The town of Lakehorn is built on a grid system. Town hall is located downtown at point (0,0). A new school is located 3 miles north and 2 miles east of town hall. Only students who live outside a 5-mile radius from the school are eligible to ride the school bus. Which of the following students are eligible to ride the bus? Select all that apply.

Answer:

I think album is another name of CD.

Answer:

Step-by-step explanation:

Answer:

a. 6

Step-by-step explanation:

AB +BC =AC

2x-2+2x+10=32

4x+8=32

4x=32-8

4x=24

x=24/4

x=6

Answer:

The answer is "6000".

Step-by-step explanation:

It seems to be a total of 30 buddies there. Every column has 10 seats so that the 10 pals are now in a row. Of all the other 20 buddies, 10 are on the following row. And we have ten friends remaining and that they are sitting in the next row.

Therefore the possibility of sitting is:

[tex]30 \times 20 \times 10 = 6000[/tex]

Answer:

Step-by-step explanation:

Exponent laws:

[tex](a^{m})^{n}=a^{m*n}\\\\a^{-m}=\frac{1}{a^{m}}[/tex]

[tex](t^{\frac{15}{27}}x^{9}})^{\frac{-2}{3}}= \ t^{\frac{15}{27}*\frac{-2}{3}}*x^{9*\frac{-2}{3}}\\\\\\= t^{\frac{5}{9}*\frac{-2}{3}}*x^{3*-2}\\\\=t^{\frac{-10}{27}}x^{-6}\\\\=\frac{1}{t^{\frac{10}{27}}x^{6}}[/tex]

Answer:

894

Step-by-step explanation:

this can be "split" into 3 rectangles.

their areas can be easily calculated. and then we simply sum them all up for the answer.

rectangle 1 on the top

R1 = 5×9 = 45

rectangle 2 in the middle

R2 = (19+5)×(35-9-15) = 24×11 = 264

rectangle 3 at the bottom

R3 = 39×15 = 585

and all together

45+264+585 = 894

Hello!

14.8 = n - 0.3

n - 0.3 = 14.8

n = 14.8 + 0.3

n = 15.1 → value of n

Good luck! :)

Answer:

D: n = 15.1

Step-by-step explanation:

14.8 = n minus 0.3

14.8= n - 0.3

14.8    - is +
+
0.3
=
15.1
:D if u need help with more just ask!
I love this kind of math.

Answer:

V₂ = V₁

Step-by-step explanation:

Let the height of the rectangular prism = h

Let s represent the side length of the base of the square prism, we have;

The volume of the prism, [tex]V_{prism}[/tex] = s²·h

The volume of the square pyramid, [tex]V_{pyramid}[/tex] = (1/3)·s²·h

∴ V₁ = The area not taken up by the square pyramid = [tex]V_{prism}[/tex] - [tex]V_{pyramid}[/tex]

∴ V₁ = s²·h - (1/3)·s²·h = (2/3)·s²·h

Similarly, for the cylinder, we have;

Let h represent the height of the cylinder

Let r represent the radius of the base of the cone, we have;

Therefore;

The volume of the cylinder, [tex]V_{cylinder}[/tex] = π·r²·h

The volume of the cone, [tex]V_{cone}[/tex] = (1/3)·π·r²·h

∴ V₂ = π·r²·h - (1/3)·π·r²·h = (2/3)·π·r²·h

V₂ = (2/3)·π·r²·h

[tex]V_{cone}[/tex] = [tex]V_{pyramid}[/tex]

Therefore;

(1/3)·π·r²·h = (1/3)·s²·h

∴ π·r² = s²

Therefore, V₂ = (2/3)·π·r²·h = V₂ = (2/3)·s²·h = V₁

V₂ = V₁.

Answers:

3 chocolate cones

1 strawberry cones

===========================================================

Explanation:

Let's isolate the variable c in the first equation

c+s = 4

c = 4-s

we subtract s from both sides to get c all by itself. This will then be plugged into the second equation. I'm using the substitution property.

1.75c + 1.3s = 6.55

1.75(4-s) + 1.3s = 6.55 ..... replace c with 4-s

1.75*4 + 1.75*(-s) + 1.3s = 6.55

7 - 1.75s + 1.3s = 6.55

-0.45s + 7 = 6.55

-0.45s = 6.55 - 7

-0.45s = -0.45

s = -0.45/(-0.45)

s = 1

So he bought 1 strawberry cone. Use this value of s to find c

c = 4-s

c = 4-1

c = 3

This says he also bought 3 chocolate cones.

-------------------

As a check, we see that c+s = 3+1 = 4, showing that he bought 4 cones total.

Also,

1.75c + 1.3s = 1.75*3 + 1.3*1 = 6.55

indicating he spent $6.55 total for the four cones. This matches with what the instructions tell us, so the answer is confirmed.

Answer:

Step-by-step explanation:

[tex]\left \{ {{c+s=4} \atop {1.75c+1.3s=6.55}} \right.[/tex]

1.75c + 1.75s = 1.75 × 4 ........ (1)

1.75c + 1.3s = 6.55 ........ (2)

(1) - (2)

0.45s = 0.45 ⇒ s = 1

c + 1 = 4 ⇒ c = 3

[ 3 ] chocolate  [ 1 ] strawberry

Answer:

15/X

Step-by-step explanation:

a number divided by 15

15/X

Answer:

[tex]m\angle A= 30^{\circ}[/tex]

Step-by-step explanation:

In the question, we're given [tex]\angle A\cong \angle D[/tex]. Therefore, the measure of these two angles must be equal.

To find the value of [tex]x[/tex], set these two angles equal to each other:

[tex]4x-26=x+16[/tex]

Add 26 and subtract [tex]x[/tex] from both sides:

[tex]3x=42[/tex]

Divide both sides by 3:

[tex]x=\frac{42}{3}=14[/tex]

Since [tex]\angle A[/tex] was labelled as [tex]4x-26[/tex], substitute [tex]x=14[/tex] to find its measure:

[tex]\angle A=4(14)-26,\\\angle A=56-26,\\\angle A=\boxed{30^{\circ}}[/tex]

You can also substitute [tex]x=14[/tex] into the label of angle D as angle A is congruent to angle D for easier calculations ([tex]14+16=\boxed{30^{\circ}}[/tex]).

Given: Given that a citizen have 97 silver coins.

To find : Here we need to find that how many bronze coins would it take to equal this amount.

Solution: We know, 1 silver coin=10 bronze coin

So, 97 silver coin=10×97 bronze coin

=970 bronze coin

Therefore, 970 bronze coins would it take to equal this amount.

Answer:

x=30

Step-by-step explanation:

Hi there!

For A to be parallel to B, 5x would be equal to 3x+60. (If they were parallel, these two angles would be alternate exterior angles, which are equal.)

[tex]5x=3x+60[/tex]

Subtract 3x from both sides

[tex]5x-3x=3x+60-3x\\2x=60[/tex]

Divide both sides by 2

[tex]x=30[/tex]

I hope this helps!

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Given,

ΔABC ≅ ΔXYZ

If these 2 triangles are congruent with each other then,

∠ A = ∠ X [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

∠ B = ∠ Y [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

∠ C = ∠ Z [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]

Now,

We saw that ∠ C = ∠ Z.

⟹ So, if ∠ C = 32°, then even ∠ Z will be equal to 32°. [tex]\boxed{\sf{Equal \ angles \ have \ equal \ measurements}}[/tex]

ᶛɲƧཡэʀ ↦ C. m ∠X = 32°

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

no..........................

Work Shown:

sin(angle) = opposite/hypotenuse

sin(F) = EG/FE

sin(F) = 56/65

Refer to the diagram below.

Step-by-step explanation:

7 people = 280 liters

1 p = 40 liters

50 p = 40 x 50

50 p = 2000 liters

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

the answer is D

Step-by-step explanation:

Answer:

See explanation

Step-by-step explanation:

Function A is not clear; I will use the following in place of function A

Function A:

[tex]x \to\ 1 |\ 3 |\ 4 |\ 6[/tex]

[tex]y \to -1|\ 3|\ 5|\ 9[/tex]

Function B:

[tex]y = 2x + 4[/tex]

Required

Compare both functions

For linear functions, we often compare the slope and the y intercepts only.

Calculating the slope of function A, we have:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex](x_1,y_1) = (1,-1)[/tex]

[tex](x_2,y_2) = (3,3)[/tex]

So, we have:

[tex]m = \frac{3 - -1}{3 - 1}[/tex]

[tex]m = \frac{4}{2}[/tex]

[tex]m = 2[/tex]

To calculate the y intercept, we set [tex]x = 0[/tex], then solve for y

i.e.[tex](x,y) = (0,y)[/tex]

Using the slope formula, we have:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex]m = 2[/tex]

[tex](x_1,y_1) = (0,y)[/tex]

[tex](x_2,y_2) = (3,3)[/tex]

So, we have:

[tex]2 = \frac{3 - y}{3 - 0}[/tex]

[tex]2 = \frac{3 - y}{3}[/tex]

Multiply by 3

[tex]6 = 3 - y[/tex]

Collect like terms

[tex]y = 3 - 6[/tex]

[tex]y = -3[/tex]

So, for function A:

[tex]m = 2[/tex] -- slope

[tex]y = -3[/tex] --- y intercept

For function B

[tex]y = 2x + 4[/tex]

A linear function is represented as:

[tex]y = mx + b[/tex]

By comparison

[tex]m = 2[/tex] --- slope

[tex]b = 4[/tex] --- y intercept

By comparing the results of both functions, we have the following conclusion:

Functions A and B have the same slope (i.e. 2)

Function B has a greater y intercept (i.e. 4)

Answer:

AC is greater than BC

Step-by-step explanation:

First, we know that the angle of a straight line is 180°, so angle B as a whole is equal to 180 degrees. Therefore, angle YBC + angle ABC = 180 degrees. As angle YBC is a right angle, signified by the small square on the angle, it is 90 degrees. Therefore,

90 degrees + angle ABC = 180 degrees

subtract 90 degrees from both sides to isolate angle ABC

angle ABC = 90 degrees

Therefore, as angle ABC is equal to 90 degrees, and a right angle is 90 degrees, triangle ABC has a right angle, making it a right triangle.

In a right triangle, using the Pythagorean Theorem, the square of the side opposite the right angle is equal to the sum of the squares of the other side. Since side AC is opposite the right angle, we can say that

AC² = AB² + BC²

As the length of a side has to be greater than 0, we can say that

AC² = AB² + BC²

AB² > 0

AC² > BC²

square root both sides

AC > BC

Therefore, AC is greater than BC

Here we are provided with a diagram of a triangle. We need to find out the length of the segment LM . As we can see that ,

∆ KNL ≈ MNL , [ By AAS ]

Therefore ,

⇒ KN = MN

⇒ 14x - 3 = 25

⇒ 14x = 25 + 3

⇒ 14x = 28

⇒ x = 2

Put this x = 2 in LM :-

⇒ LM = 9x + 5

⇒ LM = 9*2 + 5

⇒ LM = 18 + 5

⇒ LM = 23

Hence the required answer is 23 .

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = \pm 5[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow \sqrt{x^2}=\sqrt{25}\\\\\rightarrow \boxed{x = \pm 5}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]x = 5 \: \: \: or \: \: \: x = - 5[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 25 = 0 \\ {x}^{2} - {5}^{2} \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5[/tex]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

hope it helps...

correct me if I'm wrong...

Given:

The inequality is:

[tex]-3x-4<2[/tex]

To find:

The values that are solutions to the given inequality.

Solution:

We have,

[tex]-3x-4<2[/tex]

Adding 4 on both sides, we get

[tex]-3x-4+4<2+4[/tex]

[tex]-3x<6[/tex]

Divide both sides by -3 and change the inequality sign because -3 is a negative value.

[tex]\dfrac{-3x}{-3}>\dfrac{6}{-3}[/tex]

[tex]x>-2[/tex]

Therefore, all the real values greater than -2 are the solutions to the given inequality.

Answer:

65 m²

Step-by-step explanation:

Area 1 :-

Area 2 :-

Area 3 :-

Total Area :-

Answer:

[tex]=2x^2+3xy-2y^2[/tex]

Step-by-step explanation:

When given the following problem;

[tex](2x-y)(x+2y)[/tex]

Distribute, multiply every number in one of the parenthesis by every number in the other;

[tex](2x-y)(x+2y)\\=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)[/tex]

Simplify,

[tex]=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)\\=2x^2+4xy-xy-2y^2\\=2x^2+3xy-2y^2[/tex]

Therefore, the final answer is;

[tex]=2x^2+3xy-2y^2[/tex]

............................

...............................................................................................................................................................................................................................................................................................................