The sum of 2 numbers is 250. One of them is greater than 150. Which of these is definitely true about the other number? a) It is equal to 100. b) It has to be less than 100. c) It has to be greater than 100. d) It has to be a number between 150 and 250. Please answer fast and do explain how you got the answer...

Answer:

[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]

Step-by-step explanation:

The question seem incomplete; however, the given parameter is assumed as

[tex]-3(2 + 4k) + 7(2k)[/tex]

Required

Simplify

[tex]-3(2 + 4k) + 7(2k)[/tex]

Start by opening the brackets

[tex]-3*2 -3* 4k + 7*2k[/tex]

[tex]-6 -12k +14k[/tex]

Collect Like Terms

[tex]-6 -12k +14k[/tex]

[tex]-6 + 2k[/tex]

Reorder the above expression

[tex]2k - 6[/tex]

The answer can be further simplified as

[tex]2(k - 3)[/tex]

Hence;

[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]

Answer:

a) 22:25 is the earliest time

b)15 min

Step-by-step explanation:

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

10:10(standard) = 22:10 (military)

22:10 -> 15min-> 22:25

Answer:

a) 22:25 is the earliest time

b)15 min

Because

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

Answer:

x = s/2

Step-by-step explanation:

● s states have joined the union in 1788

● half of s have joined in 1889

Let x be the number of states that have joined in 1889

● x = (1/2)× s

● x = s/2

Answer:

The answer is "all the choices were wrong"

Step-by-step explanation:

Given value:

[tex]\bold{26x^3y 47z^5r^3}[/tex]

In the given question all the choices were wrong because it is not equivalent to given equation:

In choice A) [tex]( 26x^3y 47z^5r^3 )^2[/tex] in the value is whole squared, that's why it is wrong.

In choice B) [tex](26xy)^{12} (47zr)^{12}[/tex] when we open its value it will give different values, that's why it is wrong.

In option C and D( [tex]26^{12} x^{32} y^{12} 47^{12} z^{52} r^{32}[/tex] and [tex]26x^{32} y^{12}47z^{52} r^{32}[/tex]) both values will give different values.  

Answer:

it's C

Step-by-step explanation:

I just did it

Answer:

3 kg

Step-by-step explanation:

given data

weights bag1 = 45 kg

weights bag2 = 63 kg

solution

we will take here first  HCF of 75 and 69

factor of 75 = 3 × 5 × 5

factor of 69 = 3 × 23

so here HCF of 75 and  69 = 3

so that here maximum weight required, to measure the weight of rice exact 3 times

so correct option is 3.  3 kg

Answer:

  4.  9 kg

Step-by-step explanation:

The greatest common factor of 45 kg and 63 kg is 9 kg.

  45 = 9×5

  63 = 9×7

A 9 kg weight could be used to weigh these amounts exactly.

_____

Comment on the problem statement

Appropriate formatting is helpful. It is difficult to tell that your answer choices are not 1.6, 2.35, 3.3, and 4.9. None of those makes any sense. With minimal formatting effort, you could list them as ...

1. 6 kg

2. 35 kg

3. 3 kg

4. 9 kg

Even better, the choices could be identified using letters and/or a separator other than a decimal point: A) 6 kg, B) 35 kg, and so on. The idea is to make it very clear what the numbers of the choices are. Less confusion is better.

Answer:

7/2 pi

or approximately 10.99557429

Step-by-step explanation:

2 pi sqrt( a/b)

let a = 49 and b = 16

2 pi sqrt( 49/16)

We know that sqrt( a/b) = sqrt(a) /sqrt(b)

2 pi sqrt(49) / sqrt(16)

2pi ( 7) / (16)

2 pi ( 7/4)

7/2 pi

This is the exact answer

We can make an approximation for pi

Using the pi button on the calculator

10.99557429

Answer:

23

Step-by-step explanation:

6x + 11 + 7x + 143 = 180

13x + 154 = 180

13x = 26

x = 2

m<RPS = 6(2) + 11 = 23

Answer:

5z

Step-by-step explanation:

As product = multiplication =>

5 x z --> 5(z)

[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]

Answer:

Nijah has 6 stickers left.

Step-by-step explanation:

Starting stickers:

45

2/5 are given away:

[tex]\frac{2}{5}[/tex] * 45

[tex]\frac{2}{5}[/tex] * [tex]\frac{45}{1}[/tex]

[tex]\frac{90}{5}[/tex]

18

1/3 of the remaining are given away:

[tex]\frac{1}{3}[/tex] * 18

[tex]\frac{1}{3}[/tex] * [tex]\frac{18}{1}[/tex]

[tex]\frac{18}{3}[/tex]

6

Nijah has 6 stickers left.

Answer:

18

Step-by-step explanation:

Find the part she gave to her sister

45 *2/5 = 18

The part remaining is

45 - 18 = 27

She gives 1/3 to Brett

27 * 1/3 = 9

She has 27 - 9 = 18

She has 18 remaining

Answer:

The answer is s^26/pq59

Step-by-step explanation:

Answer:

p^ -1 q ^ -59  s ^26

or without negative exponents

s^ 26 /(p q^ 59)

Step-by-step explanation:

When multiplying , we can add the exponents when the bases are the same

p^0 q ^ -60 r^-1 s^25  * p^-1 qrs

When there is no exponent written, there is an implied 1

p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)

p^ -1 q ^ -59 r ^0 s ^26

r^0 = 1

p^ -1 q ^ -59  s ^26

If you need  the negative exponents written as positive

a^-b = 1/ a^b

s^ 26 /(p q^ 59)

Answer:

(x + 9)(x - 8)

Step-by-step explanation:

f(x) = x^2 + x - 72

     = x^2 - 8x + 9x - 72

     = (x^2 - 8x) + (9x - 72)

     = x(x - 8) + 9(x - 8)

     = (x + 9)(x - 8)

Answer:

              x² + x - 72 = (x + 9)(x - 8)

Step-by-step explanation:

[tex]x^2+x-72\quad \implies\quad a=1\,,\quad b=1\,,\quad c=-72\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-72)}}{2\cdot1}=\dfrac{-1\pm\sqrt{1+288}}{2}=\dfrac{17\pm\sqrt{289}}{2}\\\\x_1=\dfrac{-1-17}{2}=-9\quad,\qquad x_2=\dfrac{-1+17}{2}=8\\\\\\x^2+x-72=(x-(-9))(x-8)=(x+9)(x-8)[/tex]

or:

     x² + x - 72 =

= x² + 9x - 8x - 72 =

= x(x + 9) - 8(x + 9) =

= (x + 9)(x - 8)

Answer:

2' 3"

Step-by-step explanation:

Here 4' 1" − 1' 10" is certainly possible, but to carry out this operation we must borrow 1', or 12", from 4' 1":

4' 1" becomes 3' 13", and so the original problem becomes

3' 13" - 1' 10"

which in turn becomes 2' 3"

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

Answer:

76 degrees.

Step-by-step explanation:

Let as consider O is the center of the circle . So from the figure it is clear that

[tex]\angle AOB=44^{\circ}[/tex]

[tex]\angle COD=118^{\circ}[/tex]

By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.

We know that, [tex]\angle BAD=97^{\circ}[/tex] and angle BOD is the central angle subtended by arc BD.

[tex]\angle BOD=2\times \angle BAD[/tex]

[tex]\angle BOD=2\times 97^{\circ}[/tex]

[tex]\angle BOD=194^{\circ}[/tex]

Now,

[tex]\angle BOD=\angle BOC+\angle COD[/tex]

[tex]194^{\circ}=\angle BOC+118^{\circ}[/tex]

[tex]194^{\circ}-118^{\circ}=\angle BOC[/tex]

[tex]76^{\circ}=\angle BOC[/tex]

[tex]m(arc(BC))=76^{\circ}[/tex]

Therefore, the measure of arc BC is 76 degrees.

Answer:

11 yd

Step-by-step explanation:

To find the volume of a rectangular prism, we multiply the width, length and height.

We already know the length, 18, and the height, 11, and the volume, 2178, so we can easily solve for y.

[tex]18\cdot y\cdot11=2178\\192y=2178\\y = 11[/tex]

Hope this helped!

Answer:

(a) (f o g)(x) =  x^2 - 15x + 54

(b) (g o f)(x) = x^2 + 3x - 9

(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d) (g o g)(x) = x - 18

Step-by-step explanation:

f(x) = x^2 + 3x

g(x) = x - 9

(a)

(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)

(f o g)(x) = x^2 - 18x + 81 + 3x - 27

(f o g)(x) = x^2 - 15x + 54

(b)

(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9

(c)

(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)

(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x

(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d)

(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18

Answer:

3250

Step-by-step explanation:

so for the first and 2nd show, the attendance is 2580 and 2920.

The average of both these numbers is 2750

the if the third show had 3000 people, the average attendance would only be 2875.

We need the average number to be 3000.

2750 is 250 less than 3000, so the other number must be 250 more.

3250 is how many people should go to the last show.

=====================================

Explanation:

We have 2580 people attend the first show and 2920 attend the second. So far, that's 2580+2920 = 5500 people. Add on another x people to get 5500+x, which represents the sum of all three days attendance figures. Divide this sum by 3 to get the average attendance

average attendance = (sum of individual attendance values)/(number of days)

average attendance = (5500+x)/3

So that's why (5500+x)/3 goes in the first box. The parenthesis are important to ensure that you divide all of "5500+x" over 3. If you just wrote 5500+x/3, then the computer would think you just want to divide x only over 3.

----------------

We set (5500+x)/3 equal to 3000 as we want the average of the three days to be 3000

(5500+x)/3 = 3000

5500+x = 3*3000

5500+x = 9000

x = 9000-5500

x = 3500

We need 3500 people to show up on day 3 so that the average of all three days is 3000.

3500 goes in the second box.

----------------

Check:

The figures for the three days are 2580, 2920, and 3500

They add to 2580+2920+3500 = 9000

Which divides to 9000/3 = 3000, which is the average we're after. So the answer is confirmed.

Answer:

[tex]\huge\boxed{d = 4 }[/tex]

Step-by-step explanation:

41 = 12d - 7

Adding 7 to both sides

41+7 = 12d

48 = 12 d

Dividing both sides by 12

4 = d

OR

d = 4

Answer:

[tex]\large \boxed{{d=4}}[/tex]

Step-by-step explanation:

[tex]41 =12d-7[/tex]

Add 7 on both sides.

[tex]41 +7=12d-7+7[/tex]

[tex]48=12d[/tex]

Divide both sides by 12.

[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]

[tex]4=d[/tex]

Answer:

Kameron is 50 years old.

Step-by-step explanation:

We can make equations and start filling in what we already know, assuming [tex]n[/tex] is Niko's age, [tex]L[/tex] is Lila's age, [tex]a[/tex] is Amber's age, and [tex]k[/tex] is Kamerons age.

Our first equation:

n = 3L

We know that Niko is 45, so

45 = 3L

Divide both sides by 3:

L = 15

So, Lila is 15 years old.

Another equation:

n = L + 3a

We already know Niko and Lila's age:

45 = 15 + 3a

Subtract 15 from both sides:

30 = 3a

Divide both sides by 3:

a = 10

So Amber is 10 years old.

Another equation:

k = 2(a + L)

We know Amber and Lila's age:

k = 2(10 + 15)

k = 2(25)

k = 50

So Kameron is 50 years old.

Hope this helped!

Answer:

Yes, we can.

Step-by-step explanation:

Hello, I found this one.

[tex]\displaystyle \sum_{n=0}^{\infty} \dfrac{1}{n!}[/tex]

We can prove that it exists and it is equal to e.

But this is nor arithmetic nor geometric.

Thank you

Answer:

n = -56

Step-by-step explanation:

n/8 = (-7)

Multiply each side by 8

n/8* 8 = (-7)*8

n = -56

Answer:

[tex]n=-56[/tex]

Step-by-step explanation:

We can use algebra and simplify the equation until we have n isolated.

[tex]\frac{n}{8} = -7\\\frac{n}{8}\cdot8 = -7\cdot8\\\\n=-56[/tex]

Hope this helped!

Answer:

Step-by-step explanation:

Given,

Cost price of 25 kg of vegetables ( CP ) = 25 × 20

= Rs 500

Loss amount = Rs 50

Selling price ( SP ) = ?

Loss percent = ?

Now, let's find the loss percent :

[tex] \mathsf{ \frac{loss}{cost \: price} \times 100\%}[/tex]

[tex] \mathsf{ = \frac{50}{500} \times 100\%}[/tex]

[tex] \mathsf{ = 10\%}[/tex]

Loss % = 10 %

Now, let's find the selling price:

[tex] \mathsf{ \frac{CP(100 - l\%)}{100} }[/tex]

[tex] \mathsf{ = \frac{500(100 - 10)}{100}} [/tex]

[tex] \mathsf{ = \frac{500 \times 90}{100} }[/tex]

[tex] \mathsf{ = \frac{45000}{100} }[/tex]

[tex] \mathsf{= 450}[/tex]

Hope I helped!

Best regards!

Answer:

24

Step-by-step explanation:

Answer

24!

Step-by-step explanation:

Person above me is correct :)

Answer:

Answers

product, and assign a number to each person. ... 0.82. 12–13. 9. 0.18. 1.00. Total. 50. 1.00. F requency. 0. 1. 2. 3. 4. 5. 6. 7. 8 ... 3.12 (a) x = 25661.3333, ˜x = 25514.5 (b) Skewed ... N(8.25, 0.0002857).

Answer:

the answer is c

Step-by-step explanation:

i just took the test

[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]

Answer:

white: 1/3, blue: 1/4, red: 5/12

Step-by-step explanation:

Take the amount of balls each color has and divide by 12.

White:

4/12 = 1/3

Blue:

3/12 = 1/4

Red:

5/12 (can't simplify)

Answer:

3/44 or 0.068

Step-by-step explanation:

(3/12 × 2/11 × 1/10)+(5/12 × 4/11 × 3/10)+(4/12 × 3/11 × 2/10)

=3/44

Answer:

5

Step-by-step explanation:

Answer:

5 (Follow PEMDAS left—>right)

Answer:

d. -4

Step-by-step explanation:

Let's plug in g

8 - |2(-3.5) - 5|

8 - |-7-5|

8 - |-12|

The absolute value is always positive of any number,

8 - 12

= -4

Answer:

D. -4

Step-by-step explanation:

We are given this expression:

[tex]8-|2g-5|[/tex]

and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.

[tex]8-|2(-3.5)-5|[/tex]

First, multiply 2 and -3.5

2 * -3.5 = -7

[tex]8-|-7-5|[/tex]

Next, subtract 5 from -7.

-7-5= -12

[tex]8-|-12|[/tex]

Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.

[tex]8-12[/tex]

Subtract 12 from 8.

[tex]-4[/tex]

The value of the expression is -4 and D is the correct answer.

Part (a)

BC = opposite side (furthest leg from the reference angle)

AB = adjacent side (closest leg from the reference angle)

AC = hypotenuse (always opposite the 90 degree angle)

=============================================

Part (b)

i. False. Angle B is 90 degrees as shown by the square angle marker.

ii. False. Side AB is opposite angle C. Note how "C" is part of "BC", so that means we cannot have BC be opposite C.

iii. True. Leg AB is the closer leg to angle A. We have "A" in "AB" to see this without having to draw the diagram. Refer to part (a) above.

iv. False. The longest side of any right triangle is always the hypotenuse. The longest side of any triangle is always opposite the largest angle.

==============================================

Part (c)

cos(theta) = adjacent/hypotenuse = AB/AC

tan(theta) = opposite/adjacent = BC/AB

Refer back to part (a) to determine the opposite,adjacent and hypotenuse side lengths.

==============================================

Part (d)

The reference angle has changed, so the opposite and adjacent sides swap. The hypotenuse remains the same regardless of what reference angle you pick.

sin(C) = opposite/hypotenuse = AB/AC

cos(C) = adjacent/hypotenuse = BC/AC

tan(C) = opposite/adjacent = AB/BC

Note the tangent ratio is the reciprocal of what we found back in part (c).

Answer & Step-by-step explanation:

(a)

The hypotenuse is on line CA (the hypotenuse is always opposite the 90° angle (marked by a little square))

The adjacent is on the line BA (adjacent is next to the given angle, but NOT the hypotenuse)

The opposite is on the line CB (this is opposite the given angle)

(b)

i.   false (b is a right angle)

ii.  false (the side opposite C is BA)

iii. true

iv. false (the side opposite B is the hypotenuse, and the hypotenuse is always the longest side in a triangle)

(c)

cosine ratio: [tex]cos=\frac{adjacent}{hypotenuse}[/tex]

tangent ratio: [tex]tan=\frac{opposite}{adjacent}[/tex]

The cosine and tangent ratios of the given angle:

[tex]cos0=\frac{AB}{CA} \\\\tan0=\frac{CB}{AB}[/tex]

(d)

Remember SOH-CAH-TOA:

Sine=Opposite/Hypotenuse

Cosine=Adjacent/Hypotenuse

Tangent=Opposite/Adjacent

Using the angle C, plug in the appropriate sides:

[tex]sinC=\frac{BA}{CA}\\\\ cosC=\frac{CB}{CA}\\\\ tanC=\frac{BA}{CB}[/tex]

:Done