the tape diagram represents an equation write an equation to represent the image​

Answer:

g+h+(j+k)

Step-by-step explanation:

(g+h)+j+k

(g+k)+j+h

(g+j)+h+k

(k+h)+j+h

(j+h)+g+k

Answer:

1 and 3

Step-by-step explanation:

dont mind me this needed to be longer wait still needs no be longer

Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

Answer:

Step-by-step explanation:

Let the price for children and adults package be represented with x and y respectively.

For the first week the sum of the package will be as follows:

3x+8y = 126

For the two weeks after:

6x+4y= 108

So, we will be having two equations

3x+8y = 126..... (1)

6x+4y= 108.......(2)

These are simultaneous equations

From equation 1

3x+8y = 126

3x = 126-8y

X = 126-8y/3 ............. (3)

Put equation 3 into 2

6 ( 126-8y)/3 +4y = 108

756-48y/3 +4y = 108

756-48y+12y/3 = 108

Cross multiplying

756-48y+12y= 108×3

756-48y+ 12y = 324

Collecting like terms

756-324 = 48y-12y

432= 36y

Divide both sides by 36

432/36 = 36y/36

y= 12

Substituting y into equation 1

3x+8= 126

3x+96=126

3x= 126-96

3x= 30

Divide both sides by 3

3x/3 = 30/3

x = 10

Hence for each of the packages for children and adults. It will be 10 and 12 respectively.

Answer:

24

Step-by-step explanation:

Answer:

300 meters^2

Step-by-step explanation:

10 meters radius

10^2 x pi is about 100 x 3=300

Answer:

t ≥ 18

Step-by-step explanation:

He has run 12 miles plus some more miles t.  He need to run at least 30 miles

12+t ≥ 30

Subtract 12 from each side

12+t-12 ≥ 30-12

t ≥ 18

Answer:

t 》18

Step-by-step explanation:

t + 12 》30

t 》30 - 12

t 》18

Answer:

Choose answers B and D

Step-by-step explanation:

Answer:

Choose answers B and D.

Step-by-step explanation:

Answer:

75

Step-by-step explanation:

87-12= 75

edg2020

Answer: Reduction

(0,0)

1/3

Step-by-step explanation:

Answer:

1-reduction

2-(0,0)

3-1/3

Step-by-step explanation:

Answer:

88%

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Step-by-step explanation:

V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)

V = 240 + 30 + 75 + 240

V = 585 cm^3

Answer:

after paying all expenses Ron will have $10 leftover each month.

Answer:

10 on edge

Step-by-step explanation:

Answer:

8p∧2 ± p - 1 ± 13/p ± 1

Step-by-step explanation:

Divide (9p2 + 8p3 + 12) ÷ (p + 1) and it equals 8p∧2 ± p - 1 ± 13/p ± 1

Answer:

8p^2+p-1 with a remainder of 13

Step-by-step explanation:

p+1 divided by 8p^3+9p^2+0p+12

Answer:

735.13268 units^2

Step-by-step explanation:

A=2πrh+2πr2=2·π·9·4+2·π·92≈735.13268

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units

Answer:

450

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

Adjacent / Hypotenuse = 24 / 25

Answer:

b = 4a

Step-by-step explanation:

Given

a = [tex]\frac{1}{4}[/tex] b

Multiply both sides by 4 to clear the fraction

4a = b

Answer:

She must buy 90 tiles for the cost to be the same at both stores

Step-by-step explanation:

Let x be the no. of tiles bought for the cost to be the same at both stores

Margo can purchase tile at a store for $0.89 per tile at shop 1

Cost of x tiles =0.89x

She rent a tile saw for $45.

So, total cost at Store 1 = 0.89x+45

At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile.

So, cost of 1 tile = 1.39

Cost of x tiles = 1.39x

ATQ

0.89x+45=1.39x

45=1.39x-0.89x

45=0.5x

[tex]\frac{45}{0.5}=x[/tex]

90=x

Hence She must buy 90 tiles for the cost to be the same at both stores

Answer:

C

Step-by-step explanation:

Absolute Value is the distance from 0, so when you have -|22| that means its the absolute value of 22 then add the negative sign so that means it's further from 0 than |-22|.

I hope this will help.

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

[tex]TP X TQ=TR^2[/tex]

[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

Answer:

16 units

Step-by-step explanation:

The y intercept is when the x value is 0

f(0) = 2(0)+8 = 8

The y intercept of f(x) is 8  

g(0) = -8

The y intercept of g(x)  is -8

The distance between f(0) and g(0)

8 - -8 = 8+8 = 16

The beef price is $10.65

Onions price is $2.49

Potatoes are $3.29

Tomatoes are $8.45

Asparagus is $4.99

3.25 pounds of beef is          3.25 * 10.65 =  34.61

0.65 pounds of onions is      0.65 * 2.49   =  1.62

0.2 pounds of potatoes is     0.2 * 3.29     =  0.66

0.15 pounds of tomatoes is   0.15 * 8.45   =  1.27

0.33 pounds of asparagus is 0.33 * 4.99  =  1.65

Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65

This is equal to 39.81

A recipe is mixture of ingredients.

Divya will pay $39.81 for all the ingredients in the recipe.

The beef price is $10.65 per pound

So, price of 3.25 pounds of beef is ,  [tex]3.25 * 10.65 = 34.61[/tex]

Onions price is $2.49 per pound

So, price of 0.65 pounds of onions is,  [tex]0.65 * 2.49 = 1.62[/tex]

Potatoes are $3.29 per pound

So, price of 0.2 pounds of potatoes is ,  [tex]0.2 * 3.29 = 0.66[/tex]

Tomatoes price are $8.45 per pound.

So, price of 0.15 pounds of tomatoes is  , [tex]0.15 * 8.45 = 1.27[/tex]

Asparagus price is $4.99 per pound.

So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]

Hence, total amount paid by Divya is,

             [tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]

Thus, Divya will pay $39.81 for all the ingredients in the recipe.

Learn more:

https://brainly.com/question/18994792

Answer:

x=1

Step-by-step explanation:

55+70=125

sum of angles in a triangle is 180 so

180-125=55

54x+1=55

x=1

Answer: The answer is F

Step-by-step explanation:

Answer:

x=3

Step-by-step explanation:

- 3 on both sides

2x=6

divide by 2 on both sides

x=3

Answer:

x = 3

Step-by-step explanation:

[tex]2x+3=9[/tex]

Subtract 3.

[tex]2x=9-3\\2x=6[/tex]

Divide by 2.

[tex]x=\frac{6}{2}\\ x=3[/tex]

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²