much of the drug should be given each dose

Answers

Answer:

893.42

Step-by-step explanation:

1kg=2.205pounds

so 20mg is for 2.205pounds

therefore for 197pounds will be 1784.84mg

but the dose is once every 12hrs meaning twice a day so divide 1784.84/2 to get the pounds

Is the product of two irrational numbers always an irrational​ number?

Answers

Answer:

Step-by-step explanation:

Not always.

√3 * √27 = √81 = 9

What is this used for and how do i use it..?

Answers

you have to solve each one to get your answer and I think that your answer will be inside the circle

Answer:

This is called the Unit Circle. It is used in trigonometry. It had a radius of 1.

It helps you when using the trig function of sin cos and tan.

Hope this helps!!!!

Step-by-step explanation:

+
If the
sides of a triangles are
6, 8 and n. how
many integer values of n
could be the
measure of the
third side of the triangle?

Answers

Answer:

11

Step-by-step explanation:

The sum of the shortest two sides must be greater than the longest side.

If n is the longest side:

6 + 8 > n

14 > n

If 8 is the longest side:

6 + n > 8

n > 2

So n must be an integer greater than 2 and less than 14.

n can be 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, or 13.

There are 11 possible integers.

[tex] \LARGE{ \boxed{ \rm{ \purple{Answer}}}}[/tex]

We know,

Sum of two sides of a triangle > Third side

Then,

⇛ 6 + 8 > n

⇛ 14 > n

Nextly,

Difference of two sides of a triangle < Third side

Then,

⇛ 8 - 6 < n

⇛ 2 < n

Then, Range of third side:

☃️ 2 < n < 14

Possible measures of 3rd sides = 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 or 13.

There are 11 possible values of 3rd side. Out of them, any measure is the length of 3rd side.

━━━━━━━━━━━━━━━━━━━━

What is m Round the answer to the nearest whole number.
O 30°
O 35°
O 55°
O 60°

Answers

Answer:

30

Step-by-step explanation:

fufyfuf7fjcjcufuy7fufucyyxyvkbuvufudydy shut up

Please answer this question now

Answers

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

What is the slope of the line containing the midpoint of the segment with endpoints at (2, 4) and (0, -2) and the midpoint of the segment with endpoints at (5, 1) and (1, 5)?Express your answer in simplest form. Plzzzz help!!!!

Answers

Answer:

slope = 1

Step-by-step explanation:

midpoint of (2, 4) and (0, -2)

(2 + 0)/2 = 1 and (4 + -2)/2 = 1

(1, 1)

midpoint of (5, 1) and (1, 5)

(5 + 1)/2 = 3 and (1 + 5)/2 = 3

(3, 3)

slope = (3-1)/(3-1) = 2/2 = 1

Please help me!! I'll give brainliest btw

Answers

Answer:

e. cannot be determined

Step-by-step explanation:

m = 1/2( x + x + 10) = 1/2(2x + 10) = x + 5

n = 1/2(x² + x + 10) =

m/n = (x+5)/(1/2(x² + x + 10))

Not enough information

Given the equation y = 2x + 3 what is the slope?
x
3
2
idk

Answers

Answer:

The slope is 2

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question the equation is

y = 2x + 3

Comparing this equation with the general equation above

Slope / m = 2

Hope this helps you

Other Questions
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