There are 13 dolls in a line. In how many different ways can they be arranged?

Answer:

HT = 17 cm

<T = 58°

<H = 32°

Step-by-step explanation:

✔️Find HT:

Since it's a right triangle, we would apply the Pythagorean Theorem given as c² = a² + b²

Where,

a = HW = 15 cm

b = WT = 8 cm

c = HT

Plug in the values:

HT² = 15² + 8²

HT² = 289

HT = √289

HT = 17 cm

✔️Find <T by applying trigonometric ratio formula:

Recall: SOH CAH TOA

Reference angle (θ) = <T

HW = 15 cm = Opposite side length

WT = 8 cm = Adjacent side length

Apply CAH:

Cos θ = Adj/Hyp

Substitute

Cos T = 8/15

T = [tex] cos^{-1}(0.5333) [/tex]

T ≈ 58°

✔️Find <H:

Sun of interior angles of a triangle = 180°

Therefore,

m<H + m<T + m<W = 180°

Substitute

m<H + 58° + 90° = 180°

m<H + 148° = 180°

m<H = 180° - 148°

m<H = 32°

Answer:

boat = 18

current = 2

Step-by-step explanation:

Let the speed of the current = y

Let the speed of the boat = x

x + y = 20

x - y  = 16         Add

2x = 36            Divide by 2

x = 18

The speed of the boat = 18

x + y = 20

18 + y = 20         Subtract 18

y = 20 - 18

y = 2

Answer:

100-35=65

15*0.65=9.75

so the price now is 9.75

Hope This Helps!!!

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see this attachment

Answer:

There is overwhelming evidence that human activities, especially burning fossil fuels, are leading to increased levels of carbon dioxide and other greenhouse gases in the atmosphere, which in turn amplify the natural greenhouse effect, causing the temperature of the Earth's atmosphere, ocean, and land surface to ...

Answer:

[tex]b\geq 9[/tex]

In other words, the base must be at least 9 feet long.

Step-by-step explanation:

The schools wants the height of the triangle to be eight feet, and the area of the logo to be at least 36 square feet.

Recall that the area of a triangle is given by:

[tex]\displaystyle A = \frac{1}{2}bh[/tex]

Since we want to area to be at least 36 square feet:

[tex]\displaystyle \frac{1}{2}bh \geq 36[/tex]

We are given that the height is eight feet. Substitute:

[tex]\displaystyle \frac{1}{2}(8)b\geq 36[/tex]

Simplify:

[tex]4b\geq 36[/tex]

Divide both sides by four. Hence, our inequality is:

[tex]b\geq 9[/tex]

In words, this means that the base must be at least 9 feet long.

Answer:

91 hundreths, (1*1)+(9*1/10), .19

<3 love from maddie

Answer:

(1*1)+(9*1/10) then 91 hundreths and last 0.19

Hope it helps!

Answer:

72

Step-by-step explanation:

180/2.5

= 72

Answer:

V =48 cm^3

Step-by-step explanation:

The volume of a prism is given by

V = l*w*h

V = 3*4*4

V =48 cm^3

V =48 cm^3

Step-by-step explanation:

The volume of a prism is given by

V = l*w*h

V = 3*4*4

V =48 cm^3

An ellipse is a plane curve that surrounds two focus points and has a constant sum of the two distances to the focal points at all places on the curve. In the graph, the A represents the minor axis of the ellipse.

Suppose that the major axis is of the length 2a units, and that minor axis is of 2b units, and let the ellipse is centered on (h,k) with major ellipse parallel to x-axis, then the equation of that ellipse would be:

[tex]\dfrac{(x-h)^2}{a^2} + \dfrac{(y-k)^2}{b^2} =1[/tex]

Coordinates of its foci would be: (h±c, k) where c² = a² - b²

If its major axis is parallel to y-axis, then,

coordinates of its foci would be:  (h, k±c) where c² = a² - b² and its equation would be:

[tex]\dfrac{(x-h)^2}{b^2} + \dfrac{(y-k)^2}{a^2} =1[/tex]

An ellipse is a plane curve that surrounds two focus points and has a constant sum of the two distances to the focal points at all places on the curve. Since an ellipse has two diameter, the major and the minor diameter. Therefore, in the graph, the A represents the minor axis of the ellipse.

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The function is negative for all real values of x where x < -3 or x > -1 and the domain of the function is -∝ < x < ∝

The domain of a function is the set of values that we are allowed to plug into our function. This set is the x values in a function such as f(x). The range of a function is the set of values that the function assumes. This set is the values that the function shoots out after we plug an x value in.

The range is the set of outputs of a relation or function. In other words, it's the set of possible y values. Recall that ordered pairs are of the form (x,y) so the y coordinate is listed after the x. The output is listed after the input.

Given data ,

Let the function be represented as f ( x )

Now , the value of f ( x ) is

f ( x ) = - ( x + 3 ) ( x - 1 )   be equation (1)

Now , the values of x which makes the function negative are

when x < -3

f ( x ) = - ( -ve ) ( -ve ) = -ve

when x > 1

f ( x ) = - ( +ve ) ( +ve ) = -ve

So , the domain of the function is all real numbers and -∝ < x < ∝

Hence , the function is solved

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Answer: LM = 23

Step-by-step explanation:

Solve the algebraic equations:

Line KN: (solve for x)

[tex]14x-3=25[/tex]

move the 3 to the other side with addition

[tex]14x=28[/tex]

divide by 14 to get x by itself

[tex]x=2[/tex]

Now that we have x we can find line KL:

[tex]9(2)+5\\18+5\\23[/tex]

So we now know that KL is 23 units. And we know that KL = LM

Answer:36/6

Step-by-step explanation:

1. multiply by 3 on both the bottom and top.

2. the reason being : they have the same factors of 3

Answer:

y = 2x - 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (2, - 5) into the partial equation

- 5 = 4 + c ⇒ c = - 5 - 4 = - 9

y = 2x - 9 ← equation of line

Answer:

The equation of the circle is given by:

(x-a)^2+(y-b)^2=r^2

where:

(a,b) is the center  of the circle

given that the center of our circle is (2,3) with the radius of 5, the equation will be:

(x+2)^2+(y+3)^2=5^2

expanding the above we get:

x^2+4x+4+y^2+6y+9=25

this can be simplified to be:

x^2+4x+y^2+6y=25-13

x^2+y^2+4x+6y=12

Answer:

[tex]\sf\longrightarrow \boxed{\sf x^2+y^2-4x-6y-12=0}[/tex]

Step-by-step explanation:

Here we are given the radius of circle as 5cm and the centre of the circle is (2,3) . We need to find the equation of the circle. Here we can yse the Standard equation of circle to find the equation .

Standard equation of circle :-

[tex]\sf\implies \green{ (x - h )^2+(y-k)^2 = r^2 }[/tex]

Substitute the respective values ,

[tex]\sf\longrightarrow ( x - 2 )^2 + ( y - 3)^2 = 5^2 [/tex]

Simplify the whole square ,

[tex]\sf\longrightarrow x^2 + 4 -4x + y^2+9-6y = 25[/tex]

Rearrange and add the constants ,

[tex]\sf\longrightarrow x^2 + y^2 -4x -6y +13 = 25 [/tex]

Subtract 25 on both sides ,

[tex]\sf\longrightarrow x^2 +y^2-4x-6y+13-25=0[/tex]

Simplify ,

[tex]\sf\longrightarrow \boxed{\blue{\sf x^2+y^2-4x-6y-12=0}}[/tex]

First, we'll set up two equations. One for the amount of each coin and another for the value of the coins.

N will represent nickels

D will represent dimes

N + D = 30

---The problem tells us that there are 30 total coins

0.05N + 0.10D = 2.95

---Nickels are worth 5 cents and dimes are worth 10 cents, and the total value of the coins is 2.95

Now that we have our equations, we need to solve for one of the variables in the first equation. I will solve for N.

N + D = 30

N = 30 - D

Then, we take that equation and substitute our new value for N into the second equation (value) and solve for D.

0.05(30 - D) + 0.10D = 2.95

1.5 - 0.05D + 0.10D = 2.95

1.5 + 0.05D = 2.95

0.05D = 1.45

D = 29

Now that we know how many dimes there are, we can plug that value into our equation for N and solve for N.

N = 30 - D

N = 30 - 29

N = 1

Therefore, there are 29 dimes and 1 nickel.

Hope this helps!

Answer:

2663.0 cm³ (3 s.f.)

Step-by-step explanation:

[tex]\boxed{volume \: of \: sphere = \frac{4}{3}\pi {r}^{3} }[/tex]

Radius= diameter ÷2

Radius of sphere

= 17.2 ÷2

= 8.6 cm

Volume of sphere

[tex] = \frac{4}{3} (3.14)(8.6)^{3} [/tex]

= 2663.0 cm³ (3 s.f.)

Answer:

Value of given expression x is -4

Step-by-step explanation:

Given equation in question;

4 + 2|3x + 4| = -4

Find:

Value of given expression

Computation:

4 + 2|3x + 4| = -4

Using BODMAS rule;

⇒ 4 + 2|3x + 4| = -4

⇒ 2|3x + 4| = - 4 - 4

⇒ 2|3x + 4| = - 8

⇒ |3x + 4| = - 8 / 2

⇒ |3x + 4| = - 4

⇒ 3x + 4 = - 8

⇒ 3x = -8 - 4

⇒ 3x = -12

⇒ x = -12 / 3

⇒ x = -4

Value of given expression x is -4

Answer:

I don't know the answer to this question

The simplified form of the expression √2x(7 + √2x) is 7√2x + 2x.

Option A is the correct answer.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

To simplify the expression √2x(7 + √2x), we can use the distributive property of multiplication, as follows:

√2x(7 + √2x) = √2x (7) + √2x √2x

= 7√2x + √(2x * 2x)

[since √a x √b = √(ab)]

= 7√2x + √(4x^2)

= 7√2x + 2x

Therefore,

The simplified form of the expression √2x(7 + √2x) is 7√2x + 2x.

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Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

[tex]R =(5,5)[/tex]

[tex]S= (2,1)[/tex]

[tex]T = (1,3)[/tex]

LMN

[tex]L = (0,-1)[/tex]

[tex]M= (2,-4)[/tex]

[tex]N= (-2,-3)[/tex]

Required

Compare both areas

The area of triangle is:

[tex]Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|[/tex]

For RST, we have:

[tex]Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|[/tex]

[tex]Area = \frac{1}{2}|-10|[/tex]

Remove absolute signs

[tex]Area = \frac{1}{2}*10[/tex]

[tex]Area = 10[/tex]

For LMN, we have:

[tex]Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|[/tex]

[tex]Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|[/tex]

[tex]Area = \frac{1}{2}|-14|[/tex]

Remove absolute signs

[tex]Area = \frac{1}{2}*14[/tex]

[tex]Area = 7[/tex]

By comparing both areas, we can conclude that LMN has a larger area

Answer:

area = 40 [tex]\pi[/tex] [tex]m^{2}[/tex]

vol = 32  [tex]\pi[/tex] [tex]m^{3}[/tex]

Step-by-step explanation:

area :

cir = 2  [tex]\pi[/tex]i 2 = 4 [tex]\pi[/tex]

area =  [tex]\pi[/tex] 2^2 = 4  [tex]\pi[/tex]

2(4 [tex]\pi[/tex]) + 8(4 [tex]\pi[/tex])

8  [tex]\pi[/tex] + 324 [tex]\pi[/tex] = 40  [tex]\pi[/tex]

vol = 8 * 4 [tex]\pi[/tex] = 32  [tex]\pi[/tex]

Answer:

-3 =x

Step-by-step explanation:

The angles are corresponding angles and corresponding angles are equal if the lines are parallel

2x+9 = 7x+24

Subtract 2x from each side

2x+9-2x = 7x+24-2x

9 = 5x+24

Subtract 24 from each side

9-24 = 5x

-15 = 5x

Divide by 5

-15/5 = 5x/5

-3 =x

Answer:

C

Step-by-step explanation:

y coordinates must be at the numerator, while x coordinates at the denominator

Answer:

An inverse variation give a harder one next time

Step-by-step explanation:

Answer:

504 cm²

Step-by-step explanation:

Let the length and the width of the rectangle be L cm and W cm respectively.

Perimeter= 2(L +W)

2(L +W)= 108

L +W= 108 ÷2

L +W= 54

L= 54 -W -----(1)

[tex] \frac{L}{W} = \frac{7}{2} [/tex]

Cross multiply:

2L= 7W -----(2)

Substitute (1) into (2):

2(54 -W)= 7W

Expand:

108 -2W= 7W

+2W on both sides:

9W= 108

Divide both sides by 9:

W= 108 ÷9

W= 12

Substitute W= 12 into (1):

L= 54 -12

L= 42

Area of rectangle

= length ×width

= LW

= 42(12)

= 504 cm²

Answer:

Following are the solution to the given question:

Step-by-step explanation:

For question 1:

Calculating the speed between A and B:

[tex]Time\ (t)= 1 \ hours\\\\Distance\ (d)= 10 \ km\\\\V=\frac{d}{t}=\frac{10}{1}= 10 \ kmph[/tex]

For question 2:

Calculating the speed between B and C:

[tex]Time\ (t)= (2-1)=1 \ hours\\\\Distance\ (d)= (15-10)= 5\ km\\\\V=\frac{d}{t}=\frac{5}{1}= 5 \ kmph\\[/tex]  

For question 3:

In this the speed between A and B is the double to speed between B and C.

Answer:

B. False

Step-by-step explanation:

There is not enough information to make that conclusion. The two statements are completely unrelated, so the transitive property cannot be used. None of the given statements say that ABC is congruent to MNO or PQR. That means that nothing can be assumed about DEF. To use the transitive property you would need proof that ABC=MNO or ABC=PQR. But neither of those statements are there so the answer is false.

Answer:

true

Step-by-step explanation:

a pe c

Answer:

[tex]-7x^2+x+9=-6x[/tex]

[tex]-7x^2+x+9+6x=-6x+6x[/tex]

[tex]-7x^2+7x+9=0[/tex]

[tex]quadratic\: formula[/tex]

[tex]x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}[/tex]

[tex]\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}[/tex]

[tex]x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}[/tex]

[tex]\frac{-7+\sqrt{301}}{2\left(-7\right)}[/tex]

[tex]=\frac{-7+\sqrt{301}}{-2\cdot \:7}[/tex]

[tex]=\frac{-7+\sqrt{301}}{-14}[/tex]

[tex]\frac{-7-\sqrt{301}}{2\left(-7\right)}[/tex]

[tex]=\frac{-7-\sqrt{301}}{-2\cdot \:7}[/tex]

[tex]=\frac{-7-\sqrt{301}}{-14}[/tex]

[tex]answer=\frac{7+\sqrt{301}}{14}[/tex]

[tex]OAmalOHopeO[/tex]

Answer:

D

Step-by-step explanation:

We are given the two functions:

[tex]f(x) = 5x^2-x+1 \text{ and } g(x) = -3x[/tex]

And we want to find:

[tex](f \circ g)(1)[/tex]

Recall that this is equivalent to:

[tex]=f(g(1))[/tex]

Evaluate g(1):

[tex]g(1) = -3(1) = -3[/tex]

Substitute:

[tex]=f(-3)[/tex]

Evaluate f(-3):

[tex]f(-3)=5(-3)^2-(-3)+1=49[/tex]

Therefore:

[tex](f \circ g)(1) =49[/tex]

Our answer is D.

Answer:

49

Step-by-step explanation:

ƒ(x) = 5x2 – x + 1 and g(x) = –3x

(ƒ ∘ g)(1)

First find g(1) = -3(1) = -3

Then find f(g(1) = f(-3)

f(-3) = 5(-3)^2 - (-3) +1 = 5(9) +3+1 = 45+4 = 49