Three vertices of parallelogram WXYZ are W(-5,2), X(2,4), and Z(-7, -3). Find the coordinates of vertex Y

2 liters per hour is equal to 555.6 millimeters per second.

To convert 2 liters per hour to millimeters per second, you need to follow these steps:

Step 1: Convert liters to milliliters

Since 1 liter = 1000 milliliters, multiply 2 by 1000 to get the number of milliliters per hour.

Therefore, 2 liters per hour is equal to 2000 milliliters per hour.

Step 2: Convert hours to seconds

Since 1 hour = 3600 seconds, divide the number of milliliters per hour by 3600 to get the number of milliliters per second.

Therefore, 2000 milliliters per hour is equal to 0.5556 milliliters per second.

Step 3: Convert milliliters to millimeters

Since 1 milliliter is equal to 1 cubic centimeter (cc) and 1 cc is equal to 1 cubic millimeter, 0.5556 milliliters per second is equal to 0.5556 cubic millimeters per second or 555.6 millimeters per second (since there are 1000 cubic millimeters in a milliliter).

Therefore, 2 liters per hour is equal to 555.6 millimeters per second.

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To determine the percentage of shots that the goalie saved, we need the actual numbers of saves and goals scored against the goalie. Since the specific values are not provided in the question, it is not possible to calculate the exact percentage.

However, I can explain the general process for calculating the percentage of savings.

To find the percentage of saves, we need to divide the number of saves by the total number of shots and then multiply by 100. The formula for calculating the percentage is:

Percentage of saves = (Number of saves / Total number of shots) * 100

For example, if the goalie made 30 saves out of 40 total shots, the calculation would be:

Percentage of saves = (30 / 40) * 100 = 75%

In this case, the goalie saved 75% of the shots.

Without the specific values of saves and shots, it is not possible to determine the exact percentage.

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(a) The landscaper needs 3 times the sum of the length and width of the yard in meters for the fencing.

(b) The area of the garden is one-third of the area of the yard, multiplied by 2.25.

We have,

(a) To find the amount of fencing needed, we need to determine the perimeter of the yard in meters.

According to the scale, 2 cm on the drawing represents 3 m in reality. This means that 1 cm on the drawing represents 1.5 m in reality (since 3 m divided by 2 cm is 1.5 m/cm).

Let's assume the length of the yard in the drawing is L cm and the width is W cm.

Then, the length of the actual yard would be L x 1.5 m, and the width would be W * 1.5 m.

The perimeter of the yard is given by the formula:

Perimeter = 2 x (length + width)

Substituting the actual measurements, we have:

Perimeter = 2 x (L x 1.5 m + W x 1.5 m)

= 3 x (L + W) m

Therefore, the landscaper would need 3 times the sum of the length and width of the yard in meters for the fencing.

(b) The area of the garden can be determined by calculating 1/3 of the area of the actual yard.

Let's assume the area of the yard in the drawing is A square cm. Then, the area of the actual yard would be A x (1.5 m)², since each dimension is scaled by 1.5 m/cm.

To find the area of the garden, we calculate:

Area of garden = (1/3) x Area of yard

= (1/3) x (A x (1.5 m)^2)

= (1/3) x (A x 2.25) square meters

Therefore, the area of the garden would be one-third of the area of the yard, multiplied by 2.25.

Thus,

(a) The landscaper needs 3 times the sum of the length and width of the yard in meters for the fencing.

(b) The area of the garden is one-third of the area of the yard, multiplied by 2.25.

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The expression "x - 12" can be modeled in a real world situation where you are trying to find the difference between a number x and 12. Here is an example:Suppose you have a jar containing x marbles.

You give away 12 marbles to your friend. The number of marbles you have left in the jar can be modeled by the expression "x - 12". In this situation, x represents the original number of marbles in the jar, and 12 represents the number of marbles given away to your friend. The expression "x - 12" calculates the number of marbles you have left after giving away 12.

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Ned will have travelled 2/9 mile after 1 hour

From the question, we have the following parameters that can be used in our computation:

Ned walked 1/9 of a mile in one 1/2

using the above as a guide, we have the following:

Rate = (1/9)/(1/2)

Evaluate the the quotient

Rate = 2/9

This means that he will have travelled 2/9 mile after 1 hour

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The end behaviors of the graph of the function are given by:

as x → −∞, f(x) → ∞

as x → ∞, f(x) → ∞

Thus, this is the required answer.

Solution:

The given polynomial function is of degree 2 (quadratic function).f(x) = ax² + bx + c, Where a, b, and c are real numbers with a ≠ 0.

The quadratic function has the general form: f(x) = a(x - r)(x - s)where r and s are the x-intercepts.

The given x-intercepts are (-2,0) and (2,0) which means that:r = -2 and s = 2.

So, the quadratic function can be written as:

f(x) = a(x - (-2))(x - 2)f(x) = a(x + 2)(x - 2), where a is a non-zero constant.The y-intercept is (0,-4).

We know that the y-intercept occurs where x = 0.

Substituting x = 0 and y = -4 in the quadratic function:

f(x) = a(x + 2)(x - 2)

when x = 0,

y = -4.

-4 = a(0 + 2)(0 - 2)

=> -4 = -4a

=> a = 1

The quadratic function is:

f(x) = (x + 2)(x - 2)

The end behaviors of the graph of the function are given by:

as x → −∞, f(x) → ∞

as x → ∞, f(x) → ∞

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The equation is 38.25 = 4.25h and Tomás worked for 9 hours.

To find the number of hours it took Tomás to clean the garage, we can set up an equation using the given information.

Let's assume the number of hours Tomás worked is "h."

We know that Tomás was paid $4.25 per hour, so the total amount he earned can be calculated by multiplying the hourly rate by the number of hours worked:

Total earnings = Hourly rate * Number of hours

In this case, the total earnings are $38.25, and the hourly rate is $4.25:

$38.25 = $4.25 * h

To solve for "h," we need to isolate the variable on one side of the equation. We can do this by dividing both sides of the equation by $4.25:

$38.25 / $4.25 = h

Simplifying the right side:

9 = h

Therefore, it took Tomás 9 hours to clean the garage.

By setting up the equation and solving it, we determined that Tomás worked for 9 hours.

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The length of overline A'B' after the dilation is 1/2 of the length of overline AB. The measure of angle A′ is 28°.

Given:AABC is dilated by a factor of to produce 1/2 triangle A′B′C′. A (62 degrees), B (16), C. To find:A′B′ and the measure of angle A′.Using the concept of dilations:Now, we need to find the measure of angle A′.Here, A′ is the image of A after the dilation.Since AABC is dilated by a factor of to produce 1/2 triangle A′B′C′.Therefore, the measure of angle A′ = 28°.Hence, the main answer is,The length of overline A'B' after the dilation is 1/2 of the length of overline AB. The measure of angle A′ is 28°.

As we know that, Dilations are like scaling and resizing. It is a transformation that changes the size of a shape but not its orientation or position. It is also called scaling by a factor. There are two types of dilations. They are:Enlargement: The new shape is larger than the original. The scaling factor is greater than 1.Reduction: The new shape is smaller than the original.The length of A′B′ is 1/2 of the length of AB.Measure of angle A′:Here, A′ is the image of A after the dilation.Since AABC is dilated by a factor of to produce 1/2 triangle A′B′C′.Therefore, the measure of angle A′ = 28°.The length of overline A'B' after the dilation is 1/2 of the length of overline AB. The measure of angle A′ is 28°.

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The area or amount of cloth that will be required to make the sail of the boat is 50.5 square feet (approx.).

Given that the boom of a sailboat is 26 feet long and the sail is an equilateral triangle. We have to determine the amount of cloth that will be required to make the sail of the boat.

The formula to calculate the area of an equilateral triangle is:

A = (√(3)/4)*a²,

where

A represents the area of the equilateral triangle

a represents the side of the equilateral triangle.

Here, the sail is an equilateral triangle.

Therefore, the length of each side of the sailboat is given as:

Length of each side of the sailboat = 26 feet / 3

                                                          = 8.67 feet or 8 feet (approximately)

We can calculate the area of the sail using the below formula;

A = (√(3)/4)×a²,

where,

A represents the area of the equilateral triangle

a represents the length of each side of the sailboat.

By substituting the value of a = 8.67 in the above equation, we get the area of the sail as follows:

A = (√(3)/4)×a²

A = (√(3)/4)*(8.67)²

A = 50.5 square feet (approx.)

Hence, the amount of cloth that will be required to make the sail of the boat is 50.5 square feet (approx.).

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According to given information, option C is the correct answer.

Given that Darrel divided 8,675 by 87.

His work is shown below.

Step 1: Set up the problem with the dividend under the division symbol and the divisor outside.

Step 2: Estimate a reasonable quotient and place it above the dividend. Then multiply and subtract. Bring down the next digit of the dividend.

Step 3: Repeat step 2 until the dividend has been brought down completely.

The given picture shows the steps done:

Option C: Darrel forgot to place a zero in the quotient.

Thus option C is the correct answer.

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Ali has hired Mark and Alexis to work for his shipping company, and Mark can load a truck with packages in 120 minutes, while Alexis can load the same number of packages in 240 minutes.

To find out how long they will take to load a truck together, we'll use the formula below:T = (T₁ × T₂) ÷ (T₁ + T₂)Where T is the time it takes for Mark and Alexis to load a truck together, T₁ is the time it takes for Mark to load a truck alone, and T₂ is the time it takes for Alexis to load a truck alone.

We can plug in the given values: T = (120 × 240) ÷ (120 + 240) = 28,800 ÷ 360 = 80Therefore, it would take Mark and Alexis 80 minutes to load a truck together.

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When a straight angle is split into two angles, the sum of those angles is 180 degrees because a straight angle measures 180 degrees.

Let's assume that the smaller angle is represented by x. Since the larger angle is twice as big as the smaller angle, it can be represented as 2x. Therefore, the sum of the two angles can be expressed as:

x + 2x = 180 degrees This simplifies to 3x = 180 degrees.

Dividing both sides by 3, we get: x = 60 degrees.

This means that the smaller angle is 60 degrees and the larger angle is twice as big, or 2(60) = 120 degrees.

Therefore, the two angles are 60 degrees and 120 degrees.

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The actual width of the rectangular swimming pool is given as 28 feet. Jason's drawing is made to a scale of 1 inch : 4 feet.

To find out how many inches wide Jason's drawing is, we need to divide the actual width of the pool by the scaling factor (4 feet).

28 feet / 4 feet = 7

Therefore, Jason's drawing of the pool is 7 inches wide.

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The growth of Manchester during the Industrial Revolution gave rise to several issues that had significant social, economic, and environmental implications.

As a result, reactions to these issues emerged and evolved over the course of the nineteenth century.

One major issue raised by the growth of Manchester was poor working and living conditions for the working class. Rapid industrialization led to the establishment of large factories and mills, which attracted workers from rural areas. These workers often faced long working hours, low wages, and hazardous working conditions. They lived in overcrowded and unsanitary slums, lacking proper housing, sanitation, and access to basic amenities. These harsh conditions resulted in widespread poverty, disease, and social unrest.

In response to these issues, various movements and reforms emerged throughout the nineteenth century. The labor movement gained momentum as workers organized themselves to demand better working conditions, higher wages, and shorter hours. The formation of trade unions aimed to protect workers' rights and negotiate with employers. Additionally, reformers such as Robert Owen and the Chartists advocated for social and political reforms to address the plight of the working class.

Another issue that arose with the growth of Manchester was environmental degradation. The rapid expansion of industries led to pollution of air and water sources. Factories emitted smoke and pollutants, contributing to air pollution and poor air quality. Rivers and streams became contaminated with industrial waste and sewage, leading to water pollution and health hazards.

As awareness of these environmental issues grew, there were efforts to address them. The establishment of legislation and regulations aimed to control pollution and improve public health. For example, the Alkali Act of 1863 imposed restrictions on the emission of harmful gases from factories. These measures, although limited, marked the beginning of environmental consciousness and attempts to mitigate the negative impact of industrialization.

Furthermore, the growth of Manchester highlighted class divisions and inequalities. The wealthy factory owners and industrialists thrived while the working class suffered. This socioeconomic divide led to social tensions and movements advocating for greater equality and social reforms.

Throughout the nineteenth century, the issues raised by the growth of Manchester prompted a gradual transformation in society. Reactions to these issues ranged from grassroots movements to legislative reforms. Although progress was often gradual and incremental, the recognition of the hardships faced by the working class and the need for improved working conditions, social reforms, and environmental conservation laid the groundwork for future advancements in labor rights, social equality, and environmental protection.

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Given, Aika is building a square garden. She places a garden post at (3.5, 3.5)

To find: The location of the corner that reflects (3.5, 3.5) across the y-axis.

We know that the y-axis is the vertical line through the point (0,0) and it divides the plane into two parts: left and right. When we reflect a point across the y-axis, the x-coordinate changes sign. For example, the reflection of (2,3) is (-2,3).Therefore, the reflection of (3.5, 3.5) across the y-axis is (-3.5, 3.5)

Since Aika is building a square garden, the corner opposite to (3.5, 3.5) will have coordinates (-3.5, -3.5).

Hence, the location of the corner that reflects (3.5, 3.5) across the y-axis is (-3.5, -3.5).

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The statement "m∠PQT is 9" is false.In the given scenario, ray QS bisects ∠PQR. This means that ∠PQS and ∠SQR are equal in measure because they are the two halves of the same angle.

Let's denote the measure of ∠PQS as (7x - 6)° and the measure of ∠SQR as (4x + 15)°. Since these two angles are equal, we can set up an equation: (7x - 6) = (4x + 15). Solving this equation, we find x = 7.

Now, to find the measure of ∠PQT, we need to substitute the value of x into the expression (7x - 6)°. Plugging in x = 7, we get (7 * 7 - 6)° = 43°. Therefore, the correct statement should be "m∠PQT is 43," not 9. Thus, the statement "m∠PQT is 9" is false.

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Based on the given description, the best description for this histogram would be that it has 2 clusters.

A histogram with 2 clusters indicates that the data is divided into two distinct groups or categories. In this case, the groups likely represent different ranges of science grades. The first cluster may correspond to grades in the range of 50-59, while the second cluster may represent grades in the range of 70-79.

The term "symmetrical" does not apply to this description, as it refers to a distribution where the data is evenly distributed around a central value. However, based on the given information, the focus is on the presence of two distinct clusters in the histogram.

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The measure of segment QS can be determined by adding the lengths of QR and RS. In this case, since QR is 10 units long and RS is 7 units long, the measure of QS would be 17 units.

To find the measure of segment QS, we need to add the lengths of QR and RS. Given that QR is 10 units long and RS is 7 units long, we can calculate the measure of QS by adding these two lengths together. Therefore, QS = QR + RS = 10 + 7 = 17. Hence, the measure of segment QS is 17 units. By adding the lengths of the two segments that make up QS, we obtain the total length of the segment itself.

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The amount of lemonade left after the consumption of 280 ml of lemonade by 14 children is 4.08 liters. The given problem can be solved by using basic mathematical operations. In the problem, it is shown that there are 14 children at the birthday party, and each child drinks 280 ml of lemonade.

And, 8 liters of lemonade are also available. The solution of the problem is as follows:

1 litre of liquid = 1000 ml of liquid

8 liters of liquid = 8 × 1000

                   = 8000 ml of liquid

Now, we can calculate the total lemonade consumed by the 14 children as follows:

Total lemonade consumed = 14 × 280

                                          = 3920 ml of liquid

                                      = 3.92liters of liquid

Therefore, the amount of lemonade left after 14 children have consumed 280 ml of lemonade each is given by:

Amount of lemonade left = 8 − 3.92

                                = 4.08liters of liquid

Therefore, 4.08 liters of lemonade is left after the 280 ml of lemonade consumption by 14 children. The problem is calculating the amount of lemonade left after 14 children have consumed 280 ml of lemonade each. To solve the problem, we first need to calculate the total amount of lemonade consumed by the 14 children. We know that each child consumed 280 ml of lemonade.

Now, we can calculate the amount of lemonade left after 14 children have consumed 280 ml of lemonade each. The amount of lemonade left is given by the difference between the total amount of lemonade available and the total lemonade consumed by the 14 children.

Therefore,

Amount of lemonade left = Total lemonade available − Total lemonade consumed

                                     = 8000 − 3920

                               = 4080 ml of liquid

                            = 4.08litres of liquid

Therefore, 4.08 liters of lemonade is left after the 280 ml of lemonade consumption by 14 children.

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Therefore, the probability of a randomly chosen boy having a height less than 66 inches is 15.87%.

The heights of the Lincoln High School boys have a normal distribution with a mean height of 70 inches and a standard deviation of 4 inches. The probability of a randomly chosen boy having a height less than 66 inches is asked. We can solve this problem by using the standard normal distribution or z-distribution. The standard normal distribution has a mean of zero and a standard deviation of one. It is a normal distribution that has been transformed to have a mean of 0 and a standard deviation of 1. Therefore, we must convert the given values into z-scores. The z-score formula is:
z = (x - μ) / σ
where x is the value we are interested in, μ is the mean, and σ is the standard deviation.
In this problem, we want to find the probability that a boy's height is less than 66 inches, so x = 66. Using the formula above, we get:
z = (66 - 70) / 4 = -1
This means that a boy's height of 66 inches is one standard deviation below the mean. To find the probability of a boy having a height less than 66 inches, we look up the area to the left of the z-score of -1 in the standard normal distribution table. The table gives us the probability of a randomly chosen boy having a height less than 66 inches as 0.1587 or 15.87%.
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The definite integral ∫(0 to 2) f(x)√(16 - x^4) dx, using u-substitution (u = x^2), simplifies to ∫(0 to 4) f(√u)√(16 - u^2) (1/2) du. The specific value of the integral depends on the function f(x) provided.

To solve the integral ∫(0 to 2) f(x)√(16 - x^4) dx using u-substitution, we begin by letting u = x^2. This choice of substitution allows us to simplify the expression and integrate with respect to u instead of x.

First, we need to find the differential du in terms of dx. Differentiating u = x^2 with respect to x, we have du = 2x dx.

Next, we substitute u and du into the integral. The limits of integration will also change accordingly. When x = 0, u = (0)^2 = 0, and when x = 2, u = (2)^2 = 4. The new integral becomes ∫(0 to 4) f(x)√(16 - x^4) dx = ∫(0 to 4) f(√u)√(16 - u^2) (1/2) du.

Now, we can evaluate the integral with respect to u, and then substitute back u = [tex]x^{2}[/tex] to obtain the final result.

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The first five terms of the sequence defined by the explicit formula an = (-2)^(n-1) are 1, -2, 4, -8, 16.

To find the first five terms of the sequence defined by the explicit formula an = (-2)^(n-1), we can substitute the values of n from 1 to 5 into the formula and calculate the corresponding terms:

The explicit formula for the sequence is given by an = (-2)^(n-1).

When n = 1: a1 = (-2)^(1-1) = (-2)^0 = 1

When n = 2: a2 = (-2)^(2-1) = (-2)^1 = -2

When n = 3: a3 = (-2)^(3-1) = (-2)^2 = 4

When n = 4: a4 = (-2)^(4-1) = (-2)^3 = -8

When n = 5: a5 = (-2)^(5-1) = (-2)^4 = 16

Therefore, the first five terms of the sequence are:

1, -2, 4, -8, 16

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Marcus’s average speed is 2 miles per hour less than Jane’s average speed.

From the given information, it is stated that Marcus's average speed is 2 miles per hour less than Jane's average speed. Therefore, Marcus's average speed is slightly slower than Jane's average speed. This can be observed on the graph where Marcus's line would be slightly below Jane's line.

The equation given for Jane's average speed is y = 6x, where x represents the number of hours and y represents the number of miles. This equation implies that for every hour Jane runs, she covers 6 miles. Marcus's average speed, being 2 miles per hour less than Jane's, would be represented by the equation y = 6x - 2. Thus, for every hour Marcus runs, he covers 6 miles minus 2 miles, which is 4 miles.

In conclusion, Marcus's average speed is 2 miles per hour less than Jane's average speed. This means that Jane has a slightly faster pace than Marcus during the marathon.

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The midpoint of the line segment connecting two points can be found by averaging their corresponding coordinates. Therefore, to obtain the midpoint of line BC, we add the coordinates of B and C and divide by 2.

Midpoint of line BC is given by:

\[\left(\frac{-1-3}{2},\frac{1-1}{2},\frac{2+0}{2}\right)=(-2,0,1)\]

The length of line AD is found by using the distance formula, which is given as:

\[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\]

Thus, we need to find the coordinates of point D and A to determine the length of AD. The coordinates of D are the average of the coordinates of B and C.

\[\left(\frac{-1-3}{2},\frac{1-1}{2},\frac{2+0}{2}\right)=(-2,0,1)\]The coordinates of A are (1,2,-1).

The distance between A and D is found by substituting these values into the distance formula:

\[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\] \[d=\sqrt{(1-(-2))^2+(2-0)^2+(-1-1)^2}\] \[d=\sqrt{(3)^2+(2)^2+(-2)^2}\] \[d=\sqrt{9+4+4}\] \[d=\sqrt{17}\]

Thus, the distance between points A and D is sqrt(17).Therefore, the midpoint of line BC is (-2,0,1) and the distance between points A and D is sqrt(17).

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`The measure or dimensions of the shorter sides will be 2.65 cm, given that the longer sides measure 40. 5 centimeters and the shorter sides measure 34. 5 centimeters and the scale-factor used for reduction is 13.

Given that,

The longer sides of the rectangular measure 40.5 cm.

The shorter sides of the rectangular measure 34.5 cm.

Scale factor = 13.

The scale factor is the ratio of the length of a side of one figure to the length of the corresponding side of the second figure.

To find the measure of the shorter sides of a rectangle, multiply the length of the shorter sides by the scale factor.Abby decides to reduce the scale drawing of her living room by a scale factor of 13.

Multiply 34.5 cm by 1/13 to find the length of the shorter sides in the reduced scale drawing as follows;`

34.5*1/13=2.65

The measure of the shorter sides will be 2.65 cm.

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Given that Aaron ate half as much pizza as David and Aaron ate 1/4 of a pie, we can determine the fraction of the pie David ate by setting up an equation and solving for it.

Let's assume that David ate x amount of pizza, which represents the fraction of the pie he consumed. Since Aaron ate half as much pizza as David, we can express Aaron's portion as (1/2)x. We are also given that Aaron ate 1/4 of a pie, so we can set up the equation:

(1/2)x = 1/4

To solve for x, we can multiply both sides of the equation by 2 to eliminate the fraction:

2 * (1/2)x = 2 * (1/4)

x = 1/2

Therefore, David ate 1/2 of the pie. This means that Aaron ate half as much pizza as David, while David consumed the remaining half of the pie.

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The number line can be used to determine the sum of the location of point T and -1 1/2. By visually representing the positions of these points on the number line, we can determine their sum by adding their locations.

To determine the sum of the location of point T and -1 1/2, we can plot the point T on the number line and then locate -1 1/2 on the number line. We can then add the locations of these points on the number line to find their sum.

For example, if point T is located at 3 on the number line and -1 1/2 is located at -1.5, we can add 3 and -1.5 to find their sum, which would be 3 + (-1.5) = 1.5.

By using the number line, we can visually represent the locations of the points and perform addition to find their sum accurately.

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Both methods will yield the same result, which represents the probability of not seeing all three colors when drawing three balls with replacement from the given urn. The answer in this case is 3/4.

(a) Using the inclusion-exclusion principle, we define events W, G, and R for the white, green, and red balls not appearing, respectively. To calculate the probability that we did not see all three colors, we use the formula P(W U G U R) = P(W) + P(G) + P(R) - P(W ∩ G) - P(W ∩ R) - P(G ∩ R) + P(W ∩ G ∩ R). Each individual probability can be calculated by considering the number of ways each event can occur divided by the total number of possible outcomes. For example, P(W) = (3/4)^3, P(G) = (3/4)^3, P(R) = (1/2)^3, P(W ∩ G) = (2/4)^3, and so on.

(b) In the direct computation method, we calculate the probability of not seeing all three colors by subtracting the probability of seeing all three colors from 1. The probability of seeing all three colors is calculated by considering the number of ways to select one ball of each color divided by the total number of possible outcomes. There are 4 possible outcomes for each ball drawn, so the probability of seeing all three colors is 4/4 * 4/4 * 2/4 = 1/4. Therefore, the probability of not seeing all three colors is 1 - 1/4 = 3/4.

Both methods will yield the same result, which represents the probability of not seeing all three colors when drawing three balls with replacement from the given urn. The answer in this case is 3/4.


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To find the probability that we did not see all three colors when drawing 3 balls with replacement from an urn containing 1 white, 1 green, and 2 red balls, we can use the inclusion-exclusion principle or calculate directly by counting the number of ways.

To find the probability that we did not see all three colors, we can use two different calculations.

(a) Let W be the event that the white ball did not appear, G be the event that the green ball did not appear, and R be the event that the red ball did not appear. We can use the inclusion-exclusion principle to calculate the probability:

P(W ∪ G ∪ R) = P(W) + P(G) + P(R) - P(W ∩ G) - P(W ∩ R) - P(G ∩ R) + P(W ∩ G ∩ R)

(b) Alternatively, we can directly compute the probability by counting the number of ways that we did not see all three colors and dividing by the total number of possible outcomes.

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Hence, the correct option is B) 11.1.

Given that Suzy had been working for 15 minutes when she finished problem 5 and she completed all 20 questions in 45 minutes.To find what fraction of the questions Suzy had finished when she finished problem 5; we need to subtract the time taken to finish problem 5 from total time and divide it by total time and the multiply it by 20. The answer can be rounded off to the nearest tenth if necessary.

Fraction of questions completed by Suzy = [(45-15)/45] × 20= 0.556 × 20= 11.12

As we see that Suzy had completed 11.12 questions when she finished the fifth problem.

Therefore, rounding it to the nearest tenth, the decimal form of the answer is 11.1.

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The algebraic property that could be used to rewrite 4x + 2y as 2y + 4x is option C: Commutative Property of Addition.

From the question. if   a, b and c are any numbers,

Based on Associative Property of Addition, it state that:

a + ( b + c ) = ( a + b ) + c

Based on Associative Property of Multiplication, it state that:

a(bc) = (ab)c

Based on Commutative Property of Addition it state that:

a + b = b + a

Based on Commutative Property of Multiplication it state that:

ab = ba

Note that , 4x + 2y = 2y + 4x

So, Commutative Property of Addition is used in the expression.

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See text below

Which algebraic property could be used to rewrite 4x + 2y as 2y + 4x? A. Associative Property of Addition

B. Associative Property of Multiplication

C. Commutative Property of Addition

D. Commutative Property of Multiplication