there are 225 calories in a 45 gram candy bar what is the unit rate​

Answer:

Sequence number is a list of numbers that are linked by rule.

The statement that is true about the quadratic equation is (b) There are two complex solutions.

From the question, we have the following parameters that can be used in our computation:

y = 12 – 11x + 7

Express properly

So, we have

y = 12x² – 11x + 7

Next, we calculate the discriminant using

d = b² - 4ac

Where

a = 12

b = -11

c = 7

Substitute the known values in the above equation, so, we have the following representation

d = (-11)² - 4 * 12 * 7

Evaluate

d = -215

This value is less than 0

This means that it has complex solutions

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Answer:

Step-by-step explanation:

16x^2 = (4x)^2

49 = 7^2

16x^2 - 49 = (4x)^2 - (7)^2

Answer:

88 ft^3

Step-by-step explanation:

First find the volume of the rectangular prism on the left

V = l*w*h = 2*(4)*8 = 2*4*8= 64 ft^3

Then find the volume of the rectangular prism on the bottom

The base is not 5 but 5-2 since we used 2 on the left side

V = l*w*h = (5-2) *4*2 = 3*4*2 = 24 ft^3

Add them together

64+24=88

Answer:

40 degrees

Step-by-step explanation:

The formula for calculating the sum of interior angles is ( n − 2 ) × 180 (n = Number of sides)

in this scenario you have 9 sides so put it in the equation.

(9 - 2) ×180 = 1260

1260 is the sum of all the interior angles so we must divide this number by the number of sides to get the angle of one individual interior angle.

1260/9 = 140

180-140 = 40 degrees

Answer:

Option B, $2020.00

Step-by-step explanation:

Volume of the pool,

12×5×14.5+4×5×7

= 1010 ft³

each cubit foot costs $2, so 1010 ft³ will cost,

1010×$2

= $2020

Number of links = 100

Shape of each link = Circle

Radius = 2.5

Area = πr²

= 3.14×2.5×2.5

= 19.625

Now for 100 links

19.625×100

1962.5Cm²

Cost = 1962.5 × 0.06

= $117.75

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If each link is made of thin silver wire and is in the shape of a circle of radius 2.5 cm, the value of the silver chain is $94.20.

To find the value of the silver chain, we need to calculate the total length of the silver wire used in making the chain and then multiply it by the cost per centimeter.

Each link in the chain is a circle with a radius of 2.5 cm. The circumference of a circle can be calculated using the formula 2πr, where r is the radius.

In this case, the circumference of each link is:

Circumference = 2 * 3.14 * 2.5 cm = 15.7 cm

Since there are 100 links in the chain, we multiply the circumference of each link by 100 to get the total length of the silver wire used:

Total length = 15.7 cm/link * 100 links = 1570 cm

Now, we can calculate the value of the chain by multiplying the total length of the silver wire by the cost per centimeter:

Value of the chain = 1570 cm * $0.06/cm = $94.20

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Answer:

x=5

y=2

w= -5

Step-by-step explanation:

We have that the two matrix are equal, so all corresponding elements are equal.

X-Y=3

From the second row and second column, we have y=2

so x-2=3

x=5

From the third row and the first column, we have w= - 5

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ) , then

A (2, 0 ) → A' (2, 0 )

B (4, 1 ) → B' (4, - 1 )

C (6, - 4 ) → C' (6, 4 )

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

A' (2, 0 ) → A'' (- 2, 0 )

B' (4, - 1 ) → B'' (- 4, - 1 )

C' (6, 4 ) → C'' (- 6, 4 )

Answer:

60cm

Step-by-step explanation:

3×4×5

you multiply each side together

Answer:

10cm² (check explanation)

Step-by-step explanation:

using the formular;

A = ½ x Base x Height

(You did not specify which one is base etc)

I'll use any parameter;

If height = 5cm, base = 4cm

The area = (5 x 4)/2

= 20/2

= 10cm²

Answer:

SA = 112

Step-by-step explanation:

A = 2wl + 2lh + 2hw

length = 8 km

width = 2 km

height = 4 km

SA = 112 km

Answer:

IU = 161

Step-by-step explanation:

Angle Formed by Two Secants=  1/2 (difference of Intercepted Arcs)

42 = 1/2 (7m+5 - (3m-1))

Distribute the minus sign

42 = 1/2 (7m+5 - 3m+1))

Combine like terms

42 = 1/2 ( 4m+6)

Distribute the 1/2

42 = 2m+3

Subtract 3 from each side

42-3 = 2m+3-3

39 = 2m

Divide by 2

19.5 = m

The sum of the arcs = 360

IU+ 3m-1 + 7m+5 = 360

IU +10m+4 = 360

IU +10(19.5) +4 = 360

IU +195+4 = 360

IU = 360 - 199

IU=161

Answer:

B

Step-by-step explanation:

sin(theta) = perpendicular/hypotenuse

sin(34)=x/12

होय साहेब!!!!!!!!!!

Answer:

B

Step-by-step explanation:

the decay will cause loss so it's the function B

Answer:

B

Step-by-step explanation:

trust

Answer:

27

Step-by-step explanation:

Triangle proportionality theorem: when you draw a line parallel to one side of a triangle, it'll intersect the other two sides of the triangle and divide them proportionally

[tex]\frac{26}{39}=\frac{18}{x}[/tex]

Cross multiply and you get 702=26x

x=27

Answer:

x=27

Step-by-step explanation:

-We can use the triangle proportionality theorem: if line parallel to a side of a triangle intersects the other two sides, then it divides those sides proportionally.

-we write the proportion and solve for x

[tex]\frac{39}{26} =\frac{x}{18}[/tex]

[tex]x= \frac{39*18}{26}[/tex]

x= 27

As in the picture.hope it helps.......

Plzzzz mark brainlist if correct.....

Answer:

[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]

Step-by-step explanation:

we would like to solve the following trigonometric equation:

[tex] \rm \displaystyle \sin(x) \cos(3x) + \cos(x) \sin(3x) = \tan( {140}^{ \circ} ) [/tex]

the left hand side can be rewritten using angle sum indentity of sin which is given by:

[tex] \rm \displaystyle \sin( \alpha + \beta ) = \sin( \alpha ) \cos( \beta ) + \cos( \alpha ) \sin( \beta ) [/tex]

therefore Let

Thus substitute:

[tex] \rm \displaystyle \sin(x + 3x) = \tan( {140}^{ \circ} ) [/tex]

simplify addition:

[tex] \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) [/tex]

keep in mind that sin(t)=sin(π-t) saying that there're two equation to solve:

[tex] \begin{cases} \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) \\ \\ \displaystyle \sin(\pi - 4x) = \tan( {140}^{ \circ} ) \end{cases}[/tex]

take inverse trig and that yields:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle \pi - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) \end{cases}[/tex]

add π to both sides of the second equation and that yields:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi\end{cases}[/tex]

sin function has a period of 2nπ thus add the period:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) + 2n\pi\\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi + 2n\pi\end{cases}[/tex]

divide I equation by 4 and II by -4 which yields:

[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} - \frac{n\pi}{2} \end{cases}[/tex]

recall that,-½(nπ)=½(nπ) therefore,

[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} + \frac{n\pi}{2} \end{cases}[/tex]

by using a calculator we acquire:

[tex] \begin{cases} \rm \displaystyle x \approx - {14.3}^{ \circ} + \frac{n\pi}{2} \\ \\ \displaystyle x \approx {59.3}^{ \circ} + \frac{n\pi}{2} \end{cases}[/tex]

hence,

the general solution for: for the trig equation are

[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]

Answer:

Me = no it doesn't....

you = why tho

me = becoz function not given .....

so lame joke ik...

Answer:

f(5) = -2

Step-by-step explanation:

f (x) = -x + 3

Let x = 5

f(5) = -5+3

f(5) = -2

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{f(x) = -x + 3}\\\huge\boxed{\rightarrow}\huge\text{ f(x) = -5 + 3}\\\huge\boxed{\rightarrow}\huge\text{ y = -5 + 3}\\\huge\boxed{\rightarrow}\text{ y = -2}\\\\\\\boxed{\boxed{\huge\text{Answer: \bf f(x) = -2}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

definition of perpendicular lines

Answer:

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

1.5+2.5+2+4=10 b/c the figure is the half of the biger lines

The perimeter of the quadrilateral EFGH is 10 units.

Perimeter is the total length of the boundary of a closed shape. The perimeter of the polygon is measured as the sum of all the sides.

For the given situation,

The diagram shows the two quadrilaterals ABCD and EFGH.

The quadrilaterals are similar, ABCD ≅ EFGH. So their ratios are equal.

Here BC = 5.0, FG = 2.5

⇒ [tex]\frac{FG}{BC} =\frac{2.5}{5.0}[/tex]

⇒ [tex]\frac{1}{2}[/tex]

So the lengths of EFGH is half than that of ABCD.

Then the lengths of EFGH are 2.5, 2.0, 4.0, 1.5

Thus the perimeter of EFGH is

Perimeter = Sum of all sides

⇒ [tex]Perimeter = 2.5+2.0+4.0+1.5[/tex]

⇒ [tex]Perimeter = 10.0[/tex]

Hence we can conclude that the perimeter of the quadrilateral EFGH is 10 units.

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the value of 4 tenths x hundreds.

4000

Answer:

40

Step-by-step explanation:

4/10 x 100 = 40

Answer:

x = 65 degrees

Step-by-step explanation:

x° + x° + 50° = 180°

2x + 50° = 180°

2x = 180° - 50°

2x = 130°

x = 130°/2

x = 65°

Answer:

(1/21)(21×5^(x+2)-4×5^2x)

Step-by-step explanation:

5^(x+2)-4×5^x÷21×5^x

= 5^(x+2)-4×5^2x/21

= 1/21(21×5^(x+2)-4×5^2x)

Answer:

Step-by-step explanation:

This is classic right triangle trig. If you're solving for x, which you are, you have to consider how the given sides relate to that angle. The side with a length of 50 is opposite the angle x, while the side of length 36 is adjacent to angle x. The trig ratio that utilizes the sides opposite and adjacent is tangent; HOWEVER, we are looking for a missing angle. Finding missing angles on your calculator requires the 2nd button. To find the missing angle x, you are looking for the angle that has a tangent ratio of 50 over 36 (opposite over adjacent...Toa in SohCahToa). Hit the 2nd button on your calculator and then the tangent button (in degree mode, not radian mode) and you will see this on your screen:

[tex]tan^{-1}([/tex]

After the parenthesis, enter the fraction and then hit the enter button to get the angle measure in degrees:

[tex]tan^{-1}(\frac{50}{36})=54.2[/tex] degrees.

It's very important that you learn how to use your calculator to find the trig identities that give you the ratio in decimal form and how to find the missing angles. Missing angles always use the 2nd button along with whatever trig identity you are using.